I need to change a php variable after success ajax call. How do I do this?
I have a function that update path name directory in database and directory. So, I have a php variable in the beginning of page that's get the path of a file. This is called $final_path.
<?php
$path_directory = trim($pathDAO->path_dir($id_pag)[0]->path);
$final_path = trim('http://www.test.com/content/'.$path_directory);
?>
I put a hidden div in html:
<div id="dir_path" hidden="true"><?php echo $final_path; ?></div>
So, when you change the name of directory, I call an ajax function as below.
Notice after success, the php variable should be updated, but it is not happened.
$.ajax({
type:'POST',
url: 'change_name.php',
data: {id: uid, name: uname},
dataType: 'html',
success: function (data) {
var data_path = data.split("||");
var result = $.trim(data_path[0]);
var result_a = $.trim(data_path[1]);
if(result === "success") {
document.getElementById("dir_path").value = result_a;
document.getElementById("dir_path").innerHTML = result_a;
}
});
return false;
In Ajax function, I update the path name and return the result (success or fail) and the new path directory.
$success = $updatePath ->update($_POST['id'], $_POST['name']);
$path_directory = trim($pathDAO->path_dir($_POST['id'])[0]->path);
$path_dir = trim('http://www.test.com/content/'.$caminho_diretorio);
$result = $success.'||'.$path_dir;
echo $result;
That's work well. But the variable $final_path haven't updated.
What am I doing wrong?
Your $final_path variable can't be updated because the execution of the php page is already done at this point. PHP variables are not kept in memory after the server has finished processing the page.
If you need to do further processing on the server-side with this value, then you need to either store it in user-session or keep the value that you got in the resulting ajax call and send it as POST data when you call your next php page.
Related
I have a very simple jquery function that sends an Ajax call to a php file that should echo out an alert, but for the life of me, cannot get it to run. For now, I'm just trying to trigger the php to run. Here is the javascript:
function getObdDescription(){
var $code = document.getElementById("vehicle_obd_code").value;
var $length = $code.length;
if($length == 5){
window.confirm($length);
$.ajax({ url: '/new.php',
data: {action: 'test'},
type: 'post',
success:function(result)//we got the response
{
alert('Successfully called');
},
error:function(exception){alert('Exception:'+exception);}
});
}
return false;
}
Here is new.php
<?php
echo '<script language="javascript">';
echo 'alert("message successfully sent")';
echo '</script>';
?>
I'm testing in Chrome, and have the network tab up, and can see that the call is successful, as well, I get the 'Successfully called' message that pops up, so the jquery is running, and the Ajax call is successful. I also know that the url: '/new.php is correct, because when I delete new.php from my server, I get a status "404 (Not Found)" from the console and network tab. I've even test without the conditional if($length ==... and still no luck. Of course, I know that's not the problem though, because I get the 'Successfully called' response. Any ideas?
This isnt the way it works if you need to alert the text, you should do it at the front-end in your ajax success function, follow KISS (Keep It Simple Stupid) and in the php just echo the text . that is the right way to do it.
You should do this:
function getObdDescription() {
var $code = document.getElementById("vehicle_obd_code").value;
var $length = $code.length;
if ($length == 5) {
window.confirm($length);
$.ajax({
url: '/new.php',
data: {
action: 'test'
},
type: 'post',
success: function (result) //we got the response
{
alert(result);
},
error: function (exception) {
alert('Exception:' + exception);
}
});
}
return false;
}
In your php
<?php
echo 'message successfully sent';
?>
You are exactly right Muhammad. It was not going to work the way I was expecting it. I wasn't really trying to do an Ajax call, but just to get an alert box to pop up; I just wanted confirmation that the call was working, and the PHP was running. Changing the alert('Successfully called'); to alert(result); and reading the text from the php definitely confirmed that the php was running all along.
I want to stay on topic, so will post another topic if that's what's needed, but have a follow-up question. To elaborate a bit more on what I'm trying to do, I am trying to run a function in my php file, that will in turn, update a template variable. As an example, here is one such function:
function get_vehicle_makes()
{
$sql = 'SELECT DISTINCT make FROM phpbb_vehicles
WHERE year = ' . $select_vehicle_year;
$result = $db->sql_query($sql);
while($row = $db->sql_fetchrow($result))
{
$template->assign_block_vars('vehicle_makes', array(
'MAKE' => $row['make'],
));
}
$db->sql_freeresult($result);
}
Now, I know that this function works. I can then access this function in my Javascript with:
<!-- BEGIN vehicle_makes -->
var option = document.createElement("option");
option.text = ('{vehicle_makes.MAKE}');
makeSelect.add(option);
<!-- END vehicle_makes -->
This is a block loop, and will loop through the block variable set in the php function. This work upon loading the page because the page that loads, is the new.php that I'm trying to do an Ajax call to, and all of the php runs in that file upon loading. However, I need the function to run again, to update that block variable, since it will change based on a selection change in the html. I don't know if this type of block loop is common. I'm learning about them since they are used with a forum I've installed on my site, phpBB. (I've looked in their support forums for help on this.). I think another possible solution would be to return an array, but I would like to stick to the block variable if possible for the sake of consistency.
I'm using this conditional and switch to call the function:
if(isset($_POST['action']) && !empty($_POST['action'])) {
$action = $_POST['action'];
//Get vehicle vars - $select_vehicle_model is used right now, but what the heck.
$select_vehicle_year = utf8_normalize_nfc(request_var('vehicle_year', '', true));
$select_vehicle_make = utf8_normalize_nfc(request_var('vehicle_make', '', true));
$select_vehicle_model = utf8_normalize_nfc(request_var('vehicle_model', '', true));
switch($action) {
case 'get_vehicle_makes' :
get_vehicle_makes();
break;
case 'get_vehicle_models' :
get_vehicle_models();
break;
// ...etc...
}
}
And this is the javascript to run the Ajax:
function updateMakes(pageLoaded) {
var yearSelect = document.getElementById("vehicle_year");
var makeSelect = document.getElementById("vehicle_make");
var modelSelect = document.getElementById("vehicle_model");
$('#vehicle_make').html('');
$.ajax({ url: '/posting.php',
data: {action: 'get_vehicle_makes'},
type: 'post',
success:function(result)//we got the response
{
alert(result);
},
error:function(exception){alert('Exception:'+exception);}
});
<!-- BEGIN vehicle_makes -->
var option = document.createElement("option");
option.text = ('{vehicle_makes.MAKE}');
makeSelect.add(option);
<!-- END vehicle_makes -->
if(pageLoaded){
makeSelect.value='{VEHICLE_MAKE}{DRAFT_VEHICLE_MAKE}';
updateModels(true);
}else{
makeSelect.selectedIndex = -1;
updateModels(false);
}
}
The javascript will run, and the ajax will be successful. It appears that the block variable is not being set.
I am making a page on a website in PHP where a user fills out 3 fields and hits submit. The submit button should call my AJAX function to send the data to a database connection PHP file. I can confirm the data is sent from AJAX (via an alert) and the function returns a Success. This must mean my database query file is not interpreting the data correctly. Please help me understand where I went wrong.
Code from php page where the form is:
<script type="text/javascript">
function storeInvoice() {
//var c_name = document.getElementById('c_name');
//var c_license = document.getElementById('c_license');
//var c_licenseemail = document.getElementById('c_licenseemail');
var data=$('#myForm').serialize();
$.ajax({
url: "/paydb.php",
type: "POST",
data: data,
async:false,
dataType:'html',
success: function (value) {
alert("Sent: "+data);
}
});
}
</script>
Relevant Code from Database php file:
mysqli_select_db($conn, "main_db" );
$c_license = $_POST['c_license'];
$c_name = $_POST['c_name'];
$c_licenseemail = $_POST['c_licenseemail'];
//Another method was attempted below.
//$data=$_POST['serialize'];
//$c_licenseemail = $data['c_licenseemail'];
//$c_license = $data['c_license'];
//$c_name = $data['c_name'];
$query = "INSERT INTO `invoices`(`company`, `licensenum`, `licenseemail`) VALUES ('$c_name','$c_license','$c_licenseemail');";
mysqli_query($conn, $query);
The data is sent as:
c_name=testname&c_license=3&c_licenseemail=testemail%40email.com
Any help is much appreciated!
Please use the
mysqli_query($conn, $query) or die(mysqli_error($conn));
For duplicate key, you need to make the primary key to auto increment in your database.
In your success callback function replace alert(data) with alert(value) and in your database.php file echo any of the post variables to just check whether the values are correctly sent to database.php via ajax post.
I am trying to get some data from the database. I create a function that is located in functions.php file that return a value. On another page, I create a variable and just get that value. I was trying to use the onkey to check the database but then I realize that i need to know the amount of tickets even if they don't type anything.
Here is the function:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$amount_of_tickets = $row['number_of_tickets'];
}
return $amount_of_tickets;
}
And, I am trying to check the database (without refreshing the page) and get the value on this page:
application.php
$amount_of_tickets = is_ticket_able($conn);
Then, I just check that $amount_of_tickets is not 0 or 1. Because if is one then some stuff have to change.
I am doing this (inside application.php):
if($amount_of_tickets !=0){
//show the form and let them apply for tickets.
//also
if($amount_of_tickets == 1){
//just let them apply for one ticket.
}
}
EDIT: I saw that AJAX would be the right one to use, but I am so confuse using it.
UPDATE:
function.php
function is_ticket_able($conn){
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
return $ticket;
}
application.php
$amount_of_tickets = is_ticket_able($conn);
<script type="text/javascript">
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
alert(global_isTicketAble);
if( global_isTicketAble == 0 ){
window.location.replace("http://www.google.com");
}
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
});
}
</script>
So, now the problem is that when I alert(global_isTicketAble); it doesn't alert the value from the database but it does alert everything that is inside application.php...Help plzzz
Server side
Assuming you need to check $amount_of_tickets periodically and this can be computed into application.php, inside that file you'll have
<?php
// $conn is defined and set somewhere
$amount_of_tickets = is_ticket_able($conn);
echo $amount_of_tickets;
exit(0);
?>
This way when the script is invoked with a simple GET request the value is returned in the response as simple text.
Client Side
ajax is the way to go if you want to update information on page without reloading it.
Below is just a simple example (using jQuery) that may be extended to fit your needs.
The code below is a JavaScript snippet. A global is used to store the value (globals should be avoided but it's just for the purpose of the example)
Then a function is invoked and the updated value is fetched from function.php script.
The function -prior termination- schedules itself (with setTimeout) to be re-invoked after a given amount of milliseconds (to repeat the fetch value process).
var global_isTicketAble = 0;
checkTicket();
function checkTicket()
{
$.ajax(
{
url: "application.php",
method: 'GET',
dataType: 'text',
async: true,
success: function( text )
{
global_isTicketAble = text;
// eventually do something here
// with the value just fetched
// (ex. update the data displayed)
setTimeout( checkTicket, 5000 ); // check every 5 sec
}
}
}
Note that $.ajax() sends the request but does not wait for the response (as async is set to true). When the request is received the function specified as success is executed.
Complete jQuery ajax function documentation can be found here
http://api.jquery.com/jquery.ajax/
I assume that you have a page (application.php) that displays a table somewhere.
And that you wish to fill that table with the data found in you database.
I'm not sure about WHEN you want these data to be refreshed.
On button click or periodically (like ervery 5 seconds)... But it doesn't matter for what I explain below.
In application.php:
Assemble all your page as you already know how.
But inside it, somewere, just insert an empty div where your table should show:
<div id="dynamicContent"></div>
Also add this script at the bottom of the page:
<script>
function getData(){
PostData="";
$.ajax({
type: "POST",
url: "function.php",
data: PostData,
cache: true,
success: function(html){
$(Destination).html(html);
}
});
}
getData(); // Trigger it on first page load !
</script>
There is 2 variables here... I named it "PostData" and "Destination".
About PostData:
You can pass data collected on the client side to your PHP function if needed.
Suppose you'd need to pass your user's first and last name, You'd define PostData like this:
Fname=$("#Fname").val(); // user inputs
Lname=$("#Lname").val();
PostData="Fname="+Fname+"&Lname="+Lname;
In your function.php, you will retreive it like this (like any normal POST data):
$Fname=$_POST['Fname'];
$Lname=$_POST['Lname'];
If you do not need to pass data from your client side script to you server side PHP... Just define it empty.
PostData="";
Then, about Destination:
This is the place for the empty "dynamic div" id ( I named it "dynamicContent" above).
Don't forget about the hashtag (#) for an id or the dot for a class.
This is a jQuery selector.
So here, PostData would be defined like this:
Destination="#dynamicContent";
The result of the ajax request will land into that "dynamic div".
This WILL be the result of what's defined in function.php..
So, if you follow me, you have to build your table in function.php...
I mean the part where you do your database query and your while fetch.
echo "<table>";
echo "<tr><th>column title 1</th><th>column title 2</th></tr>"
while ($row = sqlsrv_fetch_array($stmt)){
echo "<tr><td>" . $row['data1'] . "</td><td>" . $row['data2'] . "</td></tr>";
}
echo "</table>";
So if you have no data, the table will be empty.
You'll only get the table and table headers... But no row.
There is then no need for a function that checks if there is data or not.
Finally... About the trigger to refresh:
In application.php, you may place a button that fires getData()... Or you may define a setInterval.
It's up to you.
This is how I use ajax to refresh part of a page without reloading it completly.
Since ajax is new to you, I hope this answer will help.
;)
------------------------
EDIT based on Ariel's comment (2016-05-01)
Okay, I understand! Try this:
In application.php:
<div id="dynamicDiv"></div>
<script type="text/javascript">
// timer to trigger the function every seconds
var checkInterval = setInterval(function(){
checkTicket();
},1000);
function checkTicket(){
$.ajax({
type: "POST",
url: "function.php",
data: "",
cache: true,
success: function(html){
$("#dynamicDiv").html(html);
}
});
}
function noMoreTikets(){
clearInterval(checkInterval);
window.location.replace("http://www.google.com");
}
</script>
In function.php:
// Remove the "function is_ticket_able($conn){" function wrapper.
// Define $conn... Or include the file where it is defined.
// I assume that your query lookup works.
$query = "select number_of_tickets from [dbo].[TICKETS_LKUP] " ;
$stmt = sqlsrv_query($conn, $query);
while ($row = sqlsrv_fetch_array($stmt)) {
$ticket = $row['number_of_tickets'];
}
// Add this instead of a return.
if($ticket>0){
echo "There is still some tickets!"; // Text that will show in "dynamicDiv"
}else{
?>
<script>
$(document).ready(function(){
noMoreTikets();
});
</script>
<?php
}
Remember that your PHP scripts are executed server-side.
That is why your "return $ticket;" wasn't doing anything.
In this ajax way to call function.php, its script is executed alone, like a single page, without any relation with application.php, which was executed long ago.
It produces text (or javascript) to be served to the client.
If you want to pass a PHP variable to the client-side javascript, you have to echo it as javascript.
So here, if the PHP variable $ticket is more than zero, some text saying that there is still tickets available will show in "dynamicDiv" and the application page will not be refreshed. I suppose it shows a button or something that allows students to get a ticket.
Else, it will be the javascript trigger to "noMoreTikets()" that will land in the "dynamicDiv".
I have the following php function.
public function dateIndaysoff($mydate=false){
if(!$mydate)return false;
$host = "localhost";
$user = "user";
$pass = "pass";
$databaseName = "database";
$tableName = "table";
$con = mysql_connect($host,$user,$pass);
$dbs = mysql_select_db($databaseName, $con);
// $db=JFactory::getDbo();
$dbs->setQuery("select date from table WHERE `date`='$mydate'")->query();
return (int) $db->loadResult();
}
This function searches an input value inside a database table column and if it finds then we have a TRUE, else FALSE.
So, i have a jquery inside .js file where i execute a specific action and i want to check if i have a TRUE or FALSE result. In jquery i use a variable called val. So inside jquery in some place i want to have something like this:
if (dateIndaysoff(val)) {something}
Any ideas?
Instead of wrapping the php code in a function you can wrap it in a if($_POST['checkDate']){//your code here}, then in javascript make an ajax request (http://www.w3schools.com/ajax/), which sends a parameter named checkDate and in the success block of the ajax call you can have your code you represented as {something}
function checkDate(){
$.post('yourPhpFile.php', {checkDate:$dateToBeChecked}, function(data){
if(data){alert("true")};
});
};
and the php:
if($_POST['checkDate']){
//your current function, $_POST['checkDate'] is the parameter sent from js
}
Just to work with your current code.
In your php file lets say datasource.php
echo dateIndaysoff()
In your requesting file lets say index.php
$.ajax({
url: "index.php",
context: document.body
}).done(function( data ) {
/* do whatever you want here */
});
You can do it with AJaX. Something like this:
A PHP file with all the functions you are using (functions.php):
function test($data) {
// ...
}
A JS to request the data:
function getTest() {
$.ajax('getTestByAJaX.php', {
"data": {"param1": "test"},
"success": function(data, status, xhr) {
}
});
}
getTestByAJaX.php. A PHP that gets the AJaX call and executes the PHP function.
require 'functions.php';
if (isset($_REQUEST["param1"])) {
echo test($_REQUEST["param1"]);
}
Ok if i got this right i have to do this:
1st) Create a .php file where i will insert my php function and above the function i will put this:
$mydate = $_POST['val'];
where $mydate is the result of the function as you can see from my first post and val is the variable i want to put in $mydate from ajax.
2nd) I will go inside .js file. Now here is the problem. Here i have a code like this:
jQuery(".datepicker").change(function() {
var val = jQuery(this).datepicker().val();
console.log(val);
if (dateIndaysoff(val)) {
console.log("hide");
jQuery('.chzn-drop li:nth-child(9)').hide();
jQuery('.chzn-drop li:nth-child(10)').hide();
} else {
console.log("show");
jQuery('.chzn-drop li:nth-child(9)').show();
jQuery('.chzn-drop li:nth-child(10)').show();
}
});
Inside this code, in the first if, i want to see if the variable val is inside my database table. So, how could i write correctly this jQuery with the Ajax you propose in order for this to work? Also please take a look maybe i have a mistake in my php function (in this function i want to connect with a database and take a TRUE if $myvalue is inside a table column)
I need help to write this without the async: false,.
var imageX;
var groupX;
$.ajax({
type:'GET',
url:'php/myphp.php',
dataType:'json',
async: false,
success: function(response){
imageX = response[0].studentName,
groupX = response[0].subjectId;
alertImageX();
}
});
function alertImageX() {
(function() {
var image = {
'back': { 'url':imageX, 'img':null },
'front': { 'url':'img/bg.jpg', 'img':null }
};
php
$query = $db->prepare('SELECT studentName, subjectId FROM grade3 WHERE eligible = ? LIMIT 1');
$array = array('Yes');
$query->execute($array);
$result = $query->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($result);
"async: false" should not be needed in this situation because your response is already processed after AJAX request is complete, as it is placed inside the "success" element. Sorry if I missed any detail
EDIT:
Sorry I just read your comment regarding what you want to achieve. The response variable contains whatever the script called by AJAX echoed (in case of a PHP script), so you basically need to echo what you want the script to return and access that through the response variable.