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Ajax file upload in PHP using javascript popup [duplicate]

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jQuery Ajax File Upload
(27 answers)
Closed 3 years ago.
I am having problem with uploading file with JavaScript Popup. This is my first experience to upload file with such JavaScript popup. I don't know how to pass the input[type:file] to the ajax function and then send to the php file for uploading.
This is the button which calls the popup:
<a class="btn btn-primary btn-sm" data-toggle="modal" data-target="#uploadDocument">Upload Document</a>
<div class="modal fade" id="uploadDocument" role="dialog">
<div class="modal-dialog" style="top: 20%;">
<div class="modal-content">
<!-- Modal Header -->
<div class="modal-header" style="background-color: #367FA9">
<h4 class="modal-title" id="myModalLabel" style="color:white">Upload Document</h4>
</div>
<!-- Modal Body -->
<div class="modal-body" style="padding-top: 20px; padding-right: 40px; padding-left: 40px;">
<!-- <img src="police/images/new.jpg" width="120px" height="100px"> -->
<p id="uploadMD"></p>
<form role="form" id="uploadForm" >
<div class="form-group">
<input type="hidden" name="" id="rowid" value="<?php echo $id; ?>">
</div>
<div class="form-group">
<label>Document Name</label>
<input type="text" name="" id="documentName" class="form-control">
</div>
<div class="form-group">
<label>Document</label>
<input type="file" class="form-control" placeholder="Please Select File" id="documentFile">
</div>
<div class="form-group text-center">
<button type="button" class="btn btn-primary submitBtn block" style="background-color: #367FA9" onclick="uploadDocument()" style="width: 100%;">Upload Document</button>
</div>
</form>
</div>
<!-- Modal Footer -->
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
The javascript code is as follows:
<script>
function uploadDocument(){
var rowid = $('#rowid').val();
var documentName = $('#documentName').val();
var documentFile = $('#documentFile').val();
if(documentName.trim() == '' ){
alert('Please write file name');
$('#documentName').focus();
return false;
}else if(documentFile.trim() == '' ){
alert('Please Select File');
$('#documentFile').focus();
return false;
}else {
$.ajax({
method:'POST',
url:'upload.php',
enctype: 'multipart/form-data',
data:'&rowid='+rowid+'&documentName='+documentName+'&documentFile='+documentFile,
success: function(result){
$('#uploadForm').trigger('reset');
if(result == '1'){
$('#uploadMD').html('<span style="color:green;">Your File is uploaded. Thank you</span>');
setTimeout(function(){ window.location.reload() }, 5000);
}
else{
$('#uploadMD').html('<span style="color:red;">Uploading Problem</span>').fadeIn().delay(5000).fadeOut();
}
}
});
}
}
</script>
and the upload.php file is here:
<?php
$rowid = $_POST['rowid'];
$documentName = $_POST['documentName'];
$file_name = $_FILES['documentFile']['name'];
$file_move = move_uploaded_file($file_tmp,"../uploads/ps/".$file_name);
include "../include/configs.php";
if ($file_move) {
$q2 = "UPDATE requests SET support_doc='$file_name' WHERE slug='$id'";
$query = mysqli_query($con, $q2);
if ($query) {
echo $success = 1;
}
}
?>
Thanks in advance.

Try formdata to pass in php file ajax call
var formData = new FormData();
formData.append('section', 'general');
formData.append('action', 'previewImg');
// Attach file
formData.append('image', $('input[type=file]')[0].files[0]);
$.ajax({
url: 'Your url here',
data: formData,
type: 'POST',
contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+)
processData: false, // NEEDED, DON'T OMIT THIS
// ... Other options like success and etc
});
Thanks

Returning json array does not shows up result on the calling script

I am posting a value on a modal dialog box and then some database operations. Now I am returning a value through
header('Content-Type: application/json', true, 200);
echo json_encode(array('status' => 'active'));
exit();
Is this a right way? All the database operations are performed correctly but console.log(result) does not show anything on the calling script. Something's wrong with the couple of lines above. It would be very helpful if somebody points out the error.
<div class="modal fade" id="myModal" role="dialog" data-backdrop="static" data-keyboard="false">
<div class="modal-dialog">
<!-- Modal content-->
<form name="frmActive" id="frmActive" action="" method="post">
<div class="modal-content" style="height:250px;">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Ideal Time activation</h4>
</div>
<div class="modal-body">
<p>Please enter activation <b>PIN</b><font color="red">*</font><br>
<p id="msg" style="color:#F00;"></p>
<input type="password" name="pin" id="pin" value="" maxlength="4" onKeyUp="checkNumber(this)" class="form-control" placeholder="Enter Pin">
<input type="hidden" id="inactiveTime">
<p style="font-size:11px"><b><font color="red">*</font><font color="grey"><b>PIN</b><i> is mentioned in your welcome email.</font></i></b></p><br>
</div>
<div class="modal-footer">
<button type="button" id="btnSubmit" name="submit" value="submit" class="btn btn-success"><i class="glyphicon glyphicon-floppy-disk"></i> Continue</button>
<input type="hidden" id="module_id" value="<?php echo $moduleId ; ?>">
<input type="hidden" id="chapter_id" value="<?php echo $chapterId ; ?>">
</div>
</div>
</form>
</div>
</div>
jQuery("#btnSubmit").on("click", function(){
var pin = jQuery("#pin").val();
var chapter_id = jQuery("#chapter_id").val();
var module_id = jQuery("#module_id").val();
var nowDate = jQuery.now();
var inactiveTime = jQuery("#inactiveTime").val();
var seconds = (nowDate - inactiveTime) / 1000;
var formData = new FormData();
formData.append("pin", pin);
formData.append("seconds", seconds);
formData.append("module_id", module_id);
formData.append("chapter_id", chapter_id);
$.ajax({
url: "processActivation.php",
type: "POST",
data: formData,
processData: false,
contentType: false,
success: function(result){
if(result['status'] == 'active')
{
jQuery('#myModal').modal('hide');
}
else
{
$("#msg").html(result) ;
}
}
});
});
And processActivation.php,
<?php
$uid = $_SESSION['session_user_id'];
$dobCheck = $db->idToField("tbl_user", "dob", $uid);
$dob = explode("-", $dobCheck);
$pin = $_REQUEST['pin'];
$moduleId = $_REQUEST['module_id'];
$chapterId = $_REQUEST['chapter_id'];
$time_taken = $_REQUEST['seconds'];
$created = date("Y-m-d h:i:s");
if($pin != $dob[0])
{
echo "Please enter valid PIN."; die;
}
else
{
$dataactivation = array("user_id"=>$uid, "module_id"=>$moduleId, "chapter_id"=>$chapterId,"time_taken"=>$time_taken, "created"=>$created);
$db->query_insert("tbl_activation", $dataactivation);
header('Content-Type: application/json', true, 200);
echo json_encode(array('status' => 'active'));
exit();
}
?>
And my browser tool shows,
Loading failed for the <script> with source “http://localhost/project/js/compatibility.js”.
studyChapterpdf.php:54
Use of captureEvents() is deprecated. To upgrade your code, use the DOM 2 addEventListener() method. For more help http://developer.mozilla.org/en/docs/DOM:element.addEventListener
studyChapterpdf.php:240:36
ReferenceError: fakewaffle is not defined[Learn More]
studyChapterpdf.php:492:3
Warning: Setting up fake worker.
pdf.js:1489:5
progress
Object { loaded: 131072, total: 551963 }
bootstrap-pdf-viewer.js:563:9
progress
Object { loaded: 551963, total: 551963 }
bootstrap-pdf-viewer.js:563:9
page=1 - getOperatorList: time=522ms, len=755

Found out the reason for it. There was an uncommented line left in one of the included files. So, the response was having the whole commented line as well as the actual return status==active. Fixed it. Thanks everyone for guiding.

keep the modal open after form submit in codeigniter and trying a bit of ajax

so this is my controller:
User_Authentication_Controller:
public function login_user(){
$username = $this->input->post('txt_login_username');
$password = md5($this->input->post('txt_login_password'));
$result=$this->LogIn_Model->login($username,$password);
redirect('Pages_Controller/homepage');
}
LogIn_Model:
public function LogIn($username,$password){
$data = array(
'username' => $username,
'password' => $password
);
$query = $this->db->get_where('user_account',$data);
return $query->result_array();
}
LOGIN MODAL:
<section id="login_modal" class="modal fade" >
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header"></div>
<div class="modal-body" id="forms">
<div class="loginmodal-container">
<h1>Login to Your Account</h1><br>
<form class="form-horizontal" id="form_login" action="" method="POST">
<div class='error_msg'></div>
<input autofocus="autofocus" type="text" id="txt_login_username" name="txt_login_username" class="form-control" />
<input type="password" id="txt_login_password" name="txt_login_password" class="form-control" />
<button class="btn btn-primary" type="submit" name="btnLogin">Login</button>
Forgot Password?
</div>
</form>
</div>
<div class="modal-footer">
<center><button type = "submit" id="login_user" class="btn btn-danger" data-dismiss="modal" >CLOSE</button></center>
</div>
</div>
</div>
</section>
VIEW:
Login
AJAX:
$(function(){
$('#login_user').submit(function(event){
var user = $('#txt_login_username').val();
var pass = $('#txt_login_password').val();
$.ajax({
type: 'POST',
url: 'User_Authentication_Controller/login_user',
data: {
'user': user,
'pass': pass
},
dataType: 'html',
success: function(results){
if(user != user){
$('.error_msg').html('error msg');
return false;
}
}
});
});
});
ALL I WANT IS IF THERE IS AN ERROR! THE will work and the modal will not close! how will I do that with CI? Is there any possible way that just put the LogIn_Model->login(); in AJAX? please help! I need this thing badly! And in addition I want that what the user inputs and if he got it wrong when he submitted the username will still be at the textbox! how will I do that also? THank you so much for help!

UPDATE form modal bootstrap in codeigniter using AJAX

Been struggling with this for about few hours. I'm attempting to have a modal drop down (Twitter bootstrap modal) that contains a form to choose a category of user. This is built in CodeIgniter. But when i try to save form's value using AJAX, the SUCCESS function won't run without alert(). I'm sorry for my bad grammar, i hope you can understand what i mean.
i need for your help...
view (kasir_halaman.php):
<div id="editModal" class="modal fade" role="modal">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h3 class="modal-title"><span class="glyphicon glyphicon-plus"></span> Ubah Kasir</h3>
</div>
<div class="modal-body">
<form action="#" id="editform" method="post" enctype="multipart/form-data">
<div class="form-group">
<label>Nama</label> <span class="error" id="report1"></span>
<input type="text" id="editnama" name="nama" class="form-control" maxlength="100" required>
</div>
<div class="form-group">
<label>E-mail</label>
<input type="email" id="editemail" name="email" class="form-control" maxlength="150" required>
</div>
<div class="form-group">
<label>Kategori</label>
<select class="form-control" name="kategoripetugas" id="editkategori" required>
<option value=""> -- Pilih Kategori -- </option>
<option value="1">Admin</option>
<option value="2">Kasir</option>
</select>
</div>
<button type="submit" class="btn btn-primary" style="width:100%;">Simpan</button>
</form>
</div>
</div>
</div>
</div>
controller (kasir.php):
public function updatePetugas($id)
{
$nama_petugas = $this->input->post('nama');
$email_petugas = $this->input->post('email');
$kategori_petugas = $this->input->post('kategoripetugas');
$data = array('nama'=>$nama_petugas, 'email'=>$email_petugas, 'kategori'=>$kategori_petugas);
$update = $this->Crud->update(array('idpetugas'=>$id), 'petugas', $data);
if($update){
echo 1;
}else{
echo 2;
}
}
javascript (petugas.js) :
$(document).ready(function(){
var check1=0; var id;
$("#nama").bind("keyup change", function(){
var nama = $(this).val();
$.ajax({
url:'kasir/cekData/kasir/nama/'+nama,
data:{send:true},
success:function(data){
if(data==1){
$("#report1").text("");
check1=1;
}else{
$("#report1").text("*nama petugas sudah terpakai");
check1=0;
}
}
});
});
$(".edit").click(function(){
id = $(this).attr('id');
$.ajax({
url:'kasir/getData/'+id,
data:{send:true},
success:function(data){
$("#editnama").val(data['nama']);
$("#editemail").val(data['email']);
$("#editkategori").val(data['kategori']);
}
});
});
$("#editform").submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url:'kasir/updatePetugas/'+id,
data:formData,
type:'POST',
contentType: false,
processData: false,
success:function(data){
if(data==1){
$("#editModal").hide();
window.location.reload(true);
}else if(data==2){
alert('gagal');
}
}
});
alert("success!"); // if i remove this alert, the success function won't run or executed
});
});

you can solve this a few ways, what is actually happening is that you are submitting the data via ajax as well as submitting the form itself.
using e or the event
$("#editform").submit(function(e){
e.preventDefault();
or by returning false on submit
});
//alert("success!"); we can comment this out because it will work now without the alert holding the page
return false;
});
in either case you can remove your alert.

Ajax is not updating data

I've got a forum in which user is allowed to edit and delete only his comments, I've defined an "edit" button, that by a click of mouse brings down a modal, and in that modal user is allowed to get access to the data's he/she has been sent before, I've written an ajax to target these field and update them whenever the users clicks on "edit" button, code totally makes sense, but so far the functionality doesn't, to make it more clear, user clicks, modal comes down, whatever he/she has been posted will appear in fields, and there is an "edit" button at the bottom of modal, which is responsible for changing and updating data. here is the modal code :
<button id="btn-btnedit" class="btn btn-primary " data-toggle="modal" data-target="#myModal<?php echo $list['id']; ?>">
Edit <i class="fa fa-pencil-square-o"></i>
</button>
<!-- Modal -->
<div class="modal fade" id="myModal<?php echo $list['id']; ?>" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal"><span aria-hidden="true">×</span><span class="sr-only">Close</span></button>
<h4 class="modal-title" id="myModalLabel">Modal title</h4>
</div>
<div class="modal-body">
<div class="container">
<form style="width: 550px;" action="" method="post" id="signin-form<?php echo $list['id']; ?>" role="form">
<input type="hidden" name="commentID" value="<?php echo $list['id']; ?>">
<div class="from-group">
<label for="title">Title: </label>
<input class="form-control" type="text" name="title" id="txttitle" value="<?php echo $list['title']; ?>" placeholder="Page Title">
</div>
<div class="from-group">
<label for="label">Label: </label>
<input class="form-control" type="text" name="label" id="txtlabel" value="<?php echo $list['label']; ?>" placeholder="Page Label">
</div>
<br>
<div class="from-group">
<label for="body">Body: </label>
<textarea class="form-control editor" name="body" id="txtbody" row="8" placeholder="Page Body"><?php echo $list['body']; ?></textarea>
</div>
<br>
<input type="hidden" name="editted" value="1">
<br>
<br>
<input type="submit" id="btnupdate" value="Edit">
</form>
</div>
</div>
as you can see I've assigned "editted" to my "name" attribute, which is later on used to call the query in the database, sql code is as below :
case 'postupdate';
if(isset($_GET['editted'])){
$title = $_GET['title'];
$label = $_GET['label'];
$body = $_GET['body'];
$action = 'Updated';
$q = "UPDATE posts SET title ='".$title."', label = '".$label."', body = '".$body."' WHERE id = ".$_GET['commentID'];
$r = mysqli_query($dbc, $q);
$message = '<p class="alert alert-success"> Your Post Is Succesfully '.$action.'</p>' ;
}
and here is the ajax code snippet;
$('#btnupdate').click(function() {
var tempTitle = $('#txttitle').val();
var tempLabel = $('#txtlabel').val();
var tempBody = $('#txtbody').val();
var tempUrl = "index.php?page=postupdate"+"&title="+tempTitle+"&label="+tempLabel+"&body="+tempBody+"&commentID=30&editted=1";
$.get(tempUrl);
});
I assume there is nothing advance about this segment of code, and i'm missing something very simple, any consideration is highly appreciated :)

This (untested code) may be similar to what you should do:
$('#btnupdate').click(function() {
var tempTitle = $('#txttitle').val();
var tempLabel = $('#txtlabel').val();
var tempBody = $('#txtbody').val();
var tempParams = {"page":"postupdate","title":tempTitle,"label":tempLabel,"body":tempBody,"commentID":30,"editted":1};
$.post("index.php",tempParams,function(data) {
alert(data);
});
});
UPDATE
Try ajax instead of get to see if some error occurs in the loading
$.ajax( {url:"index.php",data:tempParams,type: "POST"} ).done(function() {
alert( "success" );
}).fail(function() {
alert( "error" );
}).always(function() {
alert( "complete" );
});`
UPDATE
Start testing if the click handler works then (just to be sure!):
$('#btnupdate').click(function() { alert("yes at least the button was pressed"); });
UPDATE
Start testing if the script gets executed then:
alert("yes at least the script gets executed");
$('#btnupdate').click(function() { alert("yes at least the button was pressed"); });
If not you must have a javascript error somewhere.
https://webmasters.stackexchange.com/questions/8525/how-to-open-the-javascript-console-in-different-browsers
If yes, your button does not get caught by JQuery (no idea why)
anyway it's got nothing to do with ajax or get!