Alright so I kinda got stuck doing nested queries with firestore because of ForEach and nested Promise returns. From all the previous posts on stackoverflow I understood quite a bit about promises and then nesting them inside ForEach. However, I couldnt find a solution where I nest promise inside forEach which then has another forEach inside it.
I do understand that I have to use Promise.all to make the root forEach wait but how to tell it to wait until the .then() also returns something?
firebase.firestore().collection("Feeds").get().then(feedsSnapshot => {
let promiseArray = [], anotherPromiseArray = [];
feedsSnapshot.forEach(function (feed) {
let promise = checkifILikedTheFeed(feed).then(like => {
return like;
}).then(like => {
let anotherPromise = firebase.firestore().collection("Feeds").doc(feed.id).collection("Likes").get()
.then(likesSnapshot => {
if(likesSnapshot.empty){
return {
// return myData
};
} else {
let countLikes = 0;
likesSnapshot.forEach(likeDoc => {
if(likeDoc.data().isLike){
countLikes++;
}
});
return {
//myData + countLikes
};
}
});
anotherPromiseArray.push(anotherPromise);
// ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
// I thought this would work, sadly doesnt.
});
promiseArray.push(promise);
});
return Promise.all([promiseArray,anotherPromiseArray]);
}).then(feeds => {
console.log(feeds);
// ^^^^^^^^^^^^^^^^^^^
// returns [[undefined],[undefined]]
dispatch({
type: 'RETRIEVE_FEEDS',
payload: feeds,
});
});
Related
I have few api call requests which i am trying to create promises and then execute all using Promise.all but, its giving empty value instead of array. Below is my code.
function getUser(arrUser) {
var student = [];
return new Promise((resolve, reject) => {
if (arrUser.length > 0) {
var promises = arrUseridRequest.map(userRequeset => {
return getRequest(userRequeset).then(result => {
student.push(JSON.parse(result.body).result[0].Name);
console.log(student); //This is giving right details.
}).catch(error => {
reject(error);
});
});
Promise.all(promises).then(StuName => {
resolve(StuName.join());
})
}
});
}
and this is how i am trying to get the values at once:
getUser('123').then(student => {
console.log(Student) //Coming as empty
});
getRequest is my api call nodeJs request module. What's wrong in my code?
All your promises fulfill with the value undefined since you're just logging the student names, but not returning them from the then callback. As you seem to be doing only a single request, the array will be [undefined], which is joined into the empty string.
Also avoid the Promise constructor antipattern:
function getUsers(arrUser) {
const promises = arrUser.map(userId => {
return getRequest(userId).then(result => {
const students = JSON.parse(result.body).result;
return students[0].Name;
});
});
return Promise.all(promises);
}
getUsers(['123']).then(studentNames => {
console.log(studentNames);
console.log(studentNames.join());
}).catch(console.error);
I need a solution to this below confusion i have .
I have a list of promises outer_promises_list.
Inside the promise.then of each promise in this outer_promises_list , I have another list of promises inner_promises_list
What I want is a method which gets called when all the outer promises and all the promises inside them get resolved .
Here is my code to get the context :
fetch = require("node-fetch")
function all_promises_resolved_method() {
console.log("All promises resolved ! ");
}
function start_main_process() {
let outer_promises_list = []
let inner_promises = []
start_urls_list.forEach(url => {
outer_promises_list.push(fetch(url).then(resp => resp.text()))
})
outer_promises_list.forEach((outer_prom) =>
{
outer_prom.then(htmlbody =>
{
inner_promises = inner_promises.concat(get_theater_promises());
inner_promises.forEach(inner_prom => {
inner_prom.then(inner_resp => {
inner_resp.clone().text().then(inner_html_body => {
console.log("do synchronous stuff on this html body ");
})
})
})
})
console.log("inner promises skipped , will be resolved later ");
Promise.all(inner_promises.concat(outer_promises_list)).then(all_promises_resolved_method)
})
}
function get_inner_promises() {
inner_promises = []
[url1, url2, url3].forEach((url)=>{
inner_promises.push(fetch(href))
})
return inner_promises;
}
start_main_process() ;
My issue is that all_promises_resolved_method is called only when the inner_promises of the first outer promise is resolved . I need a solution to call that method when all outer promises and each of all of those inner promises are resolved. What's the easiest way and efficient way to do this ?
It seems you missed a few things in your pseudocode or there is some typo. Also, you are calling Promise.all on outer_promises_list and inner_promises twice, not sure why. Following is my solution, anyway.
Please remember that JS Promise is designed to avoid nested code. So if you are using promises while nesting callbacks or Promises, most likely you are not doing it right.
fetch = require("node-fetch")
function all_promises_resolved_method() {
console.log("All promises resolved ! ");
}
function start_main_process() {
let outer_promises_list = []
let inner_promises = []
start_urls_list.forEach(url => {
outer_promises_list.push(fetch(url).then(resp => resp.text()))
})
Promise.all(outer_prom)
.then(htmlbodyArr => {//it is an array of resolved values from all the promises in outer_prom
/*
I don't know how you are using htmlBody to create inner promise.
Following is my best guess
*/
htmlbodyArr.forEach((htmlBody)=>{
inner_promises.push(get_theater_promises(htmlBody));
})
return inner_promises;
})
.then((inner_promises)=>{
return Promise.all(inner_promises)
})
.then((innerPromiseResultArr)=>{
all_promises_resolved_method();
})
.catch((err)=> console.log(err))
/*
outer_promises_list.forEach((outer_prom) =>
{
outer_prom.then(htmlbody =>
{
inner_promises = inner_promises.concat(get_theater_promises());
inner_promises.forEach(inner_prom => {
inner_prom.then(inner_resp => {
inner_resp.clone().text().then(inner_html_body => {
console.log("do synchronous stuff on this html body ");
})
})
})
})
console.log("inner promises skipped , will be resolved later ");
Promise.all(inner_promises.concat(outer_promises_list)).then(all_promises_resolved_method)
})
*/
}
function get_inner_promises() {
inner_promises = []
[url1, url2, url3].forEach((url)=>{
inner_promises.push(fetch(href))
})
return inner_promises;
}
start_main_process() ;
After a bunch of looking into Futures, Promises, wrapAsync, I still have no idea how to fix this issue
I have this method, which takes an array of images, sends it to Google Cloud Vision for logo detection, and then pushes all detected images with logos into an array, where I try to return in my method.
Meteor.methods({
getLogos(images){
var logosArray = [];
images.forEach((image, index) => {
client
.logoDetection(image)
.then(results => {
const logos = results[0].logoAnnotations;
if(logos != ''){
logos.forEach(logo => logosArray.push(logo.description));
}
})
});
return logosArray;
},
});
However, when the method is called from the client:
Meteor.call('getLogos', images, function(error, response) {
console.log(response);
});
the empty array is always returned, and understandably so as the method returned logosArray before Google finished processing all of them and returning the results.
How to handle such a case?
With Meteor methods you can actually simply "return a Promise", and the Server method will internally wait for the Promise to resolve before sending the result to the Client:
Meteor.methods({
getLogos(images) {
return client
.logoDetection(images[0]) // Example with only 1 external async call
.then(results => {
const logos = results[0].logoAnnotations;
if (logos != '') {
return logos.map(logo => logo.description);
}
}); // `then` returns a Promise that resolves with the return value
// of its success callback
}
});
You can also convert the Promise syntax to async / await. By doing so, you no longer explicitly return a Promise (but under the hood it is still the case), but "wait" for the Promise to resolve within your method code.
Meteor.methods({
async getLogos(images) {
const results = await client.logoDetection(images[0]);
const logos = results[0].logoAnnotations;
if (logos != '') {
return logos.map(logo => logo.description);
}
}
});
Once you understand this concept, then you can step into handling several async operations and return the result once all of them have completed. For that, you can simply use Promise.all:
Meteor.methods({
getLogos(images) {
var promises = [];
images.forEach(image => {
// Accumulate the Promises in an array.
promises.push(client.logoDetection(image).then(results => {
const logos = results[0].logoAnnotations;
return (logos != '') ? logos.map(logo => logo.description) : [];
}));
});
return Promise.all(promises)
// If you want to merge all the resulting arrays...
.then(resultPerImage => resultPerImage.reduce((accumulator, imageLogosDescriptions) => {
return accumulator.concat(imageLogosDescriptions);
}, [])); // Initial accumulator value.
}
});
or with async/await:
Meteor.methods({
async getLogos(images) {
var promises = [];
images.forEach(image => {
// DO NOT await here for each individual Promise, or you will chain
// your execution instead of executing them in parallel
promises.push(client.logoDetection(image).then(results => {
const logos = results[0].logoAnnotations;
return (logos != '') ? logos.map(logo => logo.description) : [];
}));
});
// Now we can await for the Promise.all.
const resultPerImage = await Promise.all(promises);
return resultPerImage.reduce((accumulator, imageLogosDescriptions) => {
return accumulator.concat(imageLogosDescriptions);
}, []);
}
});
I have a server GET request where I am trying to create a promise from a function but it's not going too well. I need this promise to be optional, if that's possible, so that if the result is empty it should be ignored (I've marked where it shouldn't carry on with the function with the words IGNORE FUNCTION).
The idea is that it loops through the docs inside the snapshot, and adds them to an array calls jamDocs. Then if that array isn't empty it should loop through each jam and call an async function for each of them. This then sets the jam's hostName. When this is completed, the original promise should return the jamDocs.
If the jamDocs are empty, the whole promise should be ignored. Finally, after other promises are completed (there is one called profilePromise that returns a profile object), the jams should be assigned to the profile object, and the object sent back to the client with a 200 status code.
My code:
var jamsQuery = firebase.db.collection('users')
.where("hostId", "==", id)
.orderBy("createdAt")
.limit(3)
var jamsPromise = jamsQuery.get().then(snapshot => {
var jamDocs = []
snapshot.forEach(doc => {
var jam = doc.data()
jam.id = doc.id
jamDocs.push(jam)
})
if (!snapshot.length) { // Error: Each then() should return a value or throw
return // IGNORE FUNCTION
} else {
var jamNamePromises = jamDocs.map(function(jam) {
var jamRef = firebase.db.collection('users').doc(jam.hostId)
return jamRef.get().then(doc => {
if (doc.exists) {
jam.hostName = doc.data().firstName
return jam
} else {
throw new Error("yeah")
}
})
})
Promise.all(jamNamePromises)
.then(function() {
return jamDocs
})
.catch(...)
}
})
// Later on
Promise.all(profilePromise, jamsPromise)
.then(objectArray => {
var profile = objectArray[0]
myProfile.jams = jamDocs
return res.status(200).send(myProfile);
})
.catch(
res.status(500).send("Could not retrieve profile.")
)
I get errors like: Each then() should return a value or throw and Avoid nesting promises. How do I fix this? Thanks!
Your then on this line doesn't return anything and also has nested promises in it.
var jamsPromise = jamsQuery.get().then(snapshot => {
You should refactor it, to move the nested promises outside of this then:
var jamsPromise = jamsQuery.get()
.then(snapshot => {
var jamDocs = []
snapshot.forEach(doc => {
var jam = doc.data()
jam.id = doc.id
jamDocs.push(jam)
})
if (!snapshot.length) {
return // IGNORE FUNCTION
} else {
var jamNamePromises = getJamDocsPromises();
return Promise.all(jamNamePromises);
})
.catch(...)
});
function getJamDocsPromises(jamDocs) {
return jamDocs.map(function(jam) {
var jamRef = firebase.db.collection('users').doc(jam.hostId)
return jamRef.get().then(doc => {
if (doc.exists) {
jam.hostName = doc.data().firstName
return jam
} else {
throw new Error("yeah")
}
});
}
If the result is empty it should be ignored (shouldn't carry on with the function). If that array isn't empty it should loop through each jam
Don't make it more complicated than it needs to be. Looping over an empty collection does nothing anyway, so you don't need a special case for that. Just continue normally with the empty array.
var jamsPromise = jamsQuery.get().then(snapshot => {
var jamDocs = []
snapshot.forEach(doc => {
jamDocs.push(Object.assign(doc.data(), {id: doc.id}))
})
return Promise.all(jamDocs.map(function(jam) {
return firebase.db.collection('users').doc(jam.hostId).get().then(doc => {
if (doc.exists) {
jam.hostName = doc.data().firstName
return jam
} else {
throw new Error("yeah")
}
})
}))
})
I get errors like: Each then() should return a value or throw
You had forgotten a return in front of the Promise.all.
and Avoid nesting promises. How do I fix this?
There's nothing wrong with nesting promises, but in your case the .then(() => jamDocs) was not necessary since the Promise.all already resolves with an array of all the jams that the inner promises fulfill with.
I have the following functions with promises:
const ajaxRequest = (url) => {
return new Promise(function(resolve, reject) {
axios.get(url)
.then((response) => {
//console.log(response);
resolve(response);
})
.catch((error) => {
//console.log(error);
reject();
});
});
}
const xmlParser = (xml) => {
let { data } = xml;
return new Promise(function(resolve, reject) {
let parser = new DOMParser();
let xmlDoc = parser.parseFromString(data,"text/xml");
if (xmlDoc.getElementsByTagName("AdTitle").length > 0) {
let string = xmlDoc.getElementsByTagName("AdTitle")[0].childNodes[0].nodeValue;
resolve(string);
} else {
reject();
}
});
}
I'm trying to apply those functions for each object in array of JSON:
const array = [{"id": 1, "url": "www.link1.com"}, {"id": 1, "url": "www.link2.com"}]
I came up with the following solution:
function example() {
_.forEach(array, function(value) {
ajaxRequest(value.url)
.then(response => {
xmlParser(response)
.catch(err => {
console.log(err);
});
});
}
}
I was wondering if this solution is acceptable regarding 2 things:
Is it a good practice to apply forEach() on promises in the following matter.
Are there any better ways to pass previous promise results as parameter in then() chain? (I'm passing response param).
You can use .reduce() to access previous Promise.
function example() {
return array.reduce((promise, value) =>
// `prev` is either initial `Promise` value or previous `Promise` value
promise.then(prev =>
ajaxRequest(value.url).then(response => xmlParser(response))
)
, Promise.resolve())
}
// though note, no value is passed to `reject()` at `Promise` constructor calls
example().catch(err => console.log(err));
Note, Promise constructor is not necessary at ajaxRequest function.
const ajaxRequest = (url) =>
axios.get(url)
.then((response) => {
//console.log(response);
return response;
})
.catch((error) => {
//console.log(error);
});
The only issue with the code you provided is that result from xmlParser is lost, forEach loop just iterates but does not store results. To keep results you will need to use Array.map which will get Promise as a result, and then Promise.all to wait and get all results into array.
I suggest to use async/await from ES2017 which simplifies dealing with promises. Since provided code already using arrow functions, which would require transpiling for older browsers compatibility, you can add transpiling plugin to support ES2017.
In this case your code would be like:
function example() {
return Promise.all([
array.map(async (value) => {
try {
const response = await ajaxRequest(value.url);
return xmlParser(response);
} catch(err) {
console.error(err);
}
})
])
}
Above code will run all requests in parallel and return results when all requests finish. You may also want to fire and process requests one by one, this will also provide access to previous promise result if that was your question:
async function example(processResult) {
for(value of array) {
let result;
try {
// here result has value from previous parsed ajaxRequest.
const response = await ajaxRequest(value.url);
result = await xmlParser(response);
await processResult(result);
} catch(err) {
console.error(err);
}
}
}
Another solution is using Promise.all for doing this, i think is a better solution than looping arround the ajax requests.
const array = [{"id": 1, "url": "www.link1.com"}, {"id": 1, "url": "www.link2.com"}]
function example() {
return Promise.all(array.map(x => ajaxRequest(x.url)))
.then(results => {
return Promise.all(results.map(data => xmlParser(data)));
});
}
example().then(parsed => {
console.log(parsed); // will be an array of xmlParsed elements
});
Are there any better ways to pass previous promise results as
parameter in then() chain?
In fact, you can chain and resolve promises in any order and any place of code. One general rule - any chained promise with then or catch branch is just new promise, which should be chained later.
But there are no limitations. With using loops, most common solution is reduce left-side foldl, but you also can use simple let-variable with reassign with new promise.
For example, you can even design delayed promises chain:
function delayedChain() {
let resolver = null
let flow = new Promise(resolve => (resolver = resolve));
for(let i=0; i<100500; i++) {
flow = flow.then(() => {
// some loop action
})
}
return () => {
resolver();
return flow;
}
}
(delayedChain())().then((result) => {
console.log(result)
})