i try to create live search with Ajax, but i want when i click result of that search then it will automatic do the search.
my html code
<form id="search" action="">
<input type="text" class="form-control" id="qu" placeholder="search" required>
<div id="display" style="display: none"></div>
</form>
here my ajax live search
function fill(Value) {
$('#qu').val(Value);
$('#display').hide();
}
$(document).ready(function() {
$("#qu").keyup(function() {
$('#display').show();
var name = $('#qu').val();
if (name == "") {
$("#display").html("");
$("#display").hide();
}
else {
$.ajax({
type: "POST",
url: "cari.php",
data: {
search: name
},
success: function(html) {
$("#display").html(html).show();
}
});
}
});
});
here my ajax search
$(function() {
$("#search").bind('submit',function() {
$('#main_content').hide();
var value2 = $('#qu').val();
$.post('cari_user.php',{value2:value2}, function(data){
$("#main_content").html(data);
$('#main_content').fadeIn("slow");
$("#search")[0].reset();
});
return false;
});
});
in my curent code after i type query in live search input then i have to press enter/click enter button manually to search based on query i get from live search.
i want went i click result from live search then system will automatically doing the search.
I write code for you.. try with this
<form method="post" action="search.php">
<input type="text" id="search-box" name="search" autocomplete="off" class="form-control search" placeholder="Enter product / service to search">
<input type="submit" value="search" name="submit" id="hrdSearch" class="s_button">
<div id="suggesstion-box"></div>
</form>
<script>
$(document).ready(function(){
$("#search-box").keyup(function(){
$.ajax({
type: "POST",
url: "cari.php",
data:'keyword='+$(this).val(),
beforeSend: function(){
},
success: function(data){
$("#suggesstion-box").show();
$("#suggesstion-box").html(data);
$("#search-box").css("background","#FFF");
}
});
});
$("#hrdSearch").click(function (){
var v = $("#search-box").val();
window.location.href = "search.php?keyword=" + v;
return false;
});
});
function selectCountry(val) {
$("#search-box").val(val);
$("#suggesstion-box").hide();
}
</script>
cari.php
<?php
if(!empty($_POST["keyword"])) {
$query ="select * table_name where column_name like '". $_POST ["keyword"] ."%';";
$result = $db_handle->runQuery($query);
if(!empty($result)) {
?>
<ul id="country-list">
<?php
foreach($result as $country) {
?>
<li onClick="selectCountry('<?php echo $country["name"]; ?>');"><?php echo $country["name"]; ?></li>
<?php } ?>
</ul>
<?php } } ?>
Related
I want to add have a form in my Wordpress dashboard that work with ajax but my request response is 400 Bad request
add_action('admin_footer', 'vitrin_admin_ajax');
function vitrin_admin_ajax() {
?>
<script>
(function($) {
$('.vitrin-private-message-form').submit(function(event) {
event.preventDefault();
jQuery.ajax({
url: '<?php echo admin_url('admin-ajax.php'); ?>',
type: 'post',
data: {
action: 'submit_vitrin_pm',
ppmcontent: jQuery('#pmcontent').val(),
ppmusers: jQuery('#pmusers').val(),
},
success: function(data) {
// jQuery('#datafetch').html(data);
alert(data)
}
});
})
})(jQuery);
</script>
<?php
}
?>
I also add:
add_action('wp_ajax_submit_vitrin_pm', 'submit_vitrin_pm');
add_action('wp_ajax_nopriv_submit_vitrin_pm', 'submit_vitrin_pm');
and
function submit_vitrin_pm() {
echo 'ssss';
die();
}
I checked, your ajax response is working, you didn't share your html form, i added a form for check.
add_action('admin_footer', 'vitrin_admin_ajax');
function vitrin_admin_ajax() {
?>
<form action="#" method="POST" class="vitrin-private-message-form">
<div id="name-group" class="form-group">
<label for="name">Name</label>
<input
type="text"
class="form-control"
id="pmcontent"
name="name"
placeholder="Full Name"
/>
</div>
<div id="email-group" class="form-group">
<label for="email">Email</label>
<input
type="text"
class="form-control"
id="pmusers"
name="email"
placeholder="email#example.com"
/>
</div>
<button type="submit" class="btn btn-success">
Submit
</button>
</form>
<script>
(function($) {
$('.vitrin-private-message-form').submit(function(event) {
event.preventDefault();
console.log('working')
jQuery.ajax({
url: '<?php echo admin_url('admin-ajax.php'); ?>',
type: 'post',
data: {
action: 'submit_vitrin_pm',
ppmcontent: jQuery('#pmcontent').val(),
ppmusers: jQuery('#pmusers').val(),
},
success: function(data) {
// jQuery('#datafetch').html(data);
alert(data)
}
});
})
})(jQuery);
</script>
<?php
}
add_action('wp_ajax_submit_vitrin_pm', 'submit_vitrin_pm');
add_action('wp_ajax_nopriv_submit_vitrin_pm', 'submit_vitrin_pm');
function submit_vitrin_pm() {
echo 'ssss';
die();
}
I created a page, where I can easily update or insert data. It actually works, but if I click on the edit button, then I close the modal, then I add new data, it updates the previous data instead of inserting a new row. But if I refresh a page, then I update a row, it works. How can I solve this problem?
index.php:
<form method="post" id="insert_form">
<label><b>Name:</b></label>
<input type="text" name="name" id="name" class="form-control" readonly required />
<br />
<label><b>Description:</b></label>
<input type="text" name="hu" id="hu" class="form-control"></textarea>
<br />
<label><b>Cégek:</b></label>
<select name="company[]" id="company" multiple>
<?php
while($row = $huResult2->fetch_array()) {
?>
<option value="<?php echo $row['company_id'];?>"><?php echo $row['company_name'];?></option>
<?php
}
?>
</select>
<br/><br/>
<input type="hidden" name="data_id" id="data_id" />
<input type="submit" name="insert" id="insert" value="Insert" class="btn btn-success" />
</form>
<script>
$('#add').click(function() {
$('#insert').val("Insert");
$('#insert_form')[0].reset();
$('#company').multiselect('refresh');
$('#name').removeAttr('readonly');
});
// Edit roles
$(document).on('click', '.edit_data', function() {
$("#company option").prop("selected", false);
$("#name").attr('readonly', true);
var data_id = $(this).attr("id");
// Receive the current datas for the roles
$.ajax({
url: "fetchRole.php",
method: "POST",
data: {
'data_id': data_id
},
dataType: "json",
success: function(data) {
$('#name').val(data.name);
$('#hu').val(data.hu);
$.each(data.companies, function(i, e) {
$("#company option[value='" + e + "']").prop("selected", true);
});
$('#company').multiselect('refresh');
$('#data_id').val(data.id);
$('#insert').val("Update");
$('#add_data_Modal').modal('show');
}
});
});
$('#insert_form').on("submit", function(e) {
e.preventDefault();
// Update and insert
$.ajax({
url: "insertRole.php",
method: "POST",
data: $('#insert_form').serialize(),
beforeSend: function() {
$('#insert').val("Updating...");
},
success: function(data) {
$('#insert_form')[0].reset();
$('#add_data_Modal').modal('hide');
$('#role_table').html(data);
location.reload();
}
});
});
</script>
Do one thing make data_id field value blank when you are closing the modal
$('#myModal').on('hidden.bs.modal', function () {
$("#data_id").val("");
})
Maybe it will help
or on click of add new button do the same
$('#add').click(function() {
$('#insert').val("Insert");
$('#insert_form')[0].reset();
$('#company').multiselect('refresh');
$("#data_id").val("");
$('#name').removeAttr('readonly');
});
I have written a code by watching some tutorial. What it does is, if one writes a message, it adds it to database without reloading. The problem is it doesnt show me the updated database. It shows the database that was at the time of loading. What function should i add in function() to be able to that. I dont have much knowledge of javascript so if you can add it in the code it will me really helpful. Thanks
<html>
<?include_once('database.php')?>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'get',
url: 'home.php',
data: $('form').serialize(),
success: function () {
$('#comment').val('');
}
});
});
});
</script>
</head>
<!--body-->
<body>
<?php
if(isset($_GET["new_message"]))
{
$new_message = $_GET["new_message"];
$sql="INSERT INTO Messages(id, message, time, me) VALUES ('$session_usernumber', '$new_message',now(),'1')";
if(!mysqli_query($con,$sql))
{
echo"can not";
}
}
?>
</body>
<?php
$message_query="SELECT * FROM Messages Where id='$session_usernumber'";
$result = $con->query($message_query);
if ($result->num_rows > 0) {
while($row= $result->fetch_assoc())
{
echo $row['message'];
}
}
else
{
echo"Oops! You don't have any message";
}
?>
<div class="footer">
<form class="search_footer" name="sentMessage" id="contactForm" novalidate >
<input id='comment' autocomplete="off" autofocus="autofocus" type="text" name="new_message" placeholder="Type your message here.." required="required" class="textbox">
<input value="Send message" name="submit" type="submit" class="button">
</form>
</html>
Try this snippet, i think the problem is because your form doesn't send the message data to the database.
<div class="footer">
<form class="search_footer" name="sentMessage" id="contactForm" novalidate >
<input id='comment' autocomplete="off" autofocus="autofocus" type="text" name="new_message" placeholder="Type your message here.." required="required" class="textbox">
<input value="Send message" name="submit" type="submit" class="button">
</form>
</html>
<script>
$(document).ready(function(){
$.ajax({
url:'getmessages.php',type:'GET',success: function(message){console.log(message);}
});
$('form').on('submit', function (e) {
e.preventDefault();
var data = $('#comment').val();
$.ajax({
type: 'POST',
url: 'home.php',
data: {new_message: data},
success: function(response) {
console.log(response);
}
});
});
});
</script>
home.php file:
<?php
if(isset($_POST["new_message"]))
{
$new_message = $_POST["new_message"];
$sql="INSERT INTO Messages(id, message, time, me) VALUES ('$session_usernumber', '$new_message',now(),'1')";
if(!mysqli_query($con,$sql))
{
echo"can not";
}
getmessages.php
<?php
$message_query="SELECT * FROM Messages Where id='$session_usernumber'";
$result = $con->query($message_query);
if ($result->num_rows > 0) {
while($row= $result->fetch_assoc())
{
echo $row['message'];
}
}
else
{
echo"Oops! You don't have any message";
}
?>
I simply want to submit my form to the same page with ajax without page refresh. So my below code submits the form but $_POST values are not picked ... Am I submitting it properly. I don't get any error but I think my form is not submitting.
html form
<form action="" id="fixeddonation" name="fixeddonation" method="post">
<input type="hidden" class="donerProject" name="donerProject" value="test">
<input type="hidden" class="donersubProject" id="donersubProject" name="donersubProject" value="general">
<input type="hidden" class="donerLocations" id="donerLocations" name="donerLocations" value="general">
<input type="hidden" class="donationpagetype" name="donationpagetype" value="general">
<input type="hidden" class="projectadded" id="projectadded" name="projectadded" value="1">
<input type="hidden" value="302" id="pageid" name="pageid">
<div class="classsetrepet generalfixshow fullrow row fixed-page">
<div class="col-6 text-right">
<div class="prize">Fixed Amount £</div>
</div>
<div class="col-6">
<input type="text" id="oneoffamt" name="oneoffamt" class="oneoffamt validatenumber">
<span class="amt_error"></span>
</div>
</div>
<br>
<div class="row">
<div class="col-6"></div>
<div class="col-6">
<input type="submit" id="submit_gen_one" class="btn-block" value="submit" name="submit_gen_one">
</div>
</div>
</form>
Ajax code
jQuery('#fixeddonation').on('submit', function (e) {
e.preventDefault();
jQuery.ajax({
type: 'post',
url: 'wp-admin/admin-ajax.php',
data: jQuery('#fixeddonation').serialize(),
success: function (data) {
alert(data);
alert('form was submitted');
jQuery('#collapse2').addClass('in').removeAttr('aria-expanded').removeAttr('style'); jQuery('#collapse1').removeClass('in').removeAttr('aria-expanded').removeAttr('style');
}
});
return false;
});
Add a correct value to the action tag of your form and try this:
<script>
$(document).ready(function() {
var form = $('#fixeddonation');
form.submit(function(ev) {
ev.preventDefault();
var formData = form.serialize();
$.ajax({
method: 'POST',
url: form.attr('action'),
data: formData
}) .done(function(data) {
alert(data);
});
});
}); // end .ready()
</script>
Don't need return false as you already called preventDefault() first thing
First create Template
<?php
/* Template Name: Test */
get_header();
?>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script>
<div id="primary" class="content-area">
<main id="main" class="site-main">
<p class="register-message" style="display:none"></p>
<form action="#" method="POST" name="testregister" class="register-form">
<fieldset>
<label><i class="fa fa-file-text-o"></i> Register Form</label>
<input type="text" name="firstname" placeholder="Username" id="firstname">
<p id="firstname-error" style="display:none">Firstname Must Be Enter</p>
<input type="email" name="email" placeholder="Email address" id="email">
<p id="email-error" style="display:none">Email Must Be Enter</p>
<input type="submit" class="button" id="test" value="Register" >
</fieldset>
</form>
<script type="text/javascript">
jQuery('#test').on('click',function(e){
e.preventDefault();
var firstname = jQuery('#firstname').val();
var email = jQuery('#email').val();
if (firstname == "") {
jQuery('#firstname-error').show();
return false;
} else {
jQuery('#firstname-error').hide();
}
if (email == "") { jQuery('#email-error').show(); return false; }
else { jQuery('#email-error').hide(); }
jQuery.ajax({
type:"POST",
url:"<?php echo admin_url('admin-ajax.php'); ?>",
data: {
action: "test",
firstname : firstname,
email : email
},
success: function(results){
console.log(results);
jQuery('.register-message').text(results).show();
},
error: function(results) {
}
});
});
</script>
</main><!-- #main -->
</div><!-- #primary -->
after that create a function (function.php in wordpress)
add_action('wp_ajax_test', 'test', 0);
add_action('wp_ajax_nopriv_test', 'test');
function test() {
$firstname = stripcslashes($_POST['firstname']);
$email = stripcslashes($_POST['email']);
global $wpdb;
$q = $wpdb->prepare("SELECT * FROM wp_test WHERE email='".$email."' ");
$res = $wpdb->get_results($q);
if(count($res)>0)
{
echo "Email Allready Register ";
}
else
{
$user_data = array(
'firstname' => $firstname,
'email' => $email
);
$tablename = $wpdb->prefix.'test'; // if use wordpress
$user_id= $wpdb->insert( $tablename,$user_data );
echo 'we have Created an account for you';
die;
}
}
I have a simple chat app. Users type in username and message and it is supposed to be inserted into database.
This is not happening with this code, and obviously I am missing something:
FORM + SCRIPT
<form action="chat_s.php" method="post" class="send" id="form1" >
<p>
<label for="name">Name:</label>
<input type="text" name="name" id="name">
</p>
<div style="width: 480px; height: 400px; text-align: left;" id="DIV_CHAT">
</div>
<p>
<textarea id="msg" rows="5" cols="66" name="msg" placeholder="Your Message"></textarea></p>
</p>
<input class="submit" type="submit" id="button1" name="submit" value="Send" onfocus="this.blur()" />
</form>
<script>
var frm = $('#form1');
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
});
ev.preventDefault();
});
</script>
This is the php file that is supposed to insert into the database the users input:
CHAT_S.PHP
<?php
include_once 'connection.php';
if(!isset($_POST['submit'])) {}else
{
$name = mysqli_real_escape_string( $mysqli,$_POST['name']);
$msg = mysqli_real_escape_string($mysqli, $_POST['msg']);
$dt = date("Y-m-d H:i:s");
$sql = "INSERT INTO messages (username, chatdate, msg) VALUES ('$name', '$dt', '$msg')";
mysqli_query($mysqli, $sql); }
$mysqli->close();
?>
But the result is nothing. It alerts nothing! And it does not insert anything into the database, it just refreshes the chat box :(
try:
var frm = $('#form1');
frm.submit(function (ev) {
f = $('#form1');
$.ajax({
type: f.attr('method'),
url: f.attr('action'),
data: f.serialize(),
success: function (data) {
alert(data);
}
});
ev.preventDefault();
});