Develop Reference

How to prevent showing image alt text if image is loaded using css

I am loading an image through css background property , instead of using src attribute. But in that case the alt text is also showing up. How can I stop showing alt text & show it only if image is not loaded
.test {
display: block;
width: 200px;
height: 82px;
background-size: 200px 82px;
background-image: url("https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcQJr81CRJeZGFiBsA9_AOyyxegiIPctdcbNfHThnpnclmFH-mJwoQ");
}
<img class="test" alt="My background image">

You can do a little trick and hide the "text" inside the image if the image has no src attribute (or its empty).
(You can hide the text in many ways I choose one)
.test {
display: block;
width: 200px;
height: 82px;
background-size: 200px 82px;
background-image: url("https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcQJr81CRJeZGFiBsA9_AOyyxegiIPctdcbNfHThnpnclmFH-mJwoQ");
}
img:not([src]) {
font-size: 0;
position: relative;
}
img:not([src]):after {
font-size: 18px;
border: 1px solid black;
box-sizing: border-box;
content: attr(alt);
z-index: -1;
height: 100%;
width: 100%;
position: absolute;
top: 0;
left: 0
}
<img class="test" alt="My background image">
The completion for the css (the :after part) received from #Ihazkode.
For displaying the alt after the image loading you can load (with javascript) the image first, then, put it in the image and display the alt. (Based on this answer)
$('[data-image]').each(function() {
var $this = $(this);
var alt = $this.attr('alt');
var src = $(this).attr('data-image');
$this.removeAttr('alt');
$('<img/>').attr('src', src).on('load', function() {
$(this).remove();
// simulate the delay for heavy image
setTimeout(function(){
$this.css('background', 'url(' + src + ')').attr('alt', alt);
}, 1000);
}).on('error', function() {
$this.attr('alt', alt);
});
});
.test {
display: block;
width: 200px;
height: 82px;
background-size: 200px 82px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<img class="test" alt="My background image" data-image="https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcQJr81CRJeZGFiBsA9_AOyyxegiIPctdcbNfHThnpnclmFH-mJwoQ">

First of all I need to know, is there any purpose of setting background image to <img> tag?
If yes, there is no point to use <img> tag here user <div> or any other tags instead of using <img>.
As per the W3C standard tag should contain alt="some text", if <img> source not found.

Image over image with jQuery?

So, I want to put image over image. The second to be in up corner.
I want to do that with jQuery.
$("#result").on({
mouseenter:function(){
$("#article").attr("src", "button2.png");
}, ".button");
});
I want when someone hovers to article to show image for SHOW MORE

Like everyone else is saying, you can do it with just CSS. The easiest way to do it I think is to have one image as a background and then just having another image on top:
See JSFiddle
HTML:
<div class="image1">
<img src="http://icdn4.digitaltrends.com/image/microsoft_xp_bliss_desktop_image-650x0.jpg" class="image2"/>
</div>
CSS:
.image1 {
width: 650px;
height: 433px;
background: url("http://icdn4.digitaltrends.com/image/microsoft_xp_bliss_desktop_image-650x0.jpg");
}
.image1:hover .image2 {
display: block;
}
.image2 {
display: none;
width: 100px;
height: 80px;
}
==== ALTERNATE SOLUTION ====
If you have to do it with img tags you can use the following:
See JSFiddle
HTML:
<img src="http://icdn4.digitaltrends.com/image/microsoft_xp_bliss_desktop_image-650x0.jpg" class="image1"/>
<img src="http://icdn4.digitaltrends.com/image/microsoft_xp_bliss_desktop_image-650x0.jpg" class="image2"/>
CSS:
.image1 {
position: absolute;
}
.image1:hover + .image2 {
display: block;
}
.image2 {
display: none;
width: 100px;
height: 80px;
position: absolute;
z-index: 100;
}

How to center an image created in Javascript?

I have this very simple code, the problem is it doesn't give the same output using Firefox and IE: in Firefox, the images are superposed but right-aligned, and in IE they are superposed and left aligned.
What I want is that the images will be centered and superposed.
I have to create images using Javascript to use a special library in creating the images.
Thank you for your help.
HTML
<body>
<div id="Container">
<script type="text/javascript">
document.write('<img id="image1" src="image1.jpg">')
document.write('<img id="image1" src="image2.jpg">')
</script>
</div>
</body>
CSS
body {
text-align: center;
background-color: #e8e6e7;
margin-left: auto;
margin-right: auto;
}
#Container {
position: relative;
text-align: center;
margin-left: auto;
margin-right: auto;
}
#image1 {
position : absolute;
margin-left: auto;
margin-right: auto;
}
#image2 {
position : absolute;
margin-left: auto;
margin-right: auto;
}

Since you are making #image1 and #image2 be absolutely positionined, they will not adjust the width/height of the #Container. This means you can't center it, because it doesn't have the proportions to center.
The code below makes only one image be absolutely positioned. This lets your other image act as expected. You can do whatever you want with the "overlay" image.
I also included z-index, which can let you change the order of the images. This isn't necessary for this example, but if you add more images, it may be useful.
HTML
<div id="Container">
<div class="image-wrap">
<img id="image1" src="http://dummyimage.com/200x200/fa00fa/fff.png"/>
<img id="image2" src="http://dummyimage.com/200x200/00ff33/000000.png"/>
</div>
</div>
CSS
#Container .image-wrap {
position: relative;
display: inline-block;
}
#image1 {
position : relative;
z-index: 10;
}
#image2 {
position : absolute; /* Different than #image1 */
z-index: 20; /* On top of #image2 */
top: 0;
left: 0;
/* Assuming width/height of both images are the same */
}
JS Fiddle
http://jsfiddle.net/n496j/1/

First change second image id to image2.
2 tricks for centering your images is:
add one of these classes to your images:
.center {
display: block; /*can remove this line*/
margin: 0 auto;
left: 0;
right: 0;
}
.center {
left: 50%;
margin-left: -[your image width / 2]
}

Use the css
img{ display:block; margin: auto; }

well, it will help if the images would sit in some container with text-align:center;.
something like this:
// body can be be replaced with any element which contains the images
body{ text-align:center; }
body > img{ display:inline-block; max-width:49%; }
Demo page:
http://jsbin.com/hehot/1/edit

Make image fill div completely without stretching

I have large images of varying dimensions that need to completely fill 240px by 300px containers in both dimensions. Here is what I got right now, which only works for one dimension:
http://jsfiddle.net/HsE6H/
HTML
<div class="container">
<img src="http://placehold.it/300x1500">
</div>
<div class="container">
<img src="http://placehold.it/1500x300">
</div
CSS
.container {
height: 300px;
width: 240px;
background-color: red;
float: left;
overflow: hidden;
margin: 20px;
}
img {
max-width: 100%;
height: auto;
}
The proportions should stay the same. Essentially, wide images should be cut off in width, while high images need to be cut off in height. So just zooming in as much as is needed to fill the container.
Not sure why I can't get it to work, do I need JavaScript for this?
Edit: To be clear. I need everything red on the fiddle gone. The images coming in are dynamic, therefore I can't use background-images. I'm open to using JavaScript. Thanks! :)

Auto-sizing Images to Fit a Div - Making the CSS Work
Here is one way of doing it, start with the following HTML:
<div class="container portrait">
<h4>Portrait Style</h4>
<img src="http://placekitten.com/150/300">
</div>
and the CSS:
.container {
height: 300px;
width: 240px;
background-color: red;
float: left;
overflow: hidden;
margin: 20px;
}
.container img {
display: block;
}
.portrait img {
width: 100%;
}
.landscape img {
height: 100%;
}
and the demo fiddle: http://jsfiddle.net/audetwebdesign/QEpJH/
When you have an image oriented as a portrait, you need to scale the width to 100%. Conversely, when the image is landscape oriented, you need to scale the height.
Unfortunately, there is no combination of selectors in CSS that targets the aspect ratio of the image, so you can't use CSS to pick out the correct scaling.
In addition, you have no easy way of centering the image since the top left corner of the image is pinned to the top left corner of the containing block.
jQuery Helper
You can use the following jQuery action to determine which class to set based
on the aspect ratio of the image.
$(".container").each(function(){
// Uncomment the following if you need to make this dynamic
//var refH = $(this).height();
//var refW = $(this).width();
//var refRatio = refW/refH;
// Hard coded value...
var refRatio = 240/300;
var imgH = $(this).children("img").height();
var imgW = $(this).children("img").width();
if ( (imgW/imgH) < refRatio ) {
$(this).addClass("portrait");
} else {
$(this).addClass("landscape");
}
})
For each image in .container, get the height and width, test if width<height and then set the appropriate class.
Also, I added a check to take into account the aspect ratio of the containing block.
Before, I had implicitly assumed a square view panel.

For anyone looking to do this that doesn't have dynamic images, here's an all-CSS solution using background-image.
<div class="container"
style="background-image: url('http://placehold.it/300x1500');
background-size: cover; background-position: center;">
</div>
<div class="container"
style="background-image: url('http://placehold.it/1500x300');
background-size: cover; background-position: center;">
</div>
The "background-size: cover" makes it so that the image scales to cover all of the div while maintaining the aspect ratio. The CSS could also be moved to a CSS file. Although if it's dynamically generated, the background-image property will have to stay in the style attribute.

Taking out the line: max-width:100% in your CSS file seems to do the trick.
.container {
height: 300px;
width: 240px;
background-color: red;
float: left;
overflow: hidden;
margin: 20px;
}
img {
height: auto;
}
Also you can add > to your closing div in your HTML file could make the code neater.
<div class="container">
<img src="http://placehold.it/300x1500">
</div>
<div class="container">
<img src="http://placehold.it/1500x300">
</div>
Here is a working JSFiddle link: http://jsfiddle.net/HsE6H/19/

Here is another solution I found, that no need to seperate portraid or landscape or scripting.
<div class="container">
<img src="http://placehold.it/500x500" class="pic" />
</div>
CSS
.container{
position: relative;
width: 500px;
height: 300px;
margin-top: 30px;
background: #4477bb;
}
.pic{
max-width: 100%;
width: auto;
max-height: 100%;
position: absolute;
left: 0;
right: 0;
top: 0;
bottom: 0;
margin: auto;
}
Here it is, it works well...
https://jsfiddle.net/efirat/17bopn2q/2/

Background can do this
set image as background
2.
div {
-webkit-background-size: auto 100%;
-moz-background-size: auto 100%;
-o-background-size: auto 100%;
background-size: auto 100%;
}
or
div {
-webkit-background-size: cover;
-moz-background-size: cover;
-o-background-size: cover;
background-size: cover;
}

You should try this:
img {
min-width:100%;
min-height:100%;
}

I used this plugin that accounts for any ratio. It also requires imagesloaded plugin to work. This would be useful for numerous images across a site needing this treatment. Simple to initiate too.
https://github.com/johnpolacek/imagefill.js/

It works if you add the following to the parent div for img styling;
https://jsfiddle.net/yrrncees/10/
.container img {
position: relative;
vertical-align: middle;
top: 50%;
-webkit-transform: translateY(-50%);
min-height: 100%;
min-width: 100%;
object-fit:cover;
}

This could do the job:
.container {
float: left;
height: 300px;
width: 240px;
background-color: red;
margin: 20px;
}
img {
width:240px;
height:300px;
}

We went down the path with an Angular app of using a variation on the jQuery approach above. Then one of our bright colleagues came up with a pure CSS approach. See this example here: https://jsfiddle.net/jeffturner/yrrncees/1/.
Basically using line-height solved the problem for us. For those not wanting to hit the fiddle, the code fragments are:
.container {
margin: 10px;
width: 125px;
height: 125px;
line-height: 115px;
text-align: center;
border: 1px solid red;
}
.resize_fit_center {
max-width:100%;
max-height:100%;
vertical-align: middle;
}
The key is in using line-height and setting the container to do the same.

I came across this topic because I was trying to solve a similar problem. Then a lightbulb went off in my head and I couldn't believe it worked because it was so simple and so obvious.
CSS
.container {
height: 300px;
width: 240px;
background-color: red;
float: left;
overflow: hidden;
margin: 20px;
}
img {
min-width:100%;
min-height:100%;
}
Just set the min-width and min-height to 100% and it will always automatically resize to fit the div, cutting off the excess image. No muss no fuss.

Using an image as Div background has many disadvantages (like missing ALT for SEO). Instead of it, use object-fit: cover; in the image tag style!

The following solution is very short and clean if you need to insert img tag into div tag:
.container, .container img
{
max-height: 300px;
max-width: 240px;
}
Try to open every image into another page you will notice that originals are all different sized but none is streched, just zoomed:
<p></p>
<div class="container"><img src="https://www.gentoo.org/assets/img/screenshots/surface.png" /></div>
<p></p>
<div class="container"><img src="https://cdn.pixabay.com/photo/2011/03/22/22/25/winter-5701_960_720.jpg" /></div>
<p></p>
<div class="container"><img src="https://cdn.arstechnica.net/wp-content/uploads/2009/11/Screenshot-gnome-shell-overview.png" /></div>
<p></p>
<div class="container"><img src="http://i.imgur.com/OwFSTIw.png" /></div>
<p></p>
<div class="container"><img src="https://www.gentoo.org/assets/img/screenshots/surface.png" /></div>
<p></p>
<div class="container"><img src="https://freebsd.kde.org/img/screenshots/uk_maximignatenko_kde420-1.png" /></div>
<p></p>
<div class="container"><img src="https://i.ytimg.com/vi/9mrOgkYje0s/maxresdefault.jpg" /></div>
<p></p>
<div class="container"><img src="https://upload.wikimedia.org/wikipedia/commons/5/59/Linux_screenshot.jpg" /></div>
<p></p>
Also, if you don't need to use a div you can just write an even shorter css:
img
{
max-height: 300px;
max-width: 240px;
}

How do I make one element change by hovering over another?

I'm trying to do what many have asked before, but even after trying everything I still can't get the results I want.
I have an image 600px by 1600px, 4 images of 600px by 400px in a vertical line. I want to show 600px by 400px of the image at any one time. Ideally I would be able to hover over an element somewhere on my page and move the image upwards to reveal the other portions of the 600px by 400px image. In effect, I'd have 4 images viewable by hovering over 4 the elements.
I've tried various css3 and jquery solution but none have worked. I would appreciate any help with this.
HTML
<div class="mainimage">
<div class="buttonsection">
<div class="button1">Button 1</div>
<div class="button2">Button 2</div>
<div class="button3">Button 3</div>
<div class="button4">Button 4</div>
</div><!--end of buttonsection-->
<div class="rollingimage">
<img src="IMG/four-pics.png">
</div><!--end of rollingimage-->
</div><!--end of mainimage-->
</div><!--end of main content-->
CSS
.mainimage {
position: relative;
top: 0px;
left: 0px;
width: 900px;
height: 400px;
border: 2px solid #E78F25;
margin: 0 10px 20px 0;
}
.buttonsection {
width: 290px;
height: 400px;
position: relative;
float: left;
}
.button1,
.button2,
.button3,
.button4 {
display: inline;
height: 98px;
width: 290px;
border: 1px solid #E78F24;
text-align: center;
float: left;
}
.rollingimage {
width: 598px;
height: 400px;
position: relative;
overflow: hidden;
top: 0px;
left: 0px;
float: right;
}
jquery
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage').stop().animate({'top': '-200px'}, 1500);
});
});
Here is the jsfidle: http://jsfiddle.net/dirtyd77/jCvYm/1/
Thanks yet again
Gary

Just for fun, no JS:
http://jsfiddle.net/coma/MTWdb/5/
HTML
<div id="foo">
Button 1
Button 2
Button 3
Button 4
<div></div>
</div>
CSS
#foo {
width: 400px;
border: 2px solid #E78F25;
position: relative;
}
#foo > div {
position: absolute;
top: 0;
right: 0;
bottom: 0;
width: 200px;
background: #fff url(http://placekitten.com/600/1600) no-repeat 0 0;
transition: background-position .5s;
}
#foo > a {
display: block;
width: 200px;
line-height: 100px;
text-align: center;
text-decoration: none;
}
#foo > a + a {
border-top: 1px solid #E78F25;
}
#foo > a:nth-child(1):hover ~ div {
background-position: 0 0;
}
#foo > a:nth-child(2):hover ~ div {
background-position: 0 -400px;
}
#foo > a:nth-child(3):hover ~ div {
background-position: 0 -800px;
}
#foo > a:nth-child(4):hover ~ div {
background-position: 0 -1200px;
}

You need to change the positioning of the image inside the div, not the div itself. To animate my example, you could add CSS transitions for better performance than JS animations.
http://jsfiddle.net/jCvYm/8/
$('.rollingimage').find('img')

As Dom mentioned, the jsFiddle you provided didn't reference the jQuery library. It also didn't included any actual images, and only contained code for one of the three buttons. I doubt those were the original problems you were having, though. (The missing reference to jQuery might have been.)
Once I had those straightened out, I noticed that hovering the button caused the picture to slide out of the screen, instead of scrolling. The simplest way to fix that is to move the img element, instead of moving the div. (The more natural way would be to change the scroll position of the div, but I don't recall how to do that off the top of my head.)
Added CSS:
.rollingimage img {
position: relative;
}
New JS:
$(document).ready(function(){
$(".button1").hover(function(){
$('.rollingimage img').stop().animate({'top': '0px'}, 1500);
});
$(".button2").hover(function(){
$('.rollingimage img').stop().animate({'top': '-400px'}, 1500);
});
$(".button3").hover(function(){
$('.rollingimage img').stop().animate({'top': '-800px'}, 1500);
});
$(".button4").hover(function(){
$('.rollingimage img').stop().animate({'top': '-1200px'}, 1500);
});
});
jsFiddle: http://jsfiddle.net/jCvYm/6/