This question already has answers here:
Programmatically change the src of an img tag
(9 answers)
Closed 5 years ago.
function change(ele) {
document.getElementById('info').innerHTML = ele.alt;
document.getElementById('info').style.backgroundImage = "url(ele.src)";
}
<div id='info'>
This will tell you more about the below image
</div>
<div id='container'>
<div>
<img alt="The mini Barbarian" src="img\barbarian-thumb.jpg" class="pics" onmouseover="change(this)">
</div>
</div>
how do i change the background image of div with id info with the image on which the mouse hover that image is in div tag with id conatiner
please see this. Basically you can bind function inline with html. Or you can bind it dynamically. This is very simple solution. If your image path is fixed.
<script type="text/javascript">
function mouseaway(my_image) {
my_image.src = "someimage.jpg";
}
function rollover(my_image) {
my_image.src = "someimage2.jpg";
}
</script>
<img src="someimage3.jpg" onmouseover="rollover(this)" onmouseout="mouseaway(this)" />
Just assign an id to your image tag and change the image src like this.
function mouseOverImage() {
document.getElementById("img").src = "images/foo.png";
}
<img
id="img"
alt="some description/info"
src="images/blue.png"
onmouseover = "mouseOverImage()"
/>
Hope this will help
$(document).ready(function(){
$("img").hover(function(){
$(this).attr('src', 'images/alt/imagename.jpg');
});
});
Try this:
function change(e){
document.getElementById("info").style.backgroundImage = "url('"+e.src+"')";
document.getElementById("info").style.backgroundRepeat="no-repeat";
}
function change2(e){
document.getElementById("info").style.backgroundImage = "";
}
#info{
height:100px;
}
<div id='info'>
This will tell you more about the below image
</div>
<div id='container'>
<div>
<img alt="The mini Barbarian" src = "data:image/svg+xml;charset=UTF-8,%3Csvg%20width%3D%2264%22%20height%3D%2264%22%20xmlns%3D%22http%3A%2F%2Fwww.w3.org%2F2000%2Fsvg%22%20viewBox%3D%220%200%2064%2064%22%20preserveAspectRatio%3D%22none%22%3E%3Cdefs%3E%3Cstyle%20type%3D%22text%2Fcss%22%3E%23holder_1614068cdea%20text%20%7B%20fill%3Argba(255%2C255%2C255%2C.75)%3Bfont-weight%3Anormal%3Bfont-family%3AHelvetica%2C%20monospace%3Bfont-size%3A10pt%20%7D%20%3C%2Fstyle%3E%3C%2Fdefs%3E%3Cg%20id%3D%22holder_1614068cdea%22%3E%3Crect%20width%3D%2264%22%20height%3D%2264%22%20fill%3D%22%23777%22%3E%3C%2Frect%3E%3Cg%3E%3Ctext%20x%3D%2213.84375%22%20y%3D%2236.5%22%3E64x64%3C%2Ftext%3E%3C%2Fg%3E%3C%2Fg%3E%3C%2Fsvg%3E" class="pics" onmouseover="change(this)" onmouseout="change2(this)">
</div>
</div>
Related
I am new to the javascript programming so can someone help me.
This is my code
var button = document.getElementsByTagName('button')[0];
var pic = document.getElementsByTagName('img')[0];
button.addEventListener('click', colorIt, false);
function colorIt(e) {
pic.innerHTML="src=/'https://picturejs.org/adv/banner.jpg\' width=\'400px\' height=\'150px\'>";
}
<div id="picture">
<img src="" id="picture" style="display:none;">
</div>
<button id="button">Click Me</button>
Change your colorIt function to the following. You need to set the src and then set the display to block. You might also want to move the height and width to CSS.
function colorIt(e) {
pic.src='https://picturejs.org/adv/banner.jpg';
pic.width = 400;
pic.height = 150;
pic.style.display = "block";
}
function fillIt(e) {
pic.innerHTML="src=/'https://picturejs.org/adv/banner.jpg\' width=\'400px\' height=\'150px\'>";
}
The Source for the image in JavaScript is invalid. You used HTML hyperlinks in JS.
.innerHTML modifies the content between the opening and closing tags (<div>THIS</div>), not the content of the tag itself (<div THIS></div>).
You can modify the tags attribute using setAttribute or by setting a property directly:
var button = document.getElementsByTagName('button')[0];
var pic = document.getElementsByTagName('img')[0];
button.addEventListener('click', colorIt, false);
function colorIt(e) {
pic.src='https://picturejs.org/adv/banner.jpg'
pic.width='400px'
pic.height='150px'
}
<div id="picture">
<img src="" id="picture" style="display:none;">
</div>
<button id="button">Click Me</button>
You were on the right track. However, you need to set each property in JS.
ALso I could not get picturejs.org to load so I placed a picsum pic in there instead.
var button = document.getElementsByTagName('button')[0];
var pic = document.getElementsByTagName('img')[0];
button.addEventListener('click', colorIt, false);
function colorIt(e) {
pic.src='https://picsum.photos/150/400'
pic.width='400'
pic.height='150';
pic.style.display='block';
}
<div id="picture">
<img src="" id="picture" style="display:none;">
</div>
<button id="button">Click Me</button>
Please try the below code:
function fillIt(e) {
pic.style.display = "block";
pic.src ="https://libertycity.net/uploads/download/gta5_lamborghini/thumbs/4qhllsfhd8fk9bm4mf36761u37/15205818409903_63e23c-pgta535987529.jpg";
}
You need to add the root of your image in , for example depeding on where you have the image downloaded in your PC.
Hope this helps !
I'm using onerror feature to detect broken links and replace those with an image, the problem is that in my code images that are okay are clickable.
So I want to make it in that way that when the function imageOnError is called to make that image impossible to click.
I tried to do it like this (img).unbind("click");
Lik this also: img.class = "blocked";
but it doesn't work?
<img class="img img-click not-selected " src="" onerror="return imageOnError(this);" />
countImgReplaced = 0;
function imageOnError(img) {
img.onerror = '';
img.src = 'https://dummyimage.com/256x256?text=Broken%20images%20.';
(img).unbind("click");
countImgReplaced ++;
return true;
}
And also I want to get the number of times that the image is replaced I did that with countImgReplaced , but it gives me the total number of images :/
I'm really confused. Can somebody help me?
You can apply pointer-events: none; to them via a class. You can apply that using the classList API
i.e.
img.classList.add('blocked');
You can just do this in HTML tag.
<img src="../resources/images/Image1.jpg" onerror="this.src='https://www.google.co.in/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png';this.style='pointer-events: none'" />
$(document).ready(function(){
$("img").click(function(){
alert("Valid");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div style="clear:both;"><lable>Click in image(Invalid img):</lable>
<img width=200px height=200px src="../resources/images/Image1.jpg" onerror="this.src='https://www.google.co.in/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png';this.style='pointer-events: none'" />
</div>
<div style="clear:both;"><lable>Click in image (Valid img):<lable>
<img width=200px height=200px src="https://encrypted-tbn3.gstatic.com/images?q=tbn:ANd9GcQzltPjpuUfCzEsYbhTYTm4xab4wfmCTFoNllbU5ljLLEAb3VvJXkgpWvU" onerror="this.src='https://www.google.co.in/images/branding/googlelogo/2x/googlelogo_color_272x92dp.png';this.style='pointer-events: none'" /></div>
Here in the line where the image team.gif is set, I have set events onmouseout and onmouseover, but both are not working. Image is not changing, when I put mouse over it. Please help me.
<div id="about" style="position:absolute;top:1310px;width:1340px;height:655px;background-color:black;opacity:0.9">
<div style="position:absolute;top:140px;left:630px;border:thin solid #03c1cb;width:2px;height:460px " >
</div>
<img src="mission.gif" alt="mission" style="position:absolute;top:1400px;right:430px" />
<img src="vision.gif" alt="vision" style="position:absolute;top:1570px;right:420px" />
<img src="team.gif" alt="team" style="position:absolute;top:1610px;right:360px;z-index:100" onmouseover="lighton(this)" onmouseout="lightof(this)" />
<img src="3.gif" alt="light" id ="light"style="position:absolute;top:1360px;right:15px" />
</div>
my javascript code is here
<script>
lighton(x)
{
x.src="team1.gif";
}
lightof(x)
{
x.src="team.gif";
}
</script>
In your script you need to add the function keyword.
<script>
function lighton(x)
// ^^^^^^^^
{
x.src="team1.gif";
}
function lightof(x)
//^^^^^^^^
{
x.src="team.gif";
}
</script>
<img src="team.gif" alt="team" style="position:absolute;top:1610px;right:360px;z-index:100" onmouseover="this.src='team1.gif'" onmouseout="this.src='team.gif'" />
Fiddle https://jsfiddle.net/8wx8r9za/
The page will display an image's url text correctly. But I am not sure how to assign the message to the img 's src to display the image.
<DIV class="msgStyle1" id="message">Waiting for image</DIV>
<div class="imgStyle1" id="message">
<img src=whatneedtogohere /></div>
function displayText(text) {
console.log(text);
document.getElementById("message").innerHTML=text;
window.castReceiverManager.setApplicationState(text);
};
Fixed HTML (switched classes and IDs to make IDs unique) and added an image ID for simplicity:
<div id="msgStyle1" class="message">Waiting for image</div>
<div id="imgStyle1" class="message">
<img src="" id="image" />
</div>
JS:
document.getElementById('image').src = 'http://yourImagePathHere';
See it work here: http://jsfiddle.net/N3rCm/
First off, you shouldn't have multiple Id's on the page, it'll mess with your JS.
Next I would give your image a class if you can
//jquery example of what you would do
var imgSrc = 'http://wherever/youre/getting/this/from';
$('.myimageclass').attr('src', imgSrc);
//non jquery
var myImg = document.getElementsByClassName('myimageclass')[0]; //assuming it's the first one
//or if you can uniquely identify it
var myImg = document.getElementById('imgId');
myImg.src = imgSrc;
As the title suggests, I'm looking to have a little bit of jQuery - if an image is less than a defined width, it adds a class a certain element. This, for me, seems pretty easy but for some reason it's not working.
$(document).ready(function() {
var image = $('.work-each img');
if (image.width() < 500) {
$('.work-text').addClass('work-text-small');
}
});
This, should, add a class 'work-text-small' to the element 'work-text' if the image found under each .work-each is less than 500px.
Example of HTML (for each)
<div class="work-each">
<div>
<img src=""/>
<div class="work-text">
<p>Title</p>
<p>Text</p>
</div>
</div>
</div>
<div class="work-each">
<div>
<img src=""/>
<div class="work-text">
<p>Title</p>
<p>Text</p>
</div>
</div>
</div>
<div class="work-each">
<div>
<img src=""/>
<div class="work-text">
<p>Title</p>
<p>Text</p>
</div>
</div>
</div>
Thanks,
R
Use load instead, when DOM is ready only img tag is defined but the image isn't loaded yet. Its size comes when it's fully loaded
$(window).load(function () {
var image = $('.work-each img');
if (image.width() < 500) {
$('.work-text').addClass('work-text-small');
}
});
However as #rdck pointed if there are more images with class=".work-each img" code won't work so in that case you go trough each image and apply the class
$(window).load(function () {
var image = $('.work-each img');
image.each(function () {
var that = $(this);
if (that.width() < 500) {
that.next('div.work-text').addClass('work-text-small');
}
})
});
If you get dimensions using server code and set class accordingly, there would be no need to wait for image to load and css would immediately take effect as soon as html exists