How can accomplish a dual div swap on rollover? - javascript

I am looking for advice on a way to accomplish this. Given the following:
[Div A (contains an image)]
[Div B (contains a horizontal list of 8 or so text links)]
[Div C (contains text)]
Upon rolling over any link in Div B, how can I have Div A and Div C swap their respective contents out to something different that corresponds to the content of that link?
For example, if one were to rollover a Div B link called "Dogs", then upon that rollover, Div A would replace its contents and display an image of a dog and Div C would replace its contents and display text about dogs.
After rolling over that link, the new Div A and Div C contents will remain in place until a new link is rolled over.
I hope this makes sense. Does anyone have advice on the best way to accomplish this?

Assuming the href points to one resource that contains the content for both, but you can't just inject the entire output of the link into one element, something like this could work:
$('#divB a').mouseover(function() {
//get images from link, inject into divA
$('#divA').html('<strong>Loading...</strong>')
.load($(this).attr('href') + ' img');
//get divs from link, inject into divC
$('#divC').html('<strong>Loading...</strong>')
.load($(this).attr('href') + ' div');
});

Hmm... this should be pretty simple with jQuery (compared to some of the other answers here):
If you're unfamiliar with jQuery, the $() is a shortcut for calling jQuery(), and using
$(document).ready(function() {
// put all your jQuery goodness in here.
});
is a way to make sure jQuery fires at the right time. Read more about that here.
So first, add a class (ie .dogs) to each <a> element in your #divB list. Next, give each of the corresponding images the same class, and contain each of your text blocks in #divC in divs with the same class as well. The HTML would look something like this:
<div id="divA">
<img src="dogs.jpg" class="dogs" />
<img src="flowers.jpg" class="flowers" />
<img src="cars.jpg" class="cars" />
</div>
<div id="divB">
<ul>
<li>Dogs</li>
<li>Flowers</li>
<li>Cars</li>
</ul
</div>
<div id="divC">
<div class="dogs"><p>Text about dogs.</p></div>
<div class="flowers"><p>Text about flowers.</p></div>
<div class="cars"><p>Text about cars.</p></div>
</div>
Then use the following jQuery, putting this up in the <head> section of your HTML doc:
$(document).ready(function() {
$('a.dogs').hover(function() {
$('#divA img').hide("fast");
$('#divA img.dogs').show("fast");
$('#divC div').hide("fast");
$('div.dogs').show("fast");
});
});
We say when the document is ready, when you hover over the <a> element with the .dogs class, perform a function. That function will hide all of the images in #divA and immediately show the image with the .dogs class. Then it will hide all of the divs in the #divC and immediately show the div with the .dogs class.
You can do the same thing twice more for .flowers and .cars, or however many you have.
Keep in mind, there are more efficient ways of doing this too, if you're interested in looking deeper into jQuery, but this will be a solid way to get started in helping you understand exactly what jQuery is doing. And it keeps the script OUT of the HTML body, too!

You can change a div's contents with something like this:
<script type="text/javascript">
function over() {
var a = document.getElementById('a');
var c = document.getElementById('c');
a.style.backgroundImage = "url(/path/to/image)";
c.innerHTML = "<b>Dogs rock</b>";
}
</script>
<div id="a"></div>
<div id="b" onmouseover="over();"></div>
<div id="c"></div>
Then all you need to do is add whatever other div's you want and write code to change them appropriately. Set the initial state of A and C using css, or just call the over() function on page load.

Related

Replace image in another div with text upon mouse over elsewhere

I have tried around a dozen different ways to do this, I'm only going to post my most recent attempts though.
Basically I am trying to have it so that when a user hovers the mouse over an image on the page, another image in a separate div gets replaced with text.
I have the JS variables for the text elements to replace as well as the original image being replaced to put it back.
My most recent attempts were:
function replaceMainPage(x) {
$('#logozone').empty();
$('#logozone').append(x);
}
function hoverCircles(y) {
$(this).hover(replaceMainPage(y), replaceMainPage(mainLogo));
}
I don't really understand the "this" feature of JS, but have also tried that function as:
function hoverCircles(y) {
$('#logozone').hover(replaceMainPage(y), replaceMainPage(mainLogo));
}
From here I have tried calling the function is my main JS file like so:
$("#cir1").hover(replaceMainPage(logoReplacements.cakes), replaceMainPage(mainLogo));
As well as tried doing it in html on the img element itself with a onmouseover. Nothing has worked yet.
Am also open to non-JS ways of handling this, but I looked for those as well and couldn't find anything.
This will help you, here is a jsFiddle:
var oldContent = '';
$('.hoverMe').hover(function() {
oldContent = $('.toReplace').html();
$('.toReplace').html('xxxxxxxx');
}, function() {
$('.toReplace').html(oldContent);
});
HTML
<div class="hoverMe">
HOVER ME
</div>
<div class="toReplace">
<img src="//cdn2.hubspot.net/hub/360031/hubfs/feature_practicetest.jpg?t=1470774914678&width=365">
</div>
I've created a global variable called oldContent. When hover on the .hoverMe div, store the old content of that div, change the content of div, and when you move your mouse out, put back the old content.
UPDATE
Based on OP comment, I create another jsFiddle where you can set any text on the .hoverMe
If there are longer texts, or kind of texts what can not be stored in the data attribute, then add data-id="1" to n, and retreive the text through ajax based on the id.
HTML
<div id="firstImgDiv">
<div class="text"></div>
<img src="a.png" onmouseenter="replaceImg('secondImgDiv', 'new Text')">
</div>
<div id="secondImgDiv">
<div class="text"></div>
<img src="b.png" onmouseenter="replaceImg('firstImgDiv', 'new Text')">
</div>
JS
function replaceImg(id, text){
// show all images again
$('img').show();
// clear all text
$('.text').html('');
// hide target img
$('#'+id+' > img').hide();
// set target text
$('#'+id+' > .text').html(text);
}

Javascript: Create a new div in <body> tag

This is going to be hard to explain but I will do my best. I want to write a Javascript function that takes two parameters (title, content) and creates a <div> tag in the <body> tag. The <div> tag should look like this.
<div>
<h2>title</h2>
<p>content</p>
</div>
My javascript code looks like this:
function addElement (title, content) {
var newDiv = document.createElement("div");
var newH2 = document.createElement("h2");
var title = document.createTextNode(header);
newH2.appendChild(title);
var p = document.createElement("p");
var post = document.createTextNode(entry);
p.appendChild(post);
newDiv.appendChild(newH2);
newDiv.appendChild(p);
// Missing codes here...
}
I dont know how to finish my method. Because of I have almost hundreds of tags inside my page and I want this new tags (when a user makes a new input) will appear on same place somewhere in the middle of the html code page in order to keep things organized.
If you would like to use jQuery take a look at this fiddle: http://jsfiddle.net/panpymq2/
In my fiddle I am binding to a button press. Then I call a method that appends new generated html to the body of the page. You can enter change where you are appending the new HTML with CSS3 selectors. just modify the $("insert selector there").append...
UPDATE
As per the new requirements I have updated my fiddle: http://jsfiddle.net/panpymq2/1/
I now prepend the new html to the document.
You already know how to add elements as children of other elements. That's what you used to add the h2 and p to the div. You could use the same appendChild to add the div to the document:
document.body.appendChild(newDiv);
But you don't want it at the bottom of the page--you want it "in the middle of the html code page". One straightforward way to do this is to add the newDiv to a container that's in the right place, in the middle of the page.
You'd first create this container in the page HTML:
<!doctype html>
<body>
<p>stuff before</p>
<div id="container"></div>
<p>stuff after</p>
</body>
Then, finish off addElement with:
document.getElementById('container').appendChild(newDiv);
One way would be if addElement took a third parameter which is the sibling/parent you want to insert your new element next to/within.
function addElement(title, content, target) {
...
target.insertAdjacentElement('afterend', newDiv);
// or
target.appendChild(newDiv);
}
I think this is as much of an HTML as a CSS problem. I've had the same issue.
One way of solving this problem is to make an (extra) container <div> as follows:
<div id="outer_container_elems">
<div id="inner_container_elems">
...
</div>
</div>
And append to inner_container_elems
Hope this helps!

javascript click image display

What I'm trying to do is, when one of six divs is clicked, a separate div will have 3 specific divs appear in it. Each of the original six divs have three similar but different divs related to it.
http://jsfiddle.net/petiteco24601/hgo8eqdq/
$(document).ready(function () {
$(".talkbubble").mouseout(function(){
$(".sidebar").show();
});$
$(".talkbubble").click(function(){
$
How do I make it so that when you click a "talkbubble" div, a different "sidebar" div appears with all its contained elements, and when you mouseout, the first talkbubble div automatically activates?
Here is a demo of how to do this: http://jsfiddle.net/n1xb48z8/2/
The main part of this example is some javascript that looks like this:
$(document).ready(function(){
showSideBar(1);
$('.expander').click(function(){
var sidebarIndex = $(this).data('sidebar-index');
showSideBar(sidebarIndex);
});
$('#Container').mouseleave(function(){
showSideBar(1);
});
});
function showSideBar(index){
$('.sidebarContent').hide();
$('.sidebarContent[data-index="' + index + '"]').show();
}
.data('some-name') will get you the attribute data-some-name="" on the specific element, this is a html 5 attribute and if you do not want to use it you can instead give each of the elements their own class names such as:
<div class="sidebarContent subBarContent_1">
<!-- content -->
</div>
and use the '.subBarContent_1' as your jquery selector instead. You would then also have to have some sort of data attached to your clickable divs to identify which one you wanna show, you could use a hidden field to do that like:
<input type="hidden" class="subContentSelector" value="subBarContent_1" />
The javascript for that looks like this:
$(document).ready(function(){
showSideBar(1);
$('.expander').click(function(){
var sidebarSelector = $(this).find('.subContentSelector').val();
showSideBar(sidebarSelector );
});
$('#Container').mouseleave(function(){
showSideBar('subBarContent_1');
});
});
function showSideBar(selector){
$('.sidebarContent').hide();
$('.sidebarContent.' + selector).show();
}
Ps. the overflow:hidden css is because chrome was messing up the placement of the sidebar content otherwise... oh chrome, you silly goose

Using Javascript to show/hide elements depending on content in div

I am relatively inexperienced with JavaScript, and I'm working on a project that's turned into a real trial by fire for me, but hopefully this is a question that has a stupidly straightforward answer.
I'm trying to write a script that will show/hide different links on a page by changing the display style of different links.
I want to use a div element and have different links available if the user drags different images into the div. The links are in clickable pictures.
Example-
I want this linked element 'link' to be displayed only if "First_Image.png" has been dragged and dropped into div2:
<a id='link' href='link.html' style='display: none;'><IMG src="../Image.png"></a>
My div id is "div2", and it starts out empty as such:
<div id="div2" ondrop="drop(event)" ondragover="allowDrop(event)"></div>
Images on the page are set up as:
<IMG src="First_Image.png" id="First_Image" draggable="true"
ondragstart="drag(event)">
There are several such droppable images on the page. My attempt at this script is:
<script>
if (document.getElementById("div2").getElementsByTagName('img') == "First_Image")
document.getElementById('link').style.display = 'block';
return (false);
</script>
I'm not sure if my problem is that I'm not getting the information I think I am from the image in the div, or if my simple if statement isn't doing what I think it's doing. :/
If you're trying to get the values from the attributes (as the src is an attribute). You can try out Element.getAttribute.
https://developer.mozilla.org/en-US/docs/Web/API/Element.getAttribute
document.getElementById("div2").getElementsByTagName("img").getAttribute("src");
Step by step would be:
var id = document.getElementById("div2");
var elem = id.getElementsByTagName("img");
var atr = elem.getAttribute("src");
/* for comparing */
if(atr == "First_Image.png") {
return false;
}
This will produce this: First_Image.png. And also, write this:
return false; /* not (false) */
I think the error is in your comparison
if (document.getElementById("div2").getElementsByTagName('img').src.indexOf("First_Image") > -1)

How to create active/inactve thumbnails in HTML/Javascript

I am setting up a "Billboard" for the home page of a site. The billboard will have an active image displayed and there will be thumbnails of the right that are used to change the image on the billboard.
Something like this:
Currently I swap the images like this:
<div id="_bbImage">
<img src="images/bill1.png" class="bbImage" id= "MainBB"/>
</div><!--_bbImage-->
<div id="_bbTab1" class="inactiveTab">
<a href="images/bill2.png" onclick="swap(this); return false;">
<img src="images/bbtab1.png" class="bbTabImg" id="bbTabImg1" />
</a>
</div><!--bbTab1-->
and the JavaScript function looks like this:
function swap(image){document.getElementById("MainBB").src = image.href;}
But now, I would like to have the thumbnail to have a different class when Its selected or "Active" to achive this effect:
I need to accomplish the class switch to active, but I also need to make sure that the previously selected tab gets set back to the "inactive" class again.
I tried something like this:
function inactiveTab(name){document.getElementById(name).className = "inactiveTab";}
function activeTab(name){document.getElementById(name).className = "activeTab";}
function inactiveTabAll(){
inactiveTab("_bbTab1");
inactiveTab("_bbTab2");
inactiveTab("_bbTab3");
inactiveTab("_bbTab4");
inactiveTab("_bbTab5");
inactiveTab("_bbTab6");
}
with:
<div id="_bbTab1" class="inactiveTab">
<a href="images/bill1.png" onclick="swap(this); inactiveTabAll(); activeTab("_bbTab1"); return false;">
<img src="images/bbtab2.png" class="bbTabImg" id="bbTabImg1" />
</a>
</div><!--bbTab1-->
But this doesn't seem to be working, when I click on the thumbnail I just get linked to a blank page with "image/bill2.png" image displayed.
Does anyone know a good way to accomplish this, or can anyone point me in the right directions.
Thanks in advance,
Rob
In my opinion, you could have a look at the following jquery method:
http://api.jquery.com/hover/
It has callback functions, where you can make your content visible / invisible.
Instead of your "inactivateTab" - function, you could use the "hide"-method:
http://api.jquery.com/hide/
the problem is that you are using an href for the image inside the tag.
an tag is originally a link to a given url
replace
href="xx.png" with
href="javascript:swap(this); inactiveTabAll(); activeTab("_bbTab1");"
I don't understand what's the original role of the href in your code, but you don't seem to be using it anyway
Instead of img elements, use divs and put the image into the background (use the background-image style). This allows you to define which image should be displayed where in pure CSS. You can also swap images by adding/removing classes:
.bbTabImg { background-image: url(images/bbtab1-inactive.png); }
.bbTabImg.active { background-image: url(images/bbtab1.png); }
As for inactive, use this jQuery:
$('.active').removeClass('active');
This finds all elements with the active class and turns it off. Now you can set one of them active again and the CSS above will load the correct image.

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