Develop Reference

Subtracting 3 days from date

I want to calculate a reminderDate by subtracting 3 days from it. However, if the resulting date
falls on a Saturday or Sunday, it should give the date of the Friday
falls on a Friday, it should give the date of Thursday
For example
Exchange Date ReminderDate
18.06.2020 -3 days = 15.06.2020 --> OK, because Monday
17.06.2020 -3 days = 14.06.2020 --> Sunday, must be changed to 12.06.2020
16.06.2020 -3 days = 13.06.2020 --> Saturday, must be changed to 12.06.2020
15.06.2020 -3 days = 11.06.2020 --> Friday, must be changed to 11.06.2020
I tried something like this, but neither .getDay() nor .day() seem to work. And dt seems to give the date of today, and not the date of exchange.
var exchange = NWF$("#" + varAustauschtermin).val(); // date like 18.06.2020
console.log("Exchange: " + exchange);
var reminderDate = moment(exchange, "DD.MM.YYYY").format("DD.MM.YYYY");
var dt = new Date(reminderDate);
// var reminderDate = moment(exchange, "DD.MM.YYYY").subtract(3, 'days').format("DD.MM.YYYY");
// console.log("reminderDate.day(): " + reminderDate.day());
// console.log("reminderDate.getDay(): " + reminderDate.getDay());
if(dt.getDay() == 6) { // Saturday
console.log("Saturday");
reminderDate = moment(exchange, "DD.MM.YYYY").subtract(1, 'days').format("DD.MM.YYYY");
} else if (dt.getDay() == 0) { // Sunday
console.log("Sunday");
reminderDate = moment(exchange, "DD.MM.YYYY").subtract(2, 'days').format("DD.MM.YYYY");
} else if (dt.getDay() == 5) { // Friday
console.log("Friday");
reminderDate = moment(exchange, "DD.MM.YYYY").subtract(1, 'days').format("DD.MM.YYYY");
} else {
console.log("Weekday");
reminderDate = moment(exchange, "DD.MM.YYYY").subtract(3, 'days').format("DD.MM.YYYY");
}
console.log("Reminder Date: " + reminderDate);
Any help is appreciated!

If you are using momentjs then there is no need to switch to native Date object because everything you can do with momentjs and with much simplicity
Use momentjs day() to help you get the oridinal for a day of week
0 - Sunday
1 - Monday
...
..
.
6 - Saturday
To find what date will say "Saturday" come in this week you can do like moment().day("Saturday").
Then there is subtract which you are already using to rewind dates by given days.
Building on these above ideas you can try this helper function
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.0/moment.min.js"></script>
<script type="text/javascript">
function dateShift(d) {
//days numbering are 0(Sunday) to 6(Saturday)
d.subtract(3, 'days')
//Is SUNDAY?
if (d.day() == 0) {
//adjust it to friday
var upComingFri = d.day('Friday'); // date of friday in which THIS sunday is
return upComingFri.subtract(7, 'days');
//but we want to rewind as you want to stay in same week as the original date provided
}
//Is SATURDAY?
if (d.day() == 6) {
//adjust it to friday
var friday = d.day('Friday'); //sat is in same week
return friday;
}
//Is FRIDAY?
if (d.day() == 5) {
//adjust it to thursday
var thursday = d.day('Thursday');
return thursday;
}
return d;
}
t1 = moment('18.06.2020', "DD.MM.YYYY");
r1 = dateShift(t1);
console.log(r1.format("DD.MM.YYYY"))
t2 = moment('17.06.2020', "DD.MM.YYYY");
r2 = dateShift(t2);
console.log(r2.format("DD.MM.YYYY"))
t3 = moment('16.06.2020', "DD.MM.YYYY");
r3 = dateShift(t3);
console.log(r3.format("DD.MM.YYYY"))
t4 = moment('15.06.2020', "DD.MM.YYYY");
r4 = dateShift(t4);
console.log(r4.format("DD.MM.YYYY"))
</script>

It's not too hard to do this with plain javascript. Instead of subtracting 3 days, seeing what the day is, then subtracting again, you can work out the days to subtract given the initial day and do one subtraction, e.g.
// Parse string in format d.m.y to Date
function parseDMY(s) {
let [d, m, y] = s.split(/\D/);
return new Date(y, --m, d);
}
// s is date in format d.m.y
function adjustDate(s) {
let d = parseDMY(s);
// Subtract 4 days from Mon and Tue, 5 from Wed, 3 otherwise
d.setDate(d.getDate() - ([,4,4,5][d.getDay()] || 3));
return d;
}
['29.03.2020','28.03.2020','27.03.2020','26.03.2020',
'01.04.2020','31.03.2020','30.03.2020'
].forEach(s => console.log(parseDMY(s).toDateString() + ' -> ' +
adjustDate(s).toDateString()));

How to get Monday of a week as a number

I would like to get the first day of a week in a given year (assuming the week starts on a Monday).
Scenario: The year is 2016. It should return 4, because Monday the 4th of January 2016 is the first day of week 1 in 2016.
How would I do that? I want something like this:
var date = new Date();
var week = 1;
var year = 2016;
date.getMonday(week, year); // 4 (because 04/01/2016 is a Monday and is week number 1)
week = 5;
date.getMonday(week, year); // 30 (because 30/01/2016 is a Monday and is week number 5)
Thanks

You can use JavaScript's getDay() method to figure out which day of the week a date object refers to.
var output = document.getElementById('output');
var year = 2016;
var firstMonday = new Date(year, 0, 1); // year, month (zero-index), date
// starting at January 1st, increment the date until a Monday (`getDay() = 1`)
while(firstMonday.getDay() !== 1) {
firstMonday.setDate(firstMonday.getDate() + 1);
}
// output the date of the first Monday in January
output.value = firstMonday.getDate();
<textarea id="output"></textarea>

I've made a function to solve this... see bellow
function getDayInWeek(dayOfWeek, week, year){
dayOfWeek = dayOfWeek % 7; //ensure day of week
var baseDate = new Date(year, 0, 1); //get the first day
var firstDayOfWeek = baseDate.getDay(); //get the first week day
var inWeek = (week - 1) * 7; //get the days to start of week
var diff = firstDayOfWeek - dayOfWeek; //get the diff for day in that week
if(diff < 0) diff += 7;
baseDate.setDate(inWeek + diff);
return baseDate.getDate(); //get the month day
}
to use specify the week day
// 0 = sunday
// 1 = monday
// 2 = tuesday
// 3 = wednesday
// 4 = thursday
// 5 = friday
// 6 = saturday
var firstMonday = getDayInWeek(1, 1, 2016); // the monday in first week of 2016
var mondayOf5 = getDayInWeek(1, 5, 2016); // the monday in 5th week of 2016

To get ISO-8601 week, which will always be a Monday, see link:
Wikipedia
Calculate ISO 8601
function getISOWeek(week, year) {
var _date = new Date(year, 0, 1 + (week - 1) * 7);
var date_of_week = _date.getDay();
var ISOweekStart = _date;
(date_of_week <= 4) ? ISOweekStart.setDate(_date.getDate() - _date.getDay() + 1): ISOweekStart.setDate(_date.getDate() + 8 - _date.getDay());
return ISOweekStart;
}
console.log(getISOWeek(10, 2016));

How do I calculate the date in JavaScript three months prior to today?

I Am trying to form a date which is 3 months before the current date. I get the current month by the below code
var currentDate = new Date();
var currentMonth = currentDate.getMonth()+1;
Can you guys provide me the logic to calculate and form a date (an object of the Date data type) considering that when the month is January (1), 3 months before date would be OCtober (10)?

var d = new Date();
d.setMonth(d.getMonth() - 3);
This works for January. Run this snippet:
var d = new Date("January 14, 2012");
console.log(d.toLocaleDateString());
d.setMonth(d.getMonth() - 3);
console.log(d.toLocaleDateString());
There are some caveats...
A month is a curious thing. How do you define 1 month? 30 days? Most people will say that one month ago means the same day of the month on the previous month citation needed. But more than half the time, that is 31 days ago, not 30. And if today is the 31st of the month (and it isn't August or Decemeber), that day of the month doesn't exist in the previous month.
Interestingly, Google agrees with JavaScript if you ask it what day is one month before another day:
It also says that one month is 30.4167 days long:
So, is one month before March 31st the same day as one month before March 28th, 3 days earlier? This all depends on what you mean by "one month before". Go have a conversation with your product owner.
If you want to do like momentjs does, and correct these last day of the month errors by moving to the last day of the month, you can do something like this:
const d = new Date("March 31, 2019");
console.log(d.toLocaleDateString());
const month = d.getMonth();
d.setMonth(d.getMonth() - 1);
while (d.getMonth() === month) {
d.setDate(d.getDate() - 1);
}
console.log(d.toLocaleDateString());
If your requirements are more complicated than that, use some math and write some code. You are a developer! You don't have to install a library! You don't have to copy and paste from stackoverflow! You can develop the code yourself to do precisely what you need!

I recommend using a library called Moment.js.
It is well tested, works cross browser and on server side(I am using it both in Angular and Node projects). It has great support for locale dates.
http://momentjs.com/
var threeMonthsAgo = moment().subtract(3, 'months');
console.log(threeMonthsAgo.format()); // 2015-10-13T09:37:35+02:00
.format() returns string representation of date formatted in ISO 8601 format. You can also use it with custom date format like this:.format('dddd, MMMM Do YYYY, h:mm:ss a')

A "one liner" (on many line for easy read)) to be put directly into a variable:
var oneMonthAgo = new Date(
new Date().getFullYear(),
new Date().getMonth() - 1,
new Date().getDate()
);

This should handle addition/subtraction, just put a negative value in to subtract and a positive value to add. This also solves the month crossover problem.
function monthAdd(date, month) {
var temp = date;
temp = new Date(date.getFullYear(), date.getMonth(), 1);
temp.setMonth(temp.getMonth() + (month + 1));
temp.setDate(temp.getDate() - 1);
if (date.getDate() < temp.getDate()) {
temp.setDate(date.getDate());
}
return temp;
}

To make things really simple you can use DateJS, a date library for JavaScript:
http://www.datejs.com/
Example code for you:
Date.today().add({ months: -1 });

If the setMonth method offered by gilly3 isn't what you're looking for, consider:
var someDate = new Date(); // add arguments as needed
someDate.setTime(someDate.getTime() - 3*28*24*60*60);
// assumes the definition of "one month" to be "four weeks".
Can be used for any amount of time, just set the right multiples.

I like the simplicity of gilly3's answer, but users will probably be surprised that a month before March 31 is March 3. I chose to implement a version that sticks to the end of the month, so a month before March 28, 29, 30, and 31 will all be Feb 28 when it's not a leap year.
function addMonths(date, months) {
var result = new Date(date),
expectedMonth = ((date.getMonth() + months) % 12 + 12) % 12;
result.setMonth(result.getMonth() + months);
if (result.getMonth() !== expectedMonth) {
result.setDate(0);
}
return result;
}
var dt2004_05_31 = new Date("2004-05-31 0:00"),
dt2001_05_31 = new Date("2001-05-31 0:00"),
dt2001_03_31 = new Date("2001-03-31 0:00"),
dt2001_02_28 = new Date("2001-02-28 0:00"),
result = addMonths(dt2001_05_31, -2);
console.assert(dt2001_03_31.getTime() == result.getTime(), result.toDateString());
result = addMonths(dt2001_05_31, -3);
console.assert(dt2001_02_28.getTime() == result.getTime(), result.toDateString());
result = addMonths(dt2001_05_31, 36);
console.assert(dt2004_05_31.getTime() == result.getTime(), result.toDateString());
result = addMonths(dt2004_05_31, -38);
console.assert(dt2001_03_31.getTime() == result.getTime(), result.toDateString());
console.log('Done.');

Do this
let currentdate = new Date();
let last3months = new Date(currentdate.setMonth(currentdate.getMonth()-3));
Javascript's setMonth method also takes care of the year. For instance, the above code will return 2020-01-29 if currentDate is set as new Date("2020-01-29")

For get date three monts prior to today :
let d = new Date(new Date().setMonth(new Date().getMonth() - 3))
console.log(d.toISOString().slice(0, 10))
// 2022-05-24 (today is 2022-08-24)

var d = new Date("2013/01/01");
console.log(d.toLocaleDateString());
d.setMonth(d.getMonth() + 18);
console.log(d.toLocaleDateString());

This is the Smallest and easiest code.
var minDate = new Date();
minDate.setMonth(minDate.getMonth() - 3);
Declare variable which has current date.
then just by using setMonth inbuilt function we can get 3 month back date.

There is an elegant answer already but I find that its hard to read so I made my own function. For my purposes I didn't need a negative result but it wouldn't be hard to modify.
var subtractMonths = function (date1,date2) {
if (date1-date2 <=0) {
return 0;
}
var monthCount = 0;
while (date1 > date2){
monthCount++;
date1.setMonth(date1.getMonth() -1);
}
return monthCount;
}

As I don't seem to see it already suggested....
const d = new Date();
const day = d.getDate();
const goBack = 3;
for (let i = 0; i < goBack; i++) d.setDate(0);
d.setDate(day);
This will give you the date of today's date 3 months ago as .setDate(0) sets the date to the last day of last month irrespective of how many days a month contains. day is used to restore today's date value.

var todayDate = new Date().toISOString().slice(0, 10);
var d = new Date(todayDate);
d.setMonth(d.getMonth() -3);
console.log(todayDate)
console.log(d.toISOString().slice(0, 10));

d.setMonth changed local time in browser try
const calcDate = (m) => {
let date = new Date();
let day = date.getDate();
let month = date.getMonth() + 1;
let year = date.getFullYear();
let days = 0;
if (m > 0) {
for (let i = 1; i < m; i++) {
month += 1;
if (month > 12) {
year += 1;
month = 1;
}
days += new Date(year, month, 0).getDate();
}
} else {
for (let i = m; i < 0; i++) {
month -= 1;
if (month < 1) {
year -= 1;
month = 12;
}
days -= new Date(year, month, 0).getDate();
}
}
const newTime = date.getTime() + 3600 * 24 * 1000 * days;
return new Date(newTime);
};
calcDate(3)//+3 month

Since "Feb 31th" is auto converted to "March 3" or "March 2", as a month before "March 31th", which is quite counterintuitive, I decided to do it just like how I do it in my mind.
Similar to #Don Kirkby 's answer, I also revise the date with the last day of the target month.
function nMonthsAgo(date, n) {
// get the target year, month, date
const y = date.getFullYear() - Math.trunc(n / 12)
const m = date.getMonth() - n % 12
let d = date.getDate()
if (d > 27) { // get a valid date
const lastDateofMonth = new Date(y, m + 1, 0).getDate()
d = Math.min(d, lastDateofMonth)
}
return new Date(y, m, d)
}
d = new Date('2022-03-31')
nMonthsAgo(d, 1).toLocaleDateString()
Finally, I love what #gilly3 said in his answer:
If your requirements are more complicated than that, use some math and write some code. You are a developer! You don't have to install a library! You don't have to copy and paste from stackoverflow! You can develop the code yourself to do precisely what you need!

for (let monthOfYear = 0; monthOfYear < 12; monthOfYear++) {
const maxDate = new Date();
const minDate = new Date();
const max = maxDate.setMonth(maxDate.getMonth() - (monthOfYear - 1), 0);
const min = maxDate.setMonth(minDate.getMonth() - (monthOfYear), 1);
console.log('max: ', new Date(max));
console.log('min: ', new Date(min));
}

In my case I needed to substract 1 month to current date. The important part was the month number, so it doesn't care in which day of the current month you are at, I needed last month. This is my code:
var dateObj = new Date('2017-03-30 00:00:00'); //Create new date object
console.log(dateObj); // Thu Mar 30 2017 00:00:00 GMT-0300 (ART)
dateObj.setDate(1); //Set first day of the month from current date
dateObj.setDate(-1); // Substract 1 day to the first day of the month
//Now, you are in the last month
console.log(dateObj); // Mon Feb 27 2017 00:00:00 GMT-0300 (ART)
Substract 1 month to actual date it's not accurate, that's why in first place I set first day of the month (first day of any month always is first day) and in second place I substract 1 day, which always send you to last month.
Hope to help you dude.
var dateObj = new Date('2017-03-30 00:00:00'); //Create new date object
console.log(dateObj); // Thu Mar 30 2017 00:00:00 GMT-0300 (ART)
dateObj.setDate(1); //Set first day of the month from current date
dateObj.setDate(-1); // Substract 1 day to the first day of the month
//Now, you are in the last month
console.log(dateObj); // Mon Feb 27 2017 00:00:00 GMT-0300 (ART)

var date=document.getElementById("date");
var d = new Date();
document.write(d + "<br/>");
d.setMonth(d.getMonth() - 6);
document.write(d);
if(d<date)
document.write("lesser then 6 months");
else
document.write("greater then 6 months");

Pass a JS Date object and an integer of how many months you want to add/subtract. monthsToAdd can be positive or negative. Returns a JS date object.
If your originalDateObject is March 31, and you pass -1 as monthsToAdd, then your output date will be February 28.
If you pass a large number of months, say 36, it will handle the year adjustment properly as well.
const addMonthsToDate = (originalDateObject, monthsToAdd) => {
const originalDay = originalDateObject.getUTCDate();
const originalMonth = originalDateObject.getUTCMonth();
const originalYear = originalDateObject.getUTCFullYear();
const monthDayCountMap = {
"0": 31,
"1": 28,
"2": 31,
"3": 30,
"4": 31,
"5": 30,
"6": 31,
"7": 31,
"8": 30,
"9": 31,
"10": 30,
"11": 31
};
let newMonth;
if (newMonth > -1) {
newMonth = (((originalMonth + monthsToAdd) % 12)).toString();
} else {
const delta = (monthsToAdd * -1) % 12;
newMonth = originalMonth - delta < 0 ? (12+originalMonth) - delta : originalMonth - delta;
}
let newDay;
if (originalDay > monthDayCountMap[newMonth]) {
newDay = monthDayCountMap[newMonth].toString();
} else {
newDay = originalDay.toString();
}
newMonth = (+newMonth + 1).toString();
if (newMonth.length === 1) {
newMonth = '0' + newMonth;
}
if (newDay.length === 1) {
newDay = '0' + newDay;
}
if (monthsToAdd <= 0) {
monthsToAdd -= 11;
}
let newYear = (~~((originalMonth + monthsToAdd) / 12)) + originalYear;
let newTime = originalDateObject.toISOString().slice(10, 24);
const newDateISOString = `${newYear}-${newMonth}-${newDay}${newTime}`;
return new Date(newDateISOString);
};

Following code give me Just Previous Month From Current Month even the date is 31/30 of current date and last month is 30/29/28 days:
<!DOCTYPE html>
<html>
<body>
<p>Click the button to display the date after changing the month.</p>
<button onclick="myFunction()">Try it</button>
<p id="demo"></p>
<script>
function myFunction() {
var d = new Date("March 29, 2017"); // Please Try the result also for "March 31, 2017" Or "March 30, 2017"
var OneMonthBefore =new Date(d);
OneMonthBefore.setMonth(d.getMonth(),0);
if(OneMonthBefore.getDate() < d.getDate() )
{
d.setMonth(d.getMonth(),0);
}else
{
d.setMonth(d.getMonth()-1);
}
document.getElementById("demo").innerHTML = d;
}
</script>
</body>
</html>

var d = new Date();
document.write(d + "<br/>");
d.setMonth(d.getMonth() - 6);
document.write(d);

JavaScript - get the first day of the week from current date

I need the fastest way to get the first day of the week. For example: today is the 11th of November, and a Thursday; and I want the first day of this week, which is the 8th of November, and a Monday. I need the fastest method for MongoDB map function, any ideas?

Using the getDay method of Date objects, you can know the number of day of the week (being 0=Sunday, 1=Monday, etc).
You can then subtract that number of days plus one, for example:
function getMonday(d) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust when day is sunday
return new Date(d.setDate(diff));
}
getMonday(new Date()); // Mon Nov 08 2010

Not sure how it compares for performance, but this works.
var today = new Date();
var day = today.getDay() || 7; // Get current day number, converting Sun. to 7
if( day !== 1 ) // Only manipulate the date if it isn't Mon.
today.setHours(-24 * (day - 1)); // Set the hours to day number minus 1
// multiplied by negative 24
alert(today); // will be Monday
Or as a function:
# modifies _date_
function setToMonday( date ) {
var day = date.getDay() || 7;
if( day !== 1 )
date.setHours(-24 * (day - 1));
return date;
}
setToMonday(new Date());

CMS's answer is correct but assumes that Monday is the first day of the week.
Chandler Zwolle's answer is correct but fiddles with the Date prototype.
Other answers that add/subtract hours/minutes/seconds/milliseconds are wrong because not all days have 24 hours.
The function below is correct and takes a date as first parameter and the desired first day of the week as second parameter (0 for Sunday, 1 for Monday, etc.). Note: the hour, minutes and seconds are set to 0 to have the beginning of the day.
function firstDayOfWeek(dateObject, firstDayOfWeekIndex) {
const dayOfWeek = dateObject.getDay(),
firstDayOfWeek = new Date(dateObject),
diff = dayOfWeek >= firstDayOfWeekIndex ?
dayOfWeek - firstDayOfWeekIndex :
6 - dayOfWeek
firstDayOfWeek.setDate(dateObject.getDate() - diff)
firstDayOfWeek.setHours(0,0,0,0)
return firstDayOfWeek
}
// August 18th was a Saturday
let lastMonday = firstDayOfWeek(new Date('August 18, 2018 03:24:00'), 1)
// outputs something like "Mon Aug 13 2018 00:00:00 GMT+0200"
// (may vary according to your time zone)
document.write(lastMonday)

First / Last Day of The Week
To get the upcoming first day of the week, you can use something like so:
function getUpcomingSunday() {
const date = new Date();
const today = date.getDate();
const currentDay = date.getDay();
const newDate = date.setDate(today - currentDay + 7);
return new Date(newDate);
}
console.log(getUpcomingSunday());
Or to get the latest first day:
function getLastSunday() {
const date = new Date();
const today = date.getDate();
const currentDay = date.getDay();
const newDate = date.setDate(today - (currentDay || 7));
return new Date(newDate);
}
console.log(getLastSunday());
* Depending on your time zone, the beginning of the week doesn't has to start on Sunday, it can start on Friday, Saturday, Monday or any other day your machine is set to. Those methods will account for that.
* You can also format it using toISOString method like so: getLastSunday().toISOString()

Check out Date.js
Date.today().previous().monday()

var dt = new Date(); // current date of week
var currentWeekDay = dt.getDay();
var lessDays = currentWeekDay == 0 ? 6 : currentWeekDay - 1;
var wkStart = new Date(new Date(dt).setDate(dt.getDate() - lessDays));
var wkEnd = new Date(new Date(wkStart).setDate(wkStart.getDate() + 6));
This will work well.

I'm using this
function get_next_week_start() {
var now = new Date();
var next_week_start = new Date(now.getFullYear(), now.getMonth(), now.getDate()+(8 - now.getDay()));
return next_week_start;
}

Returns Monday 00am to Monday 00am.
const now = new Date()
const startOfWeek = new Date(now.getFullYear(), now.getMonth(), now.getDate() - now.getDay() + 1)
const endOfWeek = new Date(now.getFullYear(), now.getMonth(), startOfWeek.getDate() + 7)

This function uses the current millisecond time to subtract the current week, and then subtracts one more week if the current date is on a monday (javascript counts from sunday).
function getMonday(fromDate) {
// length of one day i milliseconds
var dayLength = 24 * 60 * 60 * 1000;
// Get the current date (without time)
var currentDate = new Date(fromDate.getFullYear(), fromDate.getMonth(), fromDate.getDate());
// Get the current date's millisecond for this week
var currentWeekDayMillisecond = ((currentDate.getDay()) * dayLength);
// subtract the current date with the current date's millisecond for this week
var monday = new Date(currentDate.getTime() - currentWeekDayMillisecond + dayLength);
if (monday > currentDate) {
// It is sunday, so we need to go back further
monday = new Date(monday.getTime() - (dayLength * 7));
}
return monday;
}
I have tested it when week spans over from one month to another (and also years), and it seems to work properly.

Good evening,
I prefer to just have a simple extension method:
Date.prototype.startOfWeek = function (pStartOfWeek) {
var mDifference = this.getDay() - pStartOfWeek;
if (mDifference < 0) {
mDifference += 7;
}
return new Date(this.addDays(mDifference * -1));
}
You'll notice this actually utilizes another extension method that I use:
Date.prototype.addDays = function (pDays) {
var mDate = new Date(this.valueOf());
mDate.setDate(mDate.getDate() + pDays);
return mDate;
};
Now, if your weeks start on Sunday, pass in a "0" for the pStartOfWeek parameter, like so:
var mThisSunday = new Date().startOfWeek(0);
Similarly, if your weeks start on Monday, pass in a "1" for the pStartOfWeek parameter:
var mThisMonday = new Date().startOfWeek(1);
Regards,

a more generalized version of this... this will give you any day in the current week based on what day you specify.
//returns the relative day in the week 0 = Sunday, 1 = Monday ... 6 = Saturday
function getRelativeDayInWeek(d,dy) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:dy); // adjust when day is sunday
return new Date(d.setDate(diff));
}
var monday = getRelativeDayInWeek(new Date(),1);
var friday = getRelativeDayInWeek(new Date(),5);
console.log(monday);
console.log(friday);

Simple solution for getting the first day of the week.
With this solution, it is possible to set an arbitrary start of week (e.g. Sunday = 0, Monday = 1, Tuesday = 2, etc.).
function getBeginOfWeek(date = new Date(), startOfWeek = 1) {
const result = new Date(date);
while (result.getDay() !== startOfWeek) {
result.setDate(result.getDate() - 1);
}
return result;
}
The solution correctly wraps on months (due to Date.setDate() being used)
For startOfWeek, the same constant numbers as in Date.getDay() can be used

setDate() has issues with month boundaries that are noted in comments above. A clean workaround is to find the date difference using epoch timestamps rather than the (surprisingly counterintuitive) methods on the Date object. I.e.
function getPreviousMonday(fromDate) {
var dayMillisecs = 24 * 60 * 60 * 1000;
// Get Date object truncated to date.
var d = new Date(new Date(fromDate || Date()).toISOString().slice(0, 10));
// If today is Sunday (day 0) subtract an extra 7 days.
var dayDiff = d.getDay() === 0 ? 7 : 0;
// Get date diff in millisecs to avoid setDate() bugs with month boundaries.
var mondayMillisecs = d.getTime() - (d.getDay() + dayDiff) * dayMillisecs;
// Return date as YYYY-MM-DD string.
return new Date(mondayMillisecs).toISOString().slice(0, 10);
}

Here is my solution:
function getWeekDates(){
var day_milliseconds = 24*60*60*1000;
var dates = [];
var current_date = new Date();
var monday = new Date(current_date.getTime()-(current_date.getDay()-1)*day_milliseconds);
var sunday = new Date(monday.getTime()+6*day_milliseconds);
dates.push(monday);
for(var i = 1; i < 6; i++){
dates.push(new Date(monday.getTime()+i*day_milliseconds));
}
dates.push(sunday);
return dates;
}
Now you can pick date by returned array index.

An example of the mathematically only calculation, without any Date functions.
const date = new Date();
const ts = +date;
const mondayTS = ts - ts % (60 * 60 * 24 * (7-4) * 1000);
const monday = new Date(mondayTS);
console.log(monday.toISOString(), 'Day:', monday.getDay());
const formatTS = v => new Date(v).toISOString();
const adjust = (v, d = 1) => v - v % (d * 1000);
const d = new Date('2020-04-22T21:48:17.468Z');
const ts = +d; // 1587592097468
const test = v => console.log(formatTS(adjust(ts, v)));
test(); // 2020-04-22T21:48:17.000Z
test(60); // 2020-04-22T21:48:00.000Z
test(60 * 60); // 2020-04-22T21:00:00.000Z
test(60 * 60 * 24); // 2020-04-22T00:00:00.000Z
test(60 * 60 * 24 * (7-4)); // 2020-04-20T00:00:00.000Z, monday
// So, what does `(7-4)` mean?
// 7 - days number in the week
// 4 - shifting for the weekday number of the first second of the 1970 year, the first time stamp second.
// new Date(0) ---> 1970-01-01T00:00:00.000Z
// new Date(0).getDay() ---> 4

It is important to discern between local time and UTC. I wanted to find the start of the week in UTC, so I used the following function.
function start_of_week_utc(date, start_day = 1) {
// Returns the start of the week containing a 'date'. Monday 00:00 UTC is
// considered to be the boundary between adjacent weeks, unless 'start_day' is
// specified. A Date object is returned.
date = new Date(date);
const day_of_month = date.getUTCDate();
const day_of_week = date.getUTCDay();
const difference_in_days = (
day_of_week >= start_day
? day_of_week - start_day
: day_of_week - start_day + 7
);
date.setUTCDate(day_of_month - difference_in_days);
date.setUTCHours(0);
date.setUTCMinutes(0);
date.setUTCSeconds(0);
date.setUTCMilliseconds(0);
return date;
}
To find the start of the week in a given timezone, first add the timezone offset to the input date and then subtract it from the output date.
const local_start_of_week = new Date(
start_of_week_utc(
date.getTime() + timezone_offset_ms
).getTime() - timezone_offset_ms
);

I use this:
let current_date = new Date();
let days_to_monday = 1 - current_date.getDay();
monday_date = current_date.addDays(days_to_monday);
// https://stackoverflow.com/a/563442/6533037
Date.prototype.addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
}
It works fine.

Accepted answer won't work for anyone who runs the code in UTC-XX:XX timezone.
Here is code which will work regardless of timezone for date only. This won't work if you provide time too. Only provide date or parse date and provide it as input. I have mentioned different test cases at start of the code.
function getDateForTheMonday(dateString) {
var orignalDate = new Date(dateString)
var modifiedDate = new Date(dateString)
var day = modifiedDate.getDay()
diff = modifiedDate.getDate() - day + (day == 0 ? -6:1);// adjust when day is sunday
modifiedDate.setDate(diff)
var diffInDate = orignalDate.getDate() - modifiedDate.getDate()
if(diffInDate == 6) {
diff = diff + 7
modifiedDate.setDate(diff)
}
console.log("Given Date : " + orignalDate.toUTCString())
console.log("Modified date for Monday : " + modifiedDate)
}
getDateForTheMonday("2022-08-01") // Jul month with 31 Days
getDateForTheMonday("2022-07-01") // June month with 30 days
getDateForTheMonday("2022-03-01") // Non leap year February
getDateForTheMonday("2020-03-01") // Leap year February
getDateForTheMonday("2022-01-01") // First day of the year
getDateForTheMonday("2021-12-31") // Last day of the year

Extending answer from #Christian C. Salvadó and information from #Ayyash (object is mutable) and #Awi and #Louis Ameline (set hours to 00:00:00)
The function can be like this
function getMonday(d) {
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust when day is sunday
d.setDate(diff);
d.setHours(0,0,0,0); // set hours to 00:00:00
return d; // object is mutable no need to recreate object
}
getMonday(new Date())

Check out: moment.js
Example:
moment().day(-7); // last Sunday (0 - 7)
moment().day(7); // next Sunday (0 + 7)
moment().day(10); // next Wednesday (3 + 7)
moment().day(24); // 3 Wednesdays from now (3 + 7 + 7 + 7)
Bonus: works with node.js too

Detect last week of each month with javascript

what would be a way in javascript to detect the last week of each (current) month. Or last monday of the month?

I would suggest to get the number of days in the month and then loop from the last day until getDay() gives back a Monday (1) or Sunday(0) .. based on when does your week start. Once you get your start date ... end date would be startDate + 7 so something along these lines
I found this helpful :
//Create a function that determines how many days in a month
//NOTE: iMonth is zero-based .. Jan is 0, Feb is 2 and so on ...
function daysInMonth(iMonth, iYear)
{
return 32 - new Date(iYear, iMonth, 32).getDate();
}
Then the loop:
//May - should return 31
var days_in_month = daysInMonth(4, 2010);
var weekStartDate = null;
var weekEndDate = null;
for(var i=days_in_month; i>0; i--)
{
var tmpDate = new Date(2010, 4, i);
//week starting on sunday
if(tmpDate.getDay() == 0)
{
weekStartDate = new Date(tmpDate);
weekEndDate = new Date(tmpDate.setDate(tmpDate.getDate() + 6));
//break out of the loop
break;
}
}

Playing with the date object and its methods you can do the following..
update
the complete calculations to get to last monday of the month could be compacted to
var d = new Date();
d.setMonth( d.getMonth() + 1 );
d.setDate(0);
lastmonday = d.getDate() - (d.getDay() - 1);
alert(lastmonday);
verbose example..
var now = new Date(); // get the current date
// calculate the last day of the month
if (now.getMonth() == 11 ) // if month is dec then go to next year and first month
{
nextmonth = 0;
nextyear = now.getFullYear() + 1;
}
else // otherwise go to next month of current year
{
nextmonth = now.getMonth() + 1;
nextyear = now.getFullYear();
}
var d = new Date( nextyear , nextmonth , 0); // setting day to 0 goes to last date of previous month
alert( d.getDay() ); // will alert the day of the week 0 being sunday .. you can calculate from there to get the first day of that week ..

Use getDay() to get the day of week of the last day in month and work from that (substracting the value from the number of days of the month should probably do the trick. +/- 1).

To determine whether it is a Monday, use .getDay() == 1. To determine if it is the last of the month, add seven days and compare months: nextMonday.setDate(monday.getDate()+7);
nextMonday.getMonth() == monday.getMonth();

The Javascript "Date" object is your friend.
function lastOfThisMonth(whichDay) {
var d= new Date(), month = d.getMonth();
d.setDate(1);
while (d.getDay() !== whichDay) d.setDate(d.getDate() + 1);
for (var n = 1; true; n++) {
var nd = new Date(d.getFullYear(), month, d.getDate() + n * 7);
if (nd.getMonth() !== month)
return new Date(d.getFullYear(), month, d.getDate() + (n - 1) * 7).getDate();
}
}
That'll give you the date (in the month, like 30) of the last day of the month that's the chosen day of the week (0 through 7).
Finding the last week of the month will depend on what you mean by that. If you mean the last complete week, then (if you mean Sunday - Saturday) find the last Saturday, and subtract 6. If you mean the last week that starts in the month, find the last Sunday.

You may also like to find the third Monday or the first Tuesday before or after a given date,
or flag every Wednesday between two dates.
Date.prototype.lastweek= function(wd, n){
n= n || 1;
return this.nextweek(wd, -n);
}
Date.prototype.nextweek= function(wd, n){
if(n== undefined) n= 1;
var incr= (n<0)? 1: -1,
D= new Date(this),
dd= D.getDay();
if(wd=== undefined) wd= dd;
if(dd!= wd) while(D.getDay()!= wd) D.setDate(D.getDate()+incr);
D.setDate(D.getDate()+7*n);
D.setHours(0, 0, 0, 0);
return D;
}
function lastMondayinmonth(month, year){
var day= new Date();
if(!month) month= day.getMonth()+1;
if(!year) year= day.getFullYear();
day.setFullYear(year, month, 0);
return day.lastweek(1);
}
alert(lastMondayinmonth())

i found such example that detects last monday of each week but it wont detect last monday of the month. maybe it will help to find better solution, that code looks short.
var dif, d = new Date(); // Today's date
dif = (d.getDay() + 6) % 7; // Number of days to subtract
d = new Date(d - dif * 24*60*60*1000); // Do the subtraction
alert(d); // Last monday.

OK, so far i came up with such solution making it a bit of my own way and getting a few things mentioned here. It works correct and always returns the last monday of current month.
//function that will help to check how many days in month
function daysInMonth(iMonth, iYear)
{
return 32 - new Date(iYear, iMonth, 32).getDate();
}
var dif = null;
d = new Date(); // Today's date
countDays = daysInMonth(d.getMonth(),d.getFullYear()); //Checking number of days in current month
d.setDate(countDays); //setting the date to last day of the month
dif = (d.getDay() + 6) % 7; // Number of days to subtract
d = new Date(d - dif * 24*60*60*1000); // Do the subtraction
alert(d.getDate()); //finally you get the last monday of the current month

Get the last day of the month:
/**
* Accepts either zero, one, or two parameters.
* If zero parameters: defaults to today's date
* If one parameter: Date object
* If two parameters: year, (zero-based) month
*/
function getLastDay() {
var year, month;
var lastDay = new Date();
if (arguments.length == 1) {
lastDay = arguments[0];
} else if (arguments.length > 0) {
lastDay.setYear(arguments[0]);
lastDay.setMonth(arguments[1]);
}
lastDay.setMonth(lastDay.getMonth() + 1);
lastDay.setDate(0);
return lastDay;
}
Get the last Monday:
/**
* Accepts same parameters as getLastDay()
*/
function getLastMonday() {
var lastMonday = getLastDay.apply(this, arguments);
lastMonday.setDate(lastMonday.getDate() - (lastMonday.getDay() == 0 ? 6 : (lastMonday.getDay() - 1)));
return lastMonday;
}
Get week of the year for a given day:
/**
* Accepts one parameter: Date object.
* Assumes start of week is Sunday.
*/
function getWeek(d) {
var jan1 = new Date(d.getFullYear(), 0, 1);
return Math.ceil((((d - jan1) / (24 * 60 * 60 * 1000)) + jan1.getDay() + 1) / 7);
}
Putting them together (assuming you're using Firebug):
// Get the last day of August 2006:
var august2006 = new Date(2006, 7);
var lastDayAugust2006 = getLastDay(august2006);
console.log("lastDayAugust2006: %s", lastDayAugust2006);
// ***** Testing getWeek() *****
console.group("***** Testing getWeek() *****");
// Get week of January 1, 2010 (Should be 1):
var january12010Week = getWeek(new Date(2010, 0, 1));
console.log("january12010Week: %s", january12010Week);
// Get week of January 2, 2010 (Should still be 1):
var january22010Week = getWeek(new Date(2010, 0, 2));
console.log("january22010Week: %s", january22010Week);
// Get week of January 3, 2010 (Should be 2):
var january32010Week = getWeek(new Date(2010, 0, 3));
console.log("january32010Week: %s", january32010Week);
console.groupEnd();
// *****************************
// Get the last week of this month:
var lastWeekThisMonth = getWeek(getLastDay());
console.log("lastWeekThisMonth: %s", lastWeekThisMonth);
// Get the last week of January 2007:
var lastWeekJan2007 = getWeek(getLastDay(2007, 0));
console.log("lastWeekJan2007: %s", lastWeekJan2007);
// Get the last Monday of this month:
var lastMondayThisMonth = getLastMonday();
console.log("lastMondayThisMonth: %s", lastMondayThisMonth);
// Get the week of the last Monday of this month:
var lastMondayThisMonthsWeek = getWeek(lastMondayThisMonth);
console.log("lastMondayThisMonthsWeek: %s", lastMondayThisMonthsWeek);