So I have this page here:
http://www.eminentmedia.com/development/powercity/
As you can see when you mouse over the images the div slides up and down to show more information. Unfortunately I have 2 problems that i can't figure out and I've searched but haven't found quite the right answer through google and was hoping someone could point me in the direction of a tutorial.
The first problem is that when you mouse over an image it changes to color (loads a new image), but there's a short delay when the image is loading for the first time so the user sees white. Do I have to preload the images or something in order to fix that?
My second problem is that when you move your mouse over the 'additional content area' it goes crazy and starts going up and down a bunch of times. I just don't have any idea what would cause this but i hope one of you will!
All my code is directly in the source of that page if you would like to view the source.
Thanks in advance for your help!
Yes, you have to preload the images. Thankfully, this is simple:
var images_to_preload = ['myimage.jpg', 'myimage2.jpg', ...];
$.each(images_to_preload, function(i) {
$('<img/>').attr({src: images_to_preload[i]});
});
The other thing you have to understand is that when you use jQuery you have to truly embrace it or you will end up doing things the wrong way. For example, as soon as you find yourself repeating the same piece of code in different places, you are probably doing something wrong. Right now you have this all over the place:
<div id="service" onmouseover="javascript:mouseEnter(this.id);" onmouseout="javascript:mouseLeave(this.id);">
Get that out of your head. Now. Forever. Always. Inline javascript events are not proper, especially when you have a library like jQuery at your disposal. The proper way to do what you want is this:
$(function() {
$('div.box').hover(function() {
$(this).addClass('active');
$(this).find('div.slideup').slideDown('slow');
}, function() {
$(this).removeClass('active');
$(this).find('div.slideup').slideUp('slow');
});
});
(You have to give all the #industrial, #sustainable, etc elements a class of 'box' for the above to work)
These changes will also fix your sliding problem.
I can see your images (the ones that are changing) are set in the background of a div. Here is a jquery script that preloads every image found in a css file. I have had the same problem in the past and this script solves it. It is also very easy to use:
http://www.filamentgroup.com/lab/update_automatically_preload_images_from_css_with_jquery/
I will take a look at your other problem...
1) You should be using the jquery events to drive your mouseovers. Give each div a class to indicate that its a category container and use the hover function to produce the mouseover/mouseout action you're after.
html
<div id="industrial" class="category"></div>
Javascript
$(".category").hover(
function () {
$(this).find('.container').show();
},
function () {
$(this).find('.container').hide();
}
);
I simplified the code to just do show and hide, you'll need to use your additional code to slide up and slide down.
2) Yes, you need to preload your images. Another option would be "sprite" the images. This would involve combining both the black and white and colour versions of each image into a single image. You then set it as the div's background image and simply use CSS to adjust the background-position offset. Essentially, sliding instantly from the black and white to colour images as you rollover. This technique guarentees that both images are fully loaded.
Related
I have multiple background images that are behind a block of text each. I would like to fade each background image and have the text move up when one background image fades into another.
For example
BG1 (background image 1) has Tegxt1 on top of it. As BG1 fades into BG2, Text1 moves up and is replaced by Text2.
How can I do this with simple jquery and javascript and CSS?
Here's what I tried
this._currentTimeout = setTimeout(function() {
this.slides$.eq(newSlideIndex).css('z-index', 3).fadeTo(ANIMATION_FADE_DURATION, 1, function() {
this.slides$.eq(this.currentSlideIndex).css('z-index', 1).css('opacity', 0);
this.slides$.eq(newSlideIndex).css('z-index', 2);
this.currentSlideIndex = newSlideIndex;
this._setTransitionTimerForNewSlide(this._getNextSlideIndex(), 5000);
}.bind(this));
}.bind(this), durationUntilTransition);
You did not provide enough code to generate a complete working example (How is your html structured? Where is your jQuery located on the page? What does your existing CSS look like?), so unfortunately no one on StackOverflow and give you a perfect answer. The best we can do is create a small demo of what you could do to accomplish this affect. It's then up to you to learn from the example and apply the concept to your own code.
If I was going to try to accomplish this, here's the approach I would take:
Stack images on top of each other with position: absolute;
The first image group should have the highest z-index, so it's on top. CSS can do this!
The second image group should have the second-highest z-index, so that it shows behind the first image during the fade. CSS again!
all other image_groups should have z-index below the second image. Yay for CSS!
Animate the image and text seperately
The image just needs to fade out
The text needs to fade up and out
After the first (top) image group is completely faded, move it to the bottom of the list
Remove the inline style="..." that jQuery's .animate() applies to the image group. Once we do this, the image group will adhere to the css rules we set up in step one.
JS Fiddle Demo
The first step will be done manually by you when you're writing HTML and CSS, but then your jQuery can handle steps 2-4. Then just repeat as much as you'd like. Ask questions if you need to, but try hard to apply this to your own code. Good luck!!
Here is my fiddle. I would like to achieve 'one page full screen' type of webpage. I have two sections; display one at a time by display:block/none;each section contains content; .content1, .content2 respectively; content div works as a button to fire another section. You can also see a fixed header.
Section .intro contains .content1, section .archive contains .content2.
Now, I would like to build following chain of events on click: (i) .content1 fades out, (ii) .intro gets display:none, .archive gains display:block, (iii) .content2fades in.
The other way around, respectively, on click on .content2: (i) .content2 fades out, (ii) .archive gets display:none, .intro gains display:block, (iii) .content1fades in.
I have some experience with CSS, so I made and checked css transitions for fade in, fade out effects. Up to this point, everything is clear for me.
My problem is, however, I do not know how to build the chains of events. I have googled a lot of similar questions and tried some solutions, but had no luck. I have very little experience with JavaScript, so there might be some obvious mistakes in how I tried to implement the solutions.
I do not attach script in my fiddle; I would like to ask if you could point me in the right direction rather than fix my code, because, you see, I am not sure which solution I should show--so far they all look equally hopeless for me.
Should I go with JavaScript? JQuery? Pure CSS? Could you sketch / write some code how you would handle the problem?
Could you review the idea of displayed/hidden sections for the effect I am trying to achieve?
Using jQuery's fadeIn and fadeOut should be fine:
$(".toarchive").click(function(){
$('.intro').fadeOut();
$(".intro").removeClass("active");
$(".intro").css("display", "none");
$(".archive").fadeIn();
$(".archive").css("display", "block");
$(".archive").addClass("active");
});
However, if you're worried about the wait time between fades, you can use setTimeout:
$(".toarchive").click(function(){
$('.intro').fadeOut();
$(".intro").removeClass("active");
$(".intro").css("display", "none");
setTimeout(testThis, 1000);
});
function testThis(){
$(".archive").fadeIn();
$(".archive").css("display", "block");
$(".archive").addClass("active");
}
Try here
Try this, it automaticallys does what you want and it's cleaner.
Just put class show at page container you want to show first then clicking next will loop through pages.
Or you could set page number yourself and it will show that page.
http://jsfiddle.net/ot2gyxme/
var pages = $('.full'),
len = pages.length,
showing = pages.index($('.full.show'));
$('.next').click(function(){
pages.stop().eq(showing).fadeOut(function(){
setTimeout(function(){
showing = ++showing % len; //set this number to show x page
pages.eq(showing).fadeIn();
},1000); //time logo remains visible in ms.
});
});
I'm working with a jquery and I have this image that is the main problem. I googled it but came up with nothing. Here is my content for example.
And when the guy(in the picture above) is being click I want it to slide to the left side and will looked like this. Please see image below.
So what I'm thinking is
1. using addClass and removeClass using jquery or
2. just use jquery .slide or toggle function?
If there's a solution as such how could it be done? Since I only know is using addClass tho. And also what I'm planning is when the image exceeds 800px then the girl(in the image) will be send to back of the guy image.
What you are trying to do is create a mask around the guy. The scope of this question is beyond masking. Most methods of masking don't have large browser support at this moment so posting more on this would be disingenuous. But worth googling otherwise you can use the transform property to move the picture to the left. But you won't get the results you are looking for..
But there is the option of masking the picture in Photoshop and saving it as a PNG. And then utilizing the translate CSS method to move the image to left. This is your best option. But the details of either of these methods are out of scope for this question.
Cut this guy from image and put in another div at needed position. Put blue box between those two images and use slide function. You can cut the guy from his head i think.
Basically you need to have an html structure like this:
<div id='container'>
<div id='couple'></div>
<div id='mask'></div>
</div>
Initially in your css:
#mask {
display: none;
}
And, of course, you have to align horizzontally this two div.
Your jquery will have a behavior like this:
$('#couple').on('click', slide);
var slide = function() {
$target = $('#container');
$mask = $('#mask');
$mask.fadeIn();
$target.animate({
left: "+=50"
}, 500, function() {
/* callback on end*/
});
}
For complete documentation of animate check api jquery.
$(function () {
$(".btn").on("mouseover",function(){
$(this).attr("src", $(this).attr("src").replace("images", "images/hover"));
});
$(".btn").on("mouseleave",function(){
$(this).attr("src", $(this).attr("src").replace("images/hover", "images"));
});
});
The above code is the way I change the image when the user hover on the button, when user click on it , it will redirect to other page. And the Html element is like:
<img class="btn" src="images/index_03.gif" />
The problem is , I am sure the path is correct , but when the user click on the button , during the time of loading the next page or in some case, when i hover on the image , the hovered image is not shown but broken link, why is it and how to fix it? Thanks for helping
$(this).attr("src", $(this).attr("src").replace("images/hover", "images"));
This code will reload the image, every time (or from cache).
So, during the page loading as other data is also loading at the same time, onhover image loading will be slow or broken.
I suggest you should load both images at the same time and at the same position and show/hide them on hover to get faster results.
Using CSS sprites instead of javascript calls will eliminate mouseover flickering, and reduce the total number of http requests required for your site (making it load faster).
You can achieve the same 'mouseover' functionality by using the css ':hover' pseudo element to alter the 'clip' property of the image (supported in IE6 and above).
Check out these CSS Tricks articles:
CSS Sprites: What They Are, Why They’re Cool, and How To Use Them.
CSS Sprites with Inline Images
I've been doing alot of research and there are loads of plugins and tutorials out there that cover the use of large background images. Unfortunately, they all have one thing in common - they use absolutely positioned images to behave as "fake" background images.
Normally that would work fine for me and I've done that before, however, this project has a repeating background image, so it's necessary that I use normal CSS rules to declare the background image.
All of that being said, is there a way to check to see if the image is loaded and tell jQuery to fade this background image in once it is loaded? The main thing I'm looking for is a way for jQuery to verify that the image is actually loaded. If not, then I suppose I need to settle for a simple static delay (which unfortunately ruins the effect for users who have slow connections).
Last thing - can this be done via CSS class switching/toggling so that I can change the body class before and after the image is loaded? This would be a fallback for users without javascript and would make it so I don't have to .hide() my entire body while the background image loads.
*EDIT: This thread seems to have a similar discussion but I don't think it's quite the same thing: How do I delay html text from appearing until background image sprite is loaded? *
* EDIT 2 *
Looks like the above thread worked after all, except I'm still missing the fadeIn effect. I set the fadeIn intentionally high and it's not animating for some reason, any ideas why?
<script>
$(function() {
// create a dummy image
var img = new Image();
// give it a single load handler
$(img).one('load',function() {
$('html').css('background','url(<?php bloginfo( 'template_url' ); ?>/images/red_curtain.jpg) top center repeat-y').fadeIn(12000); // fade in the elements when the image loads
});
// declare background image source
img.src = "<?php bloginfo( 'template_url' ); ?>/images/red_curtain.jpg";
// make sure if fires in case it was cached
if( img.complete )
$(img).load();
});
</script>
This seems an old thread but I found a solution for this.
Hope it can help:
$(window).load(function(){
$('<img/>').attr('src', 'images/imgsrc.png').load(function() {
$('#loading').fadeOut(500);
$('#wrapper').fadeIn(200);
});
});
Use $(document).load() to achieve what you want.
"I set the fadeIn intentionally high and it's not animating for some reason, any ideas why?"
It is, just before the page has loaded
Add display: none; to your body tag
<body style="display: none">
Then with jQuery modify your code so it looks like this:
$(img).load(function(){
$("body").show();
});
Now page content will only show after img loading is complete.
To check when the image is loaded, declare another, "regular" image (i.e. the <img> tag) with the same src and attach event handler to it. Browser won't load the same image twice, so that event will also mean that the background is loaded.
Another trick I can propose is to go back to "fake" background. In order to make it "tile", you can create an iframe, stretched to cover the whole body, and having that image as background, and then fade that iframe as you like, while the rest of the page remains safely in the "main" frame.