Develop Reference

How to replace numbers with an empty char

i need to replace phone number in string on \n new line.
My string: Jhony Jhons,jhon#gmail.com,380967574366
I tried this:
var str = 'Jhony Jhons,jhon#gmail.com,380967574366'
var regex = /[0-9]/g;
var rec = str.trim().replace(regex, '\n').split(','); //Jhony Jhons,jhon#gmail.com,
Number replace on \n but after using e-mail extra comma is in the string need to remove it.
Finally my string should look like this:
Jhony Jhons,jhon#gmail.com\n

You can try this:
var str = 'Jhony Jhons,jhon#gmail.com,380967574366';
var regex = /,[0-9]+/g;
str.replace(regex, '\n');
The snippet above may output what you want, i.e. Jhony Jhons,jhon#gmail.com\n

There's a lot of ways to that, and this is so easy, so try this simple answer:-
var str = 'Jhony Jhons,jhon#gmail.com,380967574366';
var splitted = str.split(","); //split them by comma
splitted.pop(); //removes the last element
var rec = splitted.join() + '\n'; //join them

You need a regex to select the complete phone number and also the preceding comma. Your current regex selects each digit and replaces each one with an "\n", resulting in a lot of "\n" in the result. Also the regex does not match the comma.
Use the following regex:
var str = 'Jhony Jhons,jhon#gmail.com,380967574366'
var regex = /,[0-9]+$/;
// it replaces all consecutive digits with the condition at least one digit exists (the "[0-9]+" part)
// placed at the end of the string (the "$" part)
// and also the digits must be preceded by a comma (the "," part in the beginning);
// also no need for global flag (/g) because of the $ symbol (the end of the string) which can be matched only once
var rec = str.trim().replace(regex, '\n'); //the result will be this string: Jhony Jhons,jhon#gmail.com\n

var str = "Jhony Jhons,jhon#gmail.com,380967574366";
var result = str.replace(/,\d+/g,'\\n');
console.log(result)

JS - Split string into substrings by regex

Let's say I have a string that starts by 7878 and ends by 0d0a or 0D0A such as:
var string = "78780d0101234567890123450016efe20d0a";
var string2 = "78780d0101234567890123450016efe20d0a78780d0103588990504943870016efe20d0a";
var string 3 = "78780d0101234567890123450016efe20d0a78780d0103588990504943870016efe20d0a78780d0101234567890123450016efe20d0a"
How can I split it by regex so it becomes an array like:
['78780d0101234567890123450016efe20d0a']
['78780d0101234567890123450016efe20d0a','78780d0101234567890123450016efe20d0a']
['78780d0101234567890123450016efe20d0a','78780d0101234567890123450016efe20d0a','78780d0101234567890123450016efe20d0a']

You can split the string with a positive lookahead (?=7878). The regex isn't consuming any characters, so 7878 will be part of the string.
var rgx = /(?=7878)/;
console.log(string1.split(rgx));
console.log(string2.split(rgx));
console.log(string3.split(rgx));
Another option is to split on '7878' and then take all the elements except first and add '7878' to each of them. For example:
var arr = string3.split('7878').slice(1).map(function(str){
return '7878' + str;
});
That works BUT it also matches strings that do NOT end on 0d0a. How
can I only matches those ending on 0d0a OR 0D0A?
Well, then you can use String.match with a plain regex.
console.log(string3.match(/7878.*?0d0a/ig));

Replace string that starts with specific character and ends with specific character in regular expression

I wanted to replace a string section that starts with a specific character and ends with specific character. At below, I demonstrate test case.
var reg = /pattern/gi;
var str = "asdfkadsf[xxxxx]bb";
var test = str.replace(reg,"") == "asdfkadsfbb"
console.log(test);

This pattern should work for replace anything between brackets (including the brackets):
var reg = /(\[.*?\])/gi;
var str = "asdfkadsf[xxxxx]bb";
var test = str.replace(reg,"") == "asdfkadsfbb"

based on your example, this works:
/\[.*]/gi

regex: any string between two slashes first of them is prefixed with a defined string

I'd like to get the talker name of some mp3s files paths such as the following:
/assets/audio/James_Lee/001.mp3
/assets/audio/Marc_Smith/001.mp3
/aasets/audio/blahblah/001.mp3
In the previous example we note that each talker name is surrounded by two slashes where the first of them is prefixed with the word audio. I need a pattern that matches names like the example above using javascript.
I tried at http://regexpal.com/ :
audio/.*/
but it only matches *audio/The_name/* where I need *The_name* only. The other thing I don't know how could I use such patterns with javascript replace().

This will get your the name: (?<=\/assets\/audio\/).*(?=\/)
Here's the regex in use: http://regexr.com?34747
Considering Javascript, you could do this:
var string = "/assets/audio/James_Lee/001.mp3";
var name = string.replace(/^.*\/audio\/|\/[\d]+\..*$/g, '');

Try this:
var str = "/assets/audio/James_Lee/001.mp3\n/assets/audio/Marc_Smith/001.mp3";
var pattern = /audio\/(.+?)\//g;
var match;
var matches = [];
while ((match = pattern.exec(str)) !== null){
matches.push(match[1]);
}
console.log(matches);
// If you want a string with only the names, you can re-combine the matches
str = matches.join('\n');

how about this?
str.replace(/.*audio\/([^\/]*)\/.*/,"$1")

Javascript regex to bring back all symbol matches?

I need a javascript regex object that brings back any matches of symbols in a string,
take for example the following string:
input = !"£$[]{}%^&*:#\~#';/.,<>\|¬`
then the following code:
input.match(regExObj,"g");
would return an array of matches:
[[,!,",£,$,%,^,&,*,:,#,~,#,',;,/,.,,,<,>,\,|,¬,`,]]
I have tried the following with no luck.
match(/[U+0021-U+0027]/g);
and I cannot use the following because I need to allow none ascii chars, for example Chinese characters.
[^0-9a-zA-Z\s]

var re = /[!"\[\]{}%^&*:#~#';/.<>\\|`]/g;
var matches = [];
var someString = "aejih!\"£$[]{}%^&*:#\~#';/.,<>\\|¬`oejtoj%";
while(match = re.exec(someString)) {
matches.push(match[1]);
}
Getting
['!','"','[',']','{','}','%','^','&','*',':','#','~','#',''',';','/','.','<','>','\','|','`','%]

What about
/[!"£$\[\]{}%^&*:#\\~#';\/.,<>|¬`]/g
?