I am trying to get an image to move over to a separate box upon clicking and then to be removed with a remove button I have in my html. I figured out how to add the image upon clicking it then removing it upon clicking the remove button.
The issue I am having is: when I click the image itself, it should copy over to the right but it should only copy one time and then I must .remove() the image using the button before I can click it again so it appears once more. Right now the image appears over and over upon clicking. I tried using .stop() but that stops the function entirely, I need it to work interchangeably. How do I do this using jQuery?
JQUERY CODE:
$(document).ready(function(){
$("#john").click(function(){
var johnImage = $("#john").clone(false);
$("h2").html("John is in the box");
$("h2").css({ 'color': 'red'});
$("#johnbox").prepend(johnImage);
});
Check out the below code. You should be setting clicked to false again in your remove handler.
Here is the full code after I got your remove code.
$(document).ready(function () {
var clicked = false;
$("#john").click(function () {
if (!clicked) {
var johnImage = $("#john").clone(false);
$("h2").html("John is in the box");
$("h2").css({ 'color': 'red' });
$("#johnbox").prepend(johnImage);
clicked = true;
}
});
$("#removejohn").click(function () {
clicked = false;
$("#john").remove();
$("h2").html("Click John to put him in the Box");
$("h2").css({ 'color': 'black' });
});
});
Related
<script>
$(document).ready(function() {
$("#services").click( function() {
$(".subMenus").fadeToggle("slow")
});
});
</script>
This is my code. I can hide and show the dropdown(subMenus) with this code. I want to show the dropdown in my first click which it works but I want to go to a link when I clicked to services for the second time. How can I do?
There is a perfect way for you
$("#services").one('click', function() {
$(".subMenus").fadeToggle("slow")
});
You can do this be checking the visibility of your element. When it's not visible show it, when it is move to your link:
$("#services").click( function() {
if($(".subMenus").is(":visible"))
window.location = "yourLinkHere";
else
$(".subMenus").fadeToggle("slow");
});
I am completely new to javascript (and jquery) and have been experimenting with drop down menus the past couple of days. I found this one fancy notification menu, and I tried to see what happens when I have two of them on the page. Anyways, I made a quick example of my problem here:
http://jsfiddle.net/rgt03mu4/24/
The problem is that I can have both notification containers open up if I click on both.
If I am already clicked on one of the bells, then I click on the other, it should close the other one. Instead it keeps it open, and even when you click on the other container one, it still doesn't close it. You have to click off the page or click the notification bells. I am trying to make it to where you can only have one open at a time. So in order to do this, I tried changing the names of the functions:
As you can see:
$(function() {
var nContainer = $(".notification-popup-container");
//notification popup
$("#notification-link").click(function() {
nContainer.fadeToggle(300);
return false;
});
//page click to hide the popup
$(document).click(function() {
nContainer.hide();
});
//popup notification bubble on click
nContainer.click(function() {
return false;
});
});
I added the next function to be called test(), which you would think, since it's an entirely new function it would work differently. Instead, the error still persists.
What am I doing wrong? I even gave the the new bell it's own divs and link name. I also renamed container to container2.
Set the global variable for your container:
var nContainer = $(".notification-popup-container");
var nContainer2 = $(".notification2-popup-container");
$(function() {
var nContainer = $(".notification-popup-container");
//notification popup
$("#notification-link").click(function() {
nContainer.fadeToggle(300);
nContainer2.hide(); //hide the second container
return false;
});
//page click to hide the popup
$(document).click(function() {
nContainer.hide();
});
//popup notification bubble on click
nContainer.click(function() {
return false;
});
});
And you can do same with other function.
DEMO
There is no need to give the popup containers different classnames.
I would give the a-tags a common classname instead of an id. The href can be used to identify the target popup, so the binding between the link and the target popup is set in the origin of action. The JS part would be abstracted and could be reused.
<a class='notification-link' href='#firstpopup'>X</a>
<a class='notification-link' href='#secondpopup'>X</a>
<div class='notification-popup-container' id="firstpopup">
... firstpopup
</div>
<div class='notification-popup-container' id="secondpopup">
... secondpopup
</div>
The click handler first hides all the popups before opening a new one.
$(".notification-link").click(function () {
$(".notification-popup-container").hide();
var targetId = $(this).attr('href');
$(targetId).fadeIn(300);
return false;
})
working example: http://jsfiddle.net/qyLekdwk/
The problem here is how the event propgation is handled
$(function () {
var nContainer = $(".notification-popup-container");
//notification popup
$("#notification-link").click(function () {
nContainer.fadeToggle(300);
});
//page click to hide the popup
$(document).click(function (e) {
if (!$(e.target).closest('#notification-link, .notification-popup-container').length) {
nContainer.hide();
}
});
});
$(function test() {
var nContainer2 = $(".notification2-popup-container");
//notification popup
$("#notification2-link").click(function test() {
nContainer2.fadeToggle(300);
});
$(document).click(function (e) {
if (!$(e.target).closest('#notification2-link, .notification-popup-container').length) {
nContainer2.hide();
}
});
});
Demo: Fiddle
I have a form with multiple divs with same names (full-width). They all are on the same level. One of them is hidden (with a class hide). What I want is that if I select Submit, it should not submit, first hide all the brother divs of the hidden div (in this case full-width) and unhide the one with the class hide.
Now when I press again, it should just submit the Form.
JSFiddle is here:- http://jsfiddle.net/xmqvx/2/
Your code had a couple issues:
You used event.preventDefault but passed event in as e - should be e.preventDefault
Your ID selector targeted an ID that didnt exist (changed to #submit-this)
The working code:
$("#submit-this").click(function (e) {
e.preventDefault();
if ($(".full-width").hasClass("hide")) {
$(".full-width").hide();
$(".full-width.hide").removeClass("hide").show();
} else {
alert("Submitting");
$("#this-form").submit();
}
});
http://jsfiddle.net/xmqvx/4/
You could also take advantage of JavaScript's closures like so, to avoid having your behavior be dependent on your UI:
$(document).ready(function () {
var alreadyClicked = false;
$("#submit-this").click(function (e) {
e.preventDefault();
if (alreadyClicked) {
$('#this-form').submit();
} else {
$('.full-width').hide();
$('.hide').show();
alreadyClicked = true;
}
});
});
Helo,
I have a button that displays a div after clicking this button.
But after trying many combinations of jQuery, I can not ensure that once the button clicked, the page will automatically scroll the div available while that appears.
My code
$(document).ready(function() {
var job = $("#job");
var open = $("#open");
job.hide();
open.click(function() {
job.slideDown();
$(this).fadeOut();
return false;
});
});
Thank you in advance for your answers
$("#job").hide();
$('#urBtn').on('click', function(){
if (!$("#job").is(':visible')){
$("#job").fadeOut();
}
});
I'm at a bit of a problem with jQuery and an image.
I'm trying to create a simple system where an image changes on hover (which I've successfully made work with jQuery .hover()) however I'm now trying to set it up so if the user clicks on the image, the source is permanently changed to the hover image.
The problem I'm having is when I click, the source changes but when I hover off it changes back to the "off" image! Such a simple problem but I can't find a solution.
The hover code:
$("#image").hover(function () {
$(this).attr("src", getImageSourceOn("image"));
}, function () {
$(this).attr("src", getImageSourceOff("image"));
});
The functions getImageSourceOn / Off simply return a string based on the parameter with the new source.
The onClick code:
var imageSource = $(imageID).attr("src");
var onOff = imageSource.substring((imageSource.length - 5), (imageSource.length - 4));
if (onOff == "F")
{
//alert("Off\nstrID = " + strID);
$(imageID).attr("src", getImageSourceOn(strID));
}
else
{
//alert("On");
$(imageID).attr("src", getImageSourceOff(strID));
}
This code just takes the source and looks for On / Off within the source to put the opposite as the image. I tried using .toggle() instead of this substring method but I couldn't get it to work.
Declare a global variable. Attach a function on the click event:
var clicked = false;
$("#image").click(function(){
if(!clicked)
clicked = true;
else
$(this).attr("src", getImageSourceOff("image"));
});
Then modify you hover code
$("#image").hover(function () {
$(this).attr("src", getImageSourceOn("image"));
}, function () {
if(!clicked)
$(this).attr("src", getImageSourceOff("image"));
});