Is there anything wrong in this Javascript line? [closed] - javascript

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my code is not working after adding style property, here it is:
$("#instaUser").append("<figure style='"display:inline "'><img id='"+i+"' src='"+data.data[i].profile_picture+"' alt='pic number "+i+"' height='"+200+"' width='"+200+"'> <figcaption>#"+data.data[i].username+"</figcaption></figure>");
could it be that i used the " in a wrong way?


You don't need double quotes wrapping display: inline
This is correct:
$("#instaUser").append("<figure style='display:inline'><img id='"+i+"' src='"+data.data[i].profile_picture+"' alt='pic number "+i+"' height='"+200+"' width='"+200+"'> <figcaption>#"+data.data[i].username+"</figcaption></figure>");

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Why parseInt return 1 for 31 bit binary [closed]

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Closed 1 year ago.
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In C# if I do
var value = Convert.ToInt32("1000000000000000000000000000000", 2);
It will return 1073741824 but when I do the same in javascript,
parseInt(1000000000000000000000000000000,2)
It return 1 but not 1073741824

You need to pass string as first parameter
console.log(parseInt("1000000000000000000000000000000",2))

It's because in JavaScript you're lacking the quotation marks :)
parseInt("1000000000000000000000000000000",2)
works fine.

DOM manipulation using JS function [closed]

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Closed 1 year ago.
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I am learning JS and very new to coding.
function querySelection(e){
console.log(document.querySelector(e));
}
querySelection('h5');
querySelection('#id');
querySelection('.className');
//querySelection('li: last child');
The very last query throws an error (commented). I am very new JS.I am not sure what is wrong in that query?

Change
querySelection('li: last child');
to
querySelection('li:last-child')

What is wrong with this code (javascript) [closed]

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Closed 4 years ago.
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if(!message.content.startsWith(prefix) return){
}
Parsing error : Unexpected Token return

if(!message.content.startsWith(prefix)){
return;
}
Your return was misplaced.

React.js not working [closed]

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Closed 6 years ago.
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I've been trying to do the React.js getting started but when i run the example code This happens
Here is the code

You have a typo in script tag, you're saying scipt

Retuning a string in PHP [closed]

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Closed 8 years ago.
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I wanted to return following string, but I still couldn't get it done right for couple of hours. CAn anyone tell me what did I do wrong? Thank you.
<?php
return 'rs...#gmail.com.com';
?>

You have single quotes in the JavaScript code in your onclick attribute. You need to escape these by placing a backslash before each single quote.

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