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I have one string as "testaabbaccc" in this string we contain palindrome as "abba" and it's length is 4 but how can we identify this with a JavaScript code.
var string ="testaabbaccc"
Need Output as abba is palindrome and length is 4
You can use this article and modify it to your needs.
Working demo
function isPalindrome(s) {
var rev = s.split("").reverse().join("");
return s == rev;
}
function longestPalind(s) {
var maxp_length = 0,
maxp = '';
for (var i = 0; i < s.length; i++) {
var subs = s.substr(i, s.length);
for (var j = subs.length; j >= 0; j--) {
var sub_subs = subs.substr(0, j);
if (sub_subs.length <= 1)
continue;
if (isPalindrome(sub_subs)) {
if (sub_subs.length > maxp_length) {
maxp_length = sub_subs.length;
maxp = sub_subs;
}
}
}
}
return maxp;
}
console.log(longestPalind("testaabbaccc"));
console.log(longestPalind("testaabbaccc").length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
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Javascript:Find the second longest substring from given string(input and output example added in heading)
Try this
Get sequences using RegExp
Sort them based on string length
Select second Item
function getSecondSubstring(str){
let regex = new RegExp(str.toLowerCase().split("").filter((x,i,a)=>a.indexOf(x)===i).join("+|")+"+", "ig")
let substrgroups = str.match(regex);
substrgroups.sort((a,b)=> b.length-a.length);
return substrgroups[1]
}
console.log(getSecondSubstring("ööööööðððób"));
console.log(getSecondSubstring("Aabbbccgggg"));
If you don't mind using regular expressions:
function yourFunctionName(input){
let grp = input.split(/(?<=(.))(?!\1|$)/ig);
grp.sort((a,b)=> b.length-a.length);
if(grp.length <= 0){
return null;
}
else if (grp.length == 1){
return grp[0];
}
else{
grp.sort(function(a, b){
return b.length - a.length;
});
return grp[1];
}
}
console.log(yourFunctionName("ööööööðððób"));
Or another way which does not use regular expressions...
function yourFunctionName(input){
input = input.toLowerCase();
let counter = [];
let prevChar;
let countIndex = 0;
for (let index = 0, length = input.length; index < length; index++) {
const element = input[index];
if(prevChar){
if(prevChar != element){
countIndex++;
counter[countIndex] = "";
}
}
else{
counter[countIndex] = "";
}
counter[countIndex] += element;
prevChar = element;
}
if(counter.length <= 0){
return null;
}
else if (counter.length == 1){
return counter[0];
}
else{
counter.sort(function(a, b){
return b.length - a.length;
});
return counter[1];
}
}
console.log(yourFunctionName("aaaaabbbbccdd"));
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I have been working on a ceaser cipher algorithm but I haven't been able to grasp the reason why the joined array returns spaces in a peculiar state.
function rot13(str) { // LBH QVQ VG!
var string = str.split('');
var codedStr = [];
var encoded = [];
for (var k=0; k < string.length; k++){
codedStr.push(string[k].charCodeAt());
}
for(var i = 0; i < codedStr.length; i++){
if(codedStr[i] > 77 ){
codedStr[i] -= 13;
}
else if( codedStr[i] == 32 || codedStr[i] == 63){
codedStr[i] = codedStr[i];
}
else{
codedStr[i] += 13;
}
encoded.push(codedStr[i]);
}
var decode = codedStr.map(String.fromCharCode);
var result = decode.join('');
return result;
}
// Change the inputs below to test
console.log(rot13("SERR PBQR PNZC"));
String.fromCharCode accepts multiple arguments, and map provides 3. You should use
codedStr.map(code => String.fromCharCode(code));
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I need to add one bye one value to comma separated list
my code
var Plist, Llist;
for (var i = 0; i < results.length; i++) {
var id = results[i].id;
if (id.startsWith("P")) {
Plist = // Add comma separated value
} else if (id.startsWith("L")) {
Llist = // add comma repeated value
}
}
please suggest better solution...
var Plist = "", Llist = "";
for (var i = 0; i < results.length; i++) {
var id = results[i].id;
if (id.startsWith("P")) {
Plist += id + ",";
} else if (id.startsWith("L")) {
Llist += id + ",";
}
}
if (Plist.indexOf(',') !== -1) {
Plist = Plist.substring(0, Plist.length - 1);
}
if (Llist.indexOf(',') !== -1) {
Llist = Llist.substring(0, Llist.length - 1);
}
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var test = "abcdefghijklmnopqrstuvwxyz";
for(i = 0; i < test.length; i++) {
alert(test.substring(i,1));
}
I expected each alert to return each letter of the alphabet individually.
Instead, the first 5 alerts displayed as follows. Why?
a
b
bc
bcd
bcde
var test = "abcdefghijklmnopqrstuvwxyz";
for(i = 0; i < test.length; i++) {
console.log(test.substring(i,i+1));
}
actually, it's
substring(start, end)
not
substring(start, length)
unlike substr, which is indeed, substr(start, length)
If "start" is greater than "end", this method (substring) will swap the two arguments, meaning str.substring(1,4) == str.substring(4,1).
Use:
for(i = 0; i < test.length; i++) {
alert(test[i]);
}
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Closed 9 years ago.
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I am finding css Rules and then changing it's style and i am done with it
but i don't know why i am getting this error
TypeError: sh[i] is undefined
if ("undefined"!==sh[i].cssRules)
my code is here
window.onload = function() {
var sh = document.styleSheets;
for (var i = 1; i <= sh.length; i++) {
if (sh[i].cssRules)
rule = sh[i].cssRules;
else if (sh[i].rules)
rule = sh[i].rules;
for (var j = 0; j < rule.length; j++) {
var sel = rule[j].selectorText;
if (sel == ".test") {
var R = rule[j].style;
R.color = "red";
}
}
}
var C = document.createElement("div");
C.className = "test";
C.innerHTML = "test";
var E = document.getElementById("div1");
E.appendChild(C);
}
i am finding all css that has been load to page and then find rule that i want to change.
if you have any question please ask me
Solved :
problem was at this line
for (var i = 1; i <= sh.length; i++) {
repalced <= withi <