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JavaScript application for showing the weekend dates?

I thought a lot - I tried but I could not solve it. I need a JavaScript application that shows the nearest weekend dates in the current date.
If it's a weekend now, give it the dates of this weekend, if not, then next weekend's dates.
I'm waiting for your help.
Respects.

You can use the built-in Date constructor.
var date = new Date();
var day = date.getDay();
var saturday;
var sunday;
if(day === 0 || day === 6){ //0 for Sunday, 6 for Saturday
saturday = date;
sunday = new Date(saturday.getTime());
sunday.setDate(saturday.getDate() + (day === 0 ? -1 : 1));
if(day === 0){
var temp = saturday;
saturday = sunday; //Confusing, but they are actually the wrong dates, so we are switching the dates
sunday = temp;
temp = null; //Free up some memory!
}
}
else{
//This is the complicated part, we need to find when is the next Saturday
saturday = new Date(date.getFullYear(), date.getMonth(), (date.getDate() + 6) - day);
sunday = new Date(saturday.getTime());
sunday.setDate(saturday.getDate() + (saturday.getDay() === 0 ? -1 : 1));
}
date = day = null; //Free up some memory!
document.body.innerText = [saturday, sunday];
To get the date, use saturday.getDate() or sunday.getDate().Remember that Date months are 0-based. See here for more info.

var chosenDay = new Date();
var box = [];
var counting = 0;
for (var i = 0; i < 7; i++) {
chosenDay.setDate(chosenDay.getDate() + counting);
var day = chosenDay.getDate();
var dayy = chosenDay.getDay();
var month = chosenDay.getMonth()+1;
var year = chosenDay.getFullYear();
box.push({day: day, dayy: dayy});
counting = 1;
};
Now to find Saturday and Sunday
box.map(function(obj) {
if (obj.dayy === 6) {
console.log('Saturday found');
alert(obj.day);
};
if (obj.dayy === 0) {
console.log('Sunday found');
alert(obj.day);
};
});

I interpret the "nearest" weekend as being the previous weekend for Monday and Tuesday, and the next weekend for Thursday and Friday. You didn't provide any information on what to do with Wednesday.
However, from other answers it seems you want either the current weekend for Saturday and Sunday and or the next weekend for weekdays.
The following is a little more concise than other answers:
/* Get nearest weekend to the provided date
** #param {Date} date - date to get weekends nearst to
** #returns {Array} array of Dates [Saturday, Sunday]
*/
function getNearestWeekend(date) {
// Copy date so don't mess with provided date
var d = new Date(+date);
// If weekday, move d to next Saturday else to current weekend Saturday
if (d.getDay() % 6) {
d.setDate(d.getDate() + 6 - d.getDay());
} else {
d.setDate(d.getDate() - (d.getDay()? 0 : 1));
}
// Return array with Dates for Saturday, Sunday
return [new Date(d), new Date(d.setDate(d.getDate() + 1))]
}
// Some tests
[new Date(2017,0,7), // Sat 7 Jan
new Date(2017,0,8), // Sun 8 Jan
new Date(2017,0,9), // Mon 9 Jan
new Date(2017,0,12) // Thu 12 Jan
].forEach(function(d) {
var opts = {weekday:'short', day:'numeric', month:'short'};
console.log('Date: ' + d.toLocaleString('en-GB',opts) + ' | Next weekend: ' +
getNearestWeekend(d).map(d =>d.toLocaleString('en-GB',opts)).join(' and ')
);
});

How to get Monday of a week as a number

I would like to get the first day of a week in a given year (assuming the week starts on a Monday).
Scenario: The year is 2016. It should return 4, because Monday the 4th of January 2016 is the first day of week 1 in 2016.
How would I do that? I want something like this:
var date = new Date();
var week = 1;
var year = 2016;
date.getMonday(week, year); // 4 (because 04/01/2016 is a Monday and is week number 1)
week = 5;
date.getMonday(week, year); // 30 (because 30/01/2016 is a Monday and is week number 5)
Thanks

You can use JavaScript's getDay() method to figure out which day of the week a date object refers to.
var output = document.getElementById('output');
var year = 2016;
var firstMonday = new Date(year, 0, 1); // year, month (zero-index), date
// starting at January 1st, increment the date until a Monday (`getDay() = 1`)
while(firstMonday.getDay() !== 1) {
firstMonday.setDate(firstMonday.getDate() + 1);
}
// output the date of the first Monday in January
output.value = firstMonday.getDate();
<textarea id="output"></textarea>

I've made a function to solve this... see bellow
function getDayInWeek(dayOfWeek, week, year){
dayOfWeek = dayOfWeek % 7; //ensure day of week
var baseDate = new Date(year, 0, 1); //get the first day
var firstDayOfWeek = baseDate.getDay(); //get the first week day
var inWeek = (week - 1) * 7; //get the days to start of week
var diff = firstDayOfWeek - dayOfWeek; //get the diff for day in that week
if(diff < 0) diff += 7;
baseDate.setDate(inWeek + diff);
return baseDate.getDate(); //get the month day
}
to use specify the week day
// 0 = sunday
// 1 = monday
// 2 = tuesday
// 3 = wednesday
// 4 = thursday
// 5 = friday
// 6 = saturday
var firstMonday = getDayInWeek(1, 1, 2016); // the monday in first week of 2016
var mondayOf5 = getDayInWeek(1, 5, 2016); // the monday in 5th week of 2016

To get ISO-8601 week, which will always be a Monday, see link:
Wikipedia
Calculate ISO 8601
function getISOWeek(week, year) {
var _date = new Date(year, 0, 1 + (week - 1) * 7);
var date_of_week = _date.getDay();
var ISOweekStart = _date;
(date_of_week <= 4) ? ISOweekStart.setDate(_date.getDate() - _date.getDay() + 1): ISOweekStart.setDate(_date.getDate() + 8 - _date.getDay());
return ISOweekStart;
}
console.log(getISOWeek(10, 2016));

Get weeks in year

Moment js has a function to get the number of days in a month : http://momentjs.com/docs/#/displaying/days-in-month/
However I could not find a function to find the number of iso weeks in a year (52 or 53).

Here's an answer that isn't dependent on a library. It uses a function to calculate the week in the year that 31 December falls in for the required year. If the week is 1 (i.e. 31 December is in the first week of the following year), it moves the day number lower until it gets a different value, which will be the last week of the required year.
function getWeekNumber(d) {
// Copy date so don't modify original
d = new Date(+d);
d.setHours(0, 0, 0, 0);
// Set to nearest Thursday: current date + 4 - current day number
// Make Sunday's day number 7
d.setDate(d.getDate() + 4 - (d.getDay() || 7));
// Get first day of year
var yearStart = new Date(d.getFullYear(), 0, 1);
// Calculate full weeks to nearest Thursday
var weekNo = Math.ceil((((d - yearStart) / 86400000) + 1) / 7)
// Return array of year and week number
return [d.getFullYear(), weekNo];
}
function weeksInYear(year) {
var month = 11,
day = 31,
week;
// Find week that 31 Dec is in. If is first week, reduce date until
// get previous week.
do {
d = new Date(year, month, day--);
week = getWeekNumber(d)[1];
} while (week == 1);
return week;
}
[2015, 2016, 2029, new Date().getFullYear()].forEach(year =>
console.log(`${year} has ${weeksInYear(year)} weeks`)
);
The getWeekNumber code is from here: Get week of year in JavaScript like in PHP.
Edit
Alternatively, if 31 December is in week 1 of the following year, then the subject year has 52 weeks and otherwise has 53 weeks.
function getWeekNumber(d) {
d = new Date(+d);
d.setHours(0, 0, 0, 0);
d.setDate(d.getDate() + 4 - (d.getDay() || 7));
var yearStart = new Date(d.getFullYear(), 0, 1);
var weekNo = Math.ceil((((d - yearStart) / 86400000) + 1) / 7)
return [d.getFullYear(), weekNo];
}
function weeksInYear(year) {
var d = new Date(year, 11, 31);
var week = getWeekNumber(d)[1];
return week == 1 ? 52 : week;
}
[2015, 2016, 2029, new Date().getFullYear()].forEach(year =>
console.log(`${year} has ${weeksInYear(year)} weeks`)
);

Use isoWeek on the last day of the year to get the number of weeks e.g. :
function weeksInYear(year) {
return Math.max(
moment(new Date(year, 11, 31)).isoWeek()
, moment(new Date(year, 11, 31-7)).isoWeek()
);
}

Feb. 4th 2014 the weeksInYear & isoWeeksInYear functions were added to moment.js
So today you can just use moment().isoWeeksInYear()or moment().weeksInYear()
For more into see the docs

Thought I would post a much simpler version that I derived from the wikipedia article.
https://en.wikipedia.org/wiki/ISO_week_date
The statement in the article is:
"The number of weeks in a given year is equal to the corresponding
week number of 28 December, because it is the only date that is always
in the last week of the year since it is a week before 4 January which
is always in the first week of the following year.
Using only the ordinal year number y, the number of weeks in that year
can be determined from a function, that
returns the day of the week of 31 December"
Therefore getWeekFor(new Date(2022, 11, 28) replacing the year with any year you want will always give you the number of weeks for that year.
// modified from https://stackoverflow.com/questions/6117814/get-week-of-year-in-javascript-like-in-php
const getWeekFor = (date) => {
const d = new Date(Date.UTC(date.getFullYear(), date.getMonth(), date.getDate()));
const dayNum = d.getUTCDay() || 7;
const utc = new Date(d.setUTCDate(d.getUTCDate() + 4 - dayNum));
const yearStart = new Date(Date.UTC(utc.getUTCFullYear(), 0, 1)).getTime();
return Math.ceil(((d.getTime() - yearStart) / 86400000 + 1) / 7);
};
const weeks = getWeekFor(new Date(2020, 11, 28)) // 53.
console.log(weeks);

Get all weeks and periods of that week for a year, for whom it may interest
function getWeekPeriodsInYear(year) {
weeks = [];
// Get the first and last day of the year
currentDay = moment([year, 1]).startOf('year');
dayOfWeek = moment(currentDay).day();
lastDay = moment([year, 1]).endOf('year');
weeksInYear = moment(`${year}-01-01`).isoWeeksInYear();
daysToAdd = 7 - dayOfWeek;
for (let weekNumber = 1; weekNumber < weeksInYear + 1; weekNumber++) {
let endOfWeek = moment(currentDay).add(daysToAdd, 'days');
if (moment(endOfWeek).year() !== year) {
endOfWeek = lastDay;
}
weeks.push({ weekNumber, start: currentDay.toDate(), end: endOfWeek.toDate() });
currentDay = endOfWeek.add(1, 'day');
daysToAdd = 6;
}
return weeks;
}
getWeekPeriodsInYear(new Date().getFullYear()).forEach(period =>
document.write(`Week ${period.weekNumber} from ${moment(period.start).format('DD-MM-YYYY')} up to and including ${moment(period.end).format('DD-MM-YYYY')}<br/>`)
);
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.29.1/moment.min.js"></script>

Javascript: get Monday and Sunday of the previous week

I am using the following script to get Monday (first) and Sunday (last) for the previous week:
var curr = new Date; // get current date
var first = curr.getDate() - curr.getDay() - 6; // Gets day of the month (e.g. 21) - the day of the week (e.g. wednesday = 3) = Sunday (18th) - 6
var last = first + 6; // last day is the first day + 6
var startDate = new Date(curr.setDate(first));
var endDate = new Date(curr.setDate(last));
This works fine if last Monday and Sunday were also in the same month, but I just noticed today that it doesn't work if today is December and last Monday was in November.
I'm a total JS novice, is there another way to get these dates?

You can get the previous Monday by getting the Monday of this week and subtracting 7 days. The Sunday will be one day before that, so:
var d = new Date();
// set to Monday of this week
d.setDate(d.getDate() - (d.getDay() + 6) % 7);
// set to previous Monday
d.setDate(d.getDate() - 7);
// create new date of day before
var sunday = new Date(d.getFullYear(), d.getMonth(), d.getDate() - 1);
For 2012-12-03 I get:
Mon 26 Nov 2012
Sun 25 Nov 2012
Is that what you want?
// Or new date for the following Sunday
var sunday = new Date(d.getFullYear(), d.getMonth(), d.getDate() + 6);
which gives
Sun 02 Dec 2012
In general, you can manipulate date objects by add and subtracting years, months and days. The object will handle negative values automatically, e.g.
var d = new Date(2012,11,0)
Will create a date for 2012-11-30 (noting that months are zero based so 11 is December). Also:
d.setMonth(d.getMonth() - 1); // 2012-10-30
d.setDate(d.getDate() - 30); // 2012-09-30

if you dont want to do it with an external library you should work with timestamps. i created a solution where you would substract 60*60*24*7*1000 (which is 604800000, which is 1 week in milliseconds) from the current Date and go from there:
var beforeOneWeek = new Date(new Date().getTime() - 60 * 60 * 24 * 7 * 1000)
, day = beforeOneWeek.getDay()
, diffToMonday = beforeOneWeek.getDate() - day + (day === 0 ? -6 : 1)
, lastMonday = new Date(beforeOneWeek.setDate(diffToMonday))
, lastSunday = new Date(beforeOneWeek.setDate(diffToMonday + 6));

You could use a library like moment.js.
See the subtract method http://momentjs.com/docs/#/manipulating/subtract/

A few answers mentioned moment, but no one wrote about this simple method:
moment().day(-13) // Monday last week
moment().day(-7) // Sunday last week
.day sets a week day, so it doesn't matter what day is it today, only week matters.

This is the general solution of find any day of any week.
function getParticularDayTimestamp(lastWeekDay) {
var currentWeekMonday = new Date().getDate() - new Date().getDay() + 1;
return new Date().setDate(currentWeekMonday - lastWeekDay);
}
console.log(getParticularDayTimestamp(7)) // for last week monday
console.log(getParticularDayTimestamp(1)) // for last week sunday
console.log(getParticularDayTimestamp(14)) // for last to last week monday
console.log(getParticularDayTimestamp(8)) // for last to last week sunday

Using Moment you can do the following
var lastWeek = moment().isoWeek(moment().subtract(1,'w').week());
var mondayDifference = lastWeek.dayOfYear() - lastWeek.weekday() + 1;
var sundayDifference = mondayDifference - 1;
var lastMonday = moment().dayOfYear(mondayDifference);
var lastSunday = moment().dayOfYear(sundayDifference );

it can be this simple.
var today = new Date();
var sunday = new Date(this.today.getFullYear(), this.today.getMonth(), this.today.getDate() - this.today.getDay());

Here you have a multi-purpose function:
function getThe(numOfWeeks, weekday, tense, fromDate) {
// for instance: var lastMonday = getThe(1,"Monday","before",new Date())
var targetWeekday = -1;
var dateAdjustment = clone(fromDate);
var result = clone(fromDate);
switch (weekday) {
case "Monday": targetWeekday = 8; break;
case "Tuesday": targetWeekday = 2; break;
case "Wednesday": targetWeekday = 3; break;
case "Thursday": targetWeekday = 4; break;
case "Friday": targetWeekday = 5; break;
case "Saturday": targetWeekday = 6; break;
case "Sunday": targetWeekday = 7;
}
var adjustment = 7 * (numOfWeeks - 1);
if (tense == "after") adjustment = -7 * numOfWeeks;
dateAdjustment.setDate(fromDate.getDate() - targetWeekday);
var weekday = dateAdjustment.getDay();
result.setDate(fromDate.getDate() - weekday - adjustment);
result.setHours(0,0,0,0);
return result;
}
You can find the "clone(obj)" function in the next post: https://stackoverflow.com/a/728694/6751764

You can use a third party date library to deal with dates. For example:
var startOfWeek = moment().startOf('week').toDate();
var endOfWeek = moment().endOf('week').toDate();
if you want to use JavaScript then use the below code
var curr = new Date; // get current date
var first = curr.getDate() - curr.getDay()+1; // First day is the day of the month - the day of the week
var last = first + 6; // last day is the first day + 6
var startDate = new Date(curr.setDate(first));
startDate = ""+startDate.getFullYear()+"-"+ (startDate.getMonth() + 1) + "-" + startDate.getDate()
var endDate = new Date(curr.setDate(last));
endDate = "" + (endDate.getMonth() + 1) + "/" + endDate.getDate() + "/" + endDate.getFullYear();
alert(startDate+" , "+endDate)

JavaScript - get the first day of the week from current date

I need the fastest way to get the first day of the week. For example: today is the 11th of November, and a Thursday; and I want the first day of this week, which is the 8th of November, and a Monday. I need the fastest method for MongoDB map function, any ideas?

Using the getDay method of Date objects, you can know the number of day of the week (being 0=Sunday, 1=Monday, etc).
You can then subtract that number of days plus one, for example:
function getMonday(d) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust when day is sunday
return new Date(d.setDate(diff));
}
getMonday(new Date()); // Mon Nov 08 2010

Not sure how it compares for performance, but this works.
var today = new Date();
var day = today.getDay() || 7; // Get current day number, converting Sun. to 7
if( day !== 1 ) // Only manipulate the date if it isn't Mon.
today.setHours(-24 * (day - 1)); // Set the hours to day number minus 1
// multiplied by negative 24
alert(today); // will be Monday
Or as a function:
# modifies _date_
function setToMonday( date ) {
var day = date.getDay() || 7;
if( day !== 1 )
date.setHours(-24 * (day - 1));
return date;
}
setToMonday(new Date());

CMS's answer is correct but assumes that Monday is the first day of the week.
Chandler Zwolle's answer is correct but fiddles with the Date prototype.
Other answers that add/subtract hours/minutes/seconds/milliseconds are wrong because not all days have 24 hours.
The function below is correct and takes a date as first parameter and the desired first day of the week as second parameter (0 for Sunday, 1 for Monday, etc.). Note: the hour, minutes and seconds are set to 0 to have the beginning of the day.
function firstDayOfWeek(dateObject, firstDayOfWeekIndex) {
const dayOfWeek = dateObject.getDay(),
firstDayOfWeek = new Date(dateObject),
diff = dayOfWeek >= firstDayOfWeekIndex ?
dayOfWeek - firstDayOfWeekIndex :
6 - dayOfWeek
firstDayOfWeek.setDate(dateObject.getDate() - diff)
firstDayOfWeek.setHours(0,0,0,0)
return firstDayOfWeek
}
// August 18th was a Saturday
let lastMonday = firstDayOfWeek(new Date('August 18, 2018 03:24:00'), 1)
// outputs something like "Mon Aug 13 2018 00:00:00 GMT+0200"
// (may vary according to your time zone)
document.write(lastMonday)

First / Last Day of The Week
To get the upcoming first day of the week, you can use something like so:
function getUpcomingSunday() {
const date = new Date();
const today = date.getDate();
const currentDay = date.getDay();
const newDate = date.setDate(today - currentDay + 7);
return new Date(newDate);
}
console.log(getUpcomingSunday());
Or to get the latest first day:
function getLastSunday() {
const date = new Date();
const today = date.getDate();
const currentDay = date.getDay();
const newDate = date.setDate(today - (currentDay || 7));
return new Date(newDate);
}
console.log(getLastSunday());
* Depending on your time zone, the beginning of the week doesn't has to start on Sunday, it can start on Friday, Saturday, Monday or any other day your machine is set to. Those methods will account for that.
* You can also format it using toISOString method like so: getLastSunday().toISOString()

Check out Date.js
Date.today().previous().monday()

var dt = new Date(); // current date of week
var currentWeekDay = dt.getDay();
var lessDays = currentWeekDay == 0 ? 6 : currentWeekDay - 1;
var wkStart = new Date(new Date(dt).setDate(dt.getDate() - lessDays));
var wkEnd = new Date(new Date(wkStart).setDate(wkStart.getDate() + 6));
This will work well.

I'm using this
function get_next_week_start() {
var now = new Date();
var next_week_start = new Date(now.getFullYear(), now.getMonth(), now.getDate()+(8 - now.getDay()));
return next_week_start;
}

Returns Monday 00am to Monday 00am.
const now = new Date()
const startOfWeek = new Date(now.getFullYear(), now.getMonth(), now.getDate() - now.getDay() + 1)
const endOfWeek = new Date(now.getFullYear(), now.getMonth(), startOfWeek.getDate() + 7)

This function uses the current millisecond time to subtract the current week, and then subtracts one more week if the current date is on a monday (javascript counts from sunday).
function getMonday(fromDate) {
// length of one day i milliseconds
var dayLength = 24 * 60 * 60 * 1000;
// Get the current date (without time)
var currentDate = new Date(fromDate.getFullYear(), fromDate.getMonth(), fromDate.getDate());
// Get the current date's millisecond for this week
var currentWeekDayMillisecond = ((currentDate.getDay()) * dayLength);
// subtract the current date with the current date's millisecond for this week
var monday = new Date(currentDate.getTime() - currentWeekDayMillisecond + dayLength);
if (monday > currentDate) {
// It is sunday, so we need to go back further
monday = new Date(monday.getTime() - (dayLength * 7));
}
return monday;
}
I have tested it when week spans over from one month to another (and also years), and it seems to work properly.

Good evening,
I prefer to just have a simple extension method:
Date.prototype.startOfWeek = function (pStartOfWeek) {
var mDifference = this.getDay() - pStartOfWeek;
if (mDifference < 0) {
mDifference += 7;
}
return new Date(this.addDays(mDifference * -1));
}
You'll notice this actually utilizes another extension method that I use:
Date.prototype.addDays = function (pDays) {
var mDate = new Date(this.valueOf());
mDate.setDate(mDate.getDate() + pDays);
return mDate;
};
Now, if your weeks start on Sunday, pass in a "0" for the pStartOfWeek parameter, like so:
var mThisSunday = new Date().startOfWeek(0);
Similarly, if your weeks start on Monday, pass in a "1" for the pStartOfWeek parameter:
var mThisMonday = new Date().startOfWeek(1);
Regards,

a more generalized version of this... this will give you any day in the current week based on what day you specify.
//returns the relative day in the week 0 = Sunday, 1 = Monday ... 6 = Saturday
function getRelativeDayInWeek(d,dy) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:dy); // adjust when day is sunday
return new Date(d.setDate(diff));
}
var monday = getRelativeDayInWeek(new Date(),1);
var friday = getRelativeDayInWeek(new Date(),5);
console.log(monday);
console.log(friday);

Simple solution for getting the first day of the week.
With this solution, it is possible to set an arbitrary start of week (e.g. Sunday = 0, Monday = 1, Tuesday = 2, etc.).
function getBeginOfWeek(date = new Date(), startOfWeek = 1) {
const result = new Date(date);
while (result.getDay() !== startOfWeek) {
result.setDate(result.getDate() - 1);
}
return result;
}
The solution correctly wraps on months (due to Date.setDate() being used)
For startOfWeek, the same constant numbers as in Date.getDay() can be used

setDate() has issues with month boundaries that are noted in comments above. A clean workaround is to find the date difference using epoch timestamps rather than the (surprisingly counterintuitive) methods on the Date object. I.e.
function getPreviousMonday(fromDate) {
var dayMillisecs = 24 * 60 * 60 * 1000;
// Get Date object truncated to date.
var d = new Date(new Date(fromDate || Date()).toISOString().slice(0, 10));
// If today is Sunday (day 0) subtract an extra 7 days.
var dayDiff = d.getDay() === 0 ? 7 : 0;
// Get date diff in millisecs to avoid setDate() bugs with month boundaries.
var mondayMillisecs = d.getTime() - (d.getDay() + dayDiff) * dayMillisecs;
// Return date as YYYY-MM-DD string.
return new Date(mondayMillisecs).toISOString().slice(0, 10);
}

Here is my solution:
function getWeekDates(){
var day_milliseconds = 24*60*60*1000;
var dates = [];
var current_date = new Date();
var monday = new Date(current_date.getTime()-(current_date.getDay()-1)*day_milliseconds);
var sunday = new Date(monday.getTime()+6*day_milliseconds);
dates.push(monday);
for(var i = 1; i < 6; i++){
dates.push(new Date(monday.getTime()+i*day_milliseconds));
}
dates.push(sunday);
return dates;
}
Now you can pick date by returned array index.

An example of the mathematically only calculation, without any Date functions.
const date = new Date();
const ts = +date;
const mondayTS = ts - ts % (60 * 60 * 24 * (7-4) * 1000);
const monday = new Date(mondayTS);
console.log(monday.toISOString(), 'Day:', monday.getDay());
const formatTS = v => new Date(v).toISOString();
const adjust = (v, d = 1) => v - v % (d * 1000);
const d = new Date('2020-04-22T21:48:17.468Z');
const ts = +d; // 1587592097468
const test = v => console.log(formatTS(adjust(ts, v)));
test(); // 2020-04-22T21:48:17.000Z
test(60); // 2020-04-22T21:48:00.000Z
test(60 * 60); // 2020-04-22T21:00:00.000Z
test(60 * 60 * 24); // 2020-04-22T00:00:00.000Z
test(60 * 60 * 24 * (7-4)); // 2020-04-20T00:00:00.000Z, monday
// So, what does `(7-4)` mean?
// 7 - days number in the week
// 4 - shifting for the weekday number of the first second of the 1970 year, the first time stamp second.
// new Date(0) ---> 1970-01-01T00:00:00.000Z
// new Date(0).getDay() ---> 4

It is important to discern between local time and UTC. I wanted to find the start of the week in UTC, so I used the following function.
function start_of_week_utc(date, start_day = 1) {
// Returns the start of the week containing a 'date'. Monday 00:00 UTC is
// considered to be the boundary between adjacent weeks, unless 'start_day' is
// specified. A Date object is returned.
date = new Date(date);
const day_of_month = date.getUTCDate();
const day_of_week = date.getUTCDay();
const difference_in_days = (
day_of_week >= start_day
? day_of_week - start_day
: day_of_week - start_day + 7
);
date.setUTCDate(day_of_month - difference_in_days);
date.setUTCHours(0);
date.setUTCMinutes(0);
date.setUTCSeconds(0);
date.setUTCMilliseconds(0);
return date;
}
To find the start of the week in a given timezone, first add the timezone offset to the input date and then subtract it from the output date.
const local_start_of_week = new Date(
start_of_week_utc(
date.getTime() + timezone_offset_ms
).getTime() - timezone_offset_ms
);

I use this:
let current_date = new Date();
let days_to_monday = 1 - current_date.getDay();
monday_date = current_date.addDays(days_to_monday);
// https://stackoverflow.com/a/563442/6533037
Date.prototype.addDays = function(days) {
var date = new Date(this.valueOf());
date.setDate(date.getDate() + days);
return date;
}
It works fine.

Accepted answer won't work for anyone who runs the code in UTC-XX:XX timezone.
Here is code which will work regardless of timezone for date only. This won't work if you provide time too. Only provide date or parse date and provide it as input. I have mentioned different test cases at start of the code.
function getDateForTheMonday(dateString) {
var orignalDate = new Date(dateString)
var modifiedDate = new Date(dateString)
var day = modifiedDate.getDay()
diff = modifiedDate.getDate() - day + (day == 0 ? -6:1);// adjust when day is sunday
modifiedDate.setDate(diff)
var diffInDate = orignalDate.getDate() - modifiedDate.getDate()
if(diffInDate == 6) {
diff = diff + 7
modifiedDate.setDate(diff)
}
console.log("Given Date : " + orignalDate.toUTCString())
console.log("Modified date for Monday : " + modifiedDate)
}
getDateForTheMonday("2022-08-01") // Jul month with 31 Days
getDateForTheMonday("2022-07-01") // June month with 30 days
getDateForTheMonday("2022-03-01") // Non leap year February
getDateForTheMonday("2020-03-01") // Leap year February
getDateForTheMonday("2022-01-01") // First day of the year
getDateForTheMonday("2021-12-31") // Last day of the year

Extending answer from #Christian C. Salvadó and information from #Ayyash (object is mutable) and #Awi and #Louis Ameline (set hours to 00:00:00)
The function can be like this
function getMonday(d) {
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust when day is sunday
d.setDate(diff);
d.setHours(0,0,0,0); // set hours to 00:00:00
return d; // object is mutable no need to recreate object
}
getMonday(new Date())

Check out: moment.js
Example:
moment().day(-7); // last Sunday (0 - 7)
moment().day(7); // next Sunday (0 + 7)
moment().day(10); // next Wednesday (3 + 7)
moment().day(24); // 3 Wednesdays from now (3 + 7 + 7 + 7)
Bonus: works with node.js too