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How do I replace all instances where I have #sometext# in order of the array provided?
The text is a string and my goal is to search for all instances where I have some text surrounded by the "#" character. Then replace those instances with values in the array in the order of the array
Example:
const text = "You are the #RANKED# highest ranked user (out of #TOTALUSER# people)"
const myArray = [10, 50];
After searching and replacing the text should be:
"You are the 10 highest ranked user (out of 50 people)"
text.replace(/#([^#]+)#/g, _ => myArray.shift());
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I have a string that looks like "{`index`:`20`,`value`:`RA`}<1", and I want it to become "`RA`<1". I don't think the replace function is sufficient as the index and value changes based on what I enter. Is there a way to do that?
assuming the required string is everything after the last :, except for the }, the original string can be sliced and edited as follows:
const string = "{`index`:`20`,`value`:`RA`}<1";
let newString = string.slice(string.lastIndexOf(":")+1).split("}").join("");
console.log(newString);
This will always append everything after the final } to everthing before it but after the last :, regardless of the earlier content.
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I have a requirement where i will get the input from the user. He can enter
"features1,feature2",feature3,"feature4"
something like this. I'm using this
let arr: any = message.split(/,(?=(?:(?:[^"]*"){2})*[^"]*$)/)
to split the string and i'm getting result like
[""feature1,feature2"","feature3",""feature4""]
but i want the result like this
["feature1,feature2","feature3","feature4"]
I don't thing what you're trying to achieve is possible only using split function.
After you split, loop over the error and replace " with `` (empty).
const message = `"features1,feature2",feature3,"feature4"`;
let arr = message.split(/,(?=(?:(?:[^"]*"){2})*[^"]*$)/);
arr = arr.map(el=>el.replace(/"/g,''));
console.log(arr);
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I need to to search through the document text and where it finds a pattern of 0000/0, 0000/00 or 0000/000 (where 0 can be any number) it automatically wraps that text in
0000/00
What I found for auto linkers are only when text is a URL, so it doesn't really help with what I need.
A simple regex pattern would do the trick.
text.replace(/(0000\/[0-9]{1,3})/gm, `$1`);
This will look for 0000/ followed by numbers between 0 and 9, 1 to 3 times.
simple regexp approach
document.body.innerHTML = document.body.innerHTML.replace(/(\d{4}\/\d{1,3})/g,
'$1')
Some text 0000/0 and this 1234/56 and that 7777/666
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I'm trying to make something that gives an output based on your input. I would like it to take every letter and produce something with the next letter in the alphabet. So if I entered "Hello" it would produce "Ifmmp". The only way I can think to do this is with a series of ifs and else ifs, but I would like to know if there is a faster way.
You can use the String.fromCharCode feature. For example:
let myChar = 'c';
let nextChar = String.fromCharCode(myChar.charCodeAt(0)+1);
console.log(nextChar) // 'd'
In your case, you would replace 'c' with your character variable.
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I have a string like command--o1--o2--o3 ( command,o1,o2,o3 are arbitrary words)
And I want get [o1, o2, o3] though a Regular Expression(Not a array operation or other ways. JUST only use Regular Expression).
Is there any idea to accomplish this !?
If you're using JavaScript, and assuming you want all strings after a --, you may do
var things = str.split(/--/).slice(1)
If you just want to get the 2 characters words following --, then you may use
var things = str.match(/--\w\w/g).map(function(s){ return s.slice(2) })