Say for example I have
var input = "C\\\\Program Files\\\\Need for Speed";
var output = do_it(input, ':');
Now, I would like output to have the value below :
C:\\\\Program Files\\\\Need for Speed
I need to add a character to the given string just after the first character. How can I achieve that using javascript or jquery ?
Thanks in advance
It's probably not the most efficient way, but I would do something like:
(note: this is just pseudocode)
var output = input[0] + ":" + input.substr(1, input.length);
you can use this like
String.prototype.addAt = function (index, character) {
return this.substr(0, index - 1) + character + this.substr(index-1 + character.length-1);
}
var input = "C\\Program Files\\Need for Speed";
var result = input.addAt(2, ':');
Heres one way of doing it:
Fiddle: http://jsfiddle.net/FjfB9/
var input = "C\\Program Files\\Need for Speed"
var do_it = function(str, char) {
var str = str.split(''),
temp = str.shift()
str.unshift(temp, char)
return str.join('')
}
console.log(do_it(input, ":"))
Related
The following is my element id and I want to update it dynamically.
invoice[46][ap_details][4][ap_header_id]
I want to update only second number, i.e. [4], like this:
invoice[46][ap_details][5][ap_header_id]
I am using below code which is updating both the values.
var strNewName = $(this).attr('name').replace(/\[\d+\]/g, function(strName) {
strName = strName.replace(/[\[\]']+/g, '');
var intNumber = parseInt(strName) + 1;
return '[' + intNumber + ']';
});
Any help would be appreciated.
var strName = "invoice[46][ap_details][4][ap_header_id]";
var parts = strName.split('[');
parts[3] = parts[3].replace(/^\d+/, n => +n + 1);
var strNewName = parts.join('[');
console.log(strNewName);
If you don't want to use arrow functions replace this line:
parts[3] = parts[3].replace(/^\d+/, n => +n + 1);
with this:
parts[3] = parts[3].replace(/^\d+/, function(n) { return +n + 1; });
Explanation:
split will return an array like this:
[
"invoice",
"46]", // parts[1] to change this
"ap_details]",
"4]", // parts[3] to change this (and so on, you do the math)
"ap_header_id]"
]
The /^\d+/ will match any number at the begining (no need for the g modifier).
Replace with +n + 1 not n + 1 because n is a string, you have to force the interpretter to use it as a number or otherwise this "4" + 1 will result to this "41".
Then after you change what you want, join the parts using join with the same character you used for splitting ([).
Using this regex /((\w)+)(\[\d+\])(\[(\w)+\])(\[\d+\])(\[(\w)+\])/gi you can construct the string back and change your integer.
var match = /((\w)+)(\[\d+\])(\[(\w)+\])(\[\d+\])(\[(\w)+\])/gi.exec(youString);
//group 6 is your digit.
var newId = parseInt(match[6].replace("\[\]", "")) + 1;
var newString = match[1] + match[3] + match[4] + "[" + newId + "]" + match[7];
Here is a fiddle with the answer https://jsfiddle.net/gzfud9vc/
Maybe dont use regex to build your element id. You can do its as follows as well:
var id = 5
var name = "invoice[46][ap_details][";
name += id;
name += "][ap_header_id]";
var toReplace = "invoice[46][ap_details][~~id~~][ap_header_id]"
var replaced = toReplace.replace(/~~id~~/g, id);
console.log(name);
console.log(replaced);
JavaScript Split,
str = '123.2345.34' ,
expected output 123.2345 and 34
Str = 123,23.34.23
expected output 123,23.34 and 23
Goal : JS function to Split a string based on dot(from last) in O(n).
There may be n number of ,.(commas or dots) in string.
In order to split a string matching only the last character like described you need to use regex "lookahead".
This simple example works for your case:
var array = '123.2345.34'.split(/\.(?=[^\.]+$)/);
console.log(array);
Example with destructuring assignment (Ecmascript 2015)
const input = 'jquery.somePlugin.v1.6.3.js';
const [pluginName, fileExtension] = input.split(/\.(?=[^\.]+$)/);
console.log(pluginName, fileExtension);
However using either slice or substring with lastIndexOf also works, and albeit less elegant it's much faster:
var input = 'jquery.somePlugin.v1.6.3.js';
var period = input.lastIndexOf('.');
var pluginName = input.substring(0, period);
var fileExtension = input.substring(period + 1);
console.log(pluginName, fileExtension);
var str = "filename.to.split.pdf"
var arr = str.split("."); // Split the string using dot as separator
var lastVal = arr.pop(); // Get last element
var firstVal = arr.join("."); // Re-join the remaining substrings, using dot as separator
console.log(firstVal + " and " + lastVal); //Printing result
I will try something like bellow
var splitByLastDot = function(text) {
var index = text.lastIndexOf('.');
return [text.slice(0, index), text.slice(index + 1)]
}
console.log(splitByLastDot('123.2345.34'))
console.log(splitByLastDot('123,23.34.23'))
I came up with this:
var str = '123,23.34.23';
var result = str.replace(/\.([^.]+)$/, ':$1').split(':');
document.getElementById('output').innerHTML = JSON.stringify(result);
<div id="output"></div>
let returnFileIndex = str =>
str.split('.').pop();
Try this:
var str = '123.2345.34',
arr = str.split('.'),
output = arr.pop();
str = arr.join('.');
var test = 'filename.....png';
var lastStr = test.lastIndexOf(".");
var str = test.substring(lastStr + 1);
console.log(str);
I'm typically using this code and this works fine for me.
Jquery:
var afterDot = value.substr(value.lastIndexOf('_') + 1);
console.log(afterDot);
Javascript:
var myString = 'asd/f/df/xc/asd/test.jpg'
var parts = myString.split('/');
var answer = parts[parts.length - 1];
console.log(answer);
Note: Replace quoted string to your own need
My own version:
var mySplit;
var str1;
var str2;
$(function(){
mySplit = function(myString){
var lastPoint = myString.lastIndexOf(".");
str1 = myString.substring(0, lastPoint);
str2 = myString.substring(lastPoint + 1);
}
mySplit('123,23.34.23');
console.log(str1);
console.log(str2);
});
Working fiddle: https://jsfiddle.net/robertrozas/no01uya0/
Str = '123,23.34.23';
var a = Str.substring(0, Str.lastIndexOf(".")) //123,23.34
var b = Str.substring(Str.lastIndexOf(".")) //23
Try this solution.
Simple Spilt logic
<script type="text/javascript">
var str = "123,23.34.23";
var str_array = str.split(".");
for (var i=0;i<str_array.length;i++)
{
if (i == (str_array.length-1))
{
alert(str_array[i]);
}
}
</script>
The simplest way is mentioned below, you will get pdf as the output:
var str = "http://somedomain.com/dir/sd/test.pdf";
var ext = str.split('.')[str.split('.').length-1];
Output: pdf
I have a string like this:
(apple,apple,orange,banana,strawberry,strawberry,strawberry). I want to count the number of occurrences for each of the characters, e.g. banana (1) apple(2) and strawberry(3). how can I do this?
The closest i could find was something like, which i dont know how to adapt for my needs:
function countOcurrences(str, value){
var regExp = new RegExp(value, "gi");
return str.match(regExp) ? str.match(regExp).length : 0;
}
Here is the easiest way to achieve that by using arrays.. without any expressions or stuff. Code is fairly simple and self explanatory along with comments:
var str = "apple,apple,orange,banana,strawberry,strawberry,strawberry";
var arr = str.split(','); //getting the array of all fruits
var counts = {}; //this array will contain count of each element at it's specific position, counts['apples']
arr.forEach(function(x) { counts[x] = (counts[x] || 0)+1; }); //checking and addition logic.. e.g. counts['apples']+1
alert("Apples: " + counts['apple']);
alert("Oranges: " + counts['orange']);
alert("Banana: " + counts['banana']);
alert("Strawberry: " + counts['strawberry']);
See the DEMO here
You can try
var wordCounts = str.split(",").reduce(function(result, word){
result[word] = (result[word] || 0) + 1;
return result;
}, {});
wordCounts will be a hash {"apple":2, "orange":1, ...}
You can print it as the format you like.
See the DEMO http://repl.it/YCO/10
You can use split also:
function getCount(str,d) {
return str.split(d).length - 1;
}
getCount("fat math cat", "at"); // return 3
I want to replace G$0 in the string gantt(G$0,$A4,$B4) with gantt(<>G$0<>,$A4,$B4). So I have the following code:
var str = '=gantt(G$0,$A4,$B4) ';
var val = "G$0";
var val2 = val.replace(/\$/, "\\$")
var reg = new RegExp(val2, 'g');
var str = str.replace(reg, '<>' + val + '<>');
The result in IE is: =gantt(<>GG$0<>,$A4,$B4) (note the GG). The problem seems to be IE10 specific.
Why is this happening, is this an IE bug?
The replace should assume a string could contain multiple instances of **G$0**.
There's no need to use RegEx at all. Stick to regular string replacement, and you won't have to escape the val string.
var str = '=gantt(G$0,$A4,$B4) ';
var val = "G$0";
var result = str.replace(val, '<>' + val + '<>');
If you want to replace multiple instances of val this can be done with .split and .join:
var str = '=gantt(G$0,$A4,$B4,G$0) ';
var val = "G$0";
var result = str.split(val).join('<>' + val + '<>');
I want to remove all occurrences of substring = . in a string except the last one.
E.G:
1.2.3.4
should become:
123.4
You can use regex with positive look ahead,
"1.2.3.4".replace(/[.](?=.*[.])/g, "");
2-liner:
function removeAllButLast(string, token) {
/* Requires STRING not contain TOKEN */
var parts = string.split(token);
return parts.slice(0,-1).join('') + token + parts.slice(-1)
}
Alternative version without the requirement on the string argument:
function removeAllButLast(string, token) {
var parts = string.split(token);
if (parts[1]===undefined)
return string;
else
return parts.slice(0,-1).join('') + token + parts.slice(-1)
}
Demo:
> removeAllButLast('a.b.c.d', '.')
"abc.d"
The following one-liner is a regular expression that takes advantage of the fact that the * character is greedy, and that replace will leave the string alone if no match is found. It works by matching [longest string including dots][dot] and leaving [rest of string], and if a match is found it strips all '.'s from it:
'a.b.c.d'.replace(/(.*)\./, x => x.replace(/\./g,'')+'.')
(If your string contains newlines, you will have to use [.\n] rather than naked .s)
You can do something like this:
var str = '1.2.3.4';
var last = str.lastIndexOf('.');
var butLast = str.substring(0, last).replace(/\./g, '');
var res = butLast + str.substring(last);
Live example:
http://jsfiddle.net/qwjaW/
You could take a positive lookahead (for keeping the last dot, if any) and replace the first coming dots.
var string = '1.2.3.4';
console.log(string.replace(/\.(?=.*\.)/g, ''));
A replaceAllButLast function is more useful than a removeAllButLast function. When you want to remove just replace with an empty string:
function replaceAllButLast(str, pOld, pNew) {
var parts = str.split(pOld)
if (parts.length === 1) return str
return parts.slice(0, -1).join(pNew) + pOld + parts.slice(-1)
}
var test = 'hello there hello there hello there'
test = replaceAllButLast(test, ' there', '')
console.log(test) // hello hello hello there
Found a much better way of doing this. Here is replaceAllButLast and appendAllButLast as they should be done. The latter does a replace whilst preserving the original match. To remove, just replace with an empty string.
var str = "hello there hello there hello there"
function replaceAllButLast(str, regex, replace) {
var reg = new RegExp(regex, 'g')
return str.replace(reg, function(match, offset, str) {
var follow = str.slice(offset);
var isLast = follow.match(reg).length == 1;
return (isLast) ? match : replace
})
}
function appendAllButLast(str, regex, append) {
var reg = new RegExp(regex, 'g')
return str.replace(reg, function(match, offset, str) {
var follow = str.slice(offset);
var isLast = follow.match(reg).length == 1;
return (isLast) ? match : match + append
})
}
var replaced = replaceAllButLast(str, / there/, ' world')
console.log(replaced)
var appended = appendAllButLast(str, / there/, ' fred')
console.log(appended)
Thanks to #leaf for these masterpieces which he gave here.
You could reverse the string, remove all occurrences of substring except the first, and reverse it again to get what you want.
function formatString() {
var arr = ('1.2.3.4').split('.');
var arrLen = arr.length-1;
var outputString = '.' + arr[arrLen];
for (var i=arr.length-2; i >= 0; i--) {
outputString = arr[i]+outputString;
}
alert(outputString);
}
See it in action here: http://jsbin.com/izebay
var s='1.2.3.4';
s=s.split('.');
s.splice(s.length-1,0,'.');
s.join('');
123.4