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Say I have an array like so...
let myArr = [0,0,2,0,0];
I want to create sort of a ripple effect such that the result of the array is [0,1,2,1,0]
This would give you the result you expect:
let myArr = [0, 0, 2, 0, 0];
createRippleArray = (myArr) => {
if (myArr.length % 2 === 0) {
console.error("createRippleArray: Array length needs to be odd number>1");
return [];
}
let midIndex = ~~(myArr.length / 2);
let mid = myArr[midIndex];
return myArr.map((e, i) => {
let res;
if (i < midIndex) {
return ~~(mid / Math.abs(midIndex - i + 1));
} else if (i === midIndex) {
return mid;
} else if (i > midIndex) {
return ~~(mid / Math.abs(midIndex - i - 1));
}
});
}
console.log(createRippleArray(myArr));
Hope this helps!
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I have code with if statement (below). Is it possible to refactor this code? because in this method is ugly if statement :(
getOverallAmount(estimate) {
const {installments} = estimate;
const {vipValue} = estimate;
if (installments !== 1) {
const oneInstallment = vipValue / installments;
const allWithOneInst = vipValue - (oneInstallment * installments) + 1;
return oneInstallment + allWithOneInst;
}
return vipValue;
}
Using a ternary operator instead of the if statement:
getOverallAmount(estimate) {
const {installments} = estimate;
const {vipValue} = estimate;
const oneInstallment = vipValue / installments;
const allWithOneInst = vipValue - (oneInstallment * installments) + 1;
return (installments !== 1) ? oneInstallment + allWithOneInst : vipValue;
}
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let fruits = [mango,banana,avocado,apple,orange,lychee];
let prices = [50,90,65,300,600,900]; // not constant value;
//Solution with If else
if(prices > 0 && prices <= 50) console.log("Mango#0-50")
if(prices > 51 && prices <= 65)console.log("Mango#0-50<br>Banana#51-65")
//So on
Is there any way to short it with loop?
This is how the result should look like
Mango#0-50
Banana#51-65
avocado#65-90
apple#91-300
orange#301-600
lychee#601-900
rest#>901
Note: I do not want to use If else;
let i = 1
fruits.map(fruit => `${fruit.name}#${i}-${i+=100}`);
You could map the fruits with their price range and slice the array by the wanted length and return a joined string.
function getValues(price) {
return temp
.slice(0, (prices.findIndex(p => price <= p) + 1) || prices.length + 1)
.join('<br>');
}
const
fruits = ['mango', 'banana', 'avocado', 'apple', 'orange', 'lychee'],
prices = [50, 90, 65, 300, 600, 900].sort((a, b) => a - b),
temp = [...fruits.map((f, i, { length }) => `${f}#${prices[i - 1] + 1 || 0}-${prices[i]}`), `rest#>${prices[prices.length - 1] + 1}`];
console.log(getValues(100));
console.log(getValues(300));
console.log(getValues(301));
console.log(getValues(1000));
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I want to get the array from:
const foo = [
FOO_BAR_A_READ_SELF,
FOO_BAR_A_WRITE_SELF,
FOO_BAR_A,
FOO_BAR_A_READ_ALL,
FOO_BAR_A_WRITE_ALL,
FOO_BAR_B_READ_SELF,
FOO_BAR_B_WRITE_SELF,
FOO_BAR_B,
FOO_BAR_B_READ_ALL,
FOO_BAR_B_WRITE_ALL
]
to
const foo = [
FOO_BAR_A,
FOO_BAR_A_READ_SELF,
FOO_BAR_A_WRITE_SELF,
FOO_BAR_A_READ_ALL,
FOO_BAR_A_WRITE_ALL,
FOO_BAR_B,
FOO_BAR_B_READ_SELF,
FOO_BAR_B_WRITE_SELF,
FOO_BAR_B_READ_ALL,
FOO_BAR_B_WRITE_ALL
]
i tried to go with the length by splitting with the "_", but I never worked with the sort function that specific.
I only used desc and asc ( return 1 > -1 ) || ( return -1 > 1 )
Can someone can explain me how I can get the wanted result?
Not sure it was my best...
var arr = [
'FOO_BAR_A_WRITE_SELF',
'FOO_BAR_A',
'FOO_BAR_A_READ_SELF',
'FOO_BAR_A_READ_ALL',
'FOO_BAR_A_WRITE_ALL',
'FOO_BAR_B_READ_SELF',
'FOO_BAR_B_WRITE_SELF',
'FOO_BAR_B',
'FOO_BAR_B_READ_ALL',
'FOO_BAR_B_WRITE_ALL'
];
const onRWorder=s=>{
let x = s.replace('_WRITE_','_')
if (x != s) x += '_WRITE'
else {
x = s.replace('_READ_','_')
if (x!= s) x += '_READ'
}
return x
}
arr.sort(function(a, b){
let a1 = onRWorder(a)
let b1 = onRWorder(b)
if(a1 < b1) { return -1 }
if(a1 > b1) { return 1 }
return 0
})
for (let z of arr) console.log(z)
.as-console-wrapper { max-height: 100% !important }
did you try this ?
var arr = [
'FOO_BAR_A_WRITE_SELF',
'FOO_BAR_A',
'FOO_BAR_A_READ_SELF',
'FOO_BAR_A_READ_ALL',
'FOO_BAR_A_WRITE_ALL',
'FOO_BAR_B_READ_SELF',
'FOO_BAR_B_WRITE_SELF',
'FOO_BAR_B',
'FOO_BAR_B_READ_ALL',
'FOO_BAR_B_WRITE_ALL'
];
var sorted = arr.sort();
console.log(sorted);
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Find the sum of all the numbers in a string which is divisible by 3 and also find the last such number (Use JavaScript). Example “The best 6 of 8 will get 9 points”, sum = 15, last=9.
Sure - use split, reduce and filter with % (modulo) for divisibility:
const str = "The best 6 of 8 will get 9 points";
const strArr = str.split("");
const threesArr = strArr.filter(e => parseInt(e) % 3 == 0);
const sumOfThrees = threesArr.reduce((acc, curr) => acc + parseInt(curr), 0);
const allNumbers = strArr.filter(e => parseInt(e));
const lastNumber = allNumbers[allNumbers.length - 1];
console.log("Sum: " + sumOfThrees);
console.log("Last: " + lastNumber);
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I have the next code in javascript:
var exponential = 2.71828182845904523536028747135266249775724709369995957496696762772407663035354759457138217852516642742746;
var numerator, denominator;
function fact(x) {
if(x==0) {
return 1;
}
return x * fact(x-1);
}
function poisson(k, landa) {
exponentialPower = Math.pow(exponential, -landa); // negative power k
landaPowerK = Math.pow(landa, k); // Landa elevated k
numerator = exponentialPower * landaPowerK;
denominator = fact(k); // factorial of k.
return (numerator / denominator);
}
I need parse to php but i don't know how...
Can somebody help me?
you should put below variables within poisson function also dont think you need to initialize $numerator and $dominator to 0;
$exponential = 2;
$numerator = 0;
$dominator = 0;
function fact($x) {
if($x==0) {
return 1;
}
return $x * fact($x-1);
}
function poisson($k, $landa)
{
$exponential = 2;
$exponentialPower = pow($exponential, -$landa);
$landaPowerK = pow($landa,$k);
$numerator = $exponentialPower * $landaPowerK;
$dominator = fact($k);
echo ($numerator / $dominator);
}
poisson(1,2);