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I'm currently learning javascript loop and right now i'm trying to make an exemple using the "For" loop but as i'm trying it keep telling me "longString is not defined".
the result i'm trying to have is to print 6 A like this "AAAAAA"
here is the code:
var longString = A;
for (var longString = A; longstring < 6; longString = longString + A) {
console.log(longString);
}
i'm sure the solution is simple but as a totally beginner i can't figure out how to solve it.
You have a typo in your break condition:
var longString = "";
for (longString = "A"; longstring < 6; longString = longString + "A") {
// Note the lowercase 's' ^
}
console.log(longString);
Also, if you want to get the length of a string, you can use string.length:
longString.length < 6;
Does this what you want?
var str = ""
for (i = 0; i < 6; i++) {
str += "A"
}
console.log(str);
Try this, the below code prints "AAAAAA" in one line.
var longString = 'A'
var str = ''
for (var i = 0; i<6; i+=1){
str = longString + str
}
console.log(str)
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I have one string as "testaabbaccc" in this string we contain palindrome as "abba" and it's length is 4 but how can we identify this with a JavaScript code.
var string ="testaabbaccc"
Need Output as abba is palindrome and length is 4
You can use this article and modify it to your needs.
Working demo
function isPalindrome(s) {
var rev = s.split("").reverse().join("");
return s == rev;
}
function longestPalind(s) {
var maxp_length = 0,
maxp = '';
for (var i = 0; i < s.length; i++) {
var subs = s.substr(i, s.length);
for (var j = subs.length; j >= 0; j--) {
var sub_subs = subs.substr(0, j);
if (sub_subs.length <= 1)
continue;
if (isPalindrome(sub_subs)) {
if (sub_subs.length > maxp_length) {
maxp_length = sub_subs.length;
maxp = sub_subs;
}
}
}
}
return maxp;
}
console.log(longestPalind("testaabbaccc"));
console.log(longestPalind("testaabbaccc").length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
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hi guys i tryed to create an empty array to fill it later. I post my code so you can help me. XD
"use strict"
var array = new array(6);
for(var i = 0; i <= 5; i++){
do {
var number = prompt("Put the element" + (i+1), 0);
}while(isNaN(number));
arr.push(number);
};
write.data(array);
It appears you may have copy and pasted some code without understanding what it is doing.
You are trying to push to an array, but you've declared your array as array, but trying to push to arr. Which is why it's not working.
var arr = new Array();
for(var i = 0; i <= 5; i++){
arr.push(i + 1);
}
console.log(arr);
alert(arr);
EDIT * You actually don't even need to declare the new Array(6), you can just use new Array() to push. However, if you would like to declare the size, you can do this instead.
var arr = new Array(6);
for(var i = 0; i <= 5; i++){
arr[i] = i + 1;
}
console.log(arr);
alert(arr);
You can also use this:
var arr = []; // create an empty object
for(var i = 0; i <= 5; i++){
arr.push(i + 1); // fill the object
}
console.log(arr);
alert(arr); // shows 1,2,3,4,5,6
This does what you are trying to achieve.
You can do it like
var a = new Array(6);
for(var i = 0;i < 6;i++){
a.push(i+1);
}
console.log(a);
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I have a javascript function:
var query1 = {{repair_semestre1}};
var query2 = {{repair_semestre2}};
var result1 = [];
var result2 = [];
for (var i = 0; i < query1.LRU.length; i++) {
result1.push(formatName(query1.LRU[i], query1.Client[i], query1.round[i]));
}
for (var i = 0; i < query2.LRU.length; i++) {
result2.push(formatName(query1.LRU[i], query1.Client[i], query1.round[i]));
}
return {
result1: result1,
result2: result2
};
function formatName(lru, turnover, round) {
return "[" + lru + "," + turnover + "," + round + "]";
}
It return the same values in result1 and result2.
How can I recovre the values of the result2.
Can you help me please.
thank you.
Just a typo, in your second for loop you are taking values from query1 instead of query2
for (var i = 0; i < query2.LRU.length; i++) {
result2.push(formatName(query1.LRU[i], query1.Client[i], query1.round[i]));//original
result2.push(formatName(query2.LRU[i], query2.Client[i], query2.round[i])); //change to this
}
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Closed 8 years ago.
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I am trying to produce the following HTML dynamically:
<ul>
<li>Butter Extra</li>
<li>Butter Extra</li>
</ul>
I was trying it this way:
var toppingval = 'Butter Extra,Butter Extra';
if (toppingval.indexOf(",") > 0)
{
var array = toppingval.split(',');
var uitaghtml = '<ul>' +
for (var z = 0; z < array.length; z++)
{
'<li>' + array[z] + '</li>' +
}
'</ul>';
}
But when I tried this it throws an exception in console as
Uncaught SyntaxError: Unexpected token for
Could anybody please let me know how to solve this?
You're trying to concatenate a for loop to a string. That is not a thing. Make a new variable that you continuously append to in your for loop.
var toppingval = 'Butter Extra,Butter Extra';
if (toppingval.indexOf(",") > 0) {
var array = toppingval.split(',');
var uitaghtml = '<ul>';
for (var z = 0; z < array.length; z++) {
uitaghtml = uitaghtml + '<li>' + array[z] + '</li>';
}
uitaghtml = uitaghtml + '</ul>';
}
You are trying to do something you cannot. Syntactically, you cannot leave open a appending operator + - which you are trying to do, but adding in li's into your ul. Try this:
var uitaghtml = $('<ul></ul>');
for (var z = 0; z < array.length; z++)
{
uitaghtml.append($("<li>" + array[z] + "</li>"));
}
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What would be a good way to turn a string into a series of digits in Javascript (I'm not talking about converting "0.5" into 0.5, but more "Hello" into 47392048)?
Any idea appreciated.
Thanks!
You can use the ASCII value of each letter:
"a letter".charCodeAt(0);
Ok, so given your comments, here is a (not widely tested) solution.
var str = "κόσμε 这是一条狗 é €";
$('#orig').after('<dd>' + str + '</dd>');
var result = "";
for (var i = 0, len = str.length, code, paddedCode; i < len; ++i) {
code = str[i].charCodeAt(0).toString();
paddedCode = code.length >= 8
? code
: new Array(8 - code.length + 1).join(0) + code; result += paddedCode;
result += paddedCode;
}
$('#nums').after('<dd>' + result + '</dd>');
var segments = result.match(/.{8}/g);
$.each(segments, function(k, v) {
$('#nums-segmented').after('<dd>' + v + '</dd>');
});
revertedString = '';
for (var i = 0, len = segments.length; i < len; i=i+2) {
revertedString += String.fromCharCode((segments[i] | 0));
}
$('#string').after('<dd>' + revertedString + '</dd>');
Run it at JSFiddle
The trick is to pad number and work with them as string when needed.