My question relates to the fact I'm querying 2 different objects from DB and the result is in JSON. I need to merge them into one.
The 2 objects have in common this two key/value IRBId = ... and id = ... and they look as an example
OBJ 1
{
"data":{
"IRBs":{
"nodes":[
{
"id":"8",
"name":"Admin ",
},
{
"id":"9",
"name":"Again",
}
],
}
}
}
OBJ 2
{
"data":{
"informedConsentForms":{
"count":3,
"nodes":[
{
"id":"93",
...
"IRBId":"9",
},
{
"id":"92",
...
"IRBId":"8",
},
{
"id":"91",
...
"IRBId":"8",
}
],
}
},
As you will see above OBJ 2 and OBJ 1 corresponding with the same at IRBid and id.
What I need is to merge the two OBJ where IRBId OBJ 2 === id OBJ 1
The result I would expect after the merge is
OBJ merged
{
[{
"id":"93",
...
"IRBId":"9",
"irb": {
"name":"Again ",
...
}
},
{
"id":"92",
...
"IRBId":"8",
"irb": {
"name":"Admin ",
...
}
},
{
"id":"91",
...
"IRBId":"8",
"irb": {
"name":"Admin ",
...
}
],
},
I don't know how to make it looks like this.
Try using Array.reduce
Logic
Loop through second object data nodes
Find the matching nodes from object 1 data nodes.
Push to accumulator with required details. (I have added only the nodes that was mentioned in in Expected resut, you can add asmuch as you need.)
const obj1 = {
"data": {
"IRBs": {
"nodes": [
{
"id": "8",
"name": "Admin ",
},
{
"id": "9",
"name": "Again",
}
],
}
}
}
const obj2 = {
"data": {
"informedConsentForms": {
"count": 3,
"nodes": [
{
"id": "93",
"IRBId": "9",
},
{
"id": "92",
"IRBId": "8",
},
{
"id": "91",
"IRBId": "8",
}
],
}
},
};
const obj1List = obj1.data.IRBs.nodes;
const output = obj2.data.informedConsentForms.nodes.reduce((acc, curr) => {
const matchingNode = obj1List.find((item) => item.id === curr.IRBId);
if (matchingNode) {
acc.push({
id: curr.id,
IRBId: curr.IRBId,
irb: {
name: matchingNode.name
}
})
}
return acc;
}, []);
console.log(output);
You need to use the map function on the nodes in the first object to construct a new object that contains the second and first object's attributes.
const obj1 = {
"data": {
"IRBs": {
"nodes": [{
"id": "8",
"obj1": "one",
"name": "Admin ",
},
{
"id": "9",
"obj1": "two",
"name": "Again",
}
]
}
}
};
const obj2 = {
"data": {
"informedConsentForms": {
"count": 3,
"nodes": [{
"id": "93",
"obj2": "1",
"IRBId": "9",
},
{
"id": "92",
"obj2": "2",
"IRBId": "8",
},
{
"id": "91",
"obj2": "3",
"IRBId": "8",
}
],
}
}
};
const obj1Data = obj1.data.IRBs.nodes;
const obj2Data = obj2.data.informedConsentForms.nodes;
const res = obj2Data.map(item => {
const obj1Item = obj1Data.find(obj1Item => item.IRBId === obj1Item.id);
return obj1Item ? { ...item, "irb": { ...obj1Item}} : { ...item};
});
console.log(res);
i am using nested loop, try this one
const obj2 = {
"data":{
"informedConsentForms":{
"count":3,
"nodes":[
{
"id":"93",
"IRBId":"9",
},
{
"id":"92",
"IRBId":"8",
},
{
"id":"91",
"IRBId":"8",
}
],
}
},
}
const obj1 = {
"data":{
"IRBs":{
"nodes":[
{
"id":"8",
"name":"Admin ",
},
{
"id":"9",
"name":"Again",
}
],
}
}
}
const result = [];
const obj2Nodes = obj2.data.informedConsentForms.nodes;
for(let i = 0; i < obj2Nodes.length; i++) {
const obj1Nodes = obj1.data.IRBs.nodes
for(let j = 0; j < obj1Nodes.length; j++) {
if(obj2Nodes[i].IRBId === obj1Nodes[j].id) {
const {id, ...reObj1Nodes} = obj1Nodes[j];
result.push({
...obj2Nodes[i],
'irb': {
...reObj1Nodes
}
})
}
}
}
console.log(result)
DEMO
(Please check the browser console for output)
I have a JSON customerItemResponse in a format
{
"totalResults": someNumber,
"results": [
{
"totalItem": 406,
"customerId": "10000"
},
{
"totalItem": 468,
"customerId": "10001"
},
{
"totalItem": 20,
"customerId": "10002"
},
...
Then I have another JSON customerInfo:
{
"totalResults": someNumber,
"results": [
{
"customerId": "10000",
"region": "4",
"area": "42",
},
{
"customerId": "10001",
"region": "4",
"area": "43",
},
{
"customerId": "10002",
"region": "5",
"area": "52",
},
Now I have to create a JSON in a format
[
{
region:'4'
regionDetails:[
{
area:'42'
customerDetails:[
{
customerId:'10000'
totalItem:406
},
{
customerId:'10005'
totalItem:301
},
]
},
{
area:'11'
customerDetails:[
{
customerId:'10010'
totalItem:11
},
{
customerId:'10021'
totalItem:105
},
]
},
]
},
{
region:'5'
regionDetails:[
{
area:'52'
customerDetails:[
{
customerId:'10002'
totalItem:52
},
{
customerId:'10027'
totalItem:310
},
]
},
{
area:'41'
customerDetails:[
{
customerId:'10017'
totalItem:109
},
{
customerId:'10041'
totalItem:450
},
]
},
]
}
]
This is the logic I have written:
customerData=<CustomerDataInterface[]>[]
mapJson() {
this.customerItemResponse.map((res, index) => {
this.customerInfo.find((obj) => {
if (obj.customerId == res.customerId) {
this.customerData.length
? this.customerData.map((data, index1) => {
if (data.region == obj.region) {
data.regionDetails.length
? data.regionDetails.map((regDetails, index2) => {
if (regDetails.area == obj.area) {
regDetails.dealerDetails.push({
customerId: obj.customerId,
totalItem: res.totalItem,
});
return;
}
if (index2 == data.regionDetails.length - 1) {
data.regionDetails.push({ area: obj.area, dealerDetails: [] });
}
})
: data.regionDetails.push({ area: obj.area, dealerDetails: [] });
return;
}
if (index1 == this.customerData.length - 1) {
this.customerData.push({ region: obj.region, regionDetails: [] });
}
})
: this.customerData.push({ region: obj.region, regionDetails: [] });
}
});
});
console.log(this.customerData);
}
Now the output of the console has several region repeated. And suppose if I have 6 unique region but the this.customerData.length is 31.
I think return; is not working as expected. And is not skipping the subsequent element.
here is an efficient way to resolving the issue using js Maps. We can build maps with info about corresponding region and then areas. and after the data is built into maps - convert it back to simple js structures, such as object and arrays
mapJson() {
const customerToTotalMap = new Map(this.customerItemResponse.map(({customerId, totalItem}) => [customerId, totalItem]));
const regionsMap = new Map();
for(let {customerId, region, area} of this.customerInfo) {
let regionAreas;
if(regionsMap.has(region)) {
regionAreas = regionsMap.get(region);
} else {
regionAreas = new Map();
regionsMap.set(region, regionAreas);
}
let areaInfo;
if(regionAreas.has(area)) {
areaInfo = regionAreas.get(area);
} else {
areaInfo = [];
regionAreas.set(area, areaInfo);
}
areaInfo.push({customerId, totalItem: customerToTotalMap.get(customerId)});
}
this.customerData = [...regionsMap.entries()].map(([region, areas]) => ({
region,
regionDetails: [...areas.entries()].map(([area, customerDetails]) => ({
area,
customerDetails
}))
}))
console.log(this.customerData);
}
This is similar to #Andrei's answer. It creates an object literal as mapper. Also, it uses mapping between the region and area when they are created. So, finally you can just get the values of the regionMapper object without going through the mapper objects again
const customerItemResponse=[{customerId:10000,totalItem:77},{customerId:10001,totalItem:37},{customerId:10002,totalItem:295},{customerId:10003,totalItem:458},{customerId:10004,totalItem:248},{customerId:10005,totalItem:35},{customerId:10006,totalItem:280},{customerId:10007,totalItem:147},{customerId:10008,totalItem:439},{customerId:10009,totalItem:401},{customerId:10010,totalItem:489},{customerId:10011,totalItem:414},{customerId:10012,totalItem:287},{customerId:10013,totalItem:391},{customerId:10014,totalItem:125},{customerId:10015,totalItem:207},{customerId:10016,totalItem:197},{customerId:10017,totalItem:151},{customerId:10018,totalItem:225},{customerId:10019,totalItem:333},{customerId:10020,totalItem:361},{customerId:10021,totalItem:225},{customerId:10022,totalItem:242},{customerId:10023,totalItem:150},{customerId:10024,totalItem:52},{customerId:10025,totalItem:475},{customerId:10026,totalItem:494},{customerId:10027,totalItem:30},{customerId:10028,totalItem:189},{customerId:10029,totalItem:112},{customerId:10030,totalItem:482},{customerId:10031,totalItem:283},{customerId:10032,totalItem:159},{customerId:10033,totalItem:440},{customerId:10034,totalItem:461},{customerId:10035,totalItem:76},{customerId:10036,totalItem:84},{customerId:10037,totalItem:392},{customerId:10038,totalItem:296},{customerId:10039,totalItem:293},{customerId:10040,totalItem:135},{customerId:10041,totalItem:348},{customerId:10042,totalItem:338},{customerId:10043,totalItem:444},{customerId:10044,totalItem:15},{customerId:10045,totalItem:32},{customerId:10046,totalItem:67},{customerId:10047,totalItem:277},{customerId:10048,totalItem:65},{customerId:10049,totalItem:95},{customerId:10050,totalItem:290}],
customerInfo=[{customerId:10000,region:"3",area:"32"},{customerId:10001,region:"2",area:"22"},{customerId:10002,region:"2",area:"25"},{customerId:10003,region:"3",area:"31"},{customerId:10004,region:"2",area:"25"},{customerId:10005,region:"1",area:"11"},{customerId:10006,region:"1",area:"14"},{customerId:10007,region:"5",area:"55"},{customerId:10008,region:"5",area:"51"},{customerId:10009,region:"4",area:"45"},{customerId:10010,region:"1",area:"14"},{customerId:10011,region:"1",area:"12"},{customerId:10012,region:"3",area:"33"},{customerId:10013,region:"2",area:"25"},{customerId:10014,region:"4",area:"41"},{customerId:10015,region:"3",area:"32"},{customerId:10016,region:"5",area:"55"},{customerId:10017,region:"2",area:"23"},{customerId:10018,region:"3",area:"33"},{customerId:10019,region:"5",area:"51"},{customerId:10020,region:"4",area:"42"},{customerId:10021,region:"1",area:"12"},{customerId:10022,region:"1",area:"14"},{customerId:10023,region:"1",area:"14"},{customerId:10024,region:"1",area:"13"},{customerId:10025,region:"4",area:"45"},{customerId:10026,region:"3",area:"34"},{customerId:10027,region:"2",area:"24"},{customerId:10028,region:"4",area:"45"},{customerId:10029,region:"2",area:"22"},{customerId:10030,region:"2",area:"22"},{customerId:10031,region:"2",area:"21"},{customerId:10032,region:"3",area:"33"},{customerId:10033,region:"1",area:"11"},{customerId:10034,region:"3",area:"33"},{customerId:10035,region:"3",area:"32"},{customerId:10036,region:"2",area:"22"},{customerId:10037,region:"4",area:"41"},{customerId:10038,region:"3",area:"31"},{customerId:10039,region:"5",area:"51"},{customerId:10040,region:"2",area:"23"},{customerId:10041,region:"4",area:"45"},{customerId:10042,region:"1",area:"14"},{customerId:10043,region:"5",area:"54"},{customerId:10044,region:"3",area:"34"},{customerId:10045,region:"5",area:"51"},{customerId:10046,region:"4",area:"42"},{customerId:10047,region:"5",area:"53"},{customerId:10048,region:"1",area:"11"},{customerId:10049,region:"3",area:"35"},{customerId:10050,region:"5",area:"51"}];
const customerItemMapper = {}
for (const c of customerItemResponse)
customerItemMapper[c.customerId] = c.totalItem
const regionMapper = {},
areaMapper = {};
for (const { customerId, region, area } of customerInfo) {
let regionKey = `Region_${region}`,
areaKey = `Area_${area}`,
totalItem = customerItemMapper[customerId];
if (!(regionKey in regionMapper))
regionMapper[regionKey] = { region, regionDetails: [] }
if (!(areaKey in areaMapper)) {
const o = { area, customerDetails: [] }
areaMapper[areaKey] = o;
regionMapper[regionKey].regionDetails.push(o) // area-region relation
}
areaMapper[areaKey].customerDetails.push({ customerId, totalItem })
}
console.log(Object.values(regionMapper))
My target is if the id from digital_assets and products matches then get the value of URL fro digital_assets and ProductName from products object. I'm able to traverse through the object and get the values of digital_assets and products but need some help to compare these two objects based on IDs to get the value of URL and ProductName. Below is what I've done so far.
var data = [{
"digital_assets": [{
"id": "AA001",
"url": "https://via.placeholder.com/150"
},{
"id": "AA002",
"url": "https://via.placeholder.com/150"
}]
}, {
"products": [{
"id": ["BB001", "AA001"],
"ProductName": "PROD 485"
},{
"id": ["BB002", "AA002"],
"ProductName": "PROD 555"
}]
}
];
$.each(data, function () {
var data = this;
//console.log(data);
$.each(data.digital_assets, function () {
var dAssets = this,
id = dAssets['id'];
// console.log(id);
});
$.each(data.products, function () {
var proData = this,
prod_id = proData['id'];
// console.log(prod_id);
$.each(prod_id, function () {
var arr_id = this;
console.log(arr_id);
});
});
});
Do I need to create new arrays and push the values into the new arrays? Then concat() these array to one. ? Bit lost any help will be appreciated.
Here is one way you can do this via Array.reduce, Array.includes, Object.entries and Array.forEach:
var data = [{ "digital_assets": [{ "id": "AA001", "url": "https://via.placeholder.com/150" }, { "id": "AA002", "url": "https://via.placeholder.com/150" } ] }, { "products": [{ "id": ["BB001", "AA001"], "ProductName": "PROD 485" }, { "id": ["BB002", "AA002"], "ProductName": "PROD 555" } ] } ]
const result = data.reduce((r,c) => {
Object.entries(c).forEach(([k,v]) =>
k == 'digital_assets'
? v.forEach(({id, url}) => r[id] = ({ id, url }))
: v.forEach(x => Object.keys(r).forEach(k => x.id.includes(k)
? r[k].ProductName = x.ProductName
: null))
)
return r
}, {})
console.log(Object.values(result))
You can use Array.prototype.find, Array.prototype.includes and Array.prototype.map to achieve this very gracefully.
let data = [
{
"digital_assets": [
{
"id": "AA001",
"url": "https://via.placeholder.com/150"
},
{
"id": "AA002",
"url": "https://via.placeholder.com/150"
}
]
},
{
"products": [
{
"id": ["BB001", "AA001"],
"ProductName": "PROD 485"
},
{
"id": ["BB002","AA002"],
"ProductName": "PROD 555"
}
]
}
];
// Find the 'digital_assets' array
let assets = data.find(d => d['digital_assets'])['digital_assets'];
// Find the 'products' array
let products = data.find(d => d['products'])['products'];
// Return an array of composed asset objects
let details = assets.map(a => {
return {
id : a.id,
url : a.url
name : products.find(p => p.id.includes(a.id)).ProductName
};
});
console.log(details);
changed answer to fit your needs:
var data = [
{
"digital_assets": [
{
"id": "AA001",
"url": "https://via.placeholder.com/150"
},
{
"id": "AA002",
"url": "https://via.placeholder.com/150"
}
]
},
{
"products": [
{
"id": ["BB001", "AA001"],
"ProductName": "PROD 485"
},
{
"id": ["BB002","AA002"],
"ProductName": "PROD 555"
}
]
}
]
let matchingIds = [];
let data_assetsObject = data.find(element => {
return Object.keys(element).includes("digital_assets")
})
let productsObject = data.find(element => {
return Object.keys(element).includes("products")
})
data_assetsObject["digital_assets"].forEach(da => {
productsObject["products"].forEach(product => {
if (product.id.includes(da.id)){
matchingIds.push({
url: da.url,
productName: product.ProductName
})
}
})
})
console.log(matchingIds);
working fiddle: https://jsfiddle.net/z2ak1fvs/3/
Hope that helped. If you dont want to use a new array, you could also store the respective data within the element you are looping through.
Edit:
I think i know why i got downvoted. My example works by making data an object, not an array. changed the snippet to show this more clearly.
Why is data an array anyway? Is there any reason for this or can you just transform it to an object?
Edit nr2:
changed the code to meet the expectations, as i understood them according to your comments. it now uses your data structure and no matter whats in data, you can now search for the objects containing the digital_assets / products property.
cheers
https://jsfiddle.net/2b1zutvx/
using map.
var myobj = data[0].digital_assets.map(function(x) {
return {
id: x.id,
url: x.url,
ProductName: data[1].products.filter(f => f.id.indexOf(x.id) > -1).map(m => m.ProductName)
};
});