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I am not getting proper output with nested for-loop in javascript [closed]

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Closed 3 years ago.
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I'm supposed to get the multiplication value of the multi-dimensional array. but I am getting '1' as output whatever values being changed in array.
function arrayMultiplyer(arr){
var multi = 1;
for(var i=0;i < arr.length; i++){
for(var j =0; j<arr[i];j++){
multi *= arr[i][j];
}
}
return multi;
}
var multi = arrayMultiplyer([[2,33],[33,2],[5,6,9]]);
console.log(multi);

You need to check arr[i].length in the j loop.
function arrayMultiplyer(arr){
var multi = 1;
for(var i=0;i < arr.length; i++){
for(var j =0; j<arr[i].length;j++){ // you need to check arr[i].length here
multi *= arr[i][j];
}
}
return multi;
}
var multi = arrayMultiplyer([[2,33],[33,2],[5,6,9]]);
console.log(multi);

You can simply do this in two lines.
function arrayMultiplyer(arr){
let flattenedArray = arr.flat();
return flattenedArray.reduce((x, y) => x * y);
}
var multi = arrayMultiplyer([[2,33],[33,2],[5,6,9]]);
console.log(multi);

An alternative solution using .reduce()
function arrayMultiplier(arr) {
return arr.reduce((tot,arr2) =>
arr2.reduce((subTot, n) =>
subTot * n
, tot)
, 1);
}

Get palindrome length from string [closed]

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I have one string as "testaabbaccc" in this string we contain palindrome as "abba" and it's length is 4 but how can we identify this with a JavaScript code.
var string ="testaabbaccc"
Need Output as abba is palindrome and length is 4

You can use this article and modify it to your needs.
Working demo
function isPalindrome(s) {
var rev = s.split("").reverse().join("");
return s == rev;
}
function longestPalind(s) {
var maxp_length = 0,
maxp = '';
for (var i = 0; i < s.length; i++) {
var subs = s.substr(i, s.length);
for (var j = subs.length; j >= 0; j--) {
var sub_subs = subs.substr(0, j);
if (sub_subs.length <= 1)
continue;
if (isPalindrome(sub_subs)) {
if (sub_subs.length > maxp_length) {
maxp_length = sub_subs.length;
maxp = sub_subs;
}
}
}
}
return maxp;
}
console.log(longestPalind("testaabbaccc"));
console.log(longestPalind("testaabbaccc").length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

Javascript nested array and setting the variable [closed]

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for (i = 0; i < length1; i++) {
for (j = 0; j < length2; j++) {
for (k = j; k < length2; k++) {}
}
}
I just wondered... in the last loop where I initialize k to be equal to j, would it cause problems for me later on?
I'm assuming every time j increments by 1, k is set to the new value of j and then increments up to length2

You are correct that for each iteration of the j-for-loop, the innermost loop will begin at J's current value and iterate up to length2-1. If this is what you want, shouldn't be a problem.

Spaces in a joined array [closed]

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I have been working on a ceaser cipher algorithm but I haven't been able to grasp the reason why the joined array returns spaces in a peculiar state.
function rot13(str) { // LBH QVQ VG!
var string = str.split('');
var codedStr = [];
var encoded = [];
for (var k=0; k < string.length; k++){
codedStr.push(string[k].charCodeAt());
}
for(var i = 0; i < codedStr.length; i++){
if(codedStr[i] > 77 ){
codedStr[i] -= 13;
}
else if( codedStr[i] == 32 || codedStr[i] == 63){
codedStr[i] = codedStr[i];
}
else{
codedStr[i] += 13;
}
encoded.push(codedStr[i]);
}
var decode = codedStr.map(String.fromCharCode);
var result = decode.join('');
return result;
}
// Change the inputs below to test
console.log(rot13("SERR PBQR PNZC"));

String.fromCharCode accepts multiple arguments, and map provides 3. You should use
codedStr.map(code => String.fromCharCode(code));

why does this loop only work once [closed]

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Closed 8 years ago.
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I can't work out why this only loops through the array once in JavaScript. It should log the second nested array as well.
JSFiddle below and code below;
http://jsfiddle.net/HJfbT/
b = [["one", "is"],
["two", "is"]];
for (var i = 0; i < b.length; i++) {
for (var x = 0; x < b[x].length; x++) {
console.log(b[i][x]);
}
}

Because you have a typo:
// --- should be i ---v
for (var x = 0; x < b[x].length; x++) {
DEMO: http://jsfiddle.net/HJfbT/1/

Use b[i].length in the second loop.

I think is because the inner loop have the running condition with an error.
Is:
for (var x = 0; x < b[x].length; x++)
but must be:
for (var x = 0; x < b[i].length; x++)