Upload File jQuery ajax MVC - javascript

I'm writing application where I need to upload file ajax I used jQuery.form library but the action go to the controller with empty list of files I don't know why here is my code html:
<form id="well-log-form" method="post" enctype="multipart/form-data">
<div class="fileUpload btn btn-primary">
<span>Well Logs</span>
<input type="file" id="well-logs" class="upload" />
</div>
</form>
and Js Code is :
document.getElementById("well-logs").onchange = function () {
var _url = "/Importer/WellLogUpload";
var options = {
beforeSubmit: showRequest,
url: _url,
type: 'post'
};
$('#well-log-form').ajaxSubmit(options);
};
function showRequest(formData, jqForm, options) {
return true;
}
function showResponse(responseText, statusText, xhr, $form) {
// $("body").append(responseText);
}
could any one help, I think it should work but I don't know why it is not working.


try this in jquery, it will post your file.
//#file is the id of { <input type="file" id="file"> }
$("#file").change(function () {
var file_data = $(this).prop("files")[0];
var form_data = new FormData();
form_data.append("file", file_data)
$.ajax({
url: "your url",
type: "post",
data: form_data,
contentType: false,
processData: false,
success: function (path) {
//on success
}
});
});

Related

How to upload multiple images with ajax?

I am trying to upload multiple image files. Please check out my code.
<form id="fileupload" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple="multiple" id="images_input">
</from>
$(document).ready(function(){
$('body').on('submit', '#fileupload', function(e){
e.preventDefault();
var files = document.getElementById("images_input").files;
var files_array = [];
$(files).each(function(index, value){
files_array.push(value);
// files_array.push(value);
});//each
var user_id = $("#user_id_input").val();
var product_name = $("#product_name_input").val();
console.log("Data",files[0]);
var url = "../filemanager/s3_laravel/public/upload";
$.ajax({
url: url,
data:{
files:files_array,
user_id: user_id,
product_name: product_name
},
type: 'POST',
success: function(data){
alert(data);
}
});
});
$('#images_input').change(function(){
$("#fileupload").submit();
});//change
When I try to submit it I get this error https://prnt.sc/l8vmhn. Please help in this regard.

Adding processData: false to your options object fixes the error.

You need to use the FormData API. Like this.
<form id="fileupload" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple="multiple" id="images_input">
</form>
<script>
$(document).ready(function(){
$('body').on('submit', '#fileupload', function(e){
e.preventDefault();
var formData = new FormData();
var files = document.getElementById("images_input").files;
$(files).each(function(index, value){
formData.append('files[]', value);
});
formData.append('user_id', $("#user_id_input").val());
formData.append('product_name', $("#product_name_input").val());
var url = "../filemanager/s3_laravel/public/upload";
$.ajax({
type: 'POST',
url: url,
contentType: false,
processData: false,
data: formData,
success: function(data){
alert(data);
}
});
});
$('#images_input').change(function(){
$("#fileupload").submit();
});
</script>

Finally It worked like this:
$(document).ready(function(){
$('#images_input').change(function(){
$("#fileupload").submit();
});//change
$("#fileupload").on('submit',function(event) {
event.preventDefault();
var formData = new FormData(this);
var url = "../filemanager/s3_laravel/public/upload";
$.ajax({
url: url,
type: "POST",
data: formData,
contentType: false,
cache: false,
processData:false,
success: function(data) {
console.log(data);
}
});//
});//submit
});//ready

Ajax form with file submission [duplicate]

This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data">
<fieldset>
<div id="legend" class="">
<legend class="">file demoe 1</legend>
<div id="alert-message" class="alert hidden"></div>
</div>
<div class="control-group">
<!-- Text input-->
<label class="control-label" for="input01">Text input</label>
<div class="controls">
<input type="text" placeholder="placeholder" class="input-xlarge" name="name">
<p class="help-block" style="display:none;">text_input</p>
</div>
<div class="control-group"> </div>
<label class="control-label">File Button</label>
<!-- File Upload -->
<div class="controls">
<input class="input-file" id="fileInput" type="file" name="file">
</div>
</div>
<div class="control-group">
<!-- Button -->
<div class="controls">
<button class="btn btn-success">Button</button>
</div>
</div>
</fieldset>
</form>
This is my JavaScript code:
<script>
$('.wpc_contact').submit(function(event){
var formname = $('.wpc_contact').attr('name');
var form = $('.wpc_contact').serialize();
var FormData = new FormData($(form)[1]);
$.ajax({
url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php',
data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData},
type : 'POST',
processData: false,
contentType: false,
success : function(data){
alert(data);
}
});
}

For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST" in options since all files must be sent via POST request.
Note: contentType: false only available from jQuery 1.6 onwards

I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({
url: 'Your url here',
data: formData,
type: "POST", //ADDED THIS LINE
// THIS MUST BE DONE FOR FILE UPLOADING
contentType: false,
processData: false,
// ... Other options like success and etc
})

<form id="upload_form" enctype="multipart/form-data">
jQuery with CodeIgniter file upload:
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: base_url + "member/upload/",
data: formData,
//use contentType, processData for sure.
contentType: false,
processData: false,
beforeSend: function() {
$('.modal .ajax_data').prepend('<img src="' +
base_url +
'"asset/images/ajax-loader.gif" />');
//$(".modal .ajax_data").html("<pre>Hold on...</pre>");
$(".modal").modal("show");
},
success: function(msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function() {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
); //
$('#done').hide();
}
});
you can use.
var form = $('form')[0];
var formData = new FormData(form);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
or
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
Both will work.

$(document).ready(function () {
$(".submit_btn").click(function (event) {
event.preventDefault();
var form = $('#fileUploadForm')[0];
var data = new FormData(form);
data.append("CustomField", "This is some extra data, testing");
$("#btnSubmit").prop("disabled", true);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "upload.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 600000,
success: function (data) {
console.log();
},
});
});
});

Better to use the native javascript to find the element by id like: document.getElementById("yourFormElementID").
$.ajax( {
url: "http://yourlocationtopost/",
type: 'POST',
data: new FormData(document.getElementById("yourFormElementID")),
processData: false,
contentType: false
} ).done(function(d) {
console.log('done');
});

$('#form-withdraw').submit(function(event) {
//prevent the form from submitting by default
event.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'function/ajax/topup.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
if(returndata == 'success')
{
swal({
title: "Great",
text: "Your Form has Been Transfer, We will comfirm the amount you reload in 3 hours",
type: "success",
showCancelButton: false,
confirmButtonColor: "#DD6B55",
confirmButtonText: "OK",
closeOnConfirm: false
},
function(){
window.location.href = '/transaction.php';
});
}
else if(returndata == 'Offline')
{
sweetAlert("Offline", "Please use other payment method", "error");
}
}
});
});

Actually The documentation shows that you can use XMLHttpRequest().send()
to simply send multiform data
in case jquery sucks

View:
<label class="btn btn-info btn-file">
Import <input type="file" style="display: none;">
</label>
<Script>
$(document).ready(function () {
$(document).on('change', ':file', function () {
var fileUpload = $(this).get(0);
var files = fileUpload.files;
var bid = 0;
if (files.length != 0) {
var data = new FormData();
for (var i = 0; i < files.length ; i++) {
data.append(files[i].name, files[i]);
}
$.ajax({
xhr: function () {
var xhr = $.ajaxSettings.xhr();
xhr.upload.onprogress = function (e) {
console.log(Math.floor(e.loaded / e.total * 100) + '%');
};
return xhr;
},
contentType: false,
processData: false,
type: 'POST',
data: data,
url: '/ControllerX/' + bid,
success: function (response) {
location.href = 'xxx/Index/';
}
});
}
});
});
</Script>
Controller:
[HttpPost]
public ActionResult ControllerX(string id)
{
var files = Request.Form.Files;
...

Good morning.
I was have the same problem with upload of multiple images. Solution was more simple than I had imagined: include [] in the name field.
<input type="file" name="files[]" multiple>
I did not make any modification on FormData.

upload an image with other parameters as JSON type using javascript

I have an object that contains parameters . I want to upload an image to a server but just using javascript.
how can I do that?
<input id="imgItem" type="file" class="form-control">
<input type="text" id="title">
<input type="text" id="description">
<button onclick="handle();">
<script>
function handle(){
var params={
title:document.getElementById('title').value,
desc: document.getElementById('description').value,
img://i don't know what I must do,
};
postItem(params, function(data){
alert(JSON.stringify(data));
});
}
function postItem(param, callbackFunction){
$.ajax({
url:myUrl,
data:param,
type:'POST',
contentType:'application/x-www-form-urlencoded',
xhrFields:{withCredentials: false},
success: function(response){
callbackFunction(response);
}
});
}
</script>

You can use FormData
var data = new FormData();
data.append('title', document.getElementById('title').value);
data.append('desc', document.getElementById('description').value);
$("input[type='file']").each(function (index) {
try {
data.append($(this).attr('name'), $(this)[0].files[0], $(this).attr('name'));
} catch (ignore) {}
});
$.ajax({
method: 'POST',
url: url,
data: data,
cache: false,
contentType: false,
processData: false
}).done(function () {
//your code here
}).fail(function (xhr, status, error) {
//your code here
}).always(function () {
//your code here
});
Or use it as regular form submission and fill in title and description values in submit event.

Spring Boot and jQuery file upload : Unsupported media type

I am trying to upload a csv file with spring boot 1.2.0 REST controller and jQuery ajax. When I send the post request, I keep getting 415:Unsupported Media type error. Here is my form:
<form id="upload_form">
<div id="message">
</div>
<br/>
<div class="row" id="upload-file-div" style="display: none">
<div class='col-sm-3'>
<label>Select File</label>
<input type="file" name="file">
</div>
<div class='col-sm-3'>
<input type="button" id="file-upload" class="btn btn-primary" value="Upload" onclick="uploadFile()"/>
</div>
</div>
</form>
Here is my method to upload file:
function uploadFile(){
var response = api.uploadCSV($("#upload_form"));
if(response.status === 'OK'){
$("#message").css('color', 'green');
}else{
$("#message").css('color', 'red');
}
$("#message").html(response.message);
}
Here is the actual jQuery POST:
upload: function (url, form, ignoreSuccess) {
var response = null;
if (!this.validate(form)) {
var array = form.serializeArray();
alert(array);
var formData = new FormData(form);
console.warn(formData);
$.ajax({
type: "POST",
url: API_PROXY + url,
data: formData,
cache: false,
contentType: false,
processData: false,
async: false,
beforeSend: function (request) {
if (api.getSession() !== null) {
request.setRequestHeader("Authorization", "Bearer " + api.getSession().bearer);
}
},
success: function () {}
}).done(function (msg) {
response = msg;
});
}
return response;
}
Following is my controller:
#RequestMapping(consumes = "multipart/form-data", method = RequestMethod.POST,
value = "/upload/twitter", produces = MediaType.APPLICATION_JSON_VALUE)
public Response<String> uploadCsv(CsvUploadModel form) {
//Code
}
I have both MultipartConfigElement and MultipartResolver annotated in my spring boot class. I am using spring boot 1.2.0. When I send the post request with PostMan (chrome extension), it works as expected. However, when I try the above jquery code, it keeps throwing unsupported media type error.
Following things I have tried:
Playing around content-type header, finally I have set the contentType to false.
Using form.serializeArray(), iterating over it and appending individual elements into formData.
Sending the form object instead of form data.
Can anyone please help me with this? Thanks in advance.

You can append your file input in your formData; the following changes needs to be made:
This:
<input type="file" name="file">
Should be:
<input type="file" name="file" id="file">
And in your ajax code, this:
var formData = new FormData(form);
console.warn(formData);
$.ajax({
type: "POST",
url: API_PROXY + url,
data: formData,
Should be:
var formData = new FormData();
formData.add("file",$('#file')[0].files)
$.ajax({
type: "POST",
url: API_PROXY + url,
data: formData,
Or:
var formData = new FormData(form[0]);
$.ajax({
type: "POST",
url: API_PROXY + url,
data: formData,

How to use FormData for AJAX file upload?

This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data">
<fieldset>
<div id="legend" class="">
<legend class="">file demoe 1</legend>
<div id="alert-message" class="alert hidden"></div>
</div>
<div class="control-group">
<!-- Text input-->
<label class="control-label" for="input01">Text input</label>
<div class="controls">
<input type="text" placeholder="placeholder" class="input-xlarge" name="name">
<p class="help-block" style="display:none;">text_input</p>
</div>
<div class="control-group"> </div>
<label class="control-label">File Button</label>
<!-- File Upload -->
<div class="controls">
<input class="input-file" id="fileInput" type="file" name="file">
</div>
</div>
<div class="control-group">
<!-- Button -->
<div class="controls">
<button class="btn btn-success">Button</button>
</div>
</div>
</fieldset>
</form>
This is my JavaScript code:
<script>
$('.wpc_contact').submit(function(event){
var formname = $('.wpc_contact').attr('name');
var form = $('.wpc_contact').serialize();
var FormData = new FormData($(form)[1]);
$.ajax({
url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php',
data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData},
type : 'POST',
processData: false,
contentType: false,
success : function(data){
alert(data);
}
});
}

For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here
var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST" in options since all files must be sent via POST request.
Note: contentType: false only available from jQuery 1.6 onwards

I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({
url: 'Your url here',
data: formData,
type: "POST", //ADDED THIS LINE
// THIS MUST BE DONE FOR FILE UPLOADING
contentType: false,
processData: false,
// ... Other options like success and etc
})

<form id="upload_form" enctype="multipart/form-data">
jQuery with CodeIgniter file upload:
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: base_url + "member/upload/",
data: formData,
//use contentType, processData for sure.
contentType: false,
processData: false,
beforeSend: function() {
$('.modal .ajax_data').prepend('<img src="' +
base_url +
'"asset/images/ajax-loader.gif" />');
//$(".modal .ajax_data").html("<pre>Hold on...</pre>");
$(".modal").modal("show");
},
success: function(msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function() {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
); //
$('#done').hide();
}
});
you can use.
var form = $('form')[0];
var formData = new FormData(form);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
or
var formData = new FormData($('#upload_form')[0]);
formData.append('tax_file', $('input[type=file]')[0].files[0]);
Both will work.

$(document).ready(function () {
$(".submit_btn").click(function (event) {
event.preventDefault();
var form = $('#fileUploadForm')[0];
var data = new FormData(form);
data.append("CustomField", "This is some extra data, testing");
$("#btnSubmit").prop("disabled", true);
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: "upload.php",
data: data,
processData: false,
contentType: false,
cache: false,
timeout: 600000,
success: function (data) {
console.log();
},
});
});
});

Better to use the native javascript to find the element by id like: document.getElementById("yourFormElementID").
$.ajax( {
url: "http://yourlocationtopost/",
type: 'POST',
data: new FormData(document.getElementById("yourFormElementID")),
processData: false,
contentType: false
} ).done(function(d) {
console.log('done');
});

$('#form-withdraw').submit(function(event) {
//prevent the form from submitting by default
event.preventDefault();
var formData = new FormData($(this)[0]);
$.ajax({
url: 'function/ajax/topup.php',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (returndata) {
if(returndata == 'success')
{
swal({
title: "Great",
text: "Your Form has Been Transfer, We will comfirm the amount you reload in 3 hours",
type: "success",
showCancelButton: false,
confirmButtonColor: "#DD6B55",
confirmButtonText: "OK",
closeOnConfirm: false
},
function(){
window.location.href = '/transaction.php';
});
}
else if(returndata == 'Offline')
{
sweetAlert("Offline", "Please use other payment method", "error");
}
}
});
});

Actually The documentation shows that you can use XMLHttpRequest().send()
to simply send multiform data
in case jquery sucks

View:
<label class="btn btn-info btn-file">
Import <input type="file" style="display: none;">
</label>
<Script>
$(document).ready(function () {
$(document).on('change', ':file', function () {
var fileUpload = $(this).get(0);
var files = fileUpload.files;
var bid = 0;
if (files.length != 0) {
var data = new FormData();
for (var i = 0; i < files.length ; i++) {
data.append(files[i].name, files[i]);
}
$.ajax({
xhr: function () {
var xhr = $.ajaxSettings.xhr();
xhr.upload.onprogress = function (e) {
console.log(Math.floor(e.loaded / e.total * 100) + '%');
};
return xhr;
},
contentType: false,
processData: false,
type: 'POST',
data: data,
url: '/ControllerX/' + bid,
success: function (response) {
location.href = 'xxx/Index/';
}
});
}
});
});
</Script>
Controller:
[HttpPost]
public ActionResult ControllerX(string id)
{
var files = Request.Form.Files;
...

Good morning.
I was have the same problem with upload of multiple images. Solution was more simple than I had imagined: include [] in the name field.
<input type="file" name="files[]" multiple>
I did not make any modification on FormData.

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