finding repeating params in query using regex [closed] - javascript

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I have a search query like
`const query = '?sortBy=recent&page=2&comments=true&sortBy=rating' // two repeating params 'sortBy'
How can I use regex for checking is there any repeating params ????

Not recommended to use regex.
Try this
const query = new URLSearchParams('?sortBy=recent&page=2&comments=true&sortBy=rating');
const keys = [...query.keys()]; // convert iterable to array
console.log(keys)
const unique = keys.length === new Set(keys).size; // return false if dupes found
console.log(unique);
// to get the dupe(s)
const dupes = keys.filter((e, i, a) => a.indexOf(e) !== i)
console.log(dupes)

Related

Ho can i make an array of only those values, that are non-unique in initial array in js? [closed]

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i have this array:
var arr = ["apple","potato","carrot","tomato","grape","banana","potato","carrot","carrot"];
As you can see, we have "potato" 2 times in this array, and also "carrot" 3 times in this array. How can i create a new array, that will content only "potato" and "carrot" values, so only values that are not single/unique in initial array?
Like this:
["potato","carrot"];
How it can be done in js?
Check this one liner:
[...new Set(arr.filter(e => arr.filter(a => a === e).length > 1))];
arr.filter(e ...) - filter array for duplicates
[...new Set(...))] - create array with unique values using set and spread syntax
Working snippet:
var arr = ["apple","potato","carrot","tomato","grape","banana","potato","carrot","carrot"];
console.log([...new Set(arr.filter(e => arr.filter(a => a === e).length > 1))]);

Remove non-numeric items in a listu using regex [closed]

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I am working with an array in Javascript that contains several IDs in them but I would like to filter out all non-numeric entries using regex and return that array of just numbers. For example, I have myArray = ['131125150138677','CI%20UW%20SYSTEMS%20S','040964100010832'] where I want to get rid of the second item in the list since it's non-numeric.
So use Filter and test to see if they are numbers
var myArray = ['131125150138677', 'CI%20UW%20SYSTEMS%20S', '040964100010832']
var filtered = myArray.filter(Number)
console.log(filtered)
var filtered2 = myArray.filter(s => s.match(/^\d+$/))
console.log(filtered2)

Returning query fragments [closed]

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I have an url that looks like this:
https://example.com/?category=123&dk=sports&dk=groupcompanyinsider&dk=local&lang=en
Is it possible to return every dk parameter separately? (no matter if there will be 1 or 5 dk parameters) so i would get separately sports, groupcompanyinsider, local.
If its not possible maybe there is a way to return all of them in one string like dk=sports&dk=groupcompanyinsiderlocal&dk=local ?
You can use the built-in javascript class URLSearchParams for this.
You can then transform this into the string you want with string concatenation and a foreach.
const url = "https://example.com/?category=123&dk=sports&dk=groupcompanyinsider&dk=local&lang=en";
var params = new URLSearchParams(url);
var result = "";
// concatenate individual values of the 'dk' query parameter
params.getAll('dk').forEach(function (item) {
result += '&dk=' + item;
});
result = result.substr(1); // remove starting '&' from the result;
console.log(result);
The result should contain your desired string.

Split arrays into multiple arrays based on string characters [closed]

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My Initial array:
var mainArray = ['car','incl','arc','linc','rca','icnl','meta','tame'];
I want the result like:
[['car','arc','rca'],['linc','icnl','incl'],['meta','tame']];
This is a compact version by using a closure for the sorted character array.
var array = ['car', 'incl', 'arc', 'linc', 'rca', 'icnl', 'meta', 'tame'],
result = Object.values(
array.reduce(
(r, s) => (a => ((r[a] = r[a] || []).push(s), r))([...s].sort()),
{}
)
);
console.log(result);

how to copy previous value in array (string) [closed]

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So how we can make a function that will take arrays of string like const numbers = ['1','2','0','3','0']
and change it for const changedNumbers = ['1','1','2','2','0','3','3','0']
Iterate with Array.map(). If '0' return '0', else return an array with two current string. Flatten by spreading into Array.concat():
const numbers = ['1','2','0','3','0']
const result = [].concat(...numbers.map((s) => +s ? [s, s] : s));
console.log(result);

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