<script>
$(document).ready(function() {
$("#services").click( function() {
$(".subMenus").fadeToggle("slow")
});
});
</script>
This is my code. I can hide and show the dropdown(subMenus) with this code. I want to show the dropdown in my first click which it works but I want to go to a link when I clicked to services for the second time. How can I do?
There is a perfect way for you
$("#services").one('click', function() {
$(".subMenus").fadeToggle("slow")
});
You can do this be checking the visibility of your element. When it's not visible show it, when it is move to your link:
$("#services").click( function() {
if($(".subMenus").is(":visible"))
window.location = "yourLinkHere";
else
$(".subMenus").fadeToggle("slow");
});
Related
I am trying to get an image to move over to a separate box upon clicking and then to be removed with a remove button I have in my html. I figured out how to add the image upon clicking it then removing it upon clicking the remove button.
The issue I am having is: when I click the image itself, it should copy over to the right but it should only copy one time and then I must .remove() the image using the button before I can click it again so it appears once more. Right now the image appears over and over upon clicking. I tried using .stop() but that stops the function entirely, I need it to work interchangeably. How do I do this using jQuery?
JQUERY CODE:
$(document).ready(function(){
$("#john").click(function(){
var johnImage = $("#john").clone(false);
$("h2").html("John is in the box");
$("h2").css({ 'color': 'red'});
$("#johnbox").prepend(johnImage);
});
Check out the below code. You should be setting clicked to false again in your remove handler.
Here is the full code after I got your remove code.
$(document).ready(function () {
var clicked = false;
$("#john").click(function () {
if (!clicked) {
var johnImage = $("#john").clone(false);
$("h2").html("John is in the box");
$("h2").css({ 'color': 'red' });
$("#johnbox").prepend(johnImage);
clicked = true;
}
});
$("#removejohn").click(function () {
clicked = false;
$("#john").remove();
$("h2").html("Click John to put him in the Box");
$("h2").css({ 'color': 'black' });
});
});
I really stuck on this, what I need is to switch the image together with the tabs text, but the image should be outside of the tabs container. I made some jQuery code, but it's not flexible in case if I want to add more tabs and the functions are duplicating, which is also looks not so well.
Is there some option, maybe a function that will check if the number of cliked tab will match with image id and switch the image according this number.
Please help :)
The code example - http://codepen.io/DeoThemes/pen/EyAjVA
jQuery:
$('#tabs-img-1').show();
$("a[href='#tab-1']").on('click', function() {
$('.tabs-img').hide();
$('#tabs-img-1').show();
});
$("a[href='#tab-2']").on('click', function() {
$('.tabs-img').hide();
$('#tabs-img-2').show();
});
$("a[href='#tab-3']").on('click', function() {
$('.tabs-img').hide();
$('#tabs-img-3').show();
});
$("a[href='#tab-4']").on('click', function() {
$('.tabs-img').hide();
$('#tabs-img-4').show();
});
$("a[href='#tab-5']").on('click', function() {
$('.tabs-img').hide();
$('#tabs-img-5').show();
});
This will do without changing any of your code. Let me know your feedback. Thanks!
$('.tabs a[data-toggle="tab"]').on('click', function() {
$('.tabs-img').hide();
$('#tabs-img-' + $(this).attr('href').split('-')[1]).show();
});
or better still you can place an attribute on the a tag which will be the id of the tab!
I have edited your Codepen.
Add custom attribute to anchor link:
Business Oriented
And then change your script to this:
$("ul.nav-tabs li a").on('click', function() {
$('.tabs-img').hide();
$($(this).attr('imgId')).show();
});
$(document).ready(function() {
$('#b1').click(function() {
$('#uch').toggle("slow");
});
$('#b2').click(function() {
$('#uch2').toggle("slow");
})
})
I'm not a programmer but somehow managed to make div buttons that opens another div when clicked but I cant manage how to make so that when I click on one button that opens div and then when I click on other button it opens div and hides previous div. I want to integrate it later to joomla template, but as I use jquery and all efforts with if not working maybe someone is clever then me. thanks in advance. I place here working fiddle too.
fiddle example of my buttons
affter some usefull answers i reedited my code and managed to simplify it and added third button , now with extra css class everything seems pretty good but when i click already opened div it reappears as if looping.
edited fiddle
$(document).ready(function() {
$('#b1').click(function() {
$('.bats').hide("slow");
$('#uch').toggle("slow");
});
$('#b2').click(function() {
$('.bats').hide("slow");
$('#uch2').toggle("slow");
});
$('#b3').click(function() {
$('.bats').hide("slow");
$('#uch3').toggle("slow");
});
})
You can call hide('slow') on the other uch element on click of the button. Try this:
$('#b1').click(function() {
$('#uch').toggle("slow");
$('#uch2').hide("slow");
});
$('#b2').click(function() {
$('#uch').hide("slow");
$('#uch2').toggle("slow");
});
Working example
Change ID To Class
$(document).ready(function() {
$('.b1').click(function() {
$('.uch').hide();
$(this).find('.uch').toggle("slow");
});
});
https://jsfiddle.net/u28f6yeL/5/
Here is a working solution for your problem:
change your JQuery code like this:
$(document).ready(function() {
$('#b1').click(function() {
if($('#uch2').css('display') != 'none'){
$('#uch2').toggle("slow");
};
$('#uch').toggle("slow");
});
$('#b2').click(function() {
if($('#uch').css('display') != 'none'){
$('#uch').toggle("slow");
};
$('#uch2').toggle("slow");
});
});
Here's a JSFiddle
you can write a function which close the one is opend! than call them in your click-funktions before toggle the other.
I am completely new to javascript (and jquery) and have been experimenting with drop down menus the past couple of days. I found this one fancy notification menu, and I tried to see what happens when I have two of them on the page. Anyways, I made a quick example of my problem here:
http://jsfiddle.net/rgt03mu4/24/
The problem is that I can have both notification containers open up if I click on both.
If I am already clicked on one of the bells, then I click on the other, it should close the other one. Instead it keeps it open, and even when you click on the other container one, it still doesn't close it. You have to click off the page or click the notification bells. I am trying to make it to where you can only have one open at a time. So in order to do this, I tried changing the names of the functions:
As you can see:
$(function() {
var nContainer = $(".notification-popup-container");
//notification popup
$("#notification-link").click(function() {
nContainer.fadeToggle(300);
return false;
});
//page click to hide the popup
$(document).click(function() {
nContainer.hide();
});
//popup notification bubble on click
nContainer.click(function() {
return false;
});
});
I added the next function to be called test(), which you would think, since it's an entirely new function it would work differently. Instead, the error still persists.
What am I doing wrong? I even gave the the new bell it's own divs and link name. I also renamed container to container2.
Set the global variable for your container:
var nContainer = $(".notification-popup-container");
var nContainer2 = $(".notification2-popup-container");
$(function() {
var nContainer = $(".notification-popup-container");
//notification popup
$("#notification-link").click(function() {
nContainer.fadeToggle(300);
nContainer2.hide(); //hide the second container
return false;
});
//page click to hide the popup
$(document).click(function() {
nContainer.hide();
});
//popup notification bubble on click
nContainer.click(function() {
return false;
});
});
And you can do same with other function.
DEMO
There is no need to give the popup containers different classnames.
I would give the a-tags a common classname instead of an id. The href can be used to identify the target popup, so the binding between the link and the target popup is set in the origin of action. The JS part would be abstracted and could be reused.
<a class='notification-link' href='#firstpopup'>X</a>
<a class='notification-link' href='#secondpopup'>X</a>
<div class='notification-popup-container' id="firstpopup">
... firstpopup
</div>
<div class='notification-popup-container' id="secondpopup">
... secondpopup
</div>
The click handler first hides all the popups before opening a new one.
$(".notification-link").click(function () {
$(".notification-popup-container").hide();
var targetId = $(this).attr('href');
$(targetId).fadeIn(300);
return false;
})
working example: http://jsfiddle.net/qyLekdwk/
The problem here is how the event propgation is handled
$(function () {
var nContainer = $(".notification-popup-container");
//notification popup
$("#notification-link").click(function () {
nContainer.fadeToggle(300);
});
//page click to hide the popup
$(document).click(function (e) {
if (!$(e.target).closest('#notification-link, .notification-popup-container').length) {
nContainer.hide();
}
});
});
$(function test() {
var nContainer2 = $(".notification2-popup-container");
//notification popup
$("#notification2-link").click(function test() {
nContainer2.fadeToggle(300);
});
$(document).click(function (e) {
if (!$(e.target).closest('#notification2-link, .notification-popup-container').length) {
nContainer2.hide();
}
});
});
Demo: Fiddle
Helo,
I have a button that displays a div after clicking this button.
But after trying many combinations of jQuery, I can not ensure that once the button clicked, the page will automatically scroll the div available while that appears.
My code
$(document).ready(function() {
var job = $("#job");
var open = $("#open");
job.hide();
open.click(function() {
job.slideDown();
$(this).fadeOut();
return false;
});
});
Thank you in advance for your answers
$("#job").hide();
$('#urBtn').on('click', function(){
if (!$("#job").is(':visible')){
$("#job").fadeOut();
}
});