Develop Reference

Converting Uint8Array to BigInt in Javascript

I have found 3 methods to convert Uint8Array to BigInt and all of them give different results for some reason. Could you please tell me which one is correct and which one should I use?
Using bigint-conversion library. We can use bigintConversion.bufToBigint() function to get a BigInt. The implementation is as follows:
export function bufToBigint (buf: ArrayBuffer|TypedArray|Buffer): bigint {
let bits = 8n
if (ArrayBuffer.isView(buf)) bits = BigInt(buf.BYTES_PER_ELEMENT * 8)
else buf = new Uint8Array(buf)
let ret = 0n
for (const i of (buf as TypedArray|Buffer).values()) {
const bi = BigInt(i)
ret = (ret << bits) + bi
}
return ret
}
Using DataView:
let view = new DataView(arr.buffer, 0);
let result = view.getBigUint64(0, true);
Using a FOR loop:
let result = BigInt(0);
for (let i = arr.length - 1; i >= 0; i++) {
result = result * BigInt(256) + BigInt(arr[i]);
}
I'm honestly confused which one is right since all of them give different results but do give results.

I'm fine with either BE or LE but I'd just like to know why these 3 methods give a different result.
One reason for the different results is that they use different endianness.
Let's turn your snippets into a form where we can execute and compare them:
let source_array = new Uint8Array([
0xff, 0xee, 0xdd, 0xcc, 0xbb, 0xaa, 0x99, 0x88,
0x77, 0x66, 0x55, 0x44, 0x33, 0x22, 0x11]);
let buffer = source_array.buffer;
function method1(buf) {
let bits = 8n
if (ArrayBuffer.isView(buf)) {
bits = BigInt(buf.BYTES_PER_ELEMENT * 8)
} else {
buf = new Uint8Array(buf)
}
let ret = 0n
for (const i of buf.values()) {
const bi = BigInt(i)
ret = (ret << bits) + bi
}
return ret
}
function method2(buf) {
let view = new DataView(buf, 0);
return view.getBigUint64(0, true);
}
function method3(buf) {
let arr = new Uint8Array(buf);
let result = BigInt(0);
for (let i = arr.length - 1; i >= 0; i--) {
result = result * BigInt(256) + BigInt(arr[i]);
}
return result;
}
console.log(method1(buffer).toString(16));
console.log(method2(buffer).toString(16));
console.log(method3(buffer).toString(16));
Note that this includes a bug fix for method3: where you wrote for (let i = arr.length - 1; i >= 0; i++), you clearly meant i-- at the end.
For "method1" this prints: ffeeddccbbaa998877665544332211
Because method1 is a big-endian conversion (first byte of the array is most-significant part of the result) without size limit.
For "method2" this prints: 8899aabbccddeeff
Because method2 is a little-endian conversion (first byte of the array is least significant part of the result) limited to 64 bits.
If you switch the second getBigUint64 argument from true to false, you get big-endian behavior: ffeeddccbbaa9988.
To eliminate the size limitation, you'd have to add a loop: using getBigUint64 you can get 64-bit chunks, which you can assemble using shifts similar to method1 and method3.
For "method3" this prints: 112233445566778899aabbccddeeff
Because method3 is a little-endian conversion without size limit. If you reverse the for-loop's direction, you'll get the same big-endian behavior as method1: result * 256n gives the same value as result << 8n; the latter is a bit faster.
(Side note: BigInt(0) and BigInt(256) are needlessly verbose, just write 0n and 256n instead. Additional benefit: 123456789123456789n does what you'd expect, BigInt(123456789123456789) does not.)
So which method should you use? That depends on:
(1) Do your incoming arrays assume BE or LE encoding?
(2) Are your BigInts limited to 64 bits or arbitrarily large?
(3) Is this performance-critical code, or are all approaches "fast enough"?
Taking a step back: if you control both parts of the overall process (converting BigInts to Uint8Array, then transmitting/storing them, then converting back to BigInt), consider simply using hexadecimal strings instead: that'll be easier to code, easier to debug, and significantly faster. Something like:
function serialize(bigint) {
return "0x" + bigint.toString(16);
}
function deserialize(serialized_bigint) {
return BigInt(serialized_bigint);
}

If you need to store really big integers that isn't bound to any base64 or 128 and also keep negative numbers then this is a solution for you...
function encode(n) {
let hex, bytes
// shift all numbers 1 step to the left and xor if less then 0
n = (n << 1n) ^ (n < 0n ? -1n : 0n)
// convert to hex
hex = n.toString(16)
// pad if neccesseery
if (hex.length % 2) hex = '0' + hex
// convert hex to bytes
bytes = hex.match(/.{1,2}/g).map(byte => parseInt(byte, 16))
return bytes
}
function decode(bytes) {
let hex, n
// convert bytes back into hex
hex = bytes.map(e => e.toString(16).padStart(2, 0)).join('')
// Convert hex to BigInt
n = BigInt(`0x`+hex)
// Shift all numbers to right and xor if the first bit was signed
n = (n >> 1n) ^ (n & 1n ? -1n : 0n)
return n
}
const input = document.querySelector('input')
input.oninput = () => {
console.clear()
const bytes = encode(BigInt(input.value))
// TODO: Save or transmit this bytes
// new Uint8Array(bytes)
console.log(bytes.join(','))
const n = decode(bytes)
console.log(n.toString(10)+'n') // cuz SO can't render bigints...
}
input.oninput()
<input type="number" value="-39287498324798237498237498273323423" style="width: 100%">

Javascript - parse string to long

I have a working script in python doing string to integer conversion based on specified radix using long(16):
modulus=public_key["n"]
modulusDecoded = long(public_key["n"], 16)
which prints:
8079d7ae567dd2c02dadd1068843136314fa3893fa1fb1ab331682c6a85cad62b208d66c9974bbbb15d52676fd9907efb158c284e96f5c7a4914fd927b7326c40efa14922c68402d05ff53b0e4ccda90bbee5e6c473613e836e2c79da1072e366d0d50933327e77651b6984ddbac1fdecf1fd8fa17e0f0646af662a8065bd873
and
90218878289834622370514047239437874345637539049004160177768047103383444023879266805615186962965710608753937825108429415800005684101842952518531920633990402573136677611127418094912644368840442620417414685225340199872975797295511475162170060618806831021437109054760851445152320452665575790602072479287289305203
respectively.
This looks like a Hex to decimal conversion.
I tried to have the same result in JS but parseInt() and parseFloat() produce something completely different. On top of that JavaScript seems not to like chars in input string and sometimes returns NaN.
Could anyone please provide a function / guidance how to get the same functionality as in Python script?

Numbers in JavaScript are floating point so they always lose precision after a certain digit. To have unlimited numbers one could rather use an array of numbers from 0 to 9, which has an unlimited range. To do so based on the hex string input, i do a hex to int array conversion, then I use the double dabble algorithm to convert the array to BCD. That can be printed easily:
const hexToArray = arr => arr.split("").map(n => parseInt(n,16));
const doubleDabble = arr => {
var l = arr.length;
for( var b = l * 4; b--;){
//add && leftshift
const overflow = arr.reduceRight((carry,n,i) => {
//apply the >4 +3, then leftshift
var shifted = ((i < (arr.length - l ) && n>4)?n+3:n ) << 1;
//just take the right four bits and add the eventual carry value
arr[i] = (shifted & 0b1111) | carry;
//carry on
return shifted > 0b1111;
}, 0);
// we've exceeded the current array, lets extend it:
if(overflow) arr.unshift(overflow);
}
return arr.slice(0,-l);
};
const arr = hexToArray("8079d7");
const result = doubleDabble(arr);
console.log(result.join(""));
Try it

Using the built in api parseInt, you can get upto 100 digts of accuracy on Firefox and 20 digits of accuracy on Chrome.
a = parseInt('8079d7ae567dd2c02dadd1068843136314fa3893fa1fb1ab331682c6a85cad62b208d66c9974bbbb15d52676fd9907efb158c284e96f5c7a4914fd927b7326c40efa14922c68402d05ff53b0e4ccda90bbee5e6c473613e836e2c79da1072e366d0d50933327e77651b6984ddbac1fdecf1fd8fa17e0f0646af662a8065bd873', 16)
a.toPrecision(110)
> Uncaught RangeError: toPrecision() argument must be between 1 and 21
# Chrome
a.toPrecision(20)
"9.0218878289834615508e+307"
# Firefox
a.toPrecision(100)
"9.021887828983461550807409292694387726882781812072572899692574101215517323445643340153182035092932819e+307"
From the ECMAScript Spec,
Let p be ? ToInteger(precision).
...
If p < 1 or p > 100, throw a RangeError exception.

As described in this answer, JavaScript numbers cannot represent integers larger than 9.007199254740991e+15 without loss of precision.
Working with larger integers in JavaScript requires a BigInt library or other special-purpose code, and large integers will then usually be represented as strings or arrays.
Re-using code from this answer helps to convert the hexadecimal number representation
8079d7ae567dd2c02dadd1068843136314fa3893fa1fb1ab331682c6a85cad62b208d66c9974bbbb15d52676fd9907efb158c284e96f5c7a4914fd927b7326c40efa14922c68402d05ff53b0e4ccda90bbee5e6c473613e836e2c79da1072e366d0d50933327e77651b6984ddbac1fdecf1fd8fa17e0f0646af662a8065bd873
to its decimal representation
90218878289834622370514047239437874345637539049004160177768047103383444023879266805615186962965710608753937825108429415800005684101842952518531920633990402573136677611127418094912644368840442620417414685225340199872975797295511475162170060618806831021437109054760851445152320452665575790602072479287289305203
as demonstrated in the following snippet:
function parseBigInt(bigint, base) {
//convert bigint string to array of digit values
for (var values = [], i = 0; i < bigint.length; i++) {
values[i] = parseInt(bigint.charAt(i), base);
}
return values;
}
function formatBigInt(values, base) {
//convert array of digit values to bigint string
for (var bigint = '', i = 0; i < values.length; i++) {
bigint += values[i].toString(base);
}
return bigint;
}
function convertBase(bigint, inputBase, outputBase) {
//takes a bigint string and converts to different base
var inputValues = parseBigInt(bigint, inputBase),
outputValues = [], //output array, little-endian/lsd order
remainder,
len = inputValues.length,
pos = 0,
i;
while (pos < len) { //while digits left in input array
remainder = 0; //set remainder to 0
for (i = pos; i < len; i++) {
//long integer division of input values divided by output base
//remainder is added to output array
remainder = inputValues[i] + remainder * inputBase;
inputValues[i] = Math.floor(remainder / outputBase);
remainder -= inputValues[i] * outputBase;
if (inputValues[i] == 0 && i == pos) {
pos++;
}
}
outputValues.push(remainder);
}
outputValues.reverse(); //transform to big-endian/msd order
return formatBigInt(outputValues, outputBase);
}
var largeNumber =
'8079d7ae567dd2c02dadd1068843136314fa389'+
'3fa1fb1ab331682c6a85cad62b208d66c9974bb'+
'bb15d52676fd9907efb158c284e96f5c7a4914f'+
'd927b7326c40efa14922c68402d05ff53b0e4cc'+
'da90bbee5e6c473613e836e2c79da1072e366d0'+
'd50933327e77651b6984ddbac1fdecf1fd8fa17'+
'e0f0646af662a8065bd873';
//convert largeNumber from base 16 to base 10
var largeIntDecimal = convertBase(largeNumber, 16, 10);
//show decimal result in console:
console.log(largeIntDecimal);
//check that it matches the expected output:
console.log('Matches expected:',
largeIntDecimal === '90218878289834622370514047239437874345637539049'+
'0041601777680471033834440238792668056151869629657106087539378251084294158000056'+
'8410184295251853192063399040257313667761112741809491264436884044262041741468522'+
'5340199872975797295511475162170060618806831021437109054760851445152320452665575'+
'790602072479287289305203'
);
//check that conversion and back-conversion results in the original number
console.log('Converts back:',
convertBase(convertBase(largeNumber, 16, 10), 10, 16) === largeNumber
);

JavaScript calculate hashcode from real number and integer number

Hi there I need function to calculate unique integer number from number (real number double precision) and integer.
Try explain I am developing GIS application in javascript and I am working with complex vector object like polygon (array of points object with two coordinate in ring) and lines array of points. I need fast algorithm to recognize that element has been changed it must be really fast because my vector object is collection of thousand points . In C# I am calculating hash code from coordinate using bitwise operation XOR.
But javascript convert all operands in bitwise operation to integer but i need convert double precision to integer before apply bitwise in c# way (binnary). In reflector i see this that c# calculate hash code fro double like this and I need this function in javascript as fast as can be.
public override unsafe int GetHashCode() //from System.Double
{
double num = this;
if (num == 0.0)
{
return 0;
}
long num2 = *((long*) &num);
return (((int) num2) ^ ((int) (num2 >> 32)));
}
Example:
var rotation = function (n) {
n = (n >> 1) | ((n & 0x001) << 31);
return n;
}
var x: number = 1;
var y: number = 5;
var hash = x ^ rotation(y); // result is -2147483645
var x1: number = 1.1;
var y1: number = 5;
var hash1 = x1 ^ rotation(y1); // result is -2147483645
Example result is not correct hash == hash1
Example 2: Using to string there is correct result but calculate Hash from string is to complicate and I thing is not fast enough.
var rotation = function (n) {
n = (n >> 1) | ((n & 0x001) << 31);
return n;
}
var GetHashCodeString = function(str: string): number {
var hash = 0, i, l, ch;
if (str.length == 0) return hash;
for (i = 0, l = str.length; i < l; i++) {
ch = str.charCodeAt(i);
hash = ((hash << 5) - hash) + ch;
hash |= 0; // Convert to 32bit integer
}
return hash;
}
var x: number = 1;
var y: number = 5;
var hash = GetHashCodeString(x.toString()) ^ rotation(GetHashCodeString(y.toString()));
//result is -2147483605
var x1: number = 1.1;
var y1: number = 5;
var hash1 = GetHashCodeString(x1.toString()) ^ rotation(GetHashCodeString(y1.toString()));
//result is -2147435090
Example2 result is correct hash != hash1
Is there some faster way than converting number to string than calculate hash from each character? Because my object is very large and it will take lot of time and operation in this way ...
I try do it using TypedArrays but yet I am not successful.
Thanks very much for your help

Hi there I tried use TypedArrays to calculate Hash code from number and the result is interesting. In IE the performance 4x better in Chrome 2x in FireFox this approach is equal to string version ...
var GetHashCodeNumber = function (n: number): number {
//create 8 byte array buffer number in js is 64bit
var arr = new ArrayBuffer(8);
//create view to array buffer
var dv = new DataView(arr);
//set number to buffer as 64 bit float
dv.setFloat64(0, n);
//now get first 32 bit from array and convert it to integer
// from offset 0
var c = dv.getInt32(0);
//now get next 32 bit from array and convert it to integer
//from offset 4
var d = dv.getInt32(4);
//XOR first end second integer numbers
return c ^ d;
}
I think this can be useful for someone
EDIT: using one buffer and DataView is faster !

Here is a faster way to do this in JavaScript.
const kBuf = new ArrayBuffer(8);
const kBufAsF64 = new Float64Array(kBuf);
const kBufAsI32 = new Int32Array(kBuf);
function hashNumber(n) {
// Remove this `if` if you want 0 and -0 to hash to different values.
if (~~n === n) {
return ~~n;
}
kBufAsF64[0] = n;
return kBufAsI32[0] ^ kBufAsI32[1];
}
It's 250x faster than the DataView approach: see benchmark.

I looked up some hashing libraries to see how they did it: xxhashjs, jshashes, etc.
Most seem to take a string or an ArrayBuffer, and also depend on UINT32-like functionality. This is equivalent to you needing a binary representation of the double (from your C# example). Notably I did not find any solution that included more-strange types, other than in another (unanswered) question.
His solution uses a method proposed here, which converts it to various typed arrays. This is most likely what you want, and the fastest accurate solution (I think).
I highly recommend that you structure your code to traverse objects/arrays as desired, and also benchmark the solution to see how comparable it is to your existing methods (the non-working one and the string one).

Converting large integer to 8 byte array in JavaScript

I'm trying to convert a large number into an 8 byte array in javascript.
Here is an IMEI that I am passing in: 45035997012373300
var bytes = new Array(7);
for(var k=0;k<8;k++) {
bytes[k] = value & (255);
value = value / 256;
}
This ends up giving the byte array: 48,47,7,44,0,0,160,0. Converted back to a long, the value is 45035997012373296, which is 4 less than the correct value.
Any idea why this is and how I can fix it to serialize into the correct bytes?

Since you are converting from decimal to bytes, dividing by 256 is an operation that is pretty easily simulated by splitting up a number in a string into parts. There are two mathematical rules that we can take advantage of.
The right-most n digits of a decimal number can determine divisibility by 2^n.
10^n will always be divisible by 2^n.
Thus we can take the number and split off the right-most 8 digits to find the remainder (i.e., & 255), divide the right part by 256, and then also divide the left part of the number by 256 separately. The remainder from the left part can be shifted into the right part of the number (the right-most 8 digits) by the formula n*10^8 \ 256 = (q*256+r)*10^8 \ 256 = q*256*10^8\256 + r*10^8\256 = q*10^8 + r*5^8, where \ is integer division and q and r are quotient and remainder, respectively for n \ 256. This yields the following method to do integer division by 256 for strings of up to 23 digits (15 normal JS precision + 8 extra yielded by this method) in length:
function divide256(n)
{
if (n.length <= 8)
{
return (Math.floor(parseInt(n) / 256)).toString();
}
else
{
var top = n.substring(0, n.length - 8);
var bottom = n.substring(n.length - 8);
var topVal = Math.floor(parseInt(top) / 256);
var bottomVal = Math.floor(parseInt(bottom) / 256);
var rem = (100000000 / 256) * (parseInt(top) % 256);
bottomVal += rem;
topVal += Math.floor(bottomVal / 100000000); // shift back possible carry
bottomVal %= 100000000;
if (topVal == 0) return bottomVal.toString();
else return topVal.toString() + bottomVal.toString();
}
}
Technically this could be implemented to divide an integer of any arbitrary size by 256, simply by recursively breaking the number into 8-digit parts and handling the division of each part separately using the same method.
Here is a working implementation that calculates the correct byte array for your example number (45035997012373300): http://jsfiddle.net/kkX2U/.
[52, 47, 7, 44, 0, 0, 160, 0]

Your value and the largest JavaScript integer compared:
45035997012373300 // Yours
9007199254740992 // JavaScript's biggest integer
JavaScript cannot represent your original value exactly as an integer; that's why your script breaking it down gives you an inexact representation.
Related:
var diff = 45035997012373300 - 45035997012373298;
// 0 (not 2)
Edit: If you can express your number as a hexadecimal string:
function bytesFromHex(str,pad){
if (str.length%2) str="0"+str;
var bytes = str.match(/../g).map(function(s){
return parseInt(s,16);
});
if (pad) for (var i=bytes.length;i<pad;++i) bytes.unshift(0);
return bytes;
}
var imei = "a000002c072f34";
var bytes = bytesFromHex(imei,8);
// [0,160,0,0,44,7,47,52]
If you need the bytes ordered from least-to-most significant, throw a .reverse() on the result.

store the imei as a hex string (if you can), then parse the string in that manner, this way you can keep the precision when you build the array. I will be back with a PoC when i get home on my regular computer, if this question has not been answered.
something like:
function parseHexString(str){
for (var i=0, j=0; i<str.length; i+=2, j++){
array[j] = parseInt("0x"+str.substr(i, 2));
}
}
or close to that whatever...

JavaScript summing large integers

In JavaScript I would like to create the binary hash of a large boolean array (54 elements) with the following method:
function bhash(arr) {
for (var i = 0, L = arr.length, sum = 0; i < L; sum += Math.pow(2,i)*arr[i++]);
return sum;
}
In short: it creates the smallest integer to store an array of booleans in. Now my problem is that javascript apparently uses floats as default. The maximum number I have to create is 2^54-1 but once javascript reaches 2^53 it starts doing weird things:
9007199254740992+1 = 9007199254740994
Is there any way of using integers instead of floats in javascript? Or large integer summations?

JavaScript uses floating point internally.
What is JavaScript's highest integer value that a number can go to without losing precision?
In other words you can't use more than 53 bits. In some implementations you may be limited to 31.
Try storing the bits in more than one variable, use a string, or get a bignum library, or if you only need to deal with integers, a biginteger library.

BigInt is being added as a native feature of JavaScript.
typeof 123;
// → 'number'
typeof 123n;
// → 'bigint'
Example:
const max = BigInt(Number.MAX_SAFE_INTEGER);
const two = 2n;
const result = max + two;
console.log(result);
// → '9007199254740993'

javascript now has experimental support for BigInt.
At the time of writing only chrome supports this.
caniuse has no entry yet.
BigInt can be either used with a constructor, e.g. BigInt(20) or by appending n, e.g. 20n
Example:
const max = Number.MAX_SAFE_INTEGER;
console.log('javascript Number limit reached', max + 1 === max + 2) // true;
console.log('javascript BigInt limit reached', BigInt(max) + 1n === BigInt(max) + 2n); // false

No. Javascript only has one numeric type. You've to code yourself or use a large integer library (and you cannot even overload arithmetic operators).
Update
This was true in 2010... now (2019) a BigInt library is being standardized and will most probably soon arrive natively in Javascript and it will be the second numeric type present (there are typed arrays, but - at least formally - values extracted from them are still double-precision floating point numbers).

Another implementation of large integer arithmetic (also using BigInt.js) is available at www.javascripter.net/math/calculators/100digitbigintcalculator.htm. Supports the operations + - * / as well as remainder, GCD, LCM, factorial, primality test, next prime, previous prime.

So while attempting one of the leetcode problem I have written a function which takes two numbers in form of string and returns the sum of those numbers in form of string.
(This doesn't work with negative numbers though we can modify this function to cover that)
var addTwoStr = function (s1, s2) {
s1 = s1.split("").reverse().join("")
s2 = s2.split("").reverse().join("")
var carry = 0, rS = '', x = null
if (s1.length > s2.length) {
for (let i = 0; i < s1.length; i++) {
let s = s1[i]
if (i < s2.length) {
x = Number(s) + Number(s2[i]) + carry
rS += String((x % 10))
carry = parseInt(x/10)
} else {
if (carry) {
x = Number(s) + carry
rS += String((x % 10))
carry = parseInt(x/10)
} else {
rS += s
}
}
}
} else {
for (let i = 0; i < s2.length; i++) {
let s = s2[i]
if (i < s1.length) {
x = Number(s) + Number(s1[i]) + carry
rS += String((x % 10))
carry = parseInt(x/10)
} else {
if (carry) {
x = Number(s) + carry
rS += String((x % 10))
carry = parseInt(x/10)
} else {
rS += s
}
}
}
}
if (carry) {
rS += String(carry)
}
return rS.split("").reverse().join("")
}
Example: addTwoStr('120354566', '321442535')
Output: "441797101"

There are various BigInteger Javascript libraries that you can find through googling. e.g. http://www.leemon.com/crypto/BigInt.html

Here's (yet another) wrapper around Leemon Baird's BigInt.js
It is used in this online demo of a big integer calculator in JavaScript which implements the usual four operations + - * /, the modulus (%), and four builtin functions : the square root (sqrt), the power (pow), the recursive factorial (fact) and a memoizing Fibonacci (fibo).

You're probably running into a byte length limit on your system. I'd take the array of booleans, convert it to an array of binary digits ([true, false, true] => [1,0,1]), then join this array into a string "101", then use parseInt('101',2), and you'll have your answer.

/** --if you want to show a big int as your wish use install and require this module
* By using 'big-integer' module is easier to use and handling the big int numbers than regular javascript
* https://www.npmjs.com/package/big-integer
*/
let bigInt = require('big-integer');
//variable: get_bigInt
let get_bigInt = bigInt("999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999");
let arr = [1, 100000, 21, 30, 4, BigInt(999999999999), get_bigInt.value];
console.log(arr[6]); // Output: 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999n
//Calculation
console.log(arr[6] + 1n); // +1
console.log(arr[6] + 100n); // +100
console.log(arr[6] - 1n); // -1
console.log(arr[6] - 10245n); // -1000n
console.log((arr[6] * 10000n) + 145n - 435n);