I want an image to change when it is hovered on. So far my code is fine. But I want the image to change back to its original image when mouse leaves the image. This is where my code doesn't work properly. What is the problem and how can I fix it? I really appreciate your help.
This is my html code:
<div onmouseover="show_large(this);" onmouseout="show_normal(this);">
<img src="2.JPG">
</div>
<script>
function show_large(element){
element.innerHTML=
'<img src="1.JPG">';
}
function show_normal(element){
element.innerHTML=
'<img src="2.JPG">';
}
</script>
And this is my css code:
div{
width: 25%;
margin: 0;
}
img{
width: 100%;
margin: 0;
}
You can achive this only with CSS and HTML, just add background-image property on your div and change img on :hover, like so:
div{
background-image: url('first-img-src.png');
transition: background-image 1s ease-in-out;
}
div:hover{
background-image: url('second-img-src.png');
}
EDIT:
You can achive same thing using mouseenter and mouseleave with changeing img.src property:
const img = document.querySelector('img');
img.addEventListener('mouseenter', (e) => {
img.src = 'second.png'
})
img.addEventListener('mouseleave', (e) => {
img.src = 'first.png'
})
Since images will have default hover events, you need to disable them for it to work on the parent div. You can disable them by adding pointer-events: none to img tag
function show_large(element) {
element.innerHTML =
'<img src="https://randomuser.me/api/portraits/men/51.jpg">';
}
function show_normal(element) {
element.innerHTML =
'<img src="https://randomuser.me/api/portraits/men/50.jpg">';
}
div {
width: 25%;
margin: 0;
}
img {
width: 100%;
margin: 0;
pointer-events: none;
}
<div onmouseover="show_large(this);" onmouseout="show_normal(this);">
<img src="https://randomuser.me/api/portraits/men/50.jpg">
</div>
You can simply do it using css it self. working jsFiddle
.image-container{
width: 300px;
}
.over{
display: none;
}
.image-container:hover .main{
display: none;
}
.image-container:hover .over{
display: block;
}
<div class="image-container">
<img class="main" src="https://www.rd.com/wp-content/uploads/2019/04/shutterstock_1013848126.jpg" width="100%" />
<img class="over" src="https://www.rd.com/wp-content/uploads/2019/05/shutterstock_671541538-e1557714950453.jpg" width="100%" />
</div>
Related
I am trying to achieve the mouse effect on carousel (https://advertising.nytimes.com/custom-content/). the cursor should change when I hover over the container. I got it working but it is stutters a lot. How to make it smooth? the stutter occurs when I add the conditional statement. Please help.
<style>
.img {
width: 100px;
height: 100px;
object-fit: cover;
position: fixed;
top: 0;
left: 0;
}
.container {
width: 700px;
height: 900px;
background-color: orangered;
overflow: hidden;
cursor: none;
}
</style>
<div class="container">
<img
class="img"
src="https://images.unsplash.com/photo-1472457897821-70d3819a0e24?ixlib=rb-4.0.3&ixid=MnwxMjA3fDB8MHxwaG90by1wYWdlfHx8fGVufDB8fHx8&auto=format&fit=crop&w=2669&q=80"
/>
</div>
<script>
const container = document.querySelector(".container");
const img = container.querySelector(".img");
document.addEventListener("mousemove", (e) => {
if (event.target == container) {
img.style.transform = `translate3d(${e.clientX}px, ${e.clientY}px, 0)`;
}
});
</script>
It is as simple as adding a Logical OR next to the event.target == container. It was moving weirdly because when your mouse would go over the image it would not be the target anymore.
To fix this we need to add an ID to the image so we can source it in our event.target. So out <img> would look something like this
<img class="img" id"img" src="https://images.unsplash.com/photo-147245789782170d3819a0e24ixlib=rb4.0.3&ixid=MnwxMjA3fDB8MHxwaG90by1wYWdlfHx8fGVufDB8fHx8&auto=format&fit=crop&w=2669&q=80"/>
After we set the id we are able to add the logical OR statement, it would look like this
event.target == container || picture
Hope I could help!
I just want to use some css to make the height of a div 0 which also makes all the heights of the sub divs 0. I then want to call a javascript function which when clicked it makes the height of the main div 100%.
Here is the code that I have written:
HTML
<div class="menuTitle" id="ButtonsTopStyle" onclick="ButtonsTop">CONNECTING RODS</div>
<div class="buttonsTop" >
<img src="Images/ButtonA.gif" alt="ImageA" class="smallButtons" />
<img src="Images/ButtonA.gif" alt="ImageA" class="smallButtons" />
<img src="Images/ButtonA.gif" alt="ImageA" class="smallButtons" />
</div>
<div class="menuTitle" id="ButtonsBottomStyle" onclick="ButtonsBottom">CRANKSHAFTS</div>
<div class="buttonsBottom">
<img src="Images/ButtonA.gif" alt="ImageA" class="smallButtons" />
<img src="Images/ButtonA.gif" alt="ImageA" class="smallButtons" />
<img src="Images/ButtonA.gif" alt="ImageA" class="smallButtons" />
</div>
CSS
.smallButtons {
box-sizing: border-box;
margin-left: 10px;
height: 50px;
width: 50px;
margin-top: 15px;
background-color: white;
}
.menuTitle {
color: white;
font-family: "Arial";
text-align: center;
font-size: 30px;
padding-bottom: 30px;
padding-top: 30px;
}
.buttonsTop {
margin-left: 23px;
}
.buttonsBottom {
height: 0;
margin-left: 23px;
}
The css I have written doesnt make the height of the .buttonBottom zero they are still being displayed on the page. I don't want them to be displayed on the page
JAVASCRIPT
function ButtonsBottom() {
document.getElementById("ButtonsTopStyle").style.height = "0";
document.getElementById("ButtonsBottomStyle").style.height = "100%";
}
function ButtonsTop() {
document.getElementById("ButtonsBottomStyle").style.height = "0";
document.getElementById("ButtonsTopStyle").style.height = "100%";
}
As you can see I want the buttonsBottom to not be visible on the page when it loads but when you click on the onclick="ButtonBottom" div it makes the height 100% and makes the onclick="ButtonsTop" div have a height of 0
Add an
overflow:hidden;
to your .buttonsBottom div
Your div is expanding in height to accommodate your content.
What I'd suggest is adding an additional class of
.hidden {
height: 0;
overflow: hidden;
}
to your CSS and then modifying your JavaScript to add/remove this class as needed.
The other option would be to use display: none; and display: block; instead of height. Which would be my preferred method as long as you aren't aiming for a transition effect on height when clicked.
try this :
function ButtonsBottom() {
document.getElementById("ButtonsTopStyle").style.height = "0";
document.getElementById("ButtonsBottomStyle").style.height = "0%";
}
function ButtonsTop() {
document.getElementById("ButtonsBottomStyle").style.height = "0";
document.getElementById("ButtonsTopStyle").style.height = "0%";
}
I'm pretty sure there is already an example for this but I couldn't find one, and I don't know exactly what to search for.
http://imgur.com/a/hHNkZ
I am trying to make a resizable div from the button circled in red above.
The photo behind this div comes from a slick slider ( http://kenwheeler.github.io/slick/ ).
<div class="slider-for">
<img src="images/product0.jpg" alt="">
<img src="images/product1.jpg" alt="">
<img src="images/product2.jpg" alt="">
<img src="images/product3.jpg" alt="">
</div>
I was thinking of making a width 0 div above, and then with the slider, increase its width with js maybe.
In this div, I want to put a recipe for that certain product. I have 4 photos, so the content has to change depending on picture. ( so it's not static content).
Does this need to be made in php?
I think this would be helpful to you:
https://jsfiddle.net/u0Ljnttg/1/
Its little bit complicated, but still good enough. :)
Just for sake of SO:
JS:
var links = document.getElementById("imageLinks");
links.onmousedown = function(e) {
var theSrc = e.target.dataset.src;
if (theSrc) {
str = "url(\"" + theSrc + "\");";
//Sorry for using this:
document.getElementById("imageBack").setAttribute("style", "background-image:" + str)
}
}
var resizer = document.getElementById("content-resize");
resizer.onmousedown = resizableStart;
function resizableStart(e) {
var elem = document.getElementById("content");
elem.originalW = elem.clientWidth;
this.onmousemove = resizableCheck;
this.onmouseup = this.onmouseout = resizableEnd;
}
function resizableCheck(e) {
var elem = document.getElementById("content");
if (elem.clientWidth === elem.originalW) {
elem.originalX = e.clientX;
this.onmousemove = resizableMove;
}
}
function resizableMove(e) {
var elem = document.getElementById("content");
var newW = elem.originalW - e.clientX + elem.originalX;
if (newW < elem.originalW) {
elem.style.width = newW + 'px';
}
}
function resizableEnd() {
this.onmousemove = this.onmouseout = this.onmouseup = null;
}
HTML:
<div class='container'>
<div class='images' id="imageBack" style="background-image: url('http://data.whicdn.com/images/20948152/large.png')">
<div class='content' id="content">
<div id="imageLinks">
<a href="#" data-src='http://ichef.bbci.co.uk/news/660/cpsprodpb/1325A/production/_88762487_junk_food.jpg'>1</a>
<a href="#" data-src='http://i.imgur.com/NhDejjN.jpg'>2</a>
<a href="#" data-src='https://s-media-cache-ak0.pinimg.com/564x/80/40/9d/80409d8c06d21e0c0416a40c2176def3.jpg'>3</a>
<a href="#" data-src='http://data.whicdn.com/images/20948152/large.png'>4</a>
</div>
<span id="content-resize"></span>
</div>
</div>
</div>
CSS:
html,
body {
min-height: 100% !important;
height: 100%;
}
.container {
width: 100%;
min-height: 100%;
height: 100%;
}
.images {
width: 100%;
min-height: 100% !important;
height: 100%;
}
#content {
min-height: 100% !important;
height: 100%;
/*Change this to change width*/
width: 70%;
resize: horizontal;
float: right;
position: relative;
background: white;
}
div {
border: 1px solid black;
}
span {
border: 1px solid black;
border-radius: 50%;
position: absolute;
top: calc(50% - 20px);
left: -10px;
cursor: pointer;
height: 40px;
width: 40px;
display: inline-block;
background: white;
}
I am not sure if you already solved this issue, but since you helped me on the other question, I am interested in helping you with this.
You have some options.
Use pure JavaScript. You can use a lib (eg: this) for that.
Use Jquery $().draggable() propriety. This might help for styling the button..
Using pure HTML & CSS resize. This is not good, since you cannot apply any style to the <div>.
You can make a workaround mixing three <div> elements,
One of them with position: fixed. This is your background.
Another for the container (with a width set manually to hide the page from user). Remove the scrollbar and force the width of your html, body to match your screen.
Another <div> inside the container for your content. This should be able to move horizontally to show and hide the elements.
I have a scrolling image gallery as follows. The CSS lays out the images in a row that scrolls horizontally. Underneath, I have a row of the same images, but as thumbnails. I want to be able to click on a thumbnail, and scroll the correct image into view.
HTML:
<div class="images_container">
<img id="image_1" src="/image1.jpg">
<img id="image_2" src="/image2.jpg">
<img id="image_3" src="/image3.jpg">
</div>
<div class="images_container thumbnails">
<img src="/image1.jpg" class="thumbnail">
<img src="/image2.jpg" class="thumbnail">
<img src="/image3.jpg" class="thumbnail">
</div>
CSS:
.images_container {
overflow-x: scroll;
overflow-y: hidden;
max-height: 50rem;
white-space: nowrap;
}
.images_container.thumbnails {
max-height: 10rem;
}
.images_container img {
vertical-align: top;
height: 50rem;
}
.images_container.thumbnails img {
height: 10rem;
}
This works up to a point, but jumping to the id of the image is problematic. If the larger image is even a few pixels into the visible viewport, it can't 'jump' to it, as it seems to be technically on the screen.
Is there a way I can use Javascript to 'scroll' the whole image into view when I click on it's corresponding thumbnail? I don't have access to jQuery on this project, but am happy to use JavaScript to make this work.
You can try this , no change in CSS, i add an id in html and call to scrollTo function :
<script>
function scrollTo(image_id){
var topLeft = document.getElementById(image_id).offsetTop;
document.getElementById('container').scrollLeft = topLeft;
}
</script>
<div id="container" class="images_container">
<img id="image_1" src="/image1.jpg" height="500px" width="500px">
<img id="image_2" src="/image2.jpg" height="500px" width="500px">
<img id="image_3" src="/image3.jpg" height="500px" width="500px">
</div>
<div class="images_container thumbnails">
<img src="/image1.jpg" class="thumbnail" onclick="scrollIntoView('image_1')">
<img src="/image2.jpg" class="thumbnail" onclick="scrollIntoView('image_2')">
<img src="/image3.jpg" class="thumbnail" onclick="scrollIntoView('image_3')">
</div>
To keep DOM cleaner I got this solution which requires only adding js
var elms = document.getElementsByClassName("thumbnail");
for (var i = 0; i < elms.length; i++) {
elms[i].onclick = function(event) {
event.preventDefault();
event.stopPropagation();
var id = this.parentNode.href.substr(this.parentNode.href.lastIndexOf('/') + 2);
var v = document.getElementById(id).getBoundingClientRect().left;
document.getElementsByClassName("images_container")[0].scrollLeft += v;
}
}
See on jsfiddle
Here's my attempt at a no (well, minimal) JS solution to a scrolling gallery. You could, in fact, remove the Javascript all together if you replaced the .active class with the :target pseudo-selector, allowing you to click your thumbnails to do the scrolling. It's just easier for me to do it this way through a fiddle
function removeClass(element, className) {
var classes = element.className.split(' ');
var key = classes.findIndex(function(name) {
return name == className
});
classes.splice(key, 1);
element.className = classes.join(' ');
}
function addClass(element, className) {
var classes = element.className.split(' ');
classes.push(className);
element.className = classes.join(' ');
}
setInterval(function() {
var current = document.querySelector('.images .image.active');
var next = current.nextElementSibling;
if (!next) {
next = document.querySelector('.images .image:first-child');
}
removeClass(current, 'active');
addClass(next, 'active');
}, 1500);
body {
margin: 0;
padding: 0;
width: 500px;
height: 500px;
}
.images {
width: 100%;
height: 100%;
position: relative;
overflow-x: hidden;
}
.image {
width: 100%;
height: 100%;
top: 0px;
position: absolute;
left: -100%;
float: left;
transition: 1s;
}
.image.active {
left: 0%;
}
.image.active ~ .image {
left: 100%;
}
.black {
background-color: black;
}
.red {
background-color: red;
}
.blue {
background-color: blue;
}
.yellow {
background-color: yellow;
}
<div class='images'>
<div class='image black active'></div>
<div class='image red'></div>
<div class='image blue'></div>
<div class='image yellow'></div>
</div>
Essentially the way it works is by making the div.images container a certain height and width, and therefore all images inside it can be positioned as you want. We initially set all .image to left: -100%, so that they're completely off screen to the left. We then set .image.active as left: 0 so that it's on screen. We then use the ~ selector to say that all siblings that come after the current (.image.current ~ .image) should be left: 100%, so completely to the right. Add in a transition, and you have a completely CSS scrolling gallery. The JS only acts as a way to change what the current active image is, and you can replace that with :target if you want.
I used div's, instead of img tags because it's easier to provide a POC with div's and background colors, but it's worked well with images in the past. Just put an <img> tag inside those <div class='image'></div> tags
I've this code:
<div class='mini'>
<div id='wrap_jcrop' class='td_wrap'>
<img id='img2crop' src=''>
</div>
</div>
With this CSS:
div.mini {
width: 300px;
height: 200px;
display: table;
}
div.td_wrap {
display: table-cell;
vertical-align: middle;
text-align: center;
}
The image source for img2crop is loaded dynamically and handled with a Jcrop api. But Jcrop aligns the image on the left.
How can I align the image in the center of the div?
Rather than modify the jcrop css file (not recommended, as per the plugin author) you can add a class to the jcrop-holder element as an option when you initialise Jcrop:
jQuery(function($) {
$('#jcrop_target').Jcrop({
addClass: 'jcrop-centered'
});
});
Add a wrapper around the img tag in your HTML, e.g.
<div class="crop-image-wrapper">
<img id="jcrop_target" src="...." alt="" />
</div>
Then add a css style, e.g.
.jcrop-centered
{
display: inline-block;
}
.crop-image-wrapper
{
text-align: center;
}
Tested in Chrome 31.0.1650.63 m - let me know if it doesn't work in other browsers? (except < IE8) :-)
Set
.jcrop-holder
{
margin: 0 auto;
}
Try margin: 0 auto;, position: relative;, float: left;.
The only thing that worked for me:
JS:
$("#img2crop").attr("src", resp).load(function(){
$("#wrap_jcrop").width(this.width);
$("#wrap_jcrop").height(this.height);
$("#wrap_jcrop").css("position", "absolute");
$("#wrap_jcrop").css("top", ($("#wrap_jcrop").parent().height() - $(this).height())/2 + "px");
$("#wrap_jcrop").css("left", ($("#wrap_jcrop").parent().width() - $(this).width())/2 + "px");
$('#img2crop').Jcrop();
});
CSS:
.mini {
position: relative;
}