I am trying to upload multiple image files. Please check out my code.
<form id="fileupload" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple="multiple" id="images_input">
</from>
$(document).ready(function(){
$('body').on('submit', '#fileupload', function(e){
e.preventDefault();
var files = document.getElementById("images_input").files;
var files_array = [];
$(files).each(function(index, value){
files_array.push(value);
// files_array.push(value);
});//each
var user_id = $("#user_id_input").val();
var product_name = $("#product_name_input").val();
console.log("Data",files[0]);
var url = "../filemanager/s3_laravel/public/upload";
$.ajax({
url: url,
data:{
files:files_array,
user_id: user_id,
product_name: product_name
},
type: 'POST',
success: function(data){
alert(data);
}
});
});
$('#images_input').change(function(){
$("#fileupload").submit();
});//change
When I try to submit it I get this error https://prnt.sc/l8vmhn. Please help in this regard.
Adding processData: false to your options object fixes the error.
You need to use the FormData API. Like this.
<form id="fileupload" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple="multiple" id="images_input">
</form>
<script>
$(document).ready(function(){
$('body').on('submit', '#fileupload', function(e){
e.preventDefault();
var formData = new FormData();
var files = document.getElementById("images_input").files;
$(files).each(function(index, value){
formData.append('files[]', value);
});
formData.append('user_id', $("#user_id_input").val());
formData.append('product_name', $("#product_name_input").val());
var url = "../filemanager/s3_laravel/public/upload";
$.ajax({
type: 'POST',
url: url,
contentType: false,
processData: false,
data: formData,
success: function(data){
alert(data);
}
});
});
$('#images_input').change(function(){
$("#fileupload").submit();
});
</script>
Finally It worked like this:
$(document).ready(function(){
$('#images_input').change(function(){
$("#fileupload").submit();
});//change
$("#fileupload").on('submit',function(event) {
event.preventDefault();
var formData = new FormData(this);
var url = "../filemanager/s3_laravel/public/upload";
$.ajax({
url: url,
type: "POST",
data: formData,
contentType: false,
cache: false,
processData:false,
success: function(data) {
console.log(data);
}
});//
});//submit
});//ready
Related
I have to send multiple files using form data but my code is not working can anybody tell me where it is wrong.
$('#fileupload').on('change', function() {
var to_user_id = $(this).data('touserid');
var chat_id = $(this).data('chat_id');
var formData = new FormData();
$.each($('input[type=file]')[0].files, function(i, value) {
formData.append('file[' + i + ']', value.files[0]);
});
//console.log(formData);
formData.append('to_user_id', to_user_id);
formData.append('chat_id', chat_id);
$.ajax({
url: 'upload.php',
type: 'POST',
data: formData,
dataType: 'json',
processData: false,
contentType: false,
cache: false,
success: function(data) {
//console.log(data);
}
})
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form method="post" name="upload_form" id="upload_form" enctype="multipart/form-data" action="upload.php">
<input type="file" name="fileupload[]" id="fileupload" multiple data-touserid="'+to_user_id+'" data-chat_id="'+getdata+'">
</form>
You have to pass the value in the form data
$.each($('input[type=file]')[0].files, function(i, value){
formData.append('file['+i+']', value); // change this to value
});
sample code which I used
$.each($('#upload_screenshot')[0].files,function(key,input){
formData.append('upload_screenshot[]', input);
});
Please implement below script code.
$('#fileupload').on('change', function(){
var to_user_id = $(this).data('touserid');
var chat_id = $(this).data('chat_id');
var form_data = new FormData();
var ins = document.getElementById('fileupload').files.length;
for (var x = 0; x < ins; x++) {
form_data.append("documentfiles[]", document.getElementById('fileupload').files[x]);
}
if(ins > 0)
{
formData.append('to_user_id', to_user_id);
formData.append('chat_id', chat_id);
$.ajax({
url: 'upload.php',,
dataType: 'text',
cache: false,
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function (response) {
},
});
}
else
{
alert("Please choose the file");
}
});
I hope your problem will be resolved.
I'm trying to post an image and some text via ajax onto my laravel server except I can't seem to add the File into the ajax request.
I have tried making a FormData and appending the needed params, I also tried serializing my form with jQuery.
$("#create-post-button").click(function(){
var CSRF_TOKEN = $('meta[name="csrf-token"]').attr('content');
// var formData = new FormData();
// formData.append('src', $('#src')[0].files[0]);
// formData.append('title', $);
// formData.append('_token', CSRF_TOKEN);
// formData.append('_method', 'POST');
event.preventDefault();
console.log($('#src')[0].files[0]);
$.ajax({
headers: {
'X-CSRF-TOKEN': CSRF_TOKEN
},
url: '/posts/create',
type: 'POST',
data:
{
'_method': 'POST',
'_token': CSRF_TOKEN,
'title':$("#title").val(),
'src': {
'name':$('#src')[0].files[0].name,
'size':$('#src')[0].files[0].size
}
},
dataType: 'json'
});
});
I expect that when I dump my $request in laravel, that it has the correct request params but also including the $file (FileBag) param for the file that is being posted.
EDIT:
I have looked up the link #charlietfl provided in the comments and it helped me a lot, so here is the end result:
$("#create-post-button").click(function(){
var CSRF_TOKEN = $('meta[name="csrf-token"]').attr('content');
event.preventDefault();
var file_data = $('#src').prop('files')[0];
var form_data = new FormData();
form_data.append('_method', 'POST');
form_data.append('_token', CSRF_TOKEN);
form_data.append('title', $('#title').val());
form_data.append('src', file_data);
$.ajax({
url: '/posts/create',
dataType: 'text',
contentType: false,
processData: false,
data: form_data,
type: 'post',
success: function(){
showSuccessUploadingPost();
},
error: function() {
showErrorUploadingPost();
}
});
});
The CSRF token at file upload required to pass as a GET parameter.
$("#create-post-button").click(function(){
var CSRF_TOKEN = $('meta[name="csrf-token"]').attr('content');
var form_data = new FormData();
form_data.append('title', $('#title').val());
jQuery.each(jQuery('#src')[0].files, function(i, file) {
data.append('src', file); //use the following line to handle multiple files upload
// data.append('src' + i, file);
});
$.ajax({
url: '/posts/create?_token=' + CSRF_TOKEN,
data: form_data,
cache: false,
contentType: false,
processData: false,
method: 'POST',
type: 'POST', // For jQuery < 1.9
success: function(){
showSuccessUploadingPost();
},
error: function() {
showErrorUploadingPost();
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>
<form id="uploadFrm" enctype="multipart/form-data" method="post">
<input type="file" name="src" />
<button id="create-post-button">Upload</button>
</form>
This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data">
<fieldset>
<div id="legend" class="">
<legend class="">file demoe 1</legend>
<div id="alert-message" class="alert hidden"></div>
</div>
<div class="control-group">
<!-- Text input-->
<label class="control-label" for="input01">Text input</label>
<div class="controls">
<input type="text" placeholder="placeholder" class="input-xlarge" name="name">
<p class="help-block" style="display:none;">text_input</p>
</div>
<div class="control-group"> </div>
<label class="control-label">File Button</label>
<!-- File Upload -->
<div class="controls">
<input class="input-file" id="fileInput" type="file" name="file">
</div>
</div>
<div class="control-group">
<!-- Button -->
<div class="controls">
<button class="btn btn-success">Button</button>
</div>
</div>
</fieldset>
</form>
This is my JavaScript code:
<script>
$('.wpc_contact').submit(function(event){
var formname = $('.wpc_contact').attr('name');
var form = $('.wpc_contact').serialize();
var FormData = new FormData($(form)[1]);
$.ajax({
url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php',
data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData},
type : 'POST',
processData: false,
contentType: false,
success : function(data){
alert(data);
}
});
}
For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST" in options since all files must be sent via POST request.
Note: contentType: false only available from jQuery 1.6 onwards
I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({
url: 'Your url here',
data: formData,
type: "POST", //ADDED THIS LINE
// THIS MUST BE DONE FOR FILE UPLOADING
contentType: false,
processData: false,
// ... Other options like success and etc
})
<form id="upload_form" enctype="multipart/form-data">
jQuery with CodeIgniter file upload:
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: base_url + "member/upload/",
data: formData,
//use contentType, processData for sure.
contentType: false,
processData: false,
beforeSend: function() {
$('.modal .ajax_data').prepend('<img src="' +
base_url +
'"asset/images/ajax-loader.gif" />');
//$(".modal .ajax_data").html("<pre>Hold on...</pre>");
$(".modal").modal("show");
},
success: function(msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function() {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
); //
$('#done').hide();
}
});
you can use.
var form = $('form')[0];
var formData = new FormData(form);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
or
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
Both will work.
$(document).ready(function () {
$(".submit_btn").click(function (event) {
event.preventDefault();
var form = $('#fileUploadForm')[0];
var data = new FormData(form);
data.append("CustomField", "This is some extra data, testing");
$("#btnSubmit").prop("disabled", true);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "upload.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 600000,
success: function (data) {
console.log();
},
});
});
});
Better to use the native javascript to find the element by id like: document.getElementById("yourFormElementID").
$.ajax( {
url: "http://yourlocationtopost/",
type: 'POST',
data: new FormData(document.getElementById("yourFormElementID")),
processData: false,
contentType: false
} ).done(function(d) {
console.log('done');
});
$('#form-withdraw').submit(function(event) {
//prevent the form from submitting by default
event.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'function/ajax/topup.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
if(returndata == 'success')
{
swal({
title: "Great",
text: "Your Form has Been Transfer, We will comfirm the amount you reload in 3 hours",
type: "success",
showCancelButton: false,
confirmButtonColor: "#DD6B55",
confirmButtonText: "OK",
closeOnConfirm: false
},
function(){
window.location.href = '/transaction.php';
});
}
else if(returndata == 'Offline')
{
sweetAlert("Offline", "Please use other payment method", "error");
}
}
});
});
Actually The documentation shows that you can use XMLHttpRequest().send()
to simply send multiform data
in case jquery sucks
View:
<label class="btn btn-info btn-file">
Import <input type="file" style="display: none;">
</label>
<Script>
$(document).ready(function () {
$(document).on('change', ':file', function () {
var fileUpload = $(this).get(0);
var files = fileUpload.files;
var bid = 0;
if (files.length != 0) {
var data = new FormData();
for (var i = 0; i < files.length ; i++) {
data.append(files[i].name, files[i]);
}
$.ajax({
xhr: function () {
var xhr = $.ajaxSettings.xhr();
xhr.upload.onprogress = function (e) {
console.log(Math.floor(e.loaded / e.total * 100) + '%');
};
return xhr;
},
contentType: false,
processData: false,
type: 'POST',
data: data,
url: '/ControllerX/' + bid,
success: function (response) {
location.href = 'xxx/Index/';
}
});
}
});
});
</Script>
Controller:
[HttpPost]
public ActionResult ControllerX(string id)
{
var files = Request.Form.Files;
...
Good morning.
I was have the same problem with upload of multiple images. Solution was more simple than I had imagined: include [] in the name field.
<input type="file" name="files[]" multiple>
I did not make any modification on FormData.
I'm writing application where I need to upload file ajax I used jQuery.form library but the action go to the controller with empty list of files I don't know why here is my code html:
<form id="well-log-form" method="post" enctype="multipart/form-data">
<div class="fileUpload btn btn-primary">
<span>Well Logs</span>
<input type="file" id="well-logs" class="upload" />
</div>
</form>
and Js Code is :
document.getElementById("well-logs").onchange = function () {
var _url = "/Importer/WellLogUpload";
var options = {
beforeSubmit: showRequest,
url: _url,
type: 'post'
};
$('#well-log-form').ajaxSubmit(options);
};
function showRequest(formData, jqForm, options) {
return true;
}
function showResponse(responseText, statusText, xhr, $form) {
// $("body").append(responseText);
}
could any one help, I think it should work but I don't know why it is not working.
try this in jquery, it will post your file.
//#file is the id of { <input type="file" id="file"> }
$("#file").change(function () {
var file_data = $(this).prop("files")[0];
var form_data = new FormData();
form_data.append("file", file_data)
$.ajax({
url: "your url",
type: "post",
data: form_data,
contentType: false,
processData: false,
success: function (path) {
//on success
}
});
});
This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data">
<fieldset>
<div id="legend" class="">
<legend class="">file demoe 1</legend>
<div id="alert-message" class="alert hidden"></div>
</div>
<div class="control-group">
<!-- Text input-->
<label class="control-label" for="input01">Text input</label>
<div class="controls">
<input type="text" placeholder="placeholder" class="input-xlarge" name="name">
<p class="help-block" style="display:none;">text_input</p>
</div>
<div class="control-group"> </div>
<label class="control-label">File Button</label>
<!-- File Upload -->
<div class="controls">
<input class="input-file" id="fileInput" type="file" name="file">
</div>
</div>
<div class="control-group">
<!-- Button -->
<div class="controls">
<button class="btn btn-success">Button</button>
</div>
</div>
</fieldset>
</form>
This is my JavaScript code:
<script>
$('.wpc_contact').submit(function(event){
var formname = $('.wpc_contact').attr('name');
var form = $('.wpc_contact').serialize();
var FormData = new FormData($(form)[1]);
$.ajax({
url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php',
data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData},
type : 'POST',
processData: false,
contentType: false,
success : function(data){
alert(data);
}
});
}
For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST" in options since all files must be sent via POST request.
Note: contentType: false only available from jQuery 1.6 onwards
I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({
url: 'Your url here',
data: formData,
type: "POST", //ADDED THIS LINE
// THIS MUST BE DONE FOR FILE UPLOADING
contentType: false,
processData: false,
// ... Other options like success and etc
})
<form id="upload_form" enctype="multipart/form-data">
jQuery with CodeIgniter file upload:
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: base_url + "member/upload/",
data: formData,
//use contentType, processData for sure.
contentType: false,
processData: false,
beforeSend: function() {
$('.modal .ajax_data').prepend('<img src="' +
base_url +
'"asset/images/ajax-loader.gif" />');
//$(".modal .ajax_data").html("<pre>Hold on...</pre>");
$(".modal").modal("show");
},
success: function(msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function() {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
); //
$('#done').hide();
}
});
you can use.
var form = $('form')[0];
var formData = new FormData(form);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
or
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
Both will work.
$(document).ready(function () {
$(".submit_btn").click(function (event) {
event.preventDefault();
var form = $('#fileUploadForm')[0];
var data = new FormData(form);
data.append("CustomField", "This is some extra data, testing");
$("#btnSubmit").prop("disabled", true);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "upload.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 600000,
success: function (data) {
console.log();
},
});
});
});
Better to use the native javascript to find the element by id like: document.getElementById("yourFormElementID").
$.ajax( {
url: "http://yourlocationtopost/",
type: 'POST',
data: new FormData(document.getElementById("yourFormElementID")),
processData: false,
contentType: false
} ).done(function(d) {
console.log('done');
});
$('#form-withdraw').submit(function(event) {
//prevent the form from submitting by default
event.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'function/ajax/topup.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
if(returndata == 'success')
{
swal({
title: "Great",
text: "Your Form has Been Transfer, We will comfirm the amount you reload in 3 hours",
type: "success",
showCancelButton: false,
confirmButtonColor: "#DD6B55",
confirmButtonText: "OK",
closeOnConfirm: false
},
function(){
window.location.href = '/transaction.php';
});
}
else if(returndata == 'Offline')
{
sweetAlert("Offline", "Please use other payment method", "error");
}
}
});
});
Actually The documentation shows that you can use XMLHttpRequest().send()
to simply send multiform data
in case jquery sucks
View:
<label class="btn btn-info btn-file">
Import <input type="file" style="display: none;">
</label>
<Script>
$(document).ready(function () {
$(document).on('change', ':file', function () {
var fileUpload = $(this).get(0);
var files = fileUpload.files;
var bid = 0;
if (files.length != 0) {
var data = new FormData();
for (var i = 0; i < files.length ; i++) {
data.append(files[i].name, files[i]);
}
$.ajax({
xhr: function () {
var xhr = $.ajaxSettings.xhr();
xhr.upload.onprogress = function (e) {
console.log(Math.floor(e.loaded / e.total * 100) + '%');
};
return xhr;
},
contentType: false,
processData: false,
type: 'POST',
data: data,
url: '/ControllerX/' + bid,
success: function (response) {
location.href = 'xxx/Index/';
}
});
}
});
});
</Script>
Controller:
[HttpPost]
public ActionResult ControllerX(string id)
{
var files = Request.Form.Files;
...
Good morning.
I was have the same problem with upload of multiple images. Solution was more simple than I had imagined: include [] in the name field.
<input type="file" name="files[]" multiple>
I did not make any modification on FormData.