Develop Reference

JavaScript parse button value to post

i have a form that contains different buttons with different values that i want to post to a controller or something equal. Here is how this could look like:
<form action="thecontroller/post" method="post" id="buttons">
<div class="select_direct">
<button class="btn_quick_select" value="A">A</button>
<button class="btn_quick_select" value="B">B</button>
<button class="btn_quick_select" value="C">C</button>
</div>
<button type="submit" name="add">
</form>
So i want to submit the selected button (A, B or C) to the controller. As i want to satisfy the Open-Close-Principle, i want to be able to do this for any amount of buttons given, so my approach ist to parse the elements by class and filter for the active one:
var buttonValue;
function getSelectedButton() {
var buttons = document.getElementsByClassName("select_direct");
buttons.foreach(function(button) {
if(button.isActive) { buttonValue = button.value; }
});
}
Is there a better way to achieve this?

So i want to submit the selected button (A, B or C) to the controller.
Sounds like you're re-inventing a radio button.
const form = document.getElementById("buttons");
form.addEventListener("submit", (e)=>{
e.preventDefault();
console.log(document.querySelector('input[name="letter"]:checked').value);
});
<form action="thecontroller/post" method="post" id="buttons">
<div class="select_direct">
A<input type="radio" value="A" name="letter" />
B<input type="radio" value="B" name="letter" />
C<input type="radio" value="C" name="letter" />
</div>
<input type="submit" name="add">
</form>

No need for JavaScript.
If you want to first click on A/B/C and then the submit button, then don't use normal buttons for A/B/C, but radio buttons and use CSS to make them look like normal buttons.
If you want to just click on A/B/C and submit immediately, remove the normal submit button and just give A/B/C type=submit.

So far what I understand form your question is that you want to POST the value of the button that is clicked. In this case you do not need a submit button. You can do it when a button is clicked. You can do it in following way:
$(".btn_quick_select").click(function(){
var btnValue = $(this).val();
//code to POST btnValue goes here...
});
Otherwise, if you want to submit then you can't do it using button. Use checkbox or radio instead. Then your markup will be look like this:
Let me konw if it is helpful for you.
<form action="thecontroller/post" method="post" id="buttons">
<div class="select_direct">
<input type="checkbox" name="xyz" value="value1">
<input type="checkbox" name="xyz" value="value2">
<input type="checkbox" name="xyz" value="value3">
</div>
<button type="submit" name="add">
</form>
And JavaScript:
$("#buttons").submit(function(e){
e.preventDefault();
var btnValue = $(this).serialize();
//code to POST btnValue goes here...
});
Hope it will be helpful. Let me know about it.

Get the value of a radio button using jquery [duplicate]

This question already has answers here:
How to check a radio button with jQuery?
(33 answers)
Closed 6 years ago.
I have this portion of code:
var checkout_options = $("#checkout").find("input[type='radio']");
$('#button-account').on('click', function () {
alert(checkout_options.value);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script>
<div id="checkout">
<p>Checkout Options:</p>
<label for="register">
<input type="radio" name="account" value="register" id="register" checked>
<b>Register Account</b></label>
<br>
<label for="guest">
<input type="radio" name="account" value="guest" id="guest">
<b>Guest Checkout</b>
</label>
<input type="button" value="Continue" id="button-account">
</div>
What I want it is to get the value of the selected radio button but with my code I only get the first radio button value, the second radio does not work.
Kindly help me fix the error.

You need to use this to refer the element inside the callback. So get value by using this.value or $(this).val() method. Although avoid :checked pseudo-class selector otherwise it only selects the first element.
var selected = $("#checkout").find("input[type='radio']");
selected.change(function(){
alert(this.value);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script>
<div id="checkout">
<p>Checkout Options:</p>
<label for="register">
<input type="radio" name="account" value="register" id="register" checked>
<b>Register Account</b></label>
<br>
<label for="guest">
<input type="radio" name="account" value="guest" id="guest">
<b>Guest Checkout</b>
</label>
</div>
You can make it simpler using :radio pseudo-class selector
$("#checkout :radio").change(function() {
alert(this.value);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script>
<div id="checkout">
<p>Checkout Options:</p>
<label for="register">
<input type="radio" name="account" value="register" id="register" checked>
<b>Register Account</b>
</label>
<br>
<label for="guest">
<input type="radio" name="account" value="guest" id="guest">
<b>Guest Checkout</b>
</label>
</div>

Your handler is only being attached to the radio button that is checked, so no handler exists for the second radio button. Attach a handler to both radio buttons:
var $radioBtn = $( "#checkout" ).find( "input[type='radio']" );
$radioBtn.on( 'change', function() {
if ( this.checked ) {
alert( this.value );
}
});

It didn't work, because you register the event handler for the initially checked value only. This is how to make it dynamically reflect the value change:
var selected = $("#checkout").find("input[name='account']");
selected.change(function(){
alert($(this).val());
});
This also makes sure that only the current radio button group is included, so you can have additional ones.
Jsfiddle:
https://jsfiddle.net/sjmhdasw/

Just use
$("input[type='radio']").on("change", function() {
console.log(this.id + " checked !");
});
It binds an event listener on all the inputs of type radio !
No need to store the selectors inside a variable (unless you're doing something with it, somewhere else in your code)

Problems with retrieving radio button value for feedback form

I'm trying to build a simple feedback form. The user will answer a series of yes or no questions. If they choose no, then they will be provided with a comment form to include text.
Currently, I'm having problems with retrieving radio button values. I am trying to print them in the console, but nothing happens when I choose the appropriate choice. If the user chooses 'no', it needs to be able to remember the comment that will get submitted.
My JSFiddle is here: http://jsfiddle.net/787x18vx/
HTML
<p>You are providing feedback</p>
<form>
<div id="question-1">
<label for="question-1">Is this correct?</label>
<input type="radio" value="yes" name="choice-1" />Yes
<input type="radio" value="no" name="choice-1" />No
</div>
<div id="question-2">
<label for="question-2">Another question</label>
<input type="radio" value="yes" name="choice-2" />Yes
<input type="radio" value="no" name="choice-2" />No
</div>
<div id="question-3">
<label for="question-3">One more question</label>
<input type="radio" value="yes" name="choice-3" />Yes
<input type="radio" value="no" name="choice-3" />No
</div>
<br />
<button>Send Feedback</button>
</form>
jQuery
var firstInput = 'input[name=choice]';
var firstInputValue = $('input[name=choice-1]:checked').val();
$(firstInput).on('click', function() {
console.log(firstInputValue);
console.log($('input[name="choice-1"]:checked').val());
console.log($('input[name="choice-2"]:checked').val());
// if value === 'no' show comment form
});

You are using input[name=choice] selector which is not exisiting.
Use input[type=radio] instead.
var firstInput = 'input[type=radio]';
var firstInputValue = $('input[name=choice-1]:checked').val();
$(firstInput).on('click', function() {
console.log(firstInputValue);
console.log($('input[name="choice-1"]:checked').val());
console.log($('input[name="choice-2"]:checked').val());
// if value === 'no' show comment form
});
Fiddle

var firstInput = 'input[name=choice]';
This is looking for something specifically with the name choice, which doesn't appear to be in your html.
There are two quick ways about this.
First, just change your selector:
$('input[type=radio]').on('click', function(){...
This will trigger the function on a click of any radio
Another way is with the wildcard selector:
var firstInput = 'input[name^=choice]';
The ^ should make is so any input with the name starting with choice gets selected.
This method should work, but targeting input[type=radio] is probably a better solution,

You are missing the -1 in your name
var firstInput = 'input[name=choice-1]';

Your selector is trying to get tags with name exactly equals 'choice'. You can search by prefix with the following
var firstInput = 'input[name|="choice"]';
This will get all tags which name starts with 'choice'

How to limit the checked checkboxes to just one at a time?

I am trying to create a filter using checkboxes. I need to only have one checkbox checked at a time. How do I do this?
Scenario: The page has a catalog of watches. The user wants to filter the watches according to for men or for women
Here is my code:
$("#filter-options :checkbox").click(function()
{
$(".collection-wrapper .strap-wrapper").hide();
$("#filter-options :checkbox:checked").each(function()
{
$("." + $(this).val()).fadeIn();
});
if($('#filter-options :checkbox').filter(':checked').length < 1)
{
$(".collection-wrapper .strap-wrapper").fadeIn();
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<h3>Filter Items</h3>
<ul id="filter-options">
<li><input type="checkbox" value="filter_man" data-filter_id="man"> Man</li>
<li><input type="checkbox" value="filter_woman" data-filter_id="woman"> Woman</li>
</ul>
<div class="collection-wrapper">
<div class="strap-wrapper filter_man">
<h2>man</h2>
<p></p>
</div>
<div class="strap-wrapper filter_woman">
<h2>woman</h2>
<p></p>
</div>
<div class="strap-wrapper filter_man filter_woman">
<h2>man / woman</h2>
<p></p>
</div>
<div class="strap-wrapper filter_woman">
<h2>woman</h2>
<p></p>
</div>
</div>
Thanks in advance!

Checkboxes are used for selecting multiple values of choices. What you need is Radio Buttons. They are used exactly for this purpose. One can select only one radio button at a time. So replace your code with:
<ul id="filter-options">
<li><input type="radio" name="filter" value="filter_man" data-filter_id="man"> Man</li>
<li><input type="radio" name="filter" value="filter_woman" data-filter_id="woman"> Woman</li>
</ul>
See an example here: http://www.w3schools.com/tags/tryit.asp?filename=tryhtml5_input_type_radio

Radio buttons are what you are looking for ;)
take at look at these links:
jQuery api demo
Fiddle example
HTML:
<form id="myForm">
<input type="radio" name="myRadio" value="1" /> 1 <br />
<input type="radio" name="myRadio" value="2" /> 2 <br />
<input type="radio" name="myRadio" value="3" /> 3 <br />
</form>
JS
$('#myForm input').on('change', function() {
alert($('input[name="myRadio"]:checked', '#myForm').val());
});

You could use radio buttons or you could do something like:
$('input[type=checkbox]').change(function(){
if ($('input[type=checkbox]:checked').length > 1) {
this.checked = false;
}
})

You could just use radio buttons, but if you want to do it with checkboxes, solution is pretty simple.
When you click on one of the checkboxes, select all the checkboxes and remove "checked" state, and then just add checked on clicked checkbox
Something like this:
// On checkbox click
$("#filter-options input[type=checkbox]").click(function(event) {
// Uncheck all checkboxes
$("#filter-options input[type=checkbox]").prop("checked", false);
// Check that one that you clicked
$(this).prop("checked", true)
});

regarding input name in javascript

Using jQuery mobile and javascript I'm attempting to produce a small quiz which would be functional on a smart phone. It isn't fully finished.
I'm attempting to create a list of radio buttons which one selected the value is carried over and submitted but why is the input name "radio=choice-v-6" when this is one of the options.
<script type="text/javascript">
var answer1 = 2;
function submit()
{
if ($('input[name=radio-choice-v-6]:checked', '#myForm').val() == answer1)
{
alert("Correct");
window.location = "#question-2"
}
else
{
alert("Incorrect");
window.location = "#incorrect"
}
}
</script>
then when I use the jQuery mobile pre-set button names I use.
<form id="myForm" name="myForm">
<fieldset data-role="controlgroup" id="radiobuttons" data-mini="true">
<input name="radio-choice-v-6" id="radio-choice-v-6a" type="radio" onclick="question1()" value="1">
<label for="radio-choice-v-6a">One</label>
<input name="radio-choice-v-6" id="radio-choice-v-6b" type="radio" onclick="question1()" value="2">
<label for="radio-choice-v-6b">Two</label>
<input name="radio-choice-v-6" id="radio-choice-v-6c" type="radio" onclick="question1()" value="3">
<label for="radio-choice-v-6c">Three</label>
</fieldset>
<td><button type="submit" id="submit" name="submit" value="Submit" onclick="submit()"></td>
</form>
I assumed I would put the input name as "radiobuttons" or "myForm"
I'm new to JavaScript and would like to know why "radio-choice-v-6" works.

'input[name=radio-choice-v-6]:checked' is the selector and targets only the radio button that is checked and has the name of radio-choice-v-6. The form in general cannot be deemed as checked and neither can the fieldset. So myForm and radiobuttons will not target the currently checked radio button.