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ajax error, the data is burried

this is my code
main.js
var save_method, table;
//Menerapkan plugin datatables
$(function(){
table = $('.table').DataTable({
"processing" : true,
"ajax" : {
"url" : "ajax/ajax_user.php?action=table_data",
"type" : "POST"
}
});
});
ajax_user.php
<?php
include "../config/database.php";
include "../library/view.php";
if ($_GET['action'] == "table_data") {
$query = mysqli_query($mysqli, "SELECT p.*, v.nama_provinsi, k.nama_kota, j.nama_tagihan FROM pelanggan P
INNER JOIN provinsi v ON p.id_provinsi = v.id_provinsi
INNER JOIN kota k ON p.id_kota = k.id_kota
INNER JOIN jenis_tagihan j ON p.id_jenis_tagihan = j.id_jenis_tagihan
ORDER BY p.id DESC");
$data = array();
$no = 1;
while($p = mysqli_fetch_assoc($query)) {
$row = array();
$row[] = $no;
$row = $p['nama_masjid'];
$row = $p['nama_pengurus'];
$row = $p['id_pelanggan'];
$row = $p['tagihan'];
$row = $p['nama_provinsi'];
$row = $p['nama_kota'];
$row = $p['nama_tagihan'];
$data[] = $row;
$no++;
}
$output = array("data" => $data);
echo json_encode($output);
}
?>
and this is my error
The last data in the array appears but the previous data disappears what's wrong ?

try this :
$data = [];
$i=0;
while($p = mysqli_fetch_assoc($query)) {
$data[$i]['nama_masjid'] = $p['nama_masjid'];
$data[$i]['nama_pengurus']= $p['nama_pengurus'];
$i++;
}
echo json_encode($data);

why can't I pass the data as json using Ajax and Jquery to the php side?

function delete_user(email)
{
//if(confirm("Do you want to remove this user with mail id: "+email))
//{
var z = {email : email}
console.log(z)
$.ajax({
url: "delete_user.php",
type: 'POST',
data: z,
success: function (data) {
console.log(data);
return false;
var i=0;
var element = "<table style='border-collapse: collapse;'>"
while(data[i] != null)
{
element = element + "<tr style='height:15px' onmouseover='rowbig(this)' onmouseout='rowsmall(this)'><td>"+data[i].fname+"&nbsp"+data[i].lname+"</td><td>"+data[i].email+"</td><td>"+data[i].dob+"</td><td><button onclick='delete_user(\""+data[i].email+"\")'><img src='delete.png' style='height:20px;width:20px'/></button></td></tr>";
i++;
}
element = element + "</table>";
$("#response").html( element );
},
cache: false,
contentType: false,
processData: false
});
//}
}
<?php
header("Content-Type:application/json");
$email ="";
function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
function deliver_res($status_message,$result)
{
header("$status_message");
$response['status_message']=$status_message;
$response['result']=$result;
$json_response=json_encode ($response);
echo $json_response;
}
$servername = 'localhost';
$username = 'root';
$password = '';
$dbname = 'webdata';
$conn = mysqli_connect($servername, $username, $password, $dbname);
if(isset($_POST['email']))
{
$email = test_input($_POST["email"]);
}
else
{
deliver_res("name not received","false");
exit();
}
$sqll="DELETE FROM admindata WHERE email='".$email."';";
$result = mysqli_query($conn,$sqll);
$return_arr = array();
$sqll="SELECT * FROM admindata ORDER BY id DESC ;";
$result = mysqli_query($conn,$sqll);
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC))
{
$row_array['fname'] = $row['fname'];
$row_array['lname'] = $row['lname'];
$row_array['email'] = $row['email'];
$row_array['dob'] = $row['dob'];
array_push($return_arr,$row_array);
}
echo json_encode($return_arr);
echo "\n";
mysqli_close($conn);
?>
I just can't seem to pass the data as JSON using AJAX and Jquery to the PHP side. Is there anything anything wrong with the syntax?

getting values from db using ajax and jquery final.html

i tried to fetch database values using jquery, but it's not working
code - final.html: http://pastebin.com/vMy5invc
api.php
<?php
$host = "localhost";
$user = "root";
$pass = "";
$databaseName = "vhc";
$tableName = "users";
$con = mysql_connect($host,$user,$pass);
$dbs = mysql_select_db($databaseName, $con);
$data = array();
$result = mysql_query("SELECT `id`,`name`,`email`,`location` FROM $tableName");
while ( $row = mysql_fetch_row($result) )
{
$data[] = $row;
}
echo json_encode( $data );
?>

you shoud replace $tableName with ".$tableName."
<?php
$host = "localhost";
$user = "root";
$pass = "";
$databaseName = "vhc";
$tableName = "users";
$con = mysql_connect($host,$user,$pass);
$dbs = mysql_select_db($databaseName, $con);
$data = array();
$result = mysql_query("SELECT `id`,`name`,`email`,`location` FROM ".$tableName."");
while ( $row = mysql_fetch_row($result) )
{
$data[] = $row;
}
echo json_encode( $data );
?>

XML not parsing in jQuery

When I try to parse my PHP-generated XML file using the jQuery Feeds plugin, it doesn't do what it's supposed to - loop through the template below and output the XML <title> tag in the place of <!=title!>. Instead, it returns just one instance of the template with nothing in place of <!=title!>.
Nothing is returned in the Chrome JavaScript console.
Strangely, I have a similar PHP-generated XML file that works just fine.
Here's the jQuery I'm using:
$('.feed').feeds({
feeds: {
feed1: 'http://www.comfyshoulderrest.com/scrape.php?id=1' // this one doesn't work
},
//max: 3,
loadingTemplate: '<h1 class="feeds-loader">Loading items...</h1>',
entryTemplate: '<div class="item"><div class="image"><img src="images/tie.jpg" style="width: 100%;"></div>' +
'<div class="text"><ul class="list-inline">' +
'<li><span class="price text-warning"><strong>£7.00</strong></span> <span class="text-muted"><strike>£14.00</strike></span></li>' +
'<li class="text-muted"><strong>Topman</strong></li></ul>' +
'<!=title!>' +
'</div></div>'
});
Here's the code that generates the XML file:
<?php
function scrape($list_url, $shop_name, $photo_location, $photo_url_root, $product_location, $product_url_root, $was_price_location, $now_price_location, $gender, $country) {
header("Content-Type: application/xml; charset=UTF-8");
$xml = new SimpleXMLElement('<rss/>');
$xml->addAttribute("version", "2.0");
$channel = $xml->addChild("channel");
$channel->addChild("product_url", $product_url);
$channel->addChild("shop_name", $shop_name);
$channel->addChild("photo_url", $photo_url);
$channel->addChild("was_price", $was_price);
$channel->addChild("now_price", $now_price);
$html = file_get_contents($list_url);
$doc = new DOMDocument();
libxml_use_internal_errors(TRUE);
if(!empty($html)) {
$doc->loadHTML($html);
libxml_clear_errors(); // remove errors for yucky html
$xpath = new DOMXPath($doc);
/* FIND LINK TO PRODUCT PAGE */
$products = array();
$row = $xpath->query($product_location);
/* Create an array containing products */
if ($row->length > 0)
{
foreach ($row as $location)
{
$product_urls[] = $product_url_root . $location->getAttribute('href');
}
}
$imgs = $xpath->query($photo_location);
/* Create an array containing the image links */
if ($imgs->length > 0)
{
foreach ($imgs as $img)
{
$photo_url[] = $photo_url_root . $img->getAttribute('src');
}
}
$result = array();
/* Create an associative array containing all the above values */
foreach ($product_urls as $i => $product_url)
{
$result = array(
'product_url' => $product_url,
'shop_name' => $shop_name,
'photo_url' => $photo_url[$i]
);
$item = $channel->addChild("item");
$item->addChild("product_url", $result['product_url']);
$item->addChild("shop_name", $result['shop_name']);
$item->addChild("photo_url", $result['photo_url']);
}
//print_r($result);
}
else
{
echo "this is empty";
}
echo $xml->asXML();
}
/* CONNECT TO DATABASE */
$dbhost = "xxx";
$dbname = "xxx";
$dbuser = "xxx";
$dbpass = "xxx";
$con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$id = $_GET['id'];
/* GET FIELDS FROM DATABASE */
$result = mysqli_query($con, "SELECT * FROM scrape WHERE id = '$id'");
while($row = mysqli_fetch_array($result)) {
$list_url = $row['list_url'];
$shop_name = $row['shop_name'];
$photo_location = $row['photo_location'];
$photo_url_root = $row['photo_url_root'];
$product_location = $row['product_location'];
$product_url_root = $row['product_url_root'];
$was_price_location - $row['was_price_location'];
$now_price_location - $row['now_price_location'];
$gender = $row['gender'];
$country = $row['country'];
scrape($list_url, $shop_name, $photo_location, $photo_url_root, $product_location, $product_url_root, $was_price_location, $now_price_location, $gender, $country);
}
mysqli_close($con);
?>

make a chain combobox using JCombo

i would like to seek some help with my code because my current code wont work...i found this plugin code from this site click here...as of now all are not working even the first combobox filtration...can anyone help me get this code work please.
index.php:
<!DOCTYPE html>
<html>
<head>
<title>test</title>
<script type="text/javascript" src="jquery/jquery-1.11.0.min.js"></script>
<script type="text/javascript" src="jquery.jCombo.min.js"></script>
<script type="text/javascript" src="jquery.jCombo.js"></script>
</head>
<body>
<form>
<select name="position" id="position"></select>
<select name="salary_grade" id="salary_grade"></select>
<select name="salary" id="salary"></select>
</form>
<script type="text/javascript">
$( document ).ready(function() {
$("#position").jCombo({ url: "getPosition.php", selected_value : '150' } );
$("#salary_grade").jCombo({ url: "getSalary_Grade.php?sgid=",
parent: "#position",
selected_value: '178'
});
$("#salary").jCombo({ url: "getSalary.php?salaryid=",
parent: "#salary_grade",
selected_value: '630'
});
});
</script>
</body>
</html>
getPosition.php:
<?php
// Connect Database
mysql_connect("localhost","root","");
mysql_select_db("test");
// Execute Query in the right order
//(value,text)
$query = "SELECT tcode, position FROM positions";
$result = mysql_query($query);
$items = array();
if($result && mysql_num_rows($result)>0) {
while($row = mysql_fetch_array($result)) {
$option = array("id" => $row[0], "value" => htmlentities($row[1]));
$items[] = $option;
}
}
mysql_close();
$data = json_encode($items);
// convert into JSON format and print
$response = isset($_GET['callback'])?$_GET['callback']."(".$data.")":$data;
echo $data;
?>
getSalary_Grade.php:
<?php
// Connect Database
mysql_connect("localhost","root","");
mysql_select_db("test");
// Get parameters from Array
$sgid = !empty($_GET['tcode'])
?intval($_GET['tcode']):0;
// if there is no city selected by GET, fetch all rows
$query = "SELECT id,salary FROM salary_grades WHERE salary_grades.id = '$sgid'";
// fetch the results
$result = mysql_query($query);
$items = array();
if($result && mysql_num_rows($result)>0) {
while($row = mysql_fetch_array($result)) {
$option = array("id" => $row[0], "value" => htmlentities($row[1]));
$items[] = $option;
}
}
mysql_close();
$data = json_encode($items);
$response = isset($_GET['callback'])?$_GET['callback']."(".$data.")":$data;
$cache->finish($response);
?>
getSalary.php:
<?php
// Connect Database
mysql_connect("localhost","root","");
mysql_select_db("test");
// Get parameters from Array
$salaryid = !empty($_GET['id'])
?intval($_GET['id']):0;
// if there is no city selected by GET, fetch all rows
$query = "SELECT id,salary FROM salarys WHERE salarys.id = '$salaryid'";
// fetch the results
$result = mysql_query($query);
$items = array();
if($result && mysql_num_rows($result)>0) {
while($row = mysql_fetch_array($result)) {
$option = array("id" => $row[0], "value" => htmlentities($row[1]));
$items[] = $option;
}
}
mysql_close();
$data = json_encode($items);
$response = isset($_GET['callback'])?$_GET['callback']."(".$data.")":$data;
$cache->finish($response);
?>

This should work:
getSalary.php
// Connect Database
mysql_connect("localhost","root","");
mysql_select_db("klayton");
// Get parameters from Array
$salaryid = !empty($_GET['salaryid'])
?intval($_GET['salaryid']):0;
// if there is no city selected by GET, fetch all rows
$query = "SELECT id,salary FROM salarys WHERE id = $salaryid";
// fetch the results
$result = mysql_query($query);
$items = array();
if($result && mysql_num_rows($result)>0) {
while($row = mysql_fetch_array($result)) {
$option = array("id" => $row['id'], "value" => htmlentities($row['salary']));
$items[] = $option;
}
}
getSalary_Grades.php
<?php
// Connect Database
mysql_connect("localhost","root","");
mysql_select_db("klayton");
// Get parameters from Array
$sgid = !empty($_GET['sgid'])
?intval($_GET['sgid']):0;
// if there is no city selected by GET, fetch all rows
$query = "SELECT id, salary FROM salary_grades WHERE id = $sgid";
// fetch the results
$result = mysql_query($query);
$items = array();
if($result && mysql_num_rows($result)>0) {
while($row = mysql_fetch_array($result)) {
$option = array("id" => $row['id'], "value" => htmlentities($row['salary']));
$items[] = $option;
}
}