DOM manipulation using JS function [closed] - javascript

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Closed 1 year ago.
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I am learning JS and very new to coding.
function querySelection(e){
console.log(document.querySelector(e));
}
querySelection('h5');
querySelection('#id');
querySelection('.className');
//querySelection('li: last child');
The very last query throws an error (commented). I am very new JS.I am not sure what is wrong in that query?

Change
querySelection('li: last child');
to
querySelection('li:last-child')

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What is wrong with this code (javascript) [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 4 years ago.
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if(!message.content.startsWith(prefix) return){
}
Parsing error : Unexpected Token return
if(!message.content.startsWith(prefix)){
return;
}
Your return was misplaced.

React.js not working [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 6 years ago.
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I've been trying to do the React.js getting started but when i run the example code This happens
Here is the code
You have a typo in script tag, you're saying scipt

validator.js bootstrap works but show not a function error [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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I have ajax form as on modal window. I want to validate the fields and i have followed the following tutorial. and Add the validator.js script into my project.
event.preventDefault();
//$('#myOrderDetailsForm').validator();
$('#myOrderDetailsForm').validator('validate')();
Here is what am seeing :
So wired .
Instead of this:
$('#myOrderDetailsForm').validator('validate')();
Use following:
$('#myOrderDetailsForm').validator('validate'); //removed ()

chargeitpro signature url not working [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 7 years ago.
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I have integrated Chargeitpro payment integrator in my application.
The payment is working good , but the signature url from chargeitpro response is not working for me.
Here is my Response only to get signature url.
AccountCardType:""
AccountEntryMethod:""
AccountExpiryDate:""
AmountBalance:0
AmountBill:0
AmountFee:0
AmountProcessed:0
ApprovalNumberResult:""
AvsResponseCode:""
AvsResponseText:""
BatchNumber:""
BillingName:""
CvvResponseCode:""
CvvResponseText:""
MaskedAccount:""
ProcessId:"55f5887d33aa780790c87abf"
ResultMessage:""
ResultStatus:"true"
SignatureURL:"http://easyintegratorapi.chargeitpro.com/signature.ashx?ID=55f5887d33aa780790c87abf"
TransactionType:"RequestSignature"
UniqueTransId:"285c6dfb949141158cb8514fd9f27945"
When i hit "http://easyintegratorapi.chargeitpro.com/signature.ashx?ID=55f5887d33aa780790c87abf" in browser , it says "Input string was not in a correct format."
Issue has been resolved by ChargeItPro.
Thanks.

Is there anything wrong in this Javascript line? [closed]

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This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
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my code is not working after adding style property, here it is:
$("#instaUser").append("<figure style='"display:inline "'><img id='"+i+"' src='"+data.data[i].profile_picture+"' alt='pic number "+i+"' height='"+200+"' width='"+200+"'> <figcaption>#"+data.data[i].username+"</figcaption></figure>");
could it be that i used the " in a wrong way?
You don't need double quotes wrapping display: inline
This is correct:
$("#instaUser").append("<figure style='display:inline'><img id='"+i+"' src='"+data.data[i].profile_picture+"' alt='pic number "+i+"' height='"+200+"' width='"+200+"'> <figcaption>#"+data.data[i].username+"</figcaption></figure>");

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