Having issues with Echo PHP/JS [closed] - javascript

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I hava an issue with my PHP/javascript code
I dont understand how to escape code it breaks my brain
echo "<button id='$date' onclick = 'document.getElementById('$date').style.display ='none'';>$date</button>";
anyone have an idea?
Everything after getElementById(' is not interpreted anymore


You have to correct the quotes.
echo "<button id=`$date` onclick = `document.getElementById('$date').style.display ='none'`;>$date</button>";
If button id is from php, you have to correct this too.


This should work
echo "<button id='$date' onclick = \"document.getElementById('$date').style.display ='none'\";>$date</button>";

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I am getting undesired output when i compare the ajax response to a string.
My backend is PHP. It is an echo 'SUCCESS' that responds to the ajax call.
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Let me attach a screenshot of the console watch window for clarity.
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Closed 7 years ago.
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Why is it I got error of unexpected illegal of TOKEN using below code?
var html = '<div id="wrap">\
<img style="width:100%;display:block">\
<div>\'
console.log(html);
I use \ to escape, it should work fine..

Here is the problem:
<div>\'
You are escaping the closing quote.

Try this
var html = '<div id="thermal-close-sales-wrap">\
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console.log(html);

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Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
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I have ajax form as on modal window. I want to validate the fields and i have followed the following tutorial. and Add the validator.js script into my project.
event.preventDefault();
//$('#myOrderDetailsForm').validator();
$('#myOrderDetailsForm').validator('validate')();
Here is what am seeing :
So wired .

Instead of this:
$('#myOrderDetailsForm').validator('validate')();
Use following:
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Closed 8 years ago.
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I wanted to return following string, but I still couldn't get it done right for couple of hours. CAn anyone tell me what did I do wrong? Thank you.
<?php
return 'rs...#gmail.com.com';
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You have single quotes in the JavaScript code in your onclick attribute. You need to escape these by placing a backslash before each single quote.

Is there anything wrong in this Javascript line? [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 8 years ago.
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my code is not working after adding style property, here it is:
$("#instaUser").append("<figure style='"display:inline "'><img id='"+i+"' src='"+data.data[i].profile_picture+"' alt='pic number "+i+"' height='"+200+"' width='"+200+"'> <figcaption>#"+data.data[i].username+"</figcaption></figure>");
could it be that i used the " in a wrong way?

You don't need double quotes wrapping display: inline
This is correct:
$("#instaUser").append("<figure style='display:inline'><img id='"+i+"' src='"+data.data[i].profile_picture+"' alt='pic number "+i+"' height='"+200+"' width='"+200+"'> <figcaption>#"+data.data[i].username+"</figcaption></figure>");

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