Using jquery, I currently append html to a div on a click event. The following code allows me to fade in only the appended portion of the div:
var html = "..";
$('<div></div>').appendTo("#id").hide().append(html).fadeIn('slow');
This portion works perfectly. But how can I later remove (fade out) only the appended portion? I tried hacking this by storing the html prior to the appending, and then simply hiding everything and showing the stored html. But this does not work well when the same procedure is reused for several divs on the same page (and this seems like poor implementation). Is there a good way to do this?
Just to give an idea of why I need this: Think of a blog type page where for every article on the page there are several comments with only x amount showing by default: the click event fetches the remaining comments and displays them, and then toggling the button again removes the appended comments and sends it back to the original state.
empty() is always an option
jQuery('#main').empty();
Give a look at the empty() function.
It might better solve the problem. Here's the link http://api.jquery.com/empty/
I'd just set and clear the html with '.html()' ...
-- edit
to be more clear, have an area layed out specifically for the addition of these comments:
<div id='commentarea1'></div>
etc.
Try:
var html = "..";
$('<div></div>').appendTo("#id").hide().append(html).fadeIn('slow').addClass('appended');
then later
$('#id .appended').fadeOut('slow'); // or whatever you want to do.
It is not that clear from the question but say you show 5 comments by default and then show x more comments. To get back to the original 5 comment default state you can remove all comments with an index greater than 4 (zero based).
The following assumes each comment goes inside its own div that has a class comment.
$('#id>div.comment:gt(4)').remove();
Related
I'm looking for a solution that will allow me to display a div when I click on a single link (which will change the way css style) with variable content (eg a sub-div with service1, service2, service3 ). This div will be displayed also propose several offers that will only display the div payment when one of these offers will be selected.
It's maybe hard to explain (i'm not english so sorry for really noob level), so maybe with this image you will "understand" a little bit more:
http://image.noelshack.com/fichiers/2015/38/1442422045-fonctionnement.jpg
I confess to being a bit lost with JavaScript for this kind of thing. I know it's probably achievable, but how? :-(
Thank you for your help folks!
If you want to go the way with altering CSS with javascript, assuming you are not creating the variable content on the fly, have the divs css for display set to none.
#divID {
display = none;
}
Then set an event listener on your link to change the display style to block.
document.getElementById("linkID").addEventListener("click", function() {
document.getElementById("divID").style.display = "block";
}
Ok so I created a crude representation of what you asked without much effects. But the fiddle I created completely functions as you intended. If you click buttons on div 1 the content of div 2 gets updated. If you click anything on div2 the information is displayed in div3. Here is the example: Working Example
window.function1 = function(){
var edits = document.getElementById('2');
edits.style.background="aliceblue";
}
//SAMPLE CODE TO EDIT ANY ELEMENT BY REFERRING BY ID. CALL SUCH FUNCTION ONCLICK
Please check the example to understand it fully.
I have created the following image gallery.
http://jsfiddle.net/sfiddle/Nf7yR/7/
I think the thing is, that even though I can get a hand on the paragraphs css, the currentIndex won't update, i.e. an event listener seems to be missing.
var thumb = document.getElementById("thumb");
myParagraphs = thumb.getElementsByTagName("p");
console.log(myParagraphs[1]);
function thumby(){
$(myParagraphs[currentIndex]).css("background-color", "red");
}
thumby();
The thing is that I can not manage to link the image index with the index of the pagination dot (which has a normal p tag).
I want to code it in that way that if the first picture is displayed the first dot is red, if the second image is displayed the second ...
How could I approach this?
Thanks for any good advice as I invested a few hours already but can not get my head around it.
PS: no, I want no plugin or ready made imagegallery, I want my approach to work :-)
You made a function thumby() but you are calling it only once (during script start). You just need to call it when you change currentIndex. Here you have fixed code: http://jsfiddle.net/Nf7yR/10/ (I commented my edits).
BTW your code looks terrible. You should indent it properly to make it easier to read :)
Can't seem to get this one to work...
I have a page that hides certain links. When the DOM is loaded, I'm using jQuery to toggle some of those elements. This is driven by using a data attribute like so:
<div class="d_btn" data-usr='48'>
<div class="hidden_button">
Then, I have the code:
$.each($(".d_btn"), function() {
var btn = $(this).data('usr');
if ( btn == '48' ){
$(this).children('.hidden_button').toggle();
}
The above all works as planned. The problem is that I am trying to remove the data-usr from the class .d_btn once the if statement is evaluated. I've tried the following and nothing works (i.e., after the page is loaded, the source still shows the data-usr attribute:
$(this).removeAttr("data-usr");
$(this).removeData("usr");
I've been working on this for a couple of hours now and...nothing! Help is greatly appreciated!
UPDATE
I've tried the great suggestions of setting the data attribute to an empty string but I'm still not getting the desired result.
To explain a little further, The reason I'm trying to remove the attribute is so when an ajax response adds another item to the page, the previously added items would already have the button either shown or hidden. Upon AJAX response, I'm calling the same function once the DOM is loaded.
Currently, when something is added via AJAX, it toggles all the buttons (showing the ones that were hidden and vice versa.) Ugh...
I'm also fully willing to try alternatives to my approach. Thanks!
UPDATE
Well, the light bulb just flashed and I am able to do what I want to do by just using .show() instead of .toggle()
Anyway, I'd still like to find an answer to this question because the page will be potentially checking hundreds of items whenever something is added - this seems horribly inefficient (even for a computer, hahaha.)
Why don't you set the value to a random value or empty variable instead if removeAttr does not work..
$(this).attr("data-usr" , '');
$(this).prop("data-usr" , '');
Changing the DOM doesn't affect the source. It affects the DOM, which you can view with the Inspector/Developer Tools. Right click => View Source will give you the original source of the page, not the actual current source as modified by JavaScript.
Set it to a blank string:
$(this).attr("data-usr", "");
I second what Kolink said: check the DOM, not the source. (Chrome: Ctrl + Shift + i).
As others have stated. Checking the source will only show the original unedited source for the webpage. What you need to do is check the DOM using developer tools.
I've just checked everything in Chrome's inspector on jsfiddle here and the attribute is definitely being removed as well as the data.
i have a jQuery code and the html code on my page. The code loads two php files on two DIVs, based on the value of a drop down list. The code is working great, loading pic and everything. However I have a small problem.
When I place the second div ( artistdetails ) inside of a seperated div from the first div, the loading pic does not appears on the second but only in the first. Content is appeared correctly though.
As I saw in firebug, the class is loading fine. I even changed the picture to something bigger but nothing was there. ( I mean the pic is not hidden somewhere).
I made a lot of experiment, I set the ID to the float:left div but nothing happens. I really need to have them in a separated DIV. Is that possible?
I would start looking at the final generated code (which you might post here or on pastebin.com with a link).
Sounds to me like something in the php forms is probably not generating valid html. For example, an unclosed entity.
It must work, i guess, if the class is added to <div id="artistdetails"></div>
Still try something like this
$('#artistdetails').empty()
.addClass('loading')
.load('forms/' + val + 'b.php',
function(){
setTimeout(
function(){ $('#artistdetails').removeClass('loading') },
2000);
});
I have a list being displayed on a JSP. On mouse hover on any of the value i need to show a description corresponding that value. Need to show description not as an alert and also cannot make the values as hyperlink.
eg.
suppose the value is ABC so on mouse hover should show AppleBoyCat.
need to use onmouseover. let me know how to do it..
What do you want to do? If you just want to show a tooltip, you can set the title attribute of any element and it will be displayed as a tooltip.
Also, the abbr tag can be used as tooltips too:
<abbr title="test">stuff</abbr>
You can go about it in two ways:
1 - a hidden dom object (a div for instance) which reveals itself when you roll over whatever
or
2 - you can rewrite the html of the particular element you're mousing over.
You can load this data in when you load everything else (either as Javascript objects, or as markup, though that's much bulkier) or you can asynchronously load the description data from a service when you mouse over (though you'll have more lag).
jQuery is a quick and dirty way to achieve this (more quick than dirty), but straight JS or pretty much any other JS library will do as well.
Perhaps not the cleanest solution but something like this:
<a class='hover' rel='tooltip'>Link</a>
//Some hidden div, putting css inline just for example
<div id='tooltip' style='display:none;'>Content</div>
$(function() {
$('.hover').mouseover(function() {
var tooltip = $(this).attr('rel');
$('#' + tooltip).fadeIn();
});
});
And offcourse add a callback hiding it again. It just takes the value from rel of the link and use as an id for the div to show.
This is a quick and dirty solution, can be made alot smoother if you just work with it a little;)
There also alot of plugins out there allowing the same functionality in a cleaner fashion.
*Edit: Just noticed you added a comment on another post that you can't use jQuery.. shouldn't tag a post with something you're not intending to use.
As TJHeuvel already said, you can simply use the title attribute.
Best approach is to build the list with both the value and title attribute from within JSP, if not possible for some reason, you can build client side array of each value and its corresponding description then using JavaScript dynamically assign the title on mouseover.
Show us some more code to get more/better help.
For simple tooltips, the title attribute is most effective, as pointed out by TJHeuvel
If you need more advanced tooltips with HTML and CSS formatting, I'd suggest you use an external library.
One that works nicely without jQuery ist wz_tooltip download here, documentation here
When included correctly, you can add tooltips by calling the functions Tip() and UnTip() as follows:
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