I have a base class which looks like the following.
class BaseClass {
.....
.....
async request(options) {
.......
.......
}
}
This is extended by another class like this.
const BaseClass = require('#myorg/base-class').BaseClass;
class MyClass extends BaseClass {
async method1() {
.............
request()
.............
}
async method2() {
.............
request()
.............
}
}
Now I am using jest to test MyClass and it's 2 methods and to mock the BaseClass and trying to send a mocked response for it's request method. Since I need to test both method1 and method2, I need to change the mock return after the first one. I am doing like this.
describe('MyClass', () => {
afterEach(() => {
jest.clearAllMocks();
jest.resetAllMocks();
});
let MockClass = class BaseClass {
request() {
return {
statusCode: 200,
body: JSON.stringify({
first_response: 'first_response'
})
};
}
};
const mock = jest.mock('#myorg/base-class', () => {
return {
BaseClass: MockClass
};
});
it('#method1 - test method one', async () => {
const myClass = require('../src').myClass;
const res = await myClass.method1();
expect(res).toEqual('first_response');
});
it('#method2 - test method 2', async () => {
mock.clearAllMocks();
mock.resetAllMocks();
MockClass = class BaseClass {
request() {
return {
statusCode: 200,
body: JSON.stringify({
random_response: 'random_response'
})
};
}
};
const myClass = require('../src').myClass;
const res = await myClass.method2();
expect(JSON.parse(res.body)).toEqual({
random_response: 'random_response'
});
expect(res.statusCode).toEqual(200);
});
});
The problem is once the mock is initialized, I am not able to reset and assign a different value as in the second test. How can I achieve that ?
I had a similar problem a year ago. I had 2 tests calling the same mocked method, but I wished to have 2 differents output.
Jest didn't provide any decent way to modify a mock once it is created, and I assume they didn't change that. (Can't link any source, sorry, it is a while ago).
I had the opportunity to discuss with some experimented and talented programmers, and the work-around was to make the tests in two different files, with 2 implementations for the mock.
Simple, pretty clean if you encounter this problem few times, but not convenient if you have to do this often.
Please let me know if you have a better work-around or a fix!
Good luck
Related
Based on this question (How to mock instance methods of a class mocked with jest.mock?), how can a specific method be mocked whilst keeping the implementation of all other methods?
There's a similar question (Jest: How to mock one specific method of a class) but this only applies if the class instance is available outside it's calling class so this wouldn't work if the class instance was inside a constructor like in this question (How to mock a constructor instantiated class instance using jest?).
For example, the Logger class is mocked to have only method1 mocked but then method2 is missing, resulting in an error:
// Logger.ts
export default Logger() {
constructor() {}
method1() {
return 'method1';
}
method2() {
return 'method2';
}
}
// Logger.test.ts
import Logger from './Logger';
jest.mock("./Logger", () => {
return {
default: class mockLogger {
method1() {
return 'mocked';
}
},
__esModule: true,
};
});
describe("Logger", () => {
it("calls logger.method1() & logger.method2 on instantiation where only method1 is mocked", () => {
const logger = new Logger(); // Assume this is called in the constructor of another object.
expect(logger.method1()).toBe('mocked');
expect(logger.method2()).toBe('method2'); // TypeError: logger.method2 is not a function.
});
});
One solution is to extend the Logger class but this results in an undefined error as the Logger is already mocked:
// ...
jest.mock("./Logger", () => {
return {
default: class mockLogger extends Logger {
override method1() {
return 'mocked';
}
},
__esModule: true,
};
});
// ...
expect(logger.method2()).toBe('method2'); // TypeError: Cannot read property 'default' of undefined
Therefore, what could be the correct way to mock only method1 but keep method2's original implementation?
You can use jest.spyOn and provide a mock implementation for method1.
// Logger.test.ts
import Logger from './Logger';
jest.spyOn(Logger.prototype, "method1").mockImplementation(() => "mocked")
describe("Logger", () => {
it("calls method1 & method2 but only method1 is mocked", () => {
const l = new Logger();
expect(l.method1()).toBe("mocked");
expect(l.method2()).toBe("method2");
})
})
But in case you have many methods and you want to mock each one of them except one single method, then you can get the original implementation of this one single method using jest.requireActual.
// Logger.test.ts
import Logger from "./Logger";
const mockMethod1 = jest.fn().mockReturnValue("mocked");
const mockMethod3 = jest.fn().mockReturnValue("mocked");
const mockMethod4 = jest.fn().mockReturnValue("mocked");
const mockMethod5 = jest.fn().mockReturnValue("mocked");
jest.mock("./Logger", () =>
jest.fn().mockImplementation(() => ({
method1: mockMethod1,
method2: jest.requireActual("./Logger").default.prototype.method2,
method3: mockMethod3,
method4: mockMethod4,
method5: mockMethod5,
}))
);
describe("Logger", () => {
it("calls all methods but only method1 is mocked", () => {
const l = new Logger();
expect(l.method1()).toBe("mocked");
expect(l.method2()).toBe("method2");
expect(l.method3()).toBe("mocked");
expect(l.method4()).toBe("mocked");
expect(l.method5()).toBe("mocked");
});
});
Note: You don't need to define an ES6 class for mocking, a constructor function also just works fine because ES6 classes are actually just syntactic sugar for constructor functions.
Mocking the prototype works:
describe("Logger", () => {
it("calls logger.method1() & logger.method2 on instantiation where only method1 is mocked", () => {
Logger.prototype.method1 = jest.fn(() => 'mocked');
const logger = new Logger();
expect(logger.method1()).toBe('mocked');
expect(logger.method2()).toBe('method2');
});
});
However, I'm not sure if this is the correct way to mock a specific method when the class instance isn't accessible so I'll leave the question open for while in case there are better solutions.
I need to spyOn a method of an object created dynamically inside another method
So consider the following:
public doStuff = () => {
const myThing = new MyThing();
myThing.doSomethingElse().then((data) => {
//do more stuff here...
})
}
I want to therefore spyOn the instance of MyThing and the call to doSomethingElse().
I did come across a solution here which make use of the object's prototype, which I attempted like so
spyOn(MyThing.prototype, 'doSomethingElse').and.returnValue(Promise.resolve({foo: 'bar'}));
But this does not work after I call doStuff() in my tests, I get an error:
Error: : doSomethingElse() method does not exist
But I know this method is fine, since it runs as expected locally.
I am unsure how to proceed, can anyone assist?
Thanks
You might be missing something in your test. This is a simple test and you can see it works as you expected
require("jasmine");
class MyThing {
async doSomethingElse() {
return { bar: "foo" };
}
}
class Stuff {
doStuff() {
const myThing = new MyThing();
myThing.doSomethingElse().then(data => {
console.log(data);
});
}
}
describe("doSomethingElse", () => {
it("toHaveBeenCalled", () => {
spyOn(MyThing.prototype, "doSomethingElse").and.returnValue(
Promise.resolve({ foo: "bar123" })
);
const stuff = new Stuff();
stuff.doStuff();
expect(MyThing.prototype.doSomethingElse).toHaveBeenCalled();
});
});
The key is to use the spyOn before you instantiate the class that contains the doStuff function. If we move the const stuff = new Stuff(); above the spyOn it fails.
Hope it helps
You can create a spy object with mock method by passing in an object where the property names represent returned data for methods.
describe('test', () => {
let mock;
beforeEach(() => {
mock = jasmine.createSpyObj('mock', {
doSomethingElse: Promise.resolve({foo: 'bar'})
});
});
it('call mock', async () => {
const result = await mock.doSomethingElse();
expect(result.foo).toEqual('bar');
});
});
<link href="https://cdnjs.cloudflare.com/ajax/libs/jasmine/3.4.0/jasmine.css" rel="stylesheet"/>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jasmine/3.4.0/jasmine.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jasmine/3.4.0/jasmine-html.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jasmine/3.4.0/boot.js"></script>
I'm trying to set a unit testing boilerplate for my company. Our front end projects are built with ES6 classes and have a dependency to our core product. The front end code gets wrapped through a build process in a whole other block of code that is basically a closure and captures the dependency. So we don't have to manually import it in order to use it.
Let's say the dependency is called productScope and it's an object that has some DOM models, internal APIs and parameters among many other things necessary for each project. At the moment, Mocha throws ReferenceError: productScope is not defined. How can I mock this object? Or should I just use the actual object?
Example:
class someClass {
constructor() {
const id = productScope.items[0].id
const item = productScope.domModel.querySelector('.some-div')
item.classList.add(`added-${id}`)
}
}
This get wrapped in core code like below:
(function(productScope) {
// front end code goes here
}(productScope)
Testing file:
import someClass from '../../js/someClass'
describe('someClass', function() {
const someClass = new someClass()
it('should be a class', function() {
console.log(someClass)
});
});
You can try something like this
describe('#someClass', () => {
let someClass;
beforeEach(() => {
global.productScope = {
// mocking productScope object
};
});
it('should be a class', () => {
someClass = new SomeClass;
console.log(someClass);
});
afterEach(() => {
delete global.productScope;
});
});
or alternatively if you want more specific mock logic for each test case
describe('#someClass', () => {
let someClass;
it('should be a class', () => {
global.productScope = {
// mocking productScope object
};
// Test logic start
someClass = new SomeClass;
console.log(someClass);
// Test logic end
delete global.productScope;
});
});
Looks like productScope is a global variable.
Something like this should work for you.
import someClass from '../../js/someClass';
describe('someClass', function() {
let someClass;
beforeEach(() => {
global.productScope = {
// you mock definition
someClass = new someClass();
};
});
it('should be a class', function() {
console.log(someClass)
});
});
I'm with other answers as well, as managing global variables seems to be the simplest and most straightforward solution.
However, you can use toString to get class's string representation, and eval it to bind to closure's scope:
class someClass {
constructor() {
this.id = scopedId
}
}
// pass class as an argument
function scopeFactory(classDef) {
// define scoped data
let scopedId = 2;
// eval is used to bind class to the local closure
// so `scopedId` will be in charge
return eval("(" + classDef + ")");
}
const scopedSomeClass = scopeFactory(someClass);
console.log(new scopedSomeClass)
Note that eval(someCLass.toString()) doesn't work without parentheses.
You can add it as a helper function, into your project.
I have the following hypothetical scenario:
// file MyClass.js in an external package
class MyClass {
myfunc = () => {
// do something
}
}
// file in my project
function myFunctionToBeTested() {
const instance = new MyClass()
instance.myFunc()
}
I need to create a test with Jest that makes sure instance.myFunc was called
One of the option is to replace MyClass module with mock implementation
const mockmyfunc = jest.fn()
jest.mock("path/to/external/package/MyClass", () => {
return jest.fn().mockImplementation(() => {
return {myfunc: mockmyfunc}
})
})
And then write following test
it("Test myfunc called in functionToBeTested", () => {
functionToBeTested()
expect(mockmyfunc).toHaveBeenCalled()
})
Note that this is not the only way, you can dive into https://facebook.github.io/jest/docs/en/es6-class-mocks.html for other alternatives.
Update
If the myfunc would be an actual function (which i guess is not an option since it's external package?)
export class MyClass {
myFunc() {
// do smth
}
}
and you would not need to replace the implementation, you could be using jest's automock
import MyClass from "path/to/external/package/MyClass"
jest.mock("path/to/external/package/MyClass")
it("Test myfunc called in functionToBeTested", () => {
functionToBeTested()
const mockMyFunc = MyClass.mock.instances[0].myFunc
expect(mockMyFunc).toHaveBeenCalled()
})
you can mock out the class and assign the default export of that file to a variable as follows:
jest.mock('../../utils/api/api');
const FakeClass = require('../someFile.js').default;
then access calls to a function on your mock class like this:
FakeClass.prototype.myFunc.mock.calls
I have an application built on typescript with decorators for some convenience property assignments and wondering how I can go about writing unit tests for them.
export function APIUrl() {
return function (target: any, key: string) {
let _value = target[key];
function getter() {
return _value;
}
function setter(newValue) {
_value = getApiURL();
}
if (delete target[key]) {
Object.defineProperty(target, key, {
get: getter,
set: setter
});
}
};
}
In a spec class I have,
it("should return url string", ()=> {
#APIUrl();
let baseURL:string;
expect(baseURL typeOf string).toBe(true)
})
Since decorators are just functions I would suggest to just test them like any other function. And only if you really need to, add one tests that shows how to use the decorator with a class/member/...
Here is an example such a test could look like:
import test from 'ava';
import { APIUrl } from './path';
const decorate = new APIUrl();
test.before(t => {
let obj = { someProp: 'foo' };
decorate(obj, 'someProp');
t.context.foo = obj;
});
test('should return original value', t => {
t.is(t.context.foo.someProp, 'foo');
});
Another approach could be to setup some properties and/or methods that use your decorators and test their usage directly.
Note: decorators can only be used on class methods and members so you'd need to create a dummy class in your test.
Here's an example:
//Test Setup
class Test {
#APIUrl()
url: string;
#AnotherDecorator()
anotherFunction() {}
}
//Unit tests
describe('Decorator Tests', () => {
it('should work', () => {
const t = new Test();
expect(t.url).toEqual("something");
expect(t.anotherFunction()).toReturn("something else");
});
}