I have this very simplified AangularJS app. It is working very well.
Now, I need to fill some fields and submit the form directly from the view, without user interaction.
Here's the Javascript code (once again, simplified and I removed many other elements)
mainApp.controller("resultsController",FormController);
function FormController($scope,APIService) {
$scope.result ="";
$scope.search = { keywords: "",
result:1,
term: "-1",
subject: "-1"};
$scope.searchNow = function() {
APIService.getTheResults($scope);
} // $scope.searchNow
}
function getResults($http) {
var results = {};
url = "...";
results.searchResults = function() {
var lurl = url + "a=s";
return $http( {method: "JSONP", url:lurl} );
} // results.searchResults
results.getTheResults = function(scope) {
var lurl = url;
$http({
method: 'POST',
url:lurl,
data:jQuery.param(scope.search),
headers:{'Content-Type':'application/x-www-form-urlencoded'}})
.success(function(lresponse){
var theResponse;
theResponse = eval(lresponse);
scope.mydata = theResponse.data[0]
})
.error( function(data,status) {
scope.result = status;
});
} // results.getTheResults
return results;
} // function getResults($http)
And here is the HTML view:
<html lang="en" ng-app="courseCatalog" ng-controller="resultsController">
<!-- some head info -->
<body>
<form id="search_form" name="search_form" ng-submit="searchNow()">
<!--
form fields in here, for example:
-->
<input type="text" id="txtkeywords" name="keywords" ng-model="search.keywords">
<input type="text" id="txtsubject" name="term" ng-model="search.subject">
<input type="text" id="textterm" name="subject" ng-model="search.term">
<input id="submit-button" name="submit-button" type="submit"
value=" Search Now "/>
</form>
<!-- Here is the , I pre-populate some form fields -->
<div id='filter_holder' class='hidden_box'>
<div class='hidden_box'>{{search.term='1|201601';}}</div>
<div class='hidden_box'>{{search.subject='6|BIO';}}</div>
</div>
<!-- And here, I try to manually submit the form -->
<script type="text/javascript">
document.getElementById('submit-button').click();
</script>
</body>
But I only get the page to reload with all the formfields in the url:
...url.../?txtterm=-1&txtsubject=-1&submit-button=+Search+Now+
I tried also submitting with document-form-submit but I get no results.
If I remove all the pre-fill/submit and manually fill and send the form I get the correct results.
Any idea on how to submit the form from the view?
Try using form method post. So change your form tag to:
<form id="search_form" name="search_form" ng-submit="searchNow()" method="post">
As described in this chapter at w3schools, when using post method the data will not be shown in the url.
"POST offers better security because the submitted data is not visible
in the page address."
Solved: I noticed that the page was trying to submit the form too quickly. First, I set a timer to 5 seconds after the form loaded and then call the click function of the submit button.
Then, I just used a window.unload function to be called when the entire DOM is created:
window.onload = function(){ document.getElementById('submit-button').click(); };
And that is working fine. I hope this helps some other people.
Thanks!
I have a feedback form in my website. Its very basic and only having a text area to put user feedback and submit.
now i am planing to add one option for attaching a picture along with feedback. Adding another text field easy but
i can't figure out how can i add a file into the JavaScript. Please suggest the required changes to add a file into the below script
function upload() {
var feedback = _("feedback").value;
var status = _("status");
if (feedback == "") {
status.innerHTML = "Empty";
} else {
status.innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "feedback.php");
ajax.onreadystatechange = function() {
if (ajaxReturn(ajax) == true) {
if (ajax.responseText != "ok") {
status.innerHTML = ajax.responseText;
} else {
window.location = "thanks.php";
}
}
}
ajax.send("feedback=" + feedback);
}
}
<form id="form1" enctype="multipart/form-data" onsubmit="return false;">
<input id="feedback" type="text">
<button id="submit" onclick="upload()">Submit Details</button>
<span id="status"></span>
</form>
Here you are:
var x = document.createElement("input");
x.setAttribute("type", "file");
document.querySelector("#form1").appendChild(x);
Hope this help.
Unless you're trying to upload the file using ajax, just submit the form to feedback.php.
<form enctype="multipart/form-data" action="feedback.php" method="post">
<input id="image-file" type="file" />
</form>
If you want to upload the image in the background (e.g. without submitting the whole form) you'll need to use Flash since JavaScript alone can't do this.
jQuery Ajax File Upload
Ajax using file upload
jquery easy example look at first answer
Okay.. so two things you will have t change:
Remove that header ('application/x-www-form-urlencoded') and add 'multipart/form-data' header instead. files can not be sent as urlencoded.
Secondly, in ajax request, instead of sending feedback as string, you need to send FormData object, which supports file upload over ajax:
var myForm = $("#form1")[0];
var formData = new FormData(myForm);
ajax.send(formData);
Update:
Forgot to mention: Of course the third thing you will need is to add to your form!
Instead of redirecting the user to a new page, I want to add an overlay over the form. Somehow, the following code returns the overlay twice.
AJAX
$(document).ready(function ()
{
$('#form_informations').submit(function ()
{
$.get('php/formulaires.php', $(this).serialize(), function (data)
{
$('#form_informations').append('<div id="conf_informations" class="confirm"><p><img src="img/check.png" /><br /><?=FORMULAIRE_SAUVEGARDE;?></p></div>');
});
return false;
});
});
The id #form_informations is only used once.
For now, the second overlay is not created in php/formulaires.php because the file is empty as I have not started parsing the data.
Why is this happening? I don't see where this second overlay is coming from.
This is the HTML form:
HTML Form
<form id="form_informations" method="post" enctype="multipart/form-data">
<!-- form here -->
<input type="submit" name="submit_general" value="Save" />
</form>
May be you can add some code like this in the submit function
if(!$("#conf_informations").size()) {
$.get... //your get request here
}
Final solution
if(!$("#conf_informations").length()) {
$.get... //your get request here
}
I currently have a HTML form which users fill in details of an advert they wish to post. I now want to be able to add a dropzone for uploading images of the item for sale.
I have found Dropzone.js which seems to do most of what I need. However, when looking into the documentation, it appears that you need to specify the class of the whole form as dropzone (as opposed to just the input element). This then means that my entire form becomes the dropzone.
Is it possible to use the dropzone in just part of my form, i.e. by only specifying the element as class "dropzone", rather than the whole form?
I could use separate forms, but I want the user to be able to submit it all with one button.
Alternatively, is there another library that can do this?
Many thanks
Here's another way to do it: add a div in your form with a classname dropzone, and implement dropzone programmatically.
HTML :
<div id="dZUpload" class="dropzone">
<div class="dz-default dz-message"></div>
</div>
JQuery:
$(document).ready(function () {
Dropzone.autoDiscover = false;
$("#dZUpload").dropzone({
url: "hn_SimpeFileUploader.ashx",
addRemoveLinks: true,
success: function (file, response) {
var imgName = response;
file.previewElement.classList.add("dz-success");
console.log("Successfully uploaded :" + imgName);
},
error: function (file, response) {
file.previewElement.classList.add("dz-error");
}
});
});
Note : Disabling autoDiscover, otherwise Dropzone will try to attach twice
I had the exact same problem and found that Varan Sinayee's answer was the only one that actually solved the original question. That answer can be simplified though, so here's a simpler version.
The steps are:
Create a normal form (don't forget the method and enctype args since this is not handled by dropzone anymore).
Put a div inside with the class="dropzone" (that's how Dropzone attaches to it) and id="yourDropzoneName" (used to change the options).
Set Dropzone's options, to set the url where the form and files will be posted, deactivate autoProcessQueue (so it only happens when user presses 'submit') and allow multiple uploads (if you need it).
Set the init function to use Dropzone instead of the default behavior when the submit button is clicked.
Still in the init function, use the "sendingmultiple" event handler to send the form data along wih the files.
Voilà ! You can now retrieve the data like you would with a normal form, in $_POST and $_FILES (in the example this would happen in upload.php)
HTML
<form action="upload.php" enctype="multipart/form-data" method="POST">
<input type="text" id ="firstname" name ="firstname" />
<input type="text" id ="lastname" name ="lastname" />
<div class="dropzone" id="myDropzone"></div>
<button type="submit" id="submit-all"> upload </button>
</form>
JS
Dropzone.options.myDropzone= {
url: 'upload.php',
autoProcessQueue: false,
uploadMultiple: true,
parallelUploads: 5,
maxFiles: 5,
maxFilesize: 1,
acceptedFiles: 'image/*',
addRemoveLinks: true,
init: function() {
dzClosure = this; // Makes sure that 'this' is understood inside the functions below.
// for Dropzone to process the queue (instead of default form behavior):
document.getElementById("submit-all").addEventListener("click", function(e) {
// Make sure that the form isn't actually being sent.
e.preventDefault();
e.stopPropagation();
dzClosure.processQueue();
});
//send all the form data along with the files:
this.on("sendingmultiple", function(data, xhr, formData) {
formData.append("firstname", jQuery("#firstname").val());
formData.append("lastname", jQuery("#lastname").val());
});
}
}
The "dropzone.js" is the most common library for uploading images.
If you want to have the "dropzone.js" as just part of your form, you should do the following steps:
1) for the client side:
HTML :
<form action="/" enctype="multipart/form-data" method="POST">
<input type="text" id ="Username" name ="Username" />
<div class="dropzone" id="my-dropzone" name="mainFileUploader">
<div class="fallback">
<input name="file" type="file" multiple />
</div>
</div>
</form>
<div>
<button type="submit" id="submit-all"> upload </button>
</div>
JQuery:
<script>
Dropzone.options.myDropzone = {
url: "/Account/Create",
autoProcessQueue: false,
uploadMultiple: true,
parallelUploads: 100,
maxFiles: 100,
acceptedFiles: "image/*",
init: function () {
var submitButton = document.querySelector("#submit-all");
var wrapperThis = this;
submitButton.addEventListener("click", function () {
wrapperThis.processQueue();
});
this.on("addedfile", function (file) {
// Create the remove button
var removeButton = Dropzone.createElement("<button class='btn btn-lg dark'>Remove File</button>");
// Listen to the click event
removeButton.addEventListener("click", function (e) {
// Make sure the button click doesn't submit the form:
e.preventDefault();
e.stopPropagation();
// Remove the file preview.
wrapperThis.removeFile(file);
// If you want to the delete the file on the server as well,
// you can do the AJAX request here.
});
// Add the button to the file preview element.
file.previewElement.appendChild(removeButton);
});
this.on('sendingmultiple', function (data, xhr, formData) {
formData.append("Username", $("#Username").val());
});
}
};
</script>
2) for the server side:
ASP.Net MVC
[HttpPost]
public ActionResult Create()
{
var postedUsername = Request.Form["Username"].ToString();
foreach (var imageFile in Request.Files)
{
}
return Json(new { status = true, Message = "Account created." });
}
I have a more automated solution for this.
HTML:
<form role="form" enctype="multipart/form-data" action="{{ $url }}" method="{{ $method }}">
{{ csrf_field() }}
<!-- You can add extra form fields here -->
<input hidden id="file" name="file"/>
<!-- You can add extra form fields here -->
<div class="dropzone dropzone-file-area" id="fileUpload">
<div class="dz-default dz-message">
<h3 class="sbold">Drop files here to upload</h3>
<span>You can also click to open file browser</span>
</div>
</div>
<!-- You can add extra form fields here -->
<button type="submit">Submit</button>
</form>
JavaScript:
Dropzone.options.fileUpload = {
url: 'blackHole.php',
addRemoveLinks: true,
accept: function(file) {
let fileReader = new FileReader();
fileReader.readAsDataURL(file);
fileReader.onloadend = function() {
let content = fileReader.result;
$('#file').val(content);
file.previewElement.classList.add("dz-success");
}
file.previewElement.classList.add("dz-complete");
}
}
Laravel:
// Get file content
$file = base64_decode(request('file'));
No need to disable DropZone Discovery and the normal form submit will be able to send the file with any other form fields through standard form serialization.
This mechanism stores the file contents as base64 string in the hidden input field when it gets processed. You can decode it back to binary string in PHP through the standard base64_decode() method.
I don't know whether this method will get compromised with large files but it works with ~40MB files.
Enyo's tutorial is excellent.
I found that the sample script in the tutorial worked well for a button embedded in the dropzone (i.e., the form element). If you wish to have the button outside the form element, I was able to accomplish it using a click event:
First, the HTML:
<form id="my-awesome-dropzone" action="/upload" class="dropzone">
<div class="dropzone-previews"></div>
<div class="fallback"> <!-- this is the fallback if JS isn't working -->
<input name="file" type="file" multiple />
</div>
</form>
<button type="submit" id="submit-all" class="btn btn-primary btn-xs">Upload the file</button>
Then, the script tag....
Dropzone.options.myAwesomeDropzone = { // The camelized version of the ID of the form element
// The configuration we've talked about above
autoProcessQueue: false,
uploadMultiple: true,
parallelUploads: 25,
maxFiles: 25,
// The setting up of the dropzone
init: function() {
var myDropzone = this;
// Here's the change from enyo's tutorial...
$("#submit-all").click(function (e) {
e.preventDefault();
e.stopPropagation();
myDropzone.processQueue();
});
}
}
Further to what sqram was saying, Dropzone has an additional undocumented option, "hiddenInputContainer". All you have to do is set this option to the selector of the form you want the hidden file field to be appended to. And voila! The ".dz-hidden-input" file field that Dropzone normally adds to the body magically moves into your form. No altering the Dropzone source code.
Now while this works to move the Dropzone file field into your form, the field has no name. So you will need to add:
_this.hiddenFileInput.setAttribute("name", "field_name[]");
to dropzone.js after this line:
_this.hiddenFileInput = document.createElement("input");
around line 547.
I want to contribute an answer here as I too have faced the same issue - we want the $_FILES element available as part of the same post as another form. My answer is based on #mrtnmgs however notes the comments added to that question.
Firstly: Dropzone posts its data via ajax
Just because you use the formData.append option still means that you must tackle the UX actions - i.e. this all happens behind the scenes and isn't a typical form post. Data is posted to your url parameter.
Secondly: If you therefore want to mimic a form post you will need to store the posted data
This requires server side code to store your $_POST or $_FILES in a session which is available to the user on another page load as the user will not go to the page where the posted data is received.
Thirdly: You need to redirect the user to the page where this data is actioned
Now you have posted your data, stored it in a session, you need to display/action it for the user in an additional page. You need to send the user to that page as well.
So for my example:
[Dropzone code: Uses Jquery]
$('#dropArea').dropzone({
url: base_url+'admin/saveProject',
maxFiles: 1,
uploadMultiple: false,
autoProcessQueue:false,
addRemoveLinks: true,
init: function(){
dzClosure = this;
$('#projectActionBtn').on('click',function(e) {
dzClosure.processQueue(); /* My button isn't a submit */
});
// My project only has 1 file hence not sendingmultiple
dzClosure.on('sending', function(data, xhr, formData) {
$('#add_user input[type="text"],#add_user textarea').each(function(){
formData.append($(this).attr('name'),$(this).val());
})
});
dzClosure.on('complete',function(){
window.location.href = base_url+'admin/saveProject';
})
},
});
You can modify the formData by catching the 'sending' event from your dropzone.
dropZone.on('sending', function(data, xhr, formData){
formData.append('fieldname', 'value');
});
In order to submit all files alongside with other form data in a single request you can copy Dropzone.js temporary hidden input nodes into your form. You can do this within addedfiles event handler:
var myDropzone = new Dropzone("myDivSelector", { url: "#", autoProcessQueue: false });
myDropzone.on("addedfiles", () => {
// Input node with selected files. It will be removed from document shortly in order to
// give user ability to choose another set of files.
var usedInput = myDropzone.hiddenFileInput;
// Append it to form after stack become empty, because if you append it earlier
// it will be removed from its parent node by Dropzone.js.
setTimeout(() => {
// myForm - is form node that you want to submit.
myForm.appendChild(usedInput);
// Set some unique name in order to submit data.
usedInput.name = "foo";
}, 0);
});
Obviosly this is a workaround dependent on implementation details. Related source code.
Working solution for 5.7.0 version
<form id="upload" enctype="multipart/form-data">
<input type="text" name="name" value="somename">
<input type="checkbox" name="terms_agreed">
<div id="previewsContainer" class="dropzone">
<div class="dz-default dz-message">
<button class="dz-button" type="button">
Drop files here to upload
</button>
</div>
</div>
<input id="dz-submit" type="submit" value="submit">
</form>
Dropzone.autoDiscover = false;
new Dropzone("#upload",{
clickable: ".dropzone",
url: "upload.php",
previewsContainer: "#previewsContainer",
uploadMultiple: true,
autoProcessQueue: false,
init() {
var myDropzone = this;
this.element.querySelector("[type=submit]").addEventListener("click", function(e){
e.preventDefault();
e.stopPropagation();
myDropzone.processQueue();
});
}
});
Here is my sample, is based on Django + Dropzone. View has select(required) and submit.
<form action="/share/upload/" class="dropzone" id="uploadDropzone">
{% csrf_token %}
<select id="warehouse" required>
<option value="">Select a warehouse</option>
{% for warehouse in warehouses %}
<option value={{forloop.counter0}}>{{warehouse.warehousename}}</option>
{% endfor %}
</select>
<button id="submit-upload btn" type="submit">upload</button>
</form>
<script src="{% static '/js/libs/dropzone/dropzone.js' %}"></script>
<script src="https://code.jquery.com/jquery-3.1.0.min.js"></script>
<script>
var filename = "";
Dropzone.options.uploadDropzone = {
paramName: "file", // The name that will be used to transfer the file,
maxFilesize: 250, // MB
autoProcessQueue: false,
accept: function(file, done) {
console.log(file.name);
filename = file.name;
done(); // !Very important
},
init: function() {
var myDropzone = this,
submitButton = document.querySelector("[type=submit]");
submitButton.addEventListener('click', function(e) {
var isValid = document.querySelector('#warehouse').reportValidity();
e.preventDefault();
e.stopPropagation();
if (isValid)
myDropzone.processQueue();
});
this.on('sendingmultiple', function(data, xhr, formData) {
formData.append("warehouse", jQuery("#warehouse option:selected").val());
});
}
};
</script>
This is just another example of how you can use Dropzone.js in an existing form.
dropzone.js :
init: function() {
this.on("success", function(file, responseText) {
//alert("HELLO ?" + responseText);
mylittlefix(responseText);
});
return noop;
},
Then, later in the file I put
function mylittlefix(responseText) {
$('#botofform').append('<input type="hidden" name="files[]" value="'+ responseText +'">');
}
This assumes you have a div with id #botofform that way when uploading you can use the uploaded files' names.
Note: my upload script returned theuploadedfilename.jpeg
dubblenote you also would need to make a cleanup script that checks the upload directory for files not in use and deletes them ..if in a front end non authenticated form :)
Try this
<div class="dropzone dz-clickable" id="myDrop">
<div class="dz-default dz-message" data-dz-message="">
<span>Drop files here to upload</span>
</div>
</div>
JS
<script>
Dropzone.autoDiscover = false;
Dropzone.default.autoDiscover=false;
$("div#myDrop").dropzone({
url: "/file/post",
});
</script>
I have a form like this:
<form name="paymentForm" id="paymentForm" action="/submit.jsp" method="post">
<fieldset id="ccData">
<input id="ccNumber" name="ccNumber"/>
</fieldset>
<fieldset id="otherData">
<input id="requestId" name="requestId"/>
</fieldset>
</form>
When you slick submit, I would like to submit(via ajax) only #ccData filedset to some different url (e.g. submitCC.jsp) and based on response I want to submit full form to actual url.
How can I achieve that ?
Use jQuery's serialize method
var formData = $("#ccData").serialize();
$.post("TheUrl",formData);
You could do that with JavaScript - e.g jQuery. You build an eventHandler like
$('#paymentForm').on('click', function () {
$(this).preventDefault();
if ($(this).hasClass('first_send')) {
$.ajax({
url: "your_url",
data: { ccData: $('#ccData').val()}
}).done(function ( data ) {
$('#paymentForm').addClass('first_send')
// examin the data, insert stuff you need and send the form again
// with ajax
})
} else {
$(this).removeClass('first_send')
// this is the second send - so do stuff here - show a result or so
}
})
With the class first_send you can check if it is the first send or the second. This is just an untested, incomplete idea how you could do it. I guess you get the big picture ...