I am trying to integrate the code from here to change image of my slide show on click (credit to cssyphus):
$(function() {
$("input:button").click(function() {
$("img:last").fadeToggle("slow", function() {
$(this).prependTo(".frame").fadeIn()
});
});
});
function Forward() {
$("img:first").fadeToggle("slow", function() {
$(this).appendTo(".frame").fadeIn(800)
});
}
function Backward() {
$("img:last").fadeToggle("slow", function() {
$(this).prependTo(".frame").fadeIn()
});
}
.frame {
position: relative;
left: 35%;
}
img {
position: absolute;
max-width: 30%;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
<h1>
<input type="button" value="PrependTo" />
<button onclick="Forward()">Go Forward</button>
<button onclick="Backward()">Go Backward</button>
</h1>
<div class="frame">
<img src="http://placeimg.com/240/180/animals">
<img src="http://placeimg.com/240/180/nature">
<img src="http://placeimg.com/240/180/people">
<img src="http://placeimg.com/240/180/sepia">
</div>
The issue arise due to the effect depending position:absolute to stack the images on top of one another. Switching it to position:relative unstack the images and they are next to one another. Using position:absolute throws off all other elements in the code to integrate into. How can I remedy this problem?
It's a little difficult to imagine how the layout is affected by the slideshow, but from looking at your code I would try one of two things:
Remove the left: 35%; css from the .frame - I'm unsure why this is there but it will push the whole frame container of the slideshow over
.frame {
position: relative;
}
Adjust the CSS for the img so it only affects the nth-children after the first one, so they will be stacked on top of one another while the first one is inherit/relative:
img {
position: relative;
}
img:nth-child(n+2) {
position: absolute;
top: 0;
left: 0;
}
Related
The background image is an image of an office. The background image will have a few <a> tags where the person can click. For example: there is an <a> tag on a computer that's on the desk. Taking this example, I want to do the following:
Hovering on the <a> tag that is over the computer, will load in a picture of the same office, however, the computer has been outlined with a white line in photoshop (Lets say: img/bureau2). Indicating that it is interactable. Hovering away from this will return it to the original picture which you see when you enter site (img/bureau1)
You can also click on the <a> tag. This will open up another image (img/bureau3).
So far I managed to get the change on hover and click to work. Issue is, hovering away from the <a> tag will cancle the click.
This is what I have so far, how can I tackle this issue?
$(".computerHover").hover(function() {
$("#backgroundImage").attr('src', 'img/bureau2.png');
},
function() {
$("#backgroundImage").attr('src', 'img/bureau.png');
});
$(".computerHover").click(function() {
$("#backgroundImage").attr('src', 'img/bureau3.png');
});
#pagina2 {
width: 100%;
height: 100%;
}
#backgroundImage {
height: 100vh;
width: 100vw;
z-index: 0;
display: block;
}
.computerHover {
width: 105px;
height: 75px;
position: absolute;
right: 28vw;
top: 40vh;
z-index: 1;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pagina2">
<div id="pagina2Background">
<img id="backgroundImage" src="img/bureau.png">
<div class="computer">
<a class="computerHover"></a>
</div>
</div>
</div>
Seems to me, what you are trying to do, is an image map. But for the sake of your question, I will focus on one particular link.
The reason the click generated image disappears when you move the mouse, is because it is still bound to the previous hover event. The hover method is a shortcut for mouseenter and mouseleave. In order to circumvent that, you need to unbind that event handler.
EDIT:
I reworked my answer to more closely resemble the code in your question. In order to "reset" the image, I would suggest using a link that the user can click to make it less confusing for them.
function switchImage() {
$(".computerHover").hover(function() {
$("#backgroundImage").attr('src', 'http://via.placeholder.com/300x300.png?text=Computer');
},
function() {
$("#backgroundImage").attr('src', 'http://via.placeholder.com/300x300.png?text=Office');
});
}
// attach the hover events when page loads
switchImage();
$(".computerHover").on("click", function() {
$(this).off("mouseenter mouseleave");
$("#backgroundImage").attr('src', 'http://via.placeholder.com/300x300.png?text=New Background');
});
// reattach hover handlers and set image back to default
$(".reset").on("click", function() {
switchImage();
$("#backgroundImage").attr('src', 'http://via.placeholder.com/300x300.png?text=Office');
});
#pagina2 {
width: 100%;
height: 100%;
}
#backgroundImage {
height: 100vh;
width: 100vw;
z-index: 0;
display: block;
}
.computerHover {
width: 105px;
height: 75px;
position: absolute;
right: 28vw;
top: 40vh;
z-index: 1;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div id="pagina2">
<div id="pagina2Background">
<a class="reset">Start Over</a>
<img id="backgroundImage" src="http://via.placeholder.com/300x300.png?text=Office">
<div class="computer">
<a class="computerHover">Computer</a>
</div>
</div>
</div>
To do what you want you'll need to keep some sort of state that indicates that the user clicked instead of just hover. In the click handler you could add a class or data-* to #backgroundImage element that you later check when you un-hover.
Example codesanbox.
In my web page I have an image that has a button positioned over it. I want to show and hide the button as mouse enter and leave the image:
$('#UserImage').mouseenter(function()
{
$('#ButtonChange').show();
}).mouseout(function()
{
$('#ButtonChange').hide();
})
It is working but as the button is contained inside the image when the mouse enters the button it is considered to leave the image so the button is hidden then at tha same moment as the button is hidden the mouseenter event is triggered again and the button is shown causing a flickering effect
any suggestion to solve this?
Edit:
$('#UserImage').mouseenter(function() {
$('#ButtonChange').show();
}).mouseout(function() {
$('#ButtonChange').hide();
})
.imageUser {
width: 150px;
height: 200px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div style="position:relative;width=150px">
<img ID="UserImage" class="imageUser" ImageUrl="~/Images/logo.jpg" />
<input type="button" ID="ButtonChange" Text="Change" style="position: absolute;top: 180px;height:25px;left:0px;width:100px;display:none">
</div>
The whole thing is also possible with pure CSS ! for such simple thing, you don't really need Jquery !
.imageUser {
width: 150px;
height: 200px;
}
.img-wrapper {
position: relative;
width: 150px
}
.img-btn {
position: absolute;
top: 180px;
height: 25px;
left: 0px;
right:0; /* gave right, to align the button in center */
margin:0 auto; /* as button as fixed width, margin aligns in center */
width: 100px;
display: none
}
.img-wrapper:hover .img-btn {display:block} /* whenever mouse hovers the image wrapper, the button is shown, other time, its hidden */
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="img-wrapper">
<img ID="UserImage" class="imageUser" ImageUrl="~/Images/logo.jpg" />
<input type="button" ID="ButtonChange" Text="Change" class="img-btn">
</div>
Try hover?
$("#UserImage").hover(function () {
$('#ButtonChange').show();
}, function () {
$('#ButtonChange').hide();
});
I don't have an image so I make a div instead. See Fiddle below.
Fiddle: https://jsfiddle.net/9koswww1/1
Change mouseenter to mouseover.
https://api.jquery.com/mouseenter/
Check the bottom of the page for an example.
try this
$('#UserImage').mouseenter(function()
{
$('#ButtonChange').show();
}).mouseleave(function()
{
$('#ButtonChange').hide();
})
I have a webpage that uses tubular.js script to show youtube video as a site background. There's a sentence on tubular page:
First, it assumes you have a single wrapper element under the body tag
that envelops all of your website content. It promotes that wrapper to
z-index: 99 and position: relative.
So following that, I wrote a simple html/css code:
<html>
<head>
<style>
* {
margin: 0;
padding: 0;
}
#logocontainer{
position: absolute;
top: 20%;
margin-top: -35px;/* half of #content height*/
left: 0;
width: 100%;
text-align:center;
}
#logo {
margin-left: auto;
margin-right: auto;
height: 75px;
}
</style>
<body>
<div id="wrapper" class="clearfix">
<div id="logocontainer">
<div id="logo">
<img src="img/logo.png"/>
</div>
</div>
</div> <!--wrapper-->
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<script type="text/javascript" charset="utf-8" src="js/jquery.tubular.1.0.js"></script>
<script type="text/javascript">
$(function() {
var options = {
videoId : '9JXVUP1hyxA',
start : 1
};
$('body').tubular(options);
});
</script>
</body>
</html>
but now, when I run it - I see only youtube video without my logo on top... I know the logo is there, because when I comment out the youtube script I can see it, however I don't see it when the video is present. I tried to add z-index:99 to #logo but that didn't do any magic... Can you help me with that?
EDIT:
As A. Wolff suggested below, I added to my css:
#wrapper{
z-index:99;
position: relative;
}
still though - no good results, video is still on top..
I see in their own Tubular they use this little script...
$('document').ready(function() {
var options = { videoId: 'ab0TSkLe-E0', start: 3 };
$('#wrapper').tubular(options);
// f-UGhWj1xww cool sepia hd
// 49SKbS7Xwf4 beautiful barn sepia
});
Just adding this keeps everything on top.
Use the code in this Fiddle as a sample.
Your must use z-index with position: relative/absolute.
Also your z-index in video must be less than in your blocks.
video {
position: absolute;
z-index: 1;
}
div {
position: relative;
z-index: 2;
}
I am working for a company and converting flash ad banners in html5.
I need to convert flash image which slides in from the left and at the same time it performs motion blur effect just like a windy effect.
I have converted slide in image but I am not sure how to add a windy effect.
Here is the car image I want to copy and this is my code jsfiddle
Thanks in advance.
HTML
<div id = "wrapper" >
<div id="mainContainer">
<div id="text">
<img id="Image_Car" src="http://i.share.pho.to/c43dc6d7_o.png" />
</div>
</div>
</div>
CSS
#wrapper {
left: 50px;
top: 50px;
width: 300px;
height:250px;
position: absolute;
}
#mainContainer {
background: url('https://secure-ds.serving-sys.com/BurstingRes/Site-8188/Type-0/5fefb401-b187-4d82-b4db-cbd2ef29cc48.gif');
width:300px;
height:250px;
overflow: hidden;
position: absolute;
}
#Image_Car {
position:absolute;
overflow: hidden;
margin:60px 8px;
left: -120px;
}
jQuery
$(document).ready(function () {
bannerAnimation();
});
function bannerAnimation() {
//Jquery Animation
$("#Image_Car").animate({
left: "30"
}, 500, function () {
$("#Image_Car").animate({
left: "10"
}, 200);
});
}
Jquery is not going to help you create motion blur unless you use a canvas, which nearly no one use for creating ads,
or,
you can create multiple instance of the images and place in same place, then animate each with slight time interval and opacity.
This is very good plugin for you:
DEMO
plugin
I want to enable drag-and-drop behaviour on my Web application. I have an image I want to drag. The image is behind another one that has transparent sections so that you can see the image beneath it. I do not want to change the order of the images. My thinking is I should use another layer on top of both images that is transparent and use it as a proxy to transfer events to the image I want to drag. jQuery UI's draggable function will not allow me to transfer the events in real-time i.e. I cannot hook into what it is doing while the drag is taking place, only when it is completed.
Is there a JavaScript library or jQuery plugin that will allow me to enable drag-and-drop on an element and have it transfer those events to another element in real-time?
Maybe I don't understand what you are trying to accomplish, but you should be able to drag and drop overlapping images without any trouble (demo).
Just wrap both images in a div and then make the div draggable:
CSS (no need to make .dragme position relative, because it is done in the draggable script)
.dragme img {
position: absolute;
top: 0;
left: 0;
}
HTML
<div class="dragme">
<img src="image1.gif">
<img src="image2.gif">
</div>
Script
$(".dragme").draggable();
I updated the demo, this isn't pretty and there might be a better way, but basically this puts an invisible overlay over the frame, then positions the image while the overlay is being dragged.
CSS
#draggable, #droppable {
width: 450px;
height: 250px;
padding: 0.5em;
margin: 10px;
background: #ddd;
color:#000;
}
.dragme {
position: relative;
width: 100px;
padding: 5px;
}
.dragme img {
position: absolute;
top: 55px;
left: 30px;
}
.demo {
width: 500px;
}
.border {
position: absolute;
top: 75px;
left: 30px;
z-index: 1;
}
HTML
<div class="demo">
<div class="border">
<img src="http://www.imageuploading.net/image/thumbs/large/border-564.png">
</div>
<div id="draggable" class="ui-widget-content">
<p>Drag from here</p>
<div class="dragme">
<img src="http://i142.photobucket.com/albums/r117/SaltyDonut/Icons/evilpuppy.gif">
</div>
</div>
<div id="droppable">
<p>Drop here</p>
</div>
</div>
Script (The demo uses $(document).ready because jsFiddle doesn't like $(window).load)
$(window).load(function(){
// cycle through draggable divs (in case there are more than one)
$(".dragme").each(function(){
var img = $(this).find('img');
var pos = img.position();
// create div overlay on image
$('<div/>', {
class : 'overlay',
css: {
position: 'relative',
top: pos.top,
left: pos.left,
width: img.outerWidth(),
height: img.outerHeight(),
zIndex: 100
}
})
// save original image position
.data('pos', [pos.left, pos.top])
.appendTo($(this));
// make overlay draggable
$(this).find('.overlay').draggable({
containment : '.demo',
revert: true,
revertDuration: 0,
handle: 'div',
// drag overlay and image
drag: function(e,ui){
img = $(this).parent().find('img');
img.css({
top: ui.position.top,
left: ui.position.left
});
},
// make image revert
stop: function(e,ui){
pos = $(this).data('pos');
$(this).parent().find('img').animate({left: pos[0], top: pos[1] },500);
}
});
});
$("#droppable").droppable({
drop : function(e,ui) {
// append entire div wrapper (.dragme)
ui.helper.parent().appendTo($(this));
}
});
});