HTML: Additional search filters control - javascript

I am using Node.js as a backend and JQuery as a frontend and I have a search box with filters as checkboxes below it see the next image
Now when I click on the filter it will be added to a used filter list also provided as an image
Then when i click on the x next to the filter it will be deleted and also unchecked. all of the prev things are working in the next code:
$('[id^="facet-"]').on('change',function(){
let xMark = '<i id="'+$(this).attr('id')+'-remove-filter" class="fa fa-times-circle" aria-hidden="true"></i>'
let key = $(this).data('key')
let keyVal = '<div id="'+$(this).attr('id')+'-span" class="btn"><span>'+$(this).data('key')+ ' > ' +$(this).data('value')+'</span>'+xMark+'</div>'
if($(this).is(':checked')){
$('.'+key+'-filters').append(keyVal)
}else{
$('#'+$(this).attr('id')+'-span').remove()
}
$('i[id$="-remove-filter"]').on('click',function(){
let checkboxId = $(this).attr('id').split('-remove-filter')[0]
$('#'+checkboxId).prop('checked', 0)
$(this).parent().remove()
})
})
As I said it's working and good so far, what should happen next is when you click on search it will take all checkboxes and post them to get some search results (this is also working since I surrounded the page with one form.
What I need is when the filters set has at least one checkbox inside it to be bordered like the next photo
I did this using the following piece of code:
$('[aria-controls="'+$(this).data('key')+'-facets"]').addClass('has-selected')
This will keep it bordered whenever some filter has been selected once and I can remove the border using
$('[aria-controls="'+$(this).data('key')+'-facets"]').removeClass('has-selected')
Here I have couple of questions
how to keep the border as long as there is at least one selected checkbox and remove it only when there are 0 selected? please note that there is more than one filters set!
I think this could be some sort of a library for people to use (with some adjustments of course). Where do I start with this?
Is there any better to apply this whole procedure? adding a filter , removing the checkbox?

Let me know if this works, I sadly can't test it:
$('[id^="facet-"]').on('change',function(){
var id = $(this).attr('id')
var key = $(this).data('key')
var value = $(this).data('value')
if($(this).is(':checked')){
let xMark = $('<i id="'+id+'-remove-filter" class="fa fa-times-circle" aria-hidden="true"></i>')
let keyElement = $('<div id="'+id+'-span" class="btn"><span>'+key+ ' > ' +value+'</span></div>')
$('.'+key+'-filters').append(keyElement)
keyElement.append(xMark)
xMark.bind('click',function(){
let checkboxId = id.split('-remove-filter')[0]
$('#'+checkboxId).prop('checked', 0).change()
// adding the change() method here will trigger the event all over again to control adding/removing class
$(this).parent().remove()
})
}else{
$('#'+id+'-span').remove()
}
var panel = $('[aria-controls="'+key+'-facets"]')
var checked_num = panel.find('input[type=checkbox]:checked').length
if(checked_num>0)
panel.addClass('has-selected')
else
panel.removeClass('has-selected')
})

Related

Link two elements, store them, and send them to remove function - Pure Javascript

I have a little Pure Javascript prototype demonstrating shopping cart functionality.
I have a Button which adds the item to the cart (and toggles to an ON state) and then a Card which represents the item in the shopping cart.
So far I have worked;
Attach data to Add to Cart Button ✓
Send data from Button to Shopping Cart and create new Item Card ✓
However, I cannot work out how to link Button and newly created Item Card so I can:
Remove Item Card and toggle button OFF or
Toggle button OFF and remove the correct Item Card
https://codepen.io/rhysyg03/pen/PdyyWE
Your help would be much appreciated.
FYI - this is just for a demo so it doesn't need to be production ready code.
Thank you.
const shoppingCartEl = document.querySelector('#js-shopping-cart');
const addToCartButton = document.querySelector('#js-add-to-cart');
var buttonToggle = false;
var itemOneData = {
name:'Shoes',
price:"$105.00"
}
function addItem(button, itemData) {
console.log("ADD");
// var itemEl = createElement('<div class="item-card"></div>');
const itemEl = document.createElement("div");
itemEl.classList.add("item-card");
itemEl.innerHTML = itemData.name + itemData.price + "<button id='js-item-cart-remove'>Remove</button>";
shoppingCartEl.appendChild(itemEl);
const itemCardRemove = document.querySelector('#js-item-cart-remove');
itemCardRemove.addEventListener('click', () => {
removeItem();
})
}
function removeItem() {
console.log("REMOVE");
// how to do this part
}
addToCartButton.addEventListener('click', () => {
if (buttonToggle == false) {
addItem(addToCartButton, itemOneData);
buttonToggle = true;
addToCartButton.innerHTML = "Remove from Cart";
} else {
// How to do this part
removeItem();
buttonToggle = false;
addToCartButton.innerHTML = "Add to Cart";
}
})
(I am sorry I am tired a bit, you should read the very ending, firstly)
You should have items like this:
var itemOneData = {
id: 1,
name:'Shoes',
price:"$105.00"
}
var itemTwoData = {
id: 2,
name:'Shoes',
price:"$105.00"
}
Then you should store identifier on the item card element:
...
itemEl.classList.add("item-card");
itemEl.setAttribute("data-item-id", itemData.id)
...
After this, when clicking on remove button, you should:
Get the id of item to be removed itemEl.getAttribute("data-item-id")
Pass the id to remove function removeItem(id)
(this was where I've given up) Find the item with the attribute "data-item-id" having value of the id and replace it to empty string ""
There is another solution, probably far less complex: when clicking on remove button simply find it's parent and replace it with empty string.
This is a quick solution, just to get what you are looking for, but of course, maybe you should be having some 'state' where you have your cart items, and render the UI based on that state. In this quick solution, what I am doing is event delegation, as we know that the one element that will exist at the beginning is the cart div. So we place the event on this element and then check which element are we clicking, and also doing some check so we assure only that an item-card can be deleted. codepen.io/anon/pen/WgaYxe?editors=1011
Hope this helps and if you need more details please feel free to ask!
Bye

How do I use session variables with jQuery?

I have a button on one page another button on a different page. This second button has the text in it "0 items selected". When the first button is clicked I want to increase the number in the second button by one.
Seeing it is transferring data over different pages I didn't manage to do it the standard way.
Please do not suggest PHP, I am unable to use it.
var yetVisited = localStorage[0];
if ($('.#CallToActionCustomise').click()){
localStorage++;
}
$('.#CallToActionCustomise').click(function(){
$(".Main_MenuButtonReview").append(localStorage);
});
<button class="Main_MenuButtonReview">0 items selected <i class="fa fa-caret-down"></i></button>
You need to access localStorage as if it were an Object, not an array.
Also, you can only store String values, so to get a number to perform math on, you will need to use parseInt.
localStorage.setItem('yetVisited', 0);
$(".Main_MenuButtonReview").text(localStorage.yetVisited + ' items selected');
$('.CallToActionCustomise').click(function()){
localStorage.yetVisited = parseInt(localStorage.yetVisited) + 1;
$(".Main_MenuButtonReview").text(localStorage.yetVisited + ' items selected');
}
Here's an example.
In addition to the above answer, I think you need to init some tag when it loaded.
Put this code on another page.
$(document).ready(function() {
if (typeof localStorage.yetVisited === 'undefined') {
localStorage.setItem('yetVisited', 0);
}
yetVisited = localStorage.yetVisited;
$('.Main_MenuButtonReview').text(yetVisited + ' items selected');
});
$(document).ready(function() {
// this area means after your page(document) ready completely.
});

Make text visible from javascript

I got a droppable area where user can drop item. And I have a field which counts difference between required and dropped items. Here is example
And line where I display difference after dropping item:
$(this).closest("div.proc")
.find('.dif')
.text('Difference: ' + ( $(this).closest("div.proc").find('.numbr').text() - n) );
The problem is how can I display difference from the beginning. So user can see it even without dropping any item. Thank you
Insert this in your code:
$(".dif").each(function(){
var $e = $(this);
$e.text('Difference: ' + $e.closest("div.proc").find('.numbr').text());
});
in the outermost scope (like just after var itm = [];).
Put your logic in $(document).ready() and display text for each div as below:
$(document).ready(function(){
$('.projLeader label').each(function(){
$(this).find('.dropped').text("Items Dropped :0")
$(this).find('.dif').text("Difference : "+$(this).find('.numbr').text())
})
})
UPDATED DEMO

jQuery - remove li from array with delete image

I'm attempting to make a menu bar that can have <li> elements added and removed. So far so good, but when I try and remove them I'm running into issues. I've toyed with this for a couple hours and now I'm wondering if this whole process could just be made easier (maybe an object?).
Anyways, here's the full code (80 lines), with comments to follow along.
var tabs = $('.accountSelectNav');
var titles = [];
var listItems = [];
// when the page loads check if tabs need to be added to the ul (menu bar)
$(document).ready(function(e) {
if ($.cookie('listItems') != null) {
console.log('not null');
//return "listItems" to it's array form.
listItems = JSON.parse($.cookie('listItems'));
$('.accountSelectNav').append(listItems);
}
});
$('.selectTable td:first-child').on('click', function(e) {
$('#home_select').removeClass('navHighlight');
//grab the text value of this cell
title = $(this).text();
$.ajax({
url:'core/functions/getAccountId.php',
type: 'post',
data: {'title' : title}
}).fail (function() {
alert('error');
}).done(function(data) {
accountId = $.trim(data);
// store values in the cookie
$.cookie('account_id', accountId, {expires : 7});
$.cookie('title', title, {expires : 7});
window.location = ('home_table.php');
});
// make sure the value is NOT currently in the array. Then add it
var found = jQuery.inArray(title, titles);
if (found == -1) {
titles.push(title);
addTab();
}
// make sure the value is NOT currently in the array. Then add it
found = jQuery.inArray(title, listItems);
if (found == -1) {
addListItem();
//place <li>'s in cookie so they may be used on multiple pages
$.cookie('listItems', JSON.stringify(listItems));
};
});
$("body").on("click", ".deleteImage", function (e) {
var removeTitle = $(this).closest('li').find('a').text();
var removeItem = $(this).closest('li')[0].outerHTML;
//remove title from "titles" array
titles = jQuery.grep(titles, function (value) {
return value != removeTitle;
});
//remove <li> from "listItems" array
listItems = jQuery.grep(listItems, function (value) {
return value != removeItem;
});
// this shows the <li> is still in the listItemsarray
console.log(listItems);
// put the array back in the cookie
$.cookie('listItems', JSON.stringify(listItems));
removeTab(this);
});
$("body").on("mouseover", ".accountSelectNav li", function(e) {
$(this).find('.deleteImage').show();
});
$("body").on("mouseleave", ".accountSelectNav li", function(e) {
$(this).find('.deleteImage').hide();
});
function addTab() {
tabs.append('<li class="navHighlight">' + '' + title + '' + '' + '<img src="images/delete.png" class="deleteImage"/>' + '' + '</li>');
};
function removeTab(del) {
$(del).closest('li').remove();
}
function addListItem() {
var s = ('<li class="navHighlight">' + '' + title + '' + '' + '<img src="images/delete.png" class="deleteImage"/>' + '' + '</li>');
listItems.push(s);
}
So you see I have two arrays of equal length that should always be the same length. One stores the title to be displayed in the tab, the other holds the html for the <li> which will be appended to the <ul>. I have no problem removing the title from its array. However removing the <li> from it's array is becoming a rather big hassle. You see when I get the <li> element after its been inflated the html inside does not exactly match what was put in, the browser adds style elements.
Example, the variable "removeItem" represents the html value of the selected <li> I wish to remove. It looks like this:
<li class="navHighlight">Test1<img src="images/delete.png" class="deleteImage" style="display: inline;"></li>
yet the value in my array "listItems" looks like this:
<li class="navHighlight">Test1<img src="images/delete.png" class="deleteImage"/></li>
So my attempt at removing it from my array always fails because they aren't a perfect match.
Now my question is how do I remove this <li> item? Also is there an easier way to do this whole process and I'm just not seeing it?
Thanks for your time.
EDIT
Fiddle by request here
Easiest way I can explain it.
Click the link to the fiddle.
Click any cell in the "App Name" column
This will add a <li> to the <ul> (menu) above of the table
When you hover over the <li> a picture appears
Click the picture
This should remove the <li>, both from the <ul> and from the array listItems
right now it does not
In the process of making this easier to check, I've taken your JSFiddle and did the following:
removed extra console.log and comments
removed interaction with cookies (since I did not have them in the first place, I figured they wouldn't just the first scenario)
After doing so I reached a point (you can see it here) where the desired functionality just works.
I even went ahead and removed the ajax stuff because that alert was driving me crazy. (here)
Since this works fine, my guess is that your issue lies between the lines that I removed.
Your usage of cookies is as follows:
To load existing tabs and add them back again
To save account_id and title, which is not used back again
To persist the listItems after a new item has been added
I then opened up the console with your version of the fiddle and the execution of javascript stops at $.cookie() with the error undefined is not a function.
This clearly indicates that the issue present in the Fiddle is that jQuery.cookie is not present and so those calls are halting the execution of the rest of your script. This also explains why it just started working when I took them out.
I posted the whole process of how I got there to indicate how I trimmed down the problem to specific parts, which is useful to reduce the problem space. When you're out of options and reach a place when you're lost, it's easier to post a question with less code and the specific part of the problem that you've identified. This will help you in finding the issues that you're facing and StackOverflow to provide proper answers to your questions.
Hope it helps!
Here is the solution I came up with. It should be much easier for people to understand than my original post. Although it's a long read it may be worth it, especially for new developers.
The point of this code is to make a menu bar out of an un-ordered list or <ul>. The menu bar needs to be used on multiple pages. So I'll be using cookies.
I start with this code to get a text value from my table.:
$('.selectTable td:first-child').on('click', function(e) {
// This value will be used later for the name of the tab or `<li>` inside our menu bar or `<ul>`
title = $(this).text();
});
Then I place the value in an array. I do this only if the array does not already have this string inside it. I do not want duplicates:
var found = jQuery.inArray(title, titles);
var titles = [];
if (found == -1) {
titles.push(title);
}
Then I store the array into a cookie, using a library like this:
$.cookie('titles', JSON.stringify(titles));
Now when any page loads that needs this menu bar I run this code to check if there are any values:
$(document).ready(function() {
if ($.cookie('titles') != null) {
titles = JSON.parse($.cookie('titles'));
}
});
Now I need to loop through the array. When I loop through the array I have to do 3 things:
1) Grab the string value.
2) Add the html to my new string so it becomes a list item or <li>.
3) Append the newly created <li> to our <ul>.
Like so:
for(var i = 0; i < titles.length; i++) {
var str = titles[i];
var listItem = '<li class="navHighlight">'
+ '<a href="#">'
+ str
+ '</a>'
+ '<a href="#">'
+ '<img src="images/delete.png" class="deleteImage"/>'
+ '</a>'
+ '</li>';
$('.accountSelectNav').append(listItem);
}
Now, if I want to remove this <li> I click the delete image found inside our <li>. What delete image you say? Look at the html I added again. You will see I add an <img> tag in there.
Now delete like so:
$("body").on("click", ".deleteImage", function (e) {
// grabs the text value of my li, which I want to remove
var removeTitle = $(this).closest('li').find('a').text();
// runs through my titles array and returns an array without the value above
titles = jQuery.grep(titles, function (value) {
return value != removeTitle;
});
});
Then I simply place the new array inside my cookie once again. Like this:
$.cookie('titles', JSON.stringify(titles));
And finally I remove the tab like this:
removeTab(this);
function removeTab(del) {
$(del).closest('li').remove();
}
Yay, I'm done. So now, if anyone has a more elegant way of accomplishing this I'm listening. I have no doubt there's a better way, javascript/jQuery isn't even close to my strong point.
The full code can be found here.

Jquery Chosen plugin. Select multiple of the same option

I'm using the chosen plugin to build multiple select input fields. See an example here: http://harvesthq.github.io/chosen/#multiple-select
The default behavior disables an option if it has already been selected. In the example above, if you were to select "Afghanistan", it would be greyed out in the drop-down menu, thus disallowing you from selecting it a second time.
I need to be able to select the same option more than once. Is there any setting in the plugin or manual override I can add that will allow for this?
I created a version of chosen that allows you to select the same item multiple times, and even sends those multiple entries to the server as POST variables. Here's how you can do it (fairly easily, I think):
(Tip: Use a search function in chosen.jquery.js to find these lines)
Change:
this.is_multiple = this.form_field.multiple;
To:
this.is_multiple = this.form_field.multiple;
this.allows_duplicates = this.options.allow_duplicates;
Change:
classes.push("result-selected");
To:
if (this.allows_duplicates) {
classes.push("active-result");
} else {
classes.push("result-selected");
}
Change:
this.form_field.options[item.options_index].selected = true;
To:
if (this.allows_duplicates && this.form_field.options[item.options_index].selected == true) {
$('<input>').attr({type:'hidden',name:this.form_field.name,value:this.form_field.options[item.options_index].value}).appendTo($(this.form_field).parent());
} else {
this.form_field.options[item.options_index].selected = true;
}
Then, when calling chosen(), make sure to include the allows_duplicates option:
$("mySelect").chosen({allow_duplicates: true})
For a workaround, use the below code on each selection (in select event) or while popup opened:
$(".chosen-results .result-selected").addClass("active-result").removeClass("result-selected");
The above code removes the result-selected class and added the active-result class on the li items. So each selected item is considered as the active result, now you can select that item again.
#adam's Answer is working very well but doesn't cover the situation that someone wants to delete some options.
So to have this functionality, alongside with Adam's tweaks you need to add this code too at:
Chosen.prototype.result_deselect = function (pos) {
var result_data;
result_data = this.results_data[pos];
// If config duplicates is enabled
if (this.allows_duplicates) {
//find fields name
var $nameField = $(this.form_field).attr('name');
// search for hidden input with same name and value of the one we are trying to delete
var $duplicateVals = $('input[type="hidden"][name="' + $nameField + '"][value="' + this.form_field.options[result_data.options_index].value + '"]');
//if we find one. we delete it and stop the rest of the function
if ($duplicateVals.length > 0) {
$duplicateVals[0].remove();
return true;
}
}
....

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