XML not parsing in jQuery - javascript

When I try to parse my PHP-generated XML file using the jQuery Feeds plugin, it doesn't do what it's supposed to - loop through the template below and output the XML <title> tag in the place of <!=title!>. Instead, it returns just one instance of the template with nothing in place of <!=title!>.
Nothing is returned in the Chrome JavaScript console.
Strangely, I have a similar PHP-generated XML file that works just fine.
Here's the jQuery I'm using:
$('.feed').feeds({
feeds: {
feed1: 'http://www.comfyshoulderrest.com/scrape.php?id=1' // this one doesn't work
},
//max: 3,
loadingTemplate: '<h1 class="feeds-loader">Loading items...</h1>',
entryTemplate: '<div class="item"><div class="image"><img src="images/tie.jpg" style="width: 100%;"></div>' +
'<div class="text"><ul class="list-inline">' +
'<li><span class="price text-warning"><strong>£7.00</strong></span> <span class="text-muted"><strike>£14.00</strike></span></li>' +
'<li class="text-muted"><strong>Topman</strong></li></ul>' +
'<!=title!>' +
'</div></div>'
});
Here's the code that generates the XML file:
<?php
function scrape($list_url, $shop_name, $photo_location, $photo_url_root, $product_location, $product_url_root, $was_price_location, $now_price_location, $gender, $country) {
header("Content-Type: application/xml; charset=UTF-8");
$xml = new SimpleXMLElement('<rss/>');
$xml->addAttribute("version", "2.0");
$channel = $xml->addChild("channel");
$channel->addChild("product_url", $product_url);
$channel->addChild("shop_name", $shop_name);
$channel->addChild("photo_url", $photo_url);
$channel->addChild("was_price", $was_price);
$channel->addChild("now_price", $now_price);
$html = file_get_contents($list_url);
$doc = new DOMDocument();
libxml_use_internal_errors(TRUE);
if(!empty($html)) {
$doc->loadHTML($html);
libxml_clear_errors(); // remove errors for yucky html
$xpath = new DOMXPath($doc);
/* FIND LINK TO PRODUCT PAGE */
$products = array();
$row = $xpath->query($product_location);
/* Create an array containing products */
if ($row->length > 0)
{
foreach ($row as $location)
{
$product_urls[] = $product_url_root . $location->getAttribute('href');
}
}
$imgs = $xpath->query($photo_location);
/* Create an array containing the image links */
if ($imgs->length > 0)
{
foreach ($imgs as $img)
{
$photo_url[] = $photo_url_root . $img->getAttribute('src');
}
}
$result = array();
/* Create an associative array containing all the above values */
foreach ($product_urls as $i => $product_url)
{
$result = array(
'product_url' => $product_url,
'shop_name' => $shop_name,
'photo_url' => $photo_url[$i]
);
$item = $channel->addChild("item");
$item->addChild("product_url", $result['product_url']);
$item->addChild("shop_name", $result['shop_name']);
$item->addChild("photo_url", $result['photo_url']);
}
//print_r($result);
}
else
{
echo "this is empty";
}
echo $xml->asXML();
}
/* CONNECT TO DATABASE */
$dbhost = "xxx";
$dbname = "xxx";
$dbuser = "xxx";
$dbpass = "xxx";
$con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$id = $_GET['id'];
/* GET FIELDS FROM DATABASE */
$result = mysqli_query($con, "SELECT * FROM scrape WHERE id = '$id'");
while($row = mysqli_fetch_array($result)) {
$list_url = $row['list_url'];
$shop_name = $row['shop_name'];
$photo_location = $row['photo_location'];
$photo_url_root = $row['photo_url_root'];
$product_location = $row['product_location'];
$product_url_root = $row['product_url_root'];
$was_price_location - $row['was_price_location'];
$now_price_location - $row['now_price_location'];
$gender = $row['gender'];
$country = $row['country'];
scrape($list_url, $shop_name, $photo_location, $photo_url_root, $product_location, $product_url_root, $was_price_location, $now_price_location, $gender, $country);
}
mysqli_close($con);
?>

Related

Get JSON Array into another file via Ajax

I'm trying to add a JSON array from a separate file into another array in my main page via Ajax. For some reason my Ajax is not working, There are 4 arrays, I need to store each of them in separate arrays in my main page. This is what I got.
load file:
<?php
session_start();
if(!isset($_SESSION['usersId']))
{
header("Location: ../index.php");
exit();
}
else
{
include_once 'includes/dbh.inc.php';
}
$id = $_SESSION['userId'];
$dBname = "infosensor";
$conn = mysqli_connect($servername, $dBUsername, $dBPassword, $dBname);
$sql = "SELECT sensor1, sensor2, sensor3 FROM `$id`;";
$result = mysqli_query($conn, $sql);
$jsonsensor1 = array();
$jsonsensor2 = array();
$jsonsensor3 = array();
$jsonsensorsum = array();
if (mysqli_num_rows($result) > 0)
{
while ($row = mysqli_fetch_assoc($result))
{
$jsonsensor1[] = intval($row['sensor1'] * ($p = pow(10, 2))) / $p;
$jsonsensor2[] = intval($row['sensor2'] * ($p = pow(10, 2))) / $p;
$jsonsensor3[] = intval($row['sensor3'] * ($p = pow(10, 2))) / $p;
$jsonsensorsum[] = intval(($row['sensor1'] + $row['sensor2'] + $row['sensor3']) * ($p = pow(10, 2))) / $p;
}
}
echo json_encode($jsonsensor1);
echo json_encode($jsonsensor2);
echo json_encode($jsonsensor3);
echo json_encode($jsonsensorsum);
?>
Output from the load file:
[5,10,10.99,10.99,13,5,14.31,1,1,5,5,5,1,5,3,3,5,5,1,5,10.32,10.32,5,8,5,10,5,5,19,5,7.36,7.36,5,12.2,12.2,2.2,2.2,23.3,5,10.87,6.87,6.87,5,5,10,10,10,10,5,5,5,5,5,0,5,5]
[8,12.5,12.5,12.53,12.53,8,10.11,1,1,8,8,8,1,8,3,3,8,8,1,8,12.83,32.32,8,8,8,10,8.31,8,10,8,18.2,18.2,8,10.3,10.3,2.29,2.29,12.3,8,8.23,2.23,2.23,8,8,10,10,10,20,5,5,5,5,8,0,8,2]
[6,8.86,8.86,8.87,8.87,6,8.33,1,2,6,2,3,1,6,3,8,6,6,1,6,8.32,7.32,6,8,6,10,3.31,6,12,6,12.3,12.3,6,11.1,11.1,4.09,4.09,33.1,6,5.16,12.16,2.16,6,6,10,20,30,30,30,30,5,0,6,0,6,5]
[19,31.36,32.36,32.4,34.4,19,32.76,3,4,19,15,16,3,19,9,14,19,19,3,19,31.47,49.96,19,24,19,30,16.62,19,41,19,37.86,37.86,19,33.6,33.6,8.6,8.6,68.7,19,24.26,21.26,11.26,19,19,30,40,50,60,40,40,15,10,19,0,19,12]
What I tried in my main page:
$(document).ready(function(){
$.getJSON("loadchart.php", function(jsonsensor1){
var sensor1 = [$jsonsensor1];
var sensor2 = [$jsonsensor2];
var sensor3 = [$jsonsensor3];
var sensorsum = [$jsonsensorsum];
});
});
Don't use multiple encode/echo calls. This will just create invalid json. Instead put your data into a single container(an object or array) and encode echo that.
For instance using a normal array:
$data = [$jsonsensor1,$jsonsensor2,$jsonsensor3,$jsonsensorsum];
echo json_encode($data);
And on the front end access them accordingly
$.getJSON("loadchart.php", function(data){
//get the arrays based on what position you put them
//in the array in the backend
//change this if you end up using a different container,
//eg php associative array or object
var sensor1 = data[0];
var sensor2 = data[1];
//and so on
});
Replace this code :
echo json_encode($jsonsensor1);
echo json_encode($jsonsensor2);
echo json_encode($jsonsensor3);
echo json_encode($jsonsensorsum);
With this code :
$data=array("jsonsensor1"=>$jsonsensor1,"jsonsensor2"=>$jsonsensor2,"jsonsensor3"=>$jsonsensor3,"jsonsensorsum"=>$jsonsensorsum);
echo json_encode($data);

Parse returned 2D-Array from PHP-Script to Javascript-Variable inside a Wordpress-Codeblock

So I have a standard php-script, which is stored in an external php-file that is located on the server in the main folder (in this case /html/mysite/getlocations.php).
<?php
function getData() {
// MySQL-Connection-Variables
$servername = "xxxxxxxxxx.hosting-data.io";
$username = "xxxxxxxxxxxxxxxxxx";
$password = "xxxxxxxxxxxxxx";
$dbname = "xxxxxxxxxxxx";
// Create connection
$conn = mysqli_connect( $servername, $username, $password, $dbname );
$conn_number = mysqli_connect( $servername, $username, $password, $dbname );
// Check connection
if ( !$conn ) {
die( "Connection failed: " . mysqli_connect_error() );
}
// SQL-Query for Locations
$sql = "SELECT ID, Beschreibung, Straße, Hausnummer, PLZ, Ort, Bezirk, Leiter, Email, Telefon, Website FROM Locations";
//SQL-Query for Number of Entries
$sql_number = "SELECT COUNT(*) FROM Locations;"
$result = mysqli_query( $conn, $sql );
// Size of MySQL-Table
$size = mysqli_query( $conn_number, $sql );
$counter = 0;
// 2D-Array with all the needed informations for further processing
$returnarray = array();
// Number of Table-Entries > 0
if ( mysqli_num_rows( $result ) > 0 ) {
// Iterate over all Entries
while ( $row = mysqli_fetch_assoc( $result ) ) {
$desription = $row[ "Beschreibung" ];
$street = $row[ "Straße" ];
$number = $row[ "Hausnummer" ];
$plz = $row[ "PLZ" ];
$city = $row[ "Ort" ];
$bezirk = $row[ "Bezirk" ];
$leiter = $row[ "Leiter" ];
$email = $row[ "Email" ];
$phone = $row[ "Telefon" ];
$website = $row[ "Website" ];
$returnarray[$counter] = array();
$returnarray[$counter]['name'] = $desription;
$returnarray[$counter]['street'] = $street;
$returnarray[$counter]['number'] = $number;
$returnarray[$counter]['plz'] = $plz;
$returnarray[$counter]['city'] = $city;
$returnarray[$counter]['bezirk'] = $bezirk;
$returnarray[$counter]['leiter'] = $leiter;
$returnarray[$counter]['email'] = $email;
$returnarray[$counter]['telefon'] = $telefon;
$returnarray[$counter]['website'] = $website;
$counter = $counter + 1;
}
}
// Close connection
mysqli_close( $conn );
return $returnarray;
}
echo getData();
?>
This php-scripts connects to a mysql-database, fetches information and stores it in a twodimensional array.
Now I want to retrieve this returned array and put it in a javascript-variable, so I can use it for further processing inside a Wordpress-Codeblock.
So my attempt was this:
<script type="text/javascript">
var data_from_ajax;
$.get('/html/mysite/getlocations.php', function(data) {
data_from_ajax = data;
});
</script>
But this didnt work like I intended it would.
You can create a JSON string using PHP's built-in json_encode function and parse it in JS with JSON.parse.
I don't think you can pass variables directly to Javascript without serialization.

Executing a Php Mysql function from Onclick NO POST

I have a php Mysql interaction and i wish to trigger the Mysql Search through an ONCLICK event.
iv thought about using a JS function or JQ and parsing the ID of selected through JS function but then im unsure as how i would re-execute the php to re-search the database with the new JS Veriable...
The code below is accurate and is what im working with...
How would i re execute the php with the new ID.. Much appreciated..
<div class="contentheader">
<header> Welcome Please Choose a Catagory</strong></header>
</div>
<div id='smallpagination' class='smallpagination'>
<?php
//search according to chosen search critera NOT LIMITED//
include("conect.php");
$startit = 0;
$startfrom = rand(0, 20);
$displayto = $startfrom + 10;
$search = "";
$startedfrom = $startfrom;
$sql = "SELECT * FROM testdata
WHERE title LIKE '%%$search%%'
LIMIT $startfrom , $displayto";
// check how many results //
$result = $conn->query($sql);
$row_cnt = $result->num_rows;
while ($row = mysqli_fetch_assoc($result)) {
$videos = $row['videos'];
$v_id = $row['id']; //<!---important is Video ID and needed for video click selection---->
$id = $row['id'];
$Name = $row['Name'];
if (empty($Name)) {
$Name = 'Annonymous';
}
$image = $row['image'];
$info = $row['info'];
if (empty($info)) {
$info = 'Contact Listee (if Provided) , No Item Information Given';
}
$phone = $row['phone'];
if (empty($phone)) {
$phone = 'See Listing';
}
$title = $row['title'];
$locate = $row['locate'];
if (empty($locate)) {
$locate = 'Not Provided';
}
$postcoded = $row['postcode'];
if (empty($postcoded)) {
$postcoded = '???';
}
$price = $row['price'];
if (empty($price)) {
$price = '?';
}
if ($price == '0') {
$price = '?';
}
$date = $row['stamp'];
if (empty($date)) {
$date = '';
}
if ($startit < 1) {
$gotid = $row['id'];
$startit = $startit + 1;
};
$vidd = $row['id'] - 0.01;
$pidd = $row['id'] - 0.02;
$type = $row['type'];
$showinglocate = $row['id'] - 0.03;
$showingphone = $row['id'] - 0.04;
$displaytype = "minlist";
//Thumbnails sized listings
if ($displaytype == "minlist") {
echo "
<div class='floaterminhomepage'>
<div class='innerfloaterminhomepage' >";
if (!empty($videos)) {
echo "
<video id='$v_id' style='position:absolute; top:0%; left:0%; width:100%; height:100%; background-size: cover; object-fit:fill;' preload='metadata' onclick='showdata({$v_id});'>
<source src='vid/{$row['videos']}.mp4' type='video/mp4'>
<source src='vid/{$row['videos']}.mp4' type='video/ogg'>
<source src='vid/{$row['videos']}.mp4' type='video/webm'>
</video >";
}
if (empty($videos)) {
echo "<img id='$vidd' src='pageimages/blank.png' style='position:absolute; top:0%; left:0%; width:100%; height:100%;'>";
}
echo "
</div>
</div>
";
}
};
?>
</div> <!---smallpagination--->
<script>
------ > SHOWDATA
RETRIEVE
ID
SCRIPT
HERE < -----
</script>
Then re-execute the folling php
----HOW WOULD I GO ABOUT THIS RE_EXECUTION.
<?php
$displayto = $startfrom;
$sql = "SELECT * FROM testdata
WHERE id={$gotid};
";
// check how many results //
$result = $conn->query($sql);
$row_cnt = $result->num_rows;
while ($row = mysqli_fetch_assoc($result)) {
$videos = $row['videos'];
$v_id = $row['id']; //<!---important is Video ID and needed for video click selection---->
$Name = $row['Name'];
if (empty($Name)) {
$Name = 'Annonymous';
}
$image = $row['image'];
$info = $row['info'];
if (empty($info)) {
$info = 'Contact Listee (if Provided) , No Item Information Given';
}
$phone = $row['phone'];
if (empty($phone)) {
$phone = 'See Listing';
}
$title = $row['title'];
$locate = $row['locate'];
if (empty($locate)) {
$locate = 'Not Provided';
}
$postcoded = $row['postcode'];
if (empty($postcoded)) {
$postcoded = '???';
}
$price = $row['price'];
if (empty($price)) {
$price = '?';
}
if ($price == '0') {
$price = '?';
}
$date = $row['stamp'];
if (empty($date)) {
$date = '';
}
$type = $row['type'];
};
echo "<div id='smallpagdata' class='smallpagdata'>
ID={$v_id}<br>
NAME={$Name}<br>
TITLE={$title}<br>
INFO={$info}<br>
PHONE={$phone}<br>
LOCATION={$locate}<br>
PRICE={$price}<br>
Listed={$date}<br>
</div>";
?>
Does "NO POST" mean "no GET" as well? Otherwise you could put your retrieval script in a different file and call that with jQuery.get or XMLHttpRequest.

How to get a php array index and use it in javascript

I have a PHP script that returns a latitude and longitude from the database.
Then I have a Javascript loop that loops according to the number of rows the PHP query returns and populate my data object with the logitude and latitude at a given index. The challenge now is - how do I get the index without hard coding it?
PHP
$DBhost = 'localhost';
$DBuser = 'root';
$DBpass = '';
$DBname = 'symptoms';
$con = mysqli_connect($DBhost, $DBuser, $DBpass) or die(mysql_error());
mysqli_select_db($con, $DBname);
$query = mysqli_query($con, 'SELECT latitude,longitude FROM markers') or die(mysql_error());
$longArr = array();
$latArr = array();
$count = 0;
while ($row = mysqli_fetch_array($query)) {
$lat = $row['latitude'];
$lon = $row['longitude'];
$latArr[$count] = $lat;
$longArr[$count] = $lon;
++$count;
}
JavaScript
var latArr = [];
var longArr = [];
var markersD = [];
var num = <?php echo $count ?>;
for (var i = 0; i < num; i++) {
var data = {
lat: '<?php echo $latArr[1]?>',
lon: '<?php echo $longArr[1]?>'
}
console.log(data);
}
You have to create json object via php
while($row = mysqli_fetch_array($query))
{
$json[] = array('lat' => $row['latitude'], 'lon' => $row['longitude']);
}
$json_string = json_encode($json);
=== JS ===
var data = <?php echo json_string; ?>;
console.log(data);
You can put all your coords in one array
$coords = array();
while($row = mysqli_fetch_array($query))
{
$coords[] = array(
'latitude' => $row['latitude'],
'longitude' => $row['longitude'],
)
}
and pass it to the js as a JSON object
var data = <?php echo json_encode($coords) ?>;
console.log(data);
All data you need should be available in the javascript

Json working for certain vars but not for others

I've made a script that requests information via Json. For some variables this works just fine, for others it doesn't.
When I use alert() for the variable neighbour1 it says the variable is undefined, when doing the same for the variables number and colour it works just fine.
This is the request script:
function getcolours() {
var hr = new XMLHttpRequest();
hr.open("GET", "camp_map_script.php", true);
hr.setRequestHeader("Content-type", "application/json");
hr.onreadystatechange = function () {
if (hr.readyState == 4 && hr.status == 200) {
var data = JSON.parse(hr.responseText);
for (var obj in data) {
number = data[obj].number;
colour = data[obj].colour;
neighbour1 = data[obj].n1;
alert (neighbour1);
window["colour" + number] = colour;
var x = document.getElementsByClassName(number + ' ' + colour);
x[0].style.display = "block";
}
}
}
hr.send(null);
}
This is the php part:
<?php
include_once("../php_includes/check_login_status.php");
?><?php
$number = "";
$sql = "SELECT camp_id FROM users WHERE username='$log_username'";
$query = mysqli_query($connect, $sql);
$row = mysqli_fetch_row($query);
$campid = $row[0];
$sql = "SELECT players FROM campaigns WHERE id='$campid'";
$query = mysqli_query($connect, $sql);
$row = mysqli_fetch_row($query);
$players = $row[0];
$number = ($players*2)-1;
$sql = "SELECT number, colour, player, n1, n2, n3, n4, n5, n6, n7, n8 FROM lands WHERE camp_id='$campid' ORDER BY number";
$query = $connect->query($sql);
$jsonData = '{';
if ($query->num_rows > 0) {
while($row = $query->fetch_assoc()) {
$jsonData .= '"obj'.$row["number"].'":{"number":"'.$row["number"].'", "colour":"'.$row["colour"].'", "player":"'.$row["player"].'", "n1":"'.$row["n1"].'"},';
}
}
$jsonData = chop($jsonData, ",");
$jsonData .= '}';
echo $jsonData;
$connect->close();
?>
Also when I check the php document the variable n1 is echoed correctly. So the error must be on the java script side or the transit.
It is probably something stupid that I'm overlooking but I just don't see it. I've copy pasted the working parts and changed them to work with other variables but it still doesn't work. :/

Categories

Resources