I have a URL from which I want to remove the substring after the second dot.
input:
google.com/xyz.abc.html
output:
google.com/xyz
The following regex works, but not sure this is the right way to do it
^([\w/]+\.[\w/]+\.)
You can use split and join, 2nd argument inside split is to limit the number of chunks, i.e here it will only output 2 element in resulting array
console.log(`google.com/xyz.abc.html`.split('.',2).join('.'))
Here is a non regex solution for this.
let inp = 'google.com/xyz.abc.html';
let out = [inp.split('/')[0], inp.split('/')[1].split('.')[0]].join('/');
console.log(out);
Related
I have this string defined
const str : string = 'hostel:uk>london>city>street';
that I want to split to see only hostel, but I see the whole string in the console
console.log(str.split([":"][1]));
You could match the first part until colon.
const
str = 'hostel:uk>london>city>street',
first = str.match(/^[^:]+/)[0];
console.log(first);
You need to put the [] after the split() as the output of a split() is an array.
So your code will change to,
console.log(str.split([":"])[0]);
Also, after the split(), "hostel" will be at the 0th index of the array.
You need to select item 0, and also do that after the split call (not inside it), and you need to pass a string into split:
console.log(str.split(":")[0]);
you can perform your desired output after adding this line
console.log(str.split(':')[0]);
I have a dynamically generated text like this
xxxxxx-xxxx-xxxxx-xxxxx-Map-B-844-0
How can I remove everything before Map ...? I know there is a hard coded way to do this by using substring() but as I said these strings are dynamic and before Map .. can change so I need to do this dynamically by removing everything before 4th index of - character.
You could remove all four minuses and the characters between from start of the string.
var string = 'xxxxxx-xxxx-xxxxx-xxxxx-Map-B-844-0',
stripped = string.replace(/^([^-]*-){4}/, '');
console.log(stripped);
I would just find the index of Map and use it to slice the string:
let str = "xxxxxx-xxxx-xxxxx-xxxxx-Map-B-844-0"
let ind = str.indexOf("Map")
console.log(str.slice(ind))
If you prefer a regex (or you may have occurrences of Map in the prefix) you man match exactly what you want with:
let str = "xxxxxx-xxxx-xxxxx-xxxxx-Map-B-844-0"
let arr = str.match(/^(?:.+?-){4}(.*)/)
console.log(arr[1])
I would just split on the word Map and take the first index
var splitUp = 'xxxxxx-xxxx-xxxxx-xxxxx-Map-B-844-0'.split('Map')
var firstPart = splitUp[0]
Uses String.replace with regex expression should be the popular solution.
Based on the OP states: so I need to do this dynamically by removing everything before 4th index of - character.,
I think another solution is split('-') first, then join the strings after 4th -.
let test = 'xxxxxx-xxxx-xxxxx-xxxxx-Map-B-844-0'
console.log(test.split('-').slice(4).join('-'))
How can I use regex in javascript to match the phone number and only the phone number in the sample string below? The way I have it written below matches "PHONE=9878906756", I need it to only match "9878906756". I think this should be relatively simple, but I've tried putting negating like characters around "PHONE=" with no luck. I can get the phone number in its own group, but that doesn't help when assigning to the javascript var, which only cares what matches.
REGEX:
/PHONE=([^,]*)/g
DATA:
3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756,
MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802,
GENDER=0, CITY=, LASTNAME=Morgan
The way you're doing it is right, you just have to get the value of the capture group rather than the value of the whole match:
var result = str.match(/PHONE=([^,]*)/); // Or result = /PHONE=([^,]*)/.exec(str);
if (result) {
console.log(result[1]); // "9878906756"
}
In the array you get back from match, the first entry is the whole match, and then there are additional entries for each capture group.
You also don't need the g flag.
Just use dataAfterRegex.substring(6) to take out the first 6 characters (i.e.: the PHONE= part).
Try
var str = "3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756, MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802, GENDER=0, CITY=, LASTNAME=Morgan";
var ph = str.match(/PHONE\=\d+/)[0].slice(-10);
console.log(ph);
I'm trying to split a TitleCase (or camelCase) string into precisely two parts using javascript. I know I can split it into multiple parts by using the lookahead:
"StringToSplit".split(/(?=[A-Z])/);
And it will make an array ['String', 'To', 'Split']
But what I need is to break it into precisely TWO parts, to produce an array like this:
['StringTo', 'Split']
Where the second element is always the last word in the TitleCase, and the first element is everything else that precedes it.
Is this what you are looking for ?
"StringToSplit".split(/(?=[A-Z][a-z]+$)/); // ["StringTo", "Split"]
Improved based on lolol answer :
"StringToSplit".split(/(?=[A-Z][^A-Z]+$)/); // ["StringTo", "Split"]
Use it like this:
s = "StringToSplit";
last = s.replace(/^.*?([A-Z][a-z]+)(?=$)/, '$1'); // Split
first = s.replace(last, ''); // StringTo
tok = [first, last]; // ["StringTo", "Split"]
You could use
(function(){
return [this.slice(0,this.length-1).join(''), this[this.length-1]];
}).call("StringToSplit".split(/(?=[A-Z])/));
//=> ["StringTo", "Split"]
In [other] words:
create the Array using split from a String
join a slice of that Array without the last element of that
Array
add that and the last element to a final Array
This is my setup:
var test =
"http://tv.website.com/video/8086844/randomstring/".match(/^.+tv.website.com\/video\/(.*\d)/);
I want to extract the video id(8086844) and the regex does work, however when another digit is added after the "randomstring", it also matches the 8086844 + randomstring + other number.
What do I have to change in order to always get just the video id.
Try this regex
/^.+tv.website.com\/video\/([\d]+)/
It will search every digit character after ...video\ word and then give all the concordant digits thereafter till any non-digit character comes
The problem is the (.*\d) part, it looks for a greedy string ends with a digit, instead you need a continues series of digits after video/, it can be done via (\d+)
change it to
var test = "http://tv.website.com/video/8086844/randomstring/dd".match(/^.+tv.website.com\/video\/(\d+)/)[1];
var test = "http://tv.website.com/video/8086844/randomstring/8";
test = test.match(/^.+tv.website.com\/video\/(\d+)/);
console.log(test);
console.log(test[1]);
Output
[ 'http://tv.website.com/video/8086844',
'8086844',
index: 0,
input: 'http://tv.website.com/video/8086844/randomstring/8' ]
8086844
You are almost there. We know that, its going to be only numbers. So instead of .*\d we are gathering only the digits and grouping them using parens.
This is the simplest of all:
Use substr here
test.substr(28,7)
Fiddle
To extract out the id from your string test:We use substr(from,to)