Form action onclick without refreshing with Ajax

Form action onclick without refreshing with Ajax - javascript

I have a simple chat app. Users type in username and message and it is supposed to be inserted into database.
This is not happening with this code, and obviously I am missing something:
FORM + SCRIPT
<form action="chat_s.php" method="post" class="send" id="form1" >
<p>
<label for="name">Name:</label>
<input type="text" name="name" id="name">
</p>
<div style="width: 480px; height: 400px; text-align: left;" id="DIV_CHAT">
</div>
<p>
<textarea id="msg" rows="5" cols="66" name="msg" placeholder="Your Message"></textarea></p>
</p>
<input class="submit" type="submit" id="button1" name="submit" value="Send" onfocus="this.blur()" />
</form>
<script>
var frm = $('#form1');
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert(data);
}
});
ev.preventDefault();
});
</script>
This is the php file that is supposed to insert into the database the users input:
CHAT_S.PHP
<?php
include_once 'connection.php';
if(!isset($_POST['submit'])) {}else
{
$name = mysqli_real_escape_string( $mysqli,$_POST['name']);
$msg = mysqli_real_escape_string($mysqli, $_POST['msg']);
$dt = date("Y-m-d H:i:s");
$sql = "INSERT INTO messages (username, chatdate, msg) VALUES ('$name', '$dt', '$msg')";
mysqli_query($mysqli, $sql); }
$mysqli->close();
?>
But the result is nothing. It alerts nothing! And it does not insert anything into the database, it just refreshes the chat box :(

try:
var frm = $('#form1');
frm.submit(function (ev) {
f = $('#form1');
$.ajax({
type: f.attr('method'),
url: f.attr('action'),
data: f.serialize(),
success: function (data) {
alert(data);
}
});
ev.preventDefault();
});

Related

How to Live Search and Search After Click with Ajax

i try to create live search with Ajax, but i want when i click result of that search then it will automatic do the search.
my html code
<form id="search" action="">
<input type="text" class="form-control" id="qu" placeholder="search" required>
<div id="display" style="display: none"></div>
</form>
here my ajax live search
function fill(Value) {
$('#qu').val(Value);
$('#display').hide();
}
$(document).ready(function() {
$("#qu").keyup(function() {
$('#display').show();
var name = $('#qu').val();
if (name == "") {
$("#display").html("");
$("#display").hide();
}
else {
$.ajax({
type: "POST",
url: "cari.php",
data: {
search: name
},
success: function(html) {
$("#display").html(html).show();
}
});
}
});
});
here my ajax search
$(function() {
$("#search").bind('submit',function() {
$('#main_content').hide();
var value2 = $('#qu').val();
$.post('cari_user.php',{value2:value2}, function(data){
$("#main_content").html(data);
$('#main_content').fadeIn("slow");
$("#search")[0].reset();
});
return false;
});
});
in my curent code after i type query in live search input then i have to press enter/click enter button manually to search based on query i get from live search.
i want went i click result from live search then system will automatically doing the search.

I write code for you.. try with this
<form method="post" action="search.php">
<input type="text" id="search-box" name="search" autocomplete="off" class="form-control search" placeholder="Enter product / service to search">
<input type="submit" value="search" name="submit" id="hrdSearch" class="s_button">
<div id="suggesstion-box"></div>
</form>
<script>
$(document).ready(function(){
$("#search-box").keyup(function(){
$.ajax({
type: "POST",
url: "cari.php",
data:'keyword='+$(this).val(),
beforeSend: function(){
},
success: function(data){
$("#suggesstion-box").show();
$("#suggesstion-box").html(data);
$("#search-box").css("background","#FFF");
}
});
});
$("#hrdSearch").click(function (){
var v = $("#search-box").val();
window.location.href = "search.php?keyword=" + v;
return false;
});
});
function selectCountry(val) {
$("#search-box").val(val);
$("#suggesstion-box").hide();
}
</script>
cari.php
<?php
if(!empty($_POST["keyword"])) {
$query ="select * table_name where column_name like '". $_POST ["keyword"] ."%';";
$result = $db_handle->runQuery($query);
if(!empty($result)) {
?>
<ul id="country-list">
<?php
foreach($result as $country) {
?>
<li onClick="selectCountry('<?php echo $country["name"]; ?>');"><?php echo $country["name"]; ?></li>
<?php } ?>
</ul>
<?php } } ?>

using AJAX to update query

I have written a code by watching some tutorial. What it does is, if one writes a message, it adds it to database without reloading. The problem is it doesnt show me the updated database. It shows the database that was at the time of loading. What function should i add in function() to be able to that. I dont have much knowledge of javascript so if you can add it in the code it will me really helpful. Thanks
<html>
<?include_once('database.php')?>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'get',
url: 'home.php',
data: $('form').serialize(),
success: function () {
$('#comment').val('');
}
});
});
});
</script>
</head>
<!--body-->
<body>
<?php
if(isset($_GET["new_message"]))
{
$new_message = $_GET["new_message"];
$sql="INSERT INTO Messages(id, message, time, me) VALUES ('$session_usernumber', '$new_message',now(),'1')";
if(!mysqli_query($con,$sql))
{
echo"can not";
}
}
?>
</body>
<?php
$message_query="SELECT * FROM Messages Where id='$session_usernumber'";
$result = $con->query($message_query);
if ($result->num_rows > 0) {
while($row= $result->fetch_assoc())
{
echo $row['message'];
}
}
else
{
echo"Oops! You don't have any message";
}
?>
<div class="footer">
<form class="search_footer" name="sentMessage" id="contactForm" novalidate >
<input id='comment' autocomplete="off" autofocus="autofocus" type="text" name="new_message" placeholder="Type your message here.." required="required" class="textbox">
<input value="Send message" name="submit" type="submit" class="button">
</form>
</html>

Try this snippet, i think the problem is because your form doesn't send the message data to the database.
<div class="footer">
<form class="search_footer" name="sentMessage" id="contactForm" novalidate >
<input id='comment' autocomplete="off" autofocus="autofocus" type="text" name="new_message" placeholder="Type your message here.." required="required" class="textbox">
<input value="Send message" name="submit" type="submit" class="button">
</form>
</html>
<script>
$(document).ready(function(){
$.ajax({
url:'getmessages.php',type:'GET',success: function(message){console.log(message);}
});
$('form').on('submit', function (e) {
e.preventDefault();
var data = $('#comment').val();
$.ajax({
type: 'POST',
url: 'home.php',
data: {new_message: data},
success: function(response) {
console.log(response);
}
});
});
});
</script>
home.php file:
<?php
if(isset($_POST["new_message"]))
{
$new_message = $_POST["new_message"];
$sql="INSERT INTO Messages(id, message, time, me) VALUES ('$session_usernumber', '$new_message',now(),'1')";
if(!mysqli_query($con,$sql))
{
echo"can not";
}
getmessages.php
<?php
$message_query="SELECT * FROM Messages Where id='$session_usernumber'";
$result = $con->query($message_query);
if ($result->num_rows > 0) {
while($row= $result->fetch_assoc())
{
echo $row['message'];
}
}
else
{
echo"Oops! You don't have any message";
}
?>

Ajax submitting form without refreshing page [duplicate]

This question already has answers here:
jQuery AJAX submit form
(20 answers)
Closed last year.
Can anyone tell me why this bit of code isn't working?
<html>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').bind('submit', function () {
$.ajax({
type: 'post',
url: 'post.php',
data: $('form').serialize(),
success: function () {
alert('form was submitted');
}
});
return false;
});
});
</script>
</head>
<body>
<form>
<input name="time" value="00:00:00.00"><br>
<input name="date" value="0000-00-00"><br>
<input name="submit" type="button" value="Submit">
</form>
</body>
</html>
When I push submit nothing happens. In the receiving php file I'm using $_POST['time'] and $_POST['date'] to put the data in a mysql query but it's just not getting the data. Any suggestions? I'm assuming it's something to do with the submit button but I can't figure it out

The form is submitting after the ajax request.
<html>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'post.php',
data: $('form').serialize(),
success: function () {
alert('form was submitted');
}
});
});
});
</script>
</head>
<body>
<form>
<input name="time" value="00:00:00.00"><br>
<input name="date" value="0000-00-00"><br>
<input name="submit" type="submit" value="Submit">
</form>
</body>
</html>

<html>
<head>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').bind('click', function (event) {
// using this page stop being refreshing
event.preventDefault();
$.ajax({
type: 'POST',
url: 'post.php',
data: $('form').serialize(),
success: function () {
alert('form was submitted');
}
});
});
});
</script>
</head>
<body>
<form>
<input name="time" value="00:00:00.00"><br>
<input name="date" value="0000-00-00"><br>
<input name="submit" type="submit" value="Submit">
</form>
</body>
</html>
PHP
<?php
if(isset($_POST["date"]) || isset($_POST["time"])) {
$time="";
$date="";
if(isset($_POST['time'])){$time=$_POST['time']}
if(isset($_POST['date'])){$date=$_POST['date']}
echo $time."<br>";
echo $date;
}
?>

JS Code
$("#submit").click(function() {
//get input field values
var name = $('#name').val();
var email = $('#email').val();
var message = $('#comment').val();
var flag = true;
/********validate all our form fields***********/
/* Name field validation */
if(name==""){
$('#name').css('border-color','red');
flag = false;
}
/* email field validation */
if(email==""){
$('#email').css('border-color','red');
flag = false;
}
/* message field validation */
if(message=="") {
$('#comment').css('border-color','red');
flag = false;
}
/********Validation end here ****/
/* If all are ok then we send ajax request to email_send.php *******/
if(flag)
{
$.ajax({
type: 'post',
url: "email_send.php",
dataType: 'json',
data: 'username='+name+'&useremail='+email+'&message='+message,
beforeSend: function() {
$('#submit').attr('disabled', true);
$('#submit').after('<span class="wait"> <img src="image/loading.gif" alt="" /></span>');
},
complete: function() {
$('#submit').attr('disabled', false);
$('.wait').remove();
},
success: function(data)
{
if(data.type == 'error')
{
output = '<div class="error">'+data.text+'</div>';
}else{
output = '<div class="success">'+data.text+'</div>';
$('input[type=text]').val('');
$('#contactform textarea').val('');
}
$("#result").hide().html(output).slideDown();
}
});
}
});
//reset previously set border colors and hide all message on .keyup()
$("#contactform input, #contactform textarea").keyup(function() {
$("#contactform input, #contactform textarea").css('border-color','');
$("#result").slideUp();
});
HTML Form
<div class="cover">
<div id="result"></div>
<div id="contactform">
<p class="contact"><label for="name">Name</label></p>
<input id="name" name="name" placeholder="Yourname" type="text">
<p class="contact"><label for="email">Email</label></p>
<input id="email" name="email" placeholder="admin#admin.com" type="text">
<p class="contact"><label for="comment">Your Message</label></p>
<textarea name="comment" id="comment" tabindex="4"></textarea> <br>
<input name="submit" id="submit" tabindex="5" value="Send Mail" type="submit" style="width:200px;">
</div>
PHP Code
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
//check if its an ajax request, exit if not
if (!isset($_SERVER['HTTP_X_REQUESTED_WITH']) AND strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') {
//exit script outputting json data
$output = json_encode(
array(
'type' => 'error',
'text' => 'Request must come from Ajax'
));
die($output);
}
//check $_POST vars are set, exit if any missing
if (!isset($_POST["username"]) || !isset($_POST["useremail"]) || !isset($_POST["message"])) {
$output = json_encode(array('type' => 'error', 'text' => 'Input fields are empty!'));
die($output);
}
//Sanitize input data using PHP filter_var().
$username = filter_var(trim($_POST["username"]), FILTER_SANITIZE_STRING);
$useremail = filter_var(trim($_POST["useremail"]), FILTER_SANITIZE_EMAIL);
$message = filter_var(trim($_POST["message"]), FILTER_SANITIZE_STRING);
//additional php validation
if (strlen($username) < 4) { // If length is less than 4 it will throw an HTTP error.
$output = json_encode(array('type' => 'error', 'text' => 'Name is too short!'));
die($output);
}
if (!filter_var($useremail, FILTER_VALIDATE_EMAIL)) { //email validation
$output = json_encode(array('type' => 'error', 'text' => 'Please enter a valid email!'));
die($output);
}
if (strlen($message) < 5) { //check emtpy message
$output = json_encode(array('type' => 'error', 'text' => 'Too short message!'));
die($output);
}
$to = "info#wearecoders.net"; //Replace with recipient email address
//proceed with PHP email.
$headers = 'From: ' . $useremail . '' . "\r\n" .
'Reply-To: ' . $useremail . '' . "\r\n" .
'X-Mailer: PHP/' . phpversion();
$sentMail = #mail($to, $subject, $message . ' -' . $username, $headers);
//$sentMail = true;
if (!$sentMail) {
$output = json_encode(array('type' => 'error', 'text' => 'Could not send mail! Please contact administrator.'));
die($output);
} else {
$output = json_encode(array('type' => 'message', 'text' => 'Hi ' . $username . ' Thank you for your email'));
die($output);
}
This page has a simpler example
http://wearecoders.net/submit-form-without-page-refresh-with-php-and-ajax/

Here is a nice plugin for jQuery that submits forms via ajax:
http://malsup.com/jquery/form/
its as simple as:
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
$(document).ready(function() {
$('#myForm').ajaxForm(function() {
alert('form was submitted');
});
});
</script>
It uses the forms action for the post location.
Not that you can't achieve this with your own code but this plugin has worked very nicely for me!

JS Code
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/ libs/jquery/1.3.0/jquery.min.js">
</script>
<script type="text/javascript" >
$(function() {
$(".submit").click(function() {
var time = $("#time").val();
var date = $("#date").val();
var dataString = 'time='+ time + '&date=' + date;
if(time=='' || date=='')
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
}
else
{
$.ajax({
type: "POST",
url: "post.php",
data: dataString,
success: function(){
$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();
}
});
}
return false;
});
});
</script>
HTML Form
<form>
<input id="time" value="00:00:00.00"><br>
<input id="date" value="0000-00-00"><br>
<input name="submit" type="button" value="Submit">
</form>
<span class="error" style="display:none"> Please Enter Valid Data</span>
<span class="success" style="display:none"> Form Submitted Success</span>
</div>
PHP Code
<?php
if($_POST)
{
$date=$_POST['date'];
$time=$_POST['time'];
mysql_query("SQL insert statement.......");
}else { }
?>
Taken From Here

type="button"
should be
type="submit"

In event handling, pass the object of event to the function and then add statement i.e.
event.preventDefault();
This will pass data to webpage without refreshing it.

$(document).ready(function(){
$('#userForm').on('submit', function(e){
e.preventDefault();
//I had an issue that the forms were submitted in geometrical progression after the next submit.
// This solved the problem.
e.stopImmediatePropagation();
// show that something is loading
$('#response').html("<b>Loading data...</b>");
// Call ajax for pass data to other place
$.ajax({
type: 'POST',
url: 'somephpfile.php',
data: $(this).serialize() // getting filed value in serialize form
})
.done(function(data){ // if getting done then call.
// show the response
$('#response').html(data);
})
.fail(function() { // if fail then getting message
// just in case posting your form failed
alert( "Posting failed." );
});
// to prevent refreshing the whole page page
return false;
});

<div class="container">
<div class="row">
<div class="col-md-3 col-sm-6 col-xs-12"></div>enter code here
<div class="col-md-6 col-sm-6 col-xs-12">
<div class="msg"></div>
<form method="post" class="frm" id="form1" onsubmit="">
<div class="form-group">
<input type="text" class="form-control" name="fname" id="fname" placeholder="enter your first neme" required>
<!--><span class="sp"><?php// echo $f_err;?></span><!-->
</div>
<div class="form-group">
<input type="text" class="form-control" name="lname" id="lname" placeholder="enter your last neme" required>
<!--><span class="sp"><?php// echo $l_err;?></span><!-->
</div>
<div class="form-group">
<input type="text" class="form-control" name="email" id="email" placeholder="enter your email Address" required>
<!--><span class="sp"><?php// echo $e_err;?></span><!-->
</div>
<div class="form-group">
<input type="number" class="form-control" name="mno" id="mno" placeholder="enter your mobile number" required>
<!--><span class="sp"><?php //echo $m_err;?></span><!-->
</div>
<div class="form-group">
<input type="password" class="form-control" name="pass" id="pass" pattern="(?=.*[a-z])(?=.*[A-Z]).{4,8}" placeholder="enter your Password" required>
<!--><span class="sp"><?php //echo $p_err;?></span><!-->
</div>
<div class="radio">
<input type="radio" value="male" name="gender" id="gender" checked>male<br>
<input type="radio" value="female" name="gender" id="gender">female<br>
<input type="radio" value="other" name="gender" id="gender">other<br>
<!--><span class="sp"> <?php //echo $r_err;?></span><!-->
</div>
<div class="checkbox">
<input type="checkbox" name="check" id="check" checked>I Agree Turms&Condition<br>
<!--><span class="sp"> <?php //echo $c_err;?></span><!-->
</div>
<input type="submit" class="btn btn-warning" name="submit" id="submit">
</form>enter code here
</div>
<div class="col-md-3 col-sm-6 col-xs-12"></div>
</div>
</div>

<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script type="text/javascript" >
$(function () {
$(".submit").click(function (event) {
var time = $("#time").val();
var date = $("#date").val();
var dataString = 'time=' + time + '&date=' + date;
console.log(dataString);
if (time == '' || date == '')
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
} else
{
$.ajax({
type: "POST",
url: "post.php",
data: dataString,
success: function (data) {
$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();
$("#data").html(data);
}
});
}
event.preventDefault();
});
});
</script>
<form action="post.php" method="POST">
<input id="time" value=""><br>
<input id="date" value=""><br>
<input name="submit" type="button" value="Submit" class="submit">
</form>
<div id="data"></div>
<span class="error" style="display:none"> Please Enter Valid Data</span>
<span class="success" style="display:none"> Form Submitted Success</span>
<?php
print_r($_POST);
if ($_POST['date']) {
$date = $_POST['date'];
$time = $_POST['time'];
echo '<h1>' . $date . '---' . $time . '</h1>';
}
else {
}
?>

Ajax form submit without page refresh

I simply want to submit my form to the same page with ajax without page refresh. So my below code submits the form but $_POST values are not picked ... Am I submitting it properly. I don't get any error but I think my form is not submitting.
html form
<form action="" id="fixeddonation" name="fixeddonation" method="post">
<input type="hidden" class="donerProject" name="donerProject" value="test">
<input type="hidden" class="donersubProject" id="donersubProject" name="donersubProject" value="general">
<input type="hidden" class="donerLocations" id="donerLocations" name="donerLocations" value="general">
<input type="hidden" class="donationpagetype" name="donationpagetype" value="general">
<input type="hidden" class="projectadded" id="projectadded" name="projectadded" value="1">
<input type="hidden" value="302" id="pageid" name="pageid">
<div class="classsetrepet generalfixshow fullrow row fixed-page">
<div class="col-6 text-right">
<div class="prize">Fixed Amount £</div>
</div>
<div class="col-6">
<input type="text" id="oneoffamt" name="oneoffamt" class="oneoffamt validatenumber">
<span class="amt_error"></span>
</div>
</div>
<br>
<div class="row">
<div class="col-6"></div>
<div class="col-6">
<input type="submit" id="submit_gen_one" class="btn-block" value="submit" name="submit_gen_one">
</div>
</div>
</form>
Ajax code
jQuery('#fixeddonation').on('submit', function (e) {
e.preventDefault();
jQuery.ajax({
type: 'post',
url: 'wp-admin/admin-ajax.php',
data: jQuery('#fixeddonation').serialize(),
success: function (data) {
alert(data);
alert('form was submitted');
jQuery('#collapse2').addClass('in').removeAttr('aria-expanded').removeAttr('style'); jQuery('#collapse1').removeClass('in').removeAttr('aria-expanded').removeAttr('style');
}
});
return false;
});

Add a correct value to the action tag of your form and try this:
<script>
$(document).ready(function() {
var form = $('#fixeddonation');
form.submit(function(ev) {
ev.preventDefault();
var formData = form.serialize();
$.ajax({
method: 'POST',
url: form.attr('action'),
data: formData
}) .done(function(data) {
alert(data);
});
});
}); // end .ready()
</script>
Don't need return false as you already called preventDefault() first thing

First create Template
<?php
/* Template Name: Test */
get_header();
?>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script>
<div id="primary" class="content-area">
<main id="main" class="site-main">
<p class="register-message" style="display:none"></p>
<form action="#" method="POST" name="testregister" class="register-form">
<fieldset>
<label><i class="fa fa-file-text-o"></i> Register Form</label>
<input type="text" name="firstname" placeholder="Username" id="firstname">
<p id="firstname-error" style="display:none">Firstname Must Be Enter</p>
<input type="email" name="email" placeholder="Email address" id="email">
<p id="email-error" style="display:none">Email Must Be Enter</p>
<input type="submit" class="button" id="test" value="Register" >
</fieldset>
</form>
<script type="text/javascript">
jQuery('#test').on('click',function(e){
e.preventDefault();
var firstname = jQuery('#firstname').val();
var email = jQuery('#email').val();
if (firstname == "") {
jQuery('#firstname-error').show();
return false;
} else {
jQuery('#firstname-error').hide();
}
if (email == "") { jQuery('#email-error').show(); return false; }
else { jQuery('#email-error').hide(); }
jQuery.ajax({
type:"POST",
url:"<?php echo admin_url('admin-ajax.php'); ?>",
data: {
action: "test",
firstname : firstname,
email : email
},
success: function(results){
console.log(results);
jQuery('.register-message').text(results).show();
},
error: function(results) {
}
});
});
</script>
</main><!-- #main -->
</div><!-- #primary -->
after that create a function (function.php in wordpress)
add_action('wp_ajax_test', 'test', 0);
add_action('wp_ajax_nopriv_test', 'test');
function test() {
$firstname = stripcslashes($_POST['firstname']);
$email = stripcslashes($_POST['email']);
global $wpdb;
$q = $wpdb->prepare("SELECT * FROM wp_test WHERE email='".$email."' ");
$res = $wpdb->get_results($q);
if(count($res)>0)
{
echo "Email Allready Register ";
}
else
{
$user_data = array(
'firstname' => $firstname,
'email' => $email
);
$tablename = $wpdb->prefix.'test'; // if use wordpress
$user_id= $wpdb->insert( $tablename,$user_data );
echo 'we have Created an account for you';
die;
}
}

issue with ajax login script

I'm very new to ajax, and I'm trying to make a login script that doesn't require a page reload - it's working well except I attempt to set a session variable on the processing page, but no session variable is set.
My form:
<div class="form-bottom">
<form role="form" class="login-form">
<div class="form-group">
<label class="sr-only" for="username">Username</label>
<input type="text" name="username" placeholder="Username..." class="form-username form-control" id="username">
</div>
<div class="form-group">
<label class="sr-only" for="password">Password</label>
<input type="password" name="password" placeholder="Password..." class="form-password form-control" id="password">
</div>
<input type="submit" id="submit" class="btn" style="width:100%;background-color:lightblue;" value="Log In" id="login"/>
</form>
<? echo $_SESSION['Name']; ?>
</div>
My ajax:
<script type="text/javascript" >
$(function() {
$("#submit").click(function() {
var username = $("#username").val();
var password = $("#password").val();
var dataString = 'username='+ username + '&password=' + password;
if(username=='' || password=='')
{
$('.success').fadeOut(200).hide();
$('.error').fadeOut(200).show();
}
else
{
$.ajax({
type: "POST",
url: "ajax/login.php",
data: dataString,
success: function(){
$('.success').fadeIn(200).show();
$('.error').fadeOut(200).hide();
window.setTimeout(function () {
location.href = "index.php";
}, 3000);
}
});
}
return false;
});
});
</script>
My php script:
include('./static/config.php');
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
if(isset($_POST)) {
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$sql = "SELECT Name FROM techs WHERE Username='$username' AND Password='$password'";
$result = mysqli_query($con, $sql);
$exists = mysqli_num_rows($result);
if($exists == 1) {
$row = mysqli_fetch_assoc($result);
$_SESSION['Name'] = $row['Name'];
}
}

I was able to get it working the way I wanted it to.
Form:
<div id="box">
<div class="row">
<div class="col-sm-6 col-sm-offset-3 form-box">
<div class="form-top">
<div class="form-top-left">
<h3>Log-in</h3>
<span id="error" class="error"></span>
</div>
<div class="form-top-right">
<i class="fa fa-key"></i>
</div>
</div>
<div id="box" class="form-bottom">
<form class="login-form" action="" method="post">
<div class="form-group">
<label class="sr-only" for="username">Username</label>
<input type="text" name="username" placeholder="Username..." class="form-username form-control" id="username">
</div>
<div class="form-group">
<label class="sr-only" for="password">Password</label>
<input type="password" name="password" placeholder="Password..." class="form-password form-control" id="password">
</div>
<input type="submit" id="login" class="btn" style="width:100%;background-color:lightblue;" value="Log In" id="login"/>
</form>
</div>
</div>
</div>
</div>
AJAX Code:
<script src="js/jquery.min.js"></script>
<script src="js/jquery.ui.shake.js"></script>
<script>
$(document).ready(function() {
$('#login').click(function()
{
var username=$("#username").val();
var password=$("#password").val();
var dataString = 'username='+username+'&password='+password;
if($.trim(username).length>0 && $.trim(password).length>0)
{
$.ajax({
type: "POST",
url: "ajax/login.php",
data: dataString,
cache: false,
beforeSend: function(){ $("#login").val('Connecting...');},
success: function(data){
if(data)
{
window.setTimeout(function () {
location.href = "index.php";
}, 3000);
}
else
{
$('#box').shake();
$("#login").val('Login')
$("#error").html("<span style='color:#cc0000'>Error:</span> Invalid username and password. ");
}
}
});
}
return false;
});
});
</script>
PHP (ajax/login.php):
<?php
include("../static/config.php");
session_start();
if(isSet($_POST['username']) && isSet($_POST['password']))
{
// username and password sent from Form
$username=mysqli_real_escape_string($con,$_POST['username']);
$password=mysqli_real_escape_string($con,$_POST['password']);
$result=mysqli_query($con,"SELECT Name FROM techs WHERE Username='$username' and Password='$password'");
$count=mysqli_num_rows($result);
$row=mysqli_fetch_array($result,MYSQLI_ASSOC);
// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1)
{
$_SESSION['Name']=$row['Name'];
echo $row['Name'];
}
}
?>

Since you've stated you're very new to Ajax, you start off pretty well.
There are however a couple of things to know how this works.
You want to avoid a page refresh, yet you don't print out any responses because you're not returning anything in the ajax request. You instead set a session variable which will show up at the next page request (so a refresh)
$.ajax({
type: 'POST',
url: 'ajax/login.php',
data: { username: $("#username").val(), password: $("#password").val() },
success: function (data) {
$('.form-bottom').html(data); // here we replace the form with output of the ajax/login.php response.
}
});
And for the PHP side of things:
$sql = "SELECT Name FROM techs WHERE Username='$username' AND Password='$password'";
if(($result = mysqli_query($con, $sql)) != false){ // always verify if your query ran successfully.
if(mysqli_num_rows($result)){ // or compare with == 1, but assuming a username is unique it can only be 1 so it equals to true.
echo mysqli_fetch_assoc($result)['name']; // index, columns, etc should always be lower cased to avoid confusion.
// Obviously you can store it in a session
// But for now just output the data so we can use it as our response.
// json is very usefull with sending large amounts of data.
}
}
The idea of Ajax is that you can request an update, but you need to update your page with javascript manually in order to make it work.

I think you forget to start the session.So start the session at the top of your script. Hope it will help.
session_start();
include('./static/config.php');
if(isset($_POST)) {
$username = mysqli_real_escape_string($con, $_POST['username']);
$password = mysqli_real_escape_string($con, $_POST['password']);
$sql = "SELECT Name FROM techs WHERE Username='$username' AND Password='$password'";
$result = mysqli_query($con, $sql);
$exists = mysqli_num_rows($result);
if($exists == 1) {
$row = mysqli_fetch_assoc($result);
$_SESSION['Name'] = $row['Name'];
}
}

3 things you could try:
On the page where you are trying to set the session variable you would have to use proper php opening tags like <?php
Second thing is that you would have to put a value in your session like $_SESSION['hello'] = 'hello';
Third thing, on every page where you handle your session you would have to call <?php session_start(); ?> for it to work.
Goodluck!

Develop Reference

JavaScript is the programming language of the Web.

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