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I have a string like this: *ngIf="thisThing > 0"
Using RegEx, I'd like to select/return ONLY the > or in some cases, <.
I have the following expression: (?<=")(?:.*?)(<|>)(?:.*?)(?=") but this still selects everything inside the quotes. I only want to match that >.
I've been testing it here: https://regex101.com/r/4KPfbT/1
I guess you're over-complexifying it. Why not this way:
\w*=".*([<>]).*"
It works, take a look:
console.log('*ngIf="thisThing > 0"'.match(/w*=".*([<>]).*"/)[1])
console.log('whatever="otherThing < 999"'.match(/w*=".*([<>]).*"/)[1])
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I have a string that looks like "{`index`:`20`,`value`:`RA`}<1", and I want it to become "`RA`<1". I don't think the replace function is sufficient as the index and value changes based on what I enter. Is there a way to do that?
assuming the required string is everything after the last :, except for the }, the original string can be sliced and edited as follows:
const string = "{`index`:`20`,`value`:`RA`}<1";
let newString = string.slice(string.lastIndexOf(":")+1).split("}").join("");
console.log(newString);
This will always append everything after the final } to everthing before it but after the last :, regardless of the earlier content.
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I have a data that looks like this
Huawei Y7P Art-L28 (4/64gb) (AAAAAAAAAAAAAA) EXP:02/19/2020
Huawei Y9 prime 2019 (BBBBBBBBBBBBBBB) EXP:07/17/2019
Oppo A31 4gb/128gb (CCCCCCCCCCCCCCC)
Vivo Y15 5000mah 4GB/64GB (1901) (DDDDDDDDDDDDDDD) EXP:06/14/2019
And the I want to get this data
AAAAAAAAAAAAAA
BBBBBBBBBBBBBBB
CCCCCCCCCCCCCCC
DDDDDDDDDDDDDDD
Basically what I want to happen is to extract the data from the set of word but my problem here is that its very unpredictable. It has no pattern at all so its hard to separate the string.
Assuming that you need a substring in last parenthesis:
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(column, '(', -1), ')', 1)
FROM source_table
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I need to to search through the document text and where it finds a pattern of 0000/0, 0000/00 or 0000/000 (where 0 can be any number) it automatically wraps that text in
0000/00
What I found for auto linkers are only when text is a URL, so it doesn't really help with what I need.
A simple regex pattern would do the trick.
text.replace(/(0000\/[0-9]{1,3})/gm, `$1`);
This will look for 0000/ followed by numbers between 0 and 9, 1 to 3 times.
simple regexp approach
document.body.innerHTML = document.body.innerHTML.replace(/(\d{4}\/\d{1,3})/g,
'$1')
Some text 0000/0 and this 1234/56 and that 7777/666
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^[a-zA-Z]\w+#[a-zA-Z_]+?\.[a-zA-Z]{2,4}$
i had tried this regex for email but it allow following cases
123#mail.com
example.mail#mail.com
Here is the code which searches for the number at the start.
If number is matched it prints message in console.
let regex = /^[0-9]/;
let object = [{email:'123#mail.com'},{email:'example.mail#mail.com'}];
for(let i =0;i<object.length;i++){
if(object[i].email.match(regex)){
console.log('E-mail ',object[i].email,' is not valid.')
}
}
This is the used regex: ^[0-9]
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I have a string like command--o1--o2--o3 ( command,o1,o2,o3 are arbitrary words)
And I want get [o1, o2, o3] though a Regular Expression(Not a array operation or other ways. JUST only use Regular Expression).
Is there any idea to accomplish this !?
If you're using JavaScript, and assuming you want all strings after a --, you may do
var things = str.split(/--/).slice(1)
If you just want to get the 2 characters words following --, then you may use
var things = str.match(/--\w\w/g).map(function(s){ return s.slice(2) })