The following is my element id and I want to update it dynamically.
invoice[46][ap_details][4][ap_header_id]
I want to update only second number, i.e. [4], like this:
invoice[46][ap_details][5][ap_header_id]
I am using below code which is updating both the values.
var strNewName = $(this).attr('name').replace(/\[\d+\]/g, function(strName) {
strName = strName.replace(/[\[\]']+/g, '');
var intNumber = parseInt(strName) + 1;
return '[' + intNumber + ']';
});
Any help would be appreciated.
var strName = "invoice[46][ap_details][4][ap_header_id]";
var parts = strName.split('[');
parts[3] = parts[3].replace(/^\d+/, n => +n + 1);
var strNewName = parts.join('[');
console.log(strNewName);
If you don't want to use arrow functions replace this line:
parts[3] = parts[3].replace(/^\d+/, n => +n + 1);
with this:
parts[3] = parts[3].replace(/^\d+/, function(n) { return +n + 1; });
Explanation:
split will return an array like this:
[
"invoice",
"46]", // parts[1] to change this
"ap_details]",
"4]", // parts[3] to change this (and so on, you do the math)
"ap_header_id]"
]
The /^\d+/ will match any number at the begining (no need for the g modifier).
Replace with +n + 1 not n + 1 because n is a string, you have to force the interpretter to use it as a number or otherwise this "4" + 1 will result to this "41".
Then after you change what you want, join the parts using join with the same character you used for splitting ([).
Using this regex /((\w)+)(\[\d+\])(\[(\w)+\])(\[\d+\])(\[(\w)+\])/gi you can construct the string back and change your integer.
var match = /((\w)+)(\[\d+\])(\[(\w)+\])(\[\d+\])(\[(\w)+\])/gi.exec(youString);
//group 6 is your digit.
var newId = parseInt(match[6].replace("\[\]", "")) + 1;
var newString = match[1] + match[3] + match[4] + "[" + newId + "]" + match[7];
Here is a fiddle with the answer https://jsfiddle.net/gzfud9vc/
Maybe dont use regex to build your element id. You can do its as follows as well:
var id = 5
var name = "invoice[46][ap_details][";
name += id;
name += "][ap_header_id]";
var toReplace = "invoice[46][ap_details][~~id~~][ap_header_id]"
var replaced = toReplace.replace(/~~id~~/g, id);
console.log(name);
console.log(replaced);
Related
I have string like:
MPG_0023
I want to find something like
MPG_0023 + 1
and I should get
MPG_0024
How to do that in JavaScript? It should take care that if there are no leading zeros, or one leading zero should still work like MPG23 should give MPG24 or MPG023 should give MPG024.
There should be no assumption that there is underscore or leading zeros, the only thing is that first part be any string or even no string and the number part may or may not have leading zeros and it is any kind of number so it should work for 0023 ( return 0024) or for gp031 ( return gp032) etc.
Here's a quick way without using regex.. as long as there's always a single underscore preceding the number and as long as the number is 4 digits, this will work.
var n = 'MPG_0023';
var a = n.split('_');
var r = a[0]+'_'+(("0000"+(++a[1])).substr(-4));
console.log(r);
Or if you do wanna do regex, the underscore won't matter.
var n = "MPG_0099";
var r = n.replace(/(\d+)/, (match)=>("0".repeat(4)+(++match)).substr(-4));
console.log(r);
You can use the regular expressions to make the changes as shown in the following code
var text = "MPG_0023";
var getPart = text.replace ( /[^\d.]/g, '' ); // returns 0023
var num = parseInt(getPart); // returns 23
var newVal = num+1; // returns 24
var reg = new RegExp(num); // create dynamic regexp
var newstring = text.replace ( reg, newVal ); // returns MPG_0024
console.log(num);
console.log(newVal);
console.log(reg);
console.log(newstring);
Using regex along with the function padStart
function add(str, n) {
return str.replace(/(\d+)/, function(match) {
var length = match.length;
var newValue = Number(match) + n;
return newValue.toString(10).padStart(length, "0");
});
}
console.log(add("MPG_023", 101));
console.log(add("MPG_0023", 101));
console.log(add("MPG_0000023", 10001));
console.log(add("MPG_0100023", 10001));
Using regular expression you can do it like this.
var text1 = 'MPG_0023';
var text2 = 'MPG_23';
var regex = /(.*_[0]*)(\d*)/;
var match1 = regex.exec(text1);
var match2 = regex.exec(text2);
var newText1 = match1[1] + (Number(match1[2]) + 1);
var newText2 = match2[1] + (Number(match2[2]) + 1);
console.log(newText1);
console.log(newText2);
Increment and pad the same value (comments inline)
var prefix = "MPG_"
var padDigit = 4; //number of total characters after prefix
var value = "MPG_0023";
console.log("currentValue ", value);
//method for padding
var fnPad = (str, padDigit) => (Array(padDigit + 1).join("0") + str).slice(-padDigit);
//method to get next value
var fnGetNextCounterValue = (value) => {
var num = value.substring(prefix.length); //extract num value
++num; //increment value
return prefix + fnPad(num, padDigit); //prepend prefix after padding
};
console.log( "Next", value = fnGetNextCounterValue(value) );
console.log( "Next", value = fnGetNextCounterValue(value) );
console.log( "Next", value = fnGetNextCounterValue(value) );
One way would e to split the string on the "_" character, increment the number and then add the zeros back to the number.
var testString = "MGP_0023";
var ary = testString.split("_");
var newNumber = Number(ary[1]) + 1;
var result = ary[0] + pad(newNumber);
// helper function to add zeros in front of the number
function pad(number) {
var str = number.toString();
while (str.length < 4) {
str = '0' + str;
}
return str;
}
You could cast to number, increment the value and cast back. Then check if you need leading zeros by looking at the length of the string.
Snippet below:
let str = "MPG_0023",
num = Number(str.substr(4)) + 1,
newStr = String(num);
function addLeading0(str) {
return str.length === 2 ? '00' + str : (str.length === 3 ? '0' + str : str);
}
console.log("MPG_" + addLeading0(newStr));
I have a Javascript array
var arr = ['[dim].[att].&[123]','[dim].[att5].&[123]','[dim4].[att].&[123]','[dim3].[att].&[123]','[dim].[att].&[222]']
from this array I need to produce output like this:
var str = " 'dim'[att] = 123 || 'dim'[att] = 222 , 'dim'[att5] = 123 , 'dim4'[att] = 123 , 'dim3'[att] = 123 ";.
I first need to split each value in the array by .& and then I need to group all the items by index 0 of the resultant array. So in this case I will group [dim].[att].&[123] & [dim].[att].&[222] becuase of [dim].[att]
From each of these items, now I need to split by ]. and produce requires output such that [dim].[att].&[123] becomes 'dim'[att] = 123
I do not want to use multiple for loops for this purpose. I already have that solution ready. So far i am able to group the items, but not sure how to generate required output. Check this fiddle for my solution
You just need to use Array.map and Array.join
var str = arr.map(function(s){
var a = s.match(/\w+/g);
return "'" + a[0] + "'[" + a[1] + "] = " + a[2];
}).join("||");
In the above, we are taking the three parts which we want into an Array using s.match(/\w+/g) and then returning in the format we want.
Also, at last, Array.join is called with || as the String
DEMO
I was looking for this; Code below and DEMO
var arr = ['[dim].[att].&[123]', '[dim].[att5].&[123]', '[dim4].[att].&[123]', '[dim3].[att].&[123]', '[dim].[att].&[222]']
var res = _.chain(arr)
.groupBy(function (x) {
return x.match(/.+?\.&/i)[0];
})
.map(function(y) {
return _.map(y, function (z) {
var a = z.match(/\w+/g);
return "'" + a[0] + "'[" + a[1] + "] = " + a[2];
}).join(" || ");
})
.value().join(", ");
console.log(res)
I want to slice the javascript variable in the given condition.
The condition is if the variable is of length 12 it should slice as 2,6,4 and if it is of length 11 it should slice as 2,5,4. How can i slice this.
Here is what i have tried.
Code :
var new_no = "("+phone_no.slice(0,2)+")-"+phone_no.slice(2,7)+"-"+phone_no.slice(7,11);
How can i make the length checking condition and slice according to my given condition ?
You can make the middle slice conditional:
var midEnd = phone_no.length == 11? 7 : 8;
var new_no = "("+phone_no.slice(0,2)+")-"+phone_no.slice(2,midEnd)+"-"+phone_no.slice(midEnd);
If you don't supply a second parameter, it will slice to the end. Though for greater browser compatibility I'd use substr instead:
var new_no = '(' + phone_no.substr(0,2) + ')-' +
phone_no.substr(2,midEnd) +
'-' + phone_no.substr(midEnd);
function preparePhoneNo(num) {
return '(' + num.slice(0, 2) + ')-' + num.slice(2, -4) + '-' + num.slice(-4);
}
var phone_no = "123465789012";
var new_no = preparePhoneNo(phone_no);
Here is my take, I would use substr
var phone_no = '12345678901';
var midGroup = phone_no.length == 11 ? 5 : 6;
var new_no = "("+phone_no.substr(0,2)+")-"+phone_no.substr(2,midGroup)+"-"+phone_no.substr(midGroup + 2);
alert(new_no);
You can simply use .length to check the length of the number and then two simple conditions will do the trick:
var phone_no = "123456789878";
if(phone_no.length === 11)
var new_no = "("+phone_no.slice(0,2)+")-"+phone_no.slice(2,7)+"-"+phone_no.slice(7,11);
else if(phone_no.length === 12)
var new_no = "("+phone_no.slice(0,2)+")-"+phone_no.slice(2,8)+"-"+phone_no.slice(8,12);
else
alert('Invalid Number');
See the DEMO here
Say for example I have
var input = "C\\\\Program Files\\\\Need for Speed";
var output = do_it(input, ':');
Now, I would like output to have the value below :
C:\\\\Program Files\\\\Need for Speed
I need to add a character to the given string just after the first character. How can I achieve that using javascript or jquery ?
Thanks in advance
It's probably not the most efficient way, but I would do something like:
(note: this is just pseudocode)
var output = input[0] + ":" + input.substr(1, input.length);
you can use this like
String.prototype.addAt = function (index, character) {
return this.substr(0, index - 1) + character + this.substr(index-1 + character.length-1);
}
var input = "C\\Program Files\\Need for Speed";
var result = input.addAt(2, ':');
Heres one way of doing it:
Fiddle: http://jsfiddle.net/FjfB9/
var input = "C\\Program Files\\Need for Speed"
var do_it = function(str, char) {
var str = str.split(''),
temp = str.shift()
str.unshift(temp, char)
return str.join('')
}
console.log(do_it(input, ":"))
i want to replace the last index of comma (,)in string with and.
eg . a,b,c with 'a,b and c'
eg q,w,e with q,w and e
DEMO
lastIndexOf finds the last index of the parameter string passed in it.
var x = 'a,b,c';
var pos = x.lastIndexOf(',');
x = x.substring(0,pos)+' and '+x.substring(pos+1);
console.log(x);
you can also use this function
function replace_last_comma_with_and(x) {
var pos = x.lastIndexOf(',');
return x.substring(0, pos) + ' and ' + x.substring(pos + 1);
}
console.log(replace_last_comma_with_and('a,b,c,d'));
An alternative solution using regex:
function replaceLastCommaWith(x, y) {
return x.replace(/,(?=[^,]*$)/, " " + y + " ");
}
console.log(replaceLastCommaWith("a,b,c,d", "and")); //a,b,c and d
console.log(replaceLastCommaWith("a,b,c,d", "or")); //a,b,c or d
This regex should do the job
"a,b,c,d".replace(/(.*),(.*)$/, "$1 and $2")
Try the following
var x= 'a,b,c,d';
x = x.replace(/,([^,]*)$/, " and $1");
Try
var str = 'a,b,c', replacement = ' and ';
str = str.replace(/,([^,]*)$/,replacement+'$1');
alert(str)
Fiddle Demo
A simple loop will help you out
first find the index of all , in your string using,
var str = "a,b,c,d,e";
var indices = [];
for(var i=0; i<str.length;i++) {
if (str[i] === ",") indices.push(i);
}
indices = [1,3,5,7] as it start from 0
len = indices.length()
str[indices[len - 1]] = '.'
This will solve your purpose.