I currently have a map of an array of users which all have a unique _id key / value.
user = [{_id: "1", ... }, {_id: "2", ... }, ... ]
I also have two other arrays, one named teams and another named accounts.
teams = [{ _id: "1", members: [{ userId: "2" }, { userId: "4" }, ... ], ... }]
accounts = [{ _id: "1", authorizedUsers: [{ userId: "3"}, ... ], ownerTeamId: "2" }, ... ]
Trying to create two comparison functions which takes the argument of user and outputs numberOfTeams and numberOfAccounts for the corresponding user.
I have attempted the numberOfTeams below but I'm not sure if it's the most optimal.
numberOfTeams(user) {
let count = 0;
teams.forEach(team => {
team.members.forEach(member => {
if (member.userId === user._id) {
count++
}
})
});
return count;
}
With the numberOfAccounts, I'm stuck on how to compare authorizedUsers === user._id OR ownerTeamId === team._id where also members.userId === user.id, and then count++.
It’s probably a good start to write a function to get the teams a user belongs to:
function containsUserId(users, id) {
return users.some(user => user.userId === id);
}
function getUserTeams(user, teams) {
return teams.filter(team =>
containsUserId(team.members, user._id));
}
because then you can write numberOfTeams using it:
numberOfTeams(user) {
return getUserTeams(user, teams).length;
}
then a similar function to get accounts:
function getUserAccounts(user, accounts) {
const userTeamIds = new Set(
getUserTeams(user).map(team => team._id)
);
return accounts.filter(account =>
containsUserId(account.authorizedUsers, user._id) ||
userTeamIds.has(accounts.ownerTeamId));
}
then numberOfAccounts using it:
numberOfAccounts(user) {
return getUserAccounts(user, accounts).length;
}
Essentially: use more functions so you can understand the steps you’re taking to solve your own problem and, in doing so, use those steps more effectively.
Related
I'm performing two MongoDB queries, and then I want to synchronize the resulting arrays, to make sure they are in the same order.
The first array is a set of (20) questions ids (this is the correct order):
q_id_arr: [
"5f86da2d37e3d200040ba523",
"5f86b6ce37e3d200040ba4c6",
"5ffc4abea04f3c0004e46cf3",
"5f86b66537e3d200040ba4c5",
"5f87f368554f370004ed17b4",
"5f86e48c37e3d200040ba53c",
"5ffc4dc4a04f3c0004e46d0b",
"5f86e19037e3d200040ba534",
"5f86aaa237e3d200040ba49b",
"5ffc479ba04f3c0004e46ce0",
"5f86b9dc37e3d200040ba4d2",
"5f85828e0e1bd30004361430",
"5f8700c937e3d200040ba548",
"5f86d81737e3d200040ba51c",
"5f8708d237e3d200040ba568",
"5f87060d37e3d200040ba55c",
"5f857dac0e1bd3000436141c",
"5f85703e0e1bd300043613ec",
"5f87e9d4554f370004ed178e",
"5f8073c04ad88e00041f015f"
]
The second array is a set of (20) results associated with the question ids:
team_trends: [
{
"_id":"5f87e9d4554f370004ed178e",
"positive":0.93,
"engaged":0.558
},
{
"_id":"5f86e19037e3d200040ba534",
"positive":0.585,
"engaged":0.567
},
{
"_id":"5f85828e0e1bd30004361430",
"positive":0.7,
"engaged":0.666
},
{
"_id":"5f8073c04ad88e00041f015f",
"positive":0.31,
"engaged":0.30999999999999994
},
{
"_id":"5f87f368554f370004ed17b4",
"positive":0.5449999999999999,
"engaged":0.57
},
{
"_id":"5f86b6ce37e3d200040ba4c6",
"positive":0.855,
"engaged":0.46599999999999997
},
{
"_id":"5f857dac0e1bd3000436141c",
"positive":0.92,
"engaged":0.524
},
{
"_id":"5f85703e0e1bd300043613ec",
"positive":0.15,
"engaged":0.39
},
{
"_id":"5f86aaa237e3d200040ba49b",
"positive":0.15000000000000002,
"engaged":0.584
},
{
"_id":"5f86b66537e3d200040ba4c5",
"positive":0.37,
"engaged":0.386
},
{
"_id":"5f86e48c37e3d200040ba53c",
"positive":0.615,
"engaged":0.548
},
{
"_id":"5ffc479ba04f3c0004e46ce0",
"positive":0.42000000000000004,
"engaged":0.583
},
{
"_id":"5f86b9dc37e3d200040ba4d2",
"positive":0.68,
"engaged":0.662
},
{
"_id":"5f86d81737e3d200040ba51c",
"positive":0.03,
"engaged":0.516
},
{
"_id":"5f87060d37e3d200040ba55c",
"positive":0.14,
"engaged":0.454
},
{
"_id":"5f86da2d37e3d200040ba523",
"positive":0.47,
"engaged":0.41500000000000004
},
{
"_id":"5f8708d237e3d200040ba568",
"positive":0.17,
"engaged":0.76
},
{
"_id":"5ffc4dc4a04f3c0004e46d0b",
"positive":0.395,
"engaged":0.53
},
{
"_id":"5ffc4abea04f3c0004e46cf3",
"positive":0.365,
"engaged":0.679
},
{
"_id":"5f8700c937e3d200040ba548",
"positive":0.93,
"engaged":0.6980000000000001
}
]
I want to reorganize team_trends into the same order as q_id_arr
Here is the code I'm using (following this SO Answer):
let c = [];
q_id_arr.forEach((q_oid => c.push(team_trends.find((obj => obj._id == q_oid)))));
However when I print console.log("the result of c"+ c) I get this result:
the result of c: [null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null,null]
Is this the right approach? Any suggestions are appreciated!
More Details:
Before this step I acquired the q_id_arr through mapping over an aggregate result, like this:
let q_id_arr = await user_trends.map(({ question_oid }) => question_oid)
When I tested console.log(typeof q_id_arr) it returned object.
How can I sort through the object??
Final code that fixed the issue.
user_trends.forEach((user => c.push(team_trends.find((obj => obj._id.toString() === user.question_oid.toString())))));
A couple of points to note here:
If you are using mongoose then it already returns an array from the aggregate function.
Mongoose uses the MongoDB NodeJs native driver at its core. In core driver ObjectId has a function .equals(otherId). It is always best to use this function for id comparisons.
References:
Comparing mongoose _id and strings
.aggregate(...).toArray is not a function
https://mongodb.github.io/node-mongodb-native/api-bson-generated/objectid.html#equals
You can try this using the arrays map method:
let sorted_team_trends = q_id_arr.map( q => team_trends.find(t => t._id === q) );
Assuming the two arrays are defined as fields like this:
let q_id_arr = [
"5f86da2d37e3d200040ba523",
"5f86b6ce37e3d200040ba4c6",
"5ffc4abea04f3c0004e46cf3",
...
];
let team_trends = [
{
"_id" : "5f87e9d4554f370004ed178e",
"positive" : 0.93,
"engaged" : 0.558
},
{
"_id" : "5f86e19037e3d200040ba534",
"positive" : 0.585,
"engaged" : 0.567
},
...
]
I am sorry if I am asking a very basic question, I have done some research over the internet but not getting anything useful.
I have a typescript object like :
var productIds=["one","two","three"];
let searchfilter = {
or: [{
id: { match:productids['0'] }
},{
id: { match:productids['1'] }
},{
id: { match:productids['2'] }
}]
};
My productIds can be dynamic and may hold different counts of values.
How can I create the same structure for a dynamic number of values. I tried forEach, but not sure about the syntax.
productids.forEach(function(value){
// not sure if this is right syntax, I am not getting desired results.
searchfilter.or = { id: { match:value }};
});
Can you help me with it?
You can create your full or array with a simple .map() :
var productIds = ["1", "2", "3"];
let searchfilter = {
or : productIds.map( n => ({ id : { match : productIds[n] } }))
};
However Mongo (which I believe you are using) has a $match method that's made to match a list :
{
$match: {
productIds: {
$in: productIds
}
}
}
I'll keep it as simple as I can
var productIds=["one","two","three"];
let searchfilter = productIds.map(p => {
return {id: { match: p }};
});
// function
addNewProduct(id: string) {
this.searchfilter.push({id: { match: id }});
}
How can I extract the 'jobs' object from a nested json list like this:
result:
{
person:
[
{
name: ""
address: ""
jobs: [
{
company:""
},
{
company:""
}
]
}
]
}
Thank you
Write a generic method to extract object properties.
function onExtract(key, data) {
if (isObject(data)) {
for (let item in data) {
if (key === item) {
return data[item];
}
const res = onExtract(key, data[item]);
if (res !== null) return res;
}
}
if (isArray(data)) {
for (let item of data) {
const res = onExtract(key, item);
if (res !== null) return res;
}
}
return null;
}
function isObject(obj) {
return Object.prototype.toString.call(obj) === "[object Object]";
}
function isArray(arr) {
return Object.prototype.toString.call(arr) === "[object Array]";
}
// test
const data = {
person: [
{
name: "",
address: "",
jobs: [
{
company: ""
},
{
company: ""
}
]
}
]
};
console.log(onExtract("jobs", data));
let's say you have a return var that contains this json value
let mappedCompanies = return.person.map(person =>
person.jobs.map(job => job.company)
).flatMap(m => m)
mappedCompanies would contain an array with all the companies names for each one of the registers in "person", all as one array of strings
you can read more about Array.map() here: https://developer.mozilla.org/pt-BR/docs/Web/JavaScript/Reference/Global_Objects/Array/map
A dynamic way to query the person[] and find jobs, is to use the javascript map() method.
Here is the code without comments.
const personsJobs = (personName, personAddress) => {
const jobs = result.person.map((el) => {
if (el.name === personName && el.address === personAddress) {
return el.jobs;
} else {
return null;
}
})
.filter((el) => el !== null);
return jobs;
};
console.log(personsJobs("wyatt", "1234 test ln"));
Here is the code with comments to explain how the personsJob function works.
// Blow is an ES6 arrow function with the parameters 'personName' and 'personAddress',
// which represents the person in which you are querying for jobs (using both a persons
// name and address so in the case of persons with the same name, you only find the jobs
// of the person you want).
const personsJobs = (personName, personAddress) => {
// Since 'person' is an array, we can use the 'map' method as stated before, which
// will create a new array (jobs) that will store the jobs a specific person has.
const jobs = result.person.map((el) => {
// el stands for the current position in the person array.
// if el's (the current person) name and address values are equal to that of the
// parameters personName and personAddress, then that persons jobs are added to the jobs // array, however, if el does not satisfy the two parameters, null is added to the jobs
// array.
// The array, upon completion, will look something like this: ["programmer", null, null]
if (el.name === personName && el.address === personAddress) {
return el.jobs;
} else {
return null;
}
})
// Finally, the filter method is called to remove all null values so that you will
// only have the persons job in the jobs array.
// After filtering, the array will look like this: ["programmer"]
.filter((el) => el !== null);
return jobs;
};
// Prints the array of wyatt's jobs
console.log(personsJobs("wyatt", "1234 test ln"));
So, following the conclusion of the function, you will have dynamically found the jobs of a specific person.
you can use flatMap function like:
const jobsData = result.person.flatMap(item => item.jobs);
Here is a flexible solution using object-scan
// const objectScan = require('object-scan');
const data = { person: [{ name: '', address: '', jobs: [{ company: '' }, { company: '' }] }] };
console.log(objectScan(['person[*].jobs'], { reverse: false, rtn: 'value' })(data));
// => [ [ { company: '' }, { company: '' } ] ]
.as-console-wrapper {max-height: 100% !important; top: 0}
<script src="https://bundle.run/object-scan#14.0.0"></script>
Disclaimer: I'm the author of object-scan
I have an activity feed, it contains a number of different types of activity for our site.
one type of activity is checkin. which logs when a user checks in and checkouts of a site.
The record entries look like so
Entryable_id | Entry_type | Action | timestamp
1 Ticket Update 12:01
3 Ticket New 12:07
4 CheckIn ClockedIn 14:30
4 CheckIn ClockedOut 17:30
What I want to do is create an array with entries in it like so
Entryable_id | ClockedIn| ClockedOut
4 14:30 17:30
so far what I have is
{
let staffCheckins = []
let checkinRecord = []
if (this.DiaryStore.entries.length) {
this.DiaryStore.entries.forEach(function(val) {
if (val.entryable_type === 'CheckIn') {
staffCheckins.push(val);
return val
}
})
}
staffCheckins.forEach(function(val) {
if (val.action === "ClockedIn") {
checkinRecord[val.entryable_id] = {
clockedIn: val.created_at,
user: val.user
}
}
if (val.action === "ClockedOut") {
checkinRecord[val.entryable_id] = {
clockedOut: val.created_at
}
}
})
console.log(completeCheckin)
},
which gives
1: clockedIn: "2019-07-22T10:26:45.000000Z",
2: clockedIn: "2019-07-22T12:38:02.000000Z"
so I assume that it is not appending to the key when i do
checkinRecord[val.entryable_id] = {clockedOut: val.created_at}
On top of that this all feels like a mess. is there a better way to filter and get what I need?
Thanks
You need to merge attribute, instead of assign to new object
staffCheckins.forEach(function(val) {
if (!checkinRecord[val.entryable_id]) {
checkinRecord[val.entryable_id] = {}
}
if (val.action === "ClockedIn") {
checkinRecord[val.entryable_id] = {
...checkinRecord[val.entryable_id],
clockedIn: val.created_at,
user: val.user
}
} else (val.action === "ClockedOut") {
checkinRecord[val.entryable_id] = {
...checkinRecord[val.entryable_id],
clockedOut: val.created_at
}
}
}
so I haven't gotten to test it because I'm out and about but you could try something like this. If they object entryable_id doesnt exist in the current object in the array, then it will create a new object with the members, otherwise it will find the object and update the fields
{
let staffCheckins = [];
let checkinRecord = [];
if (this.DiaryStore.entries.length) {
staffCheckins = this.DiaryStore.filter(val => val.entryable_type.toLowerCase() === 'checkin');
}
staffCheckins.forEach(function(val, i) {
let { action, entryable_id, created_at, user } = val;
if (!entryable_id in checkinRecord[i]) {
checkinRecord[i] = {
clockedIn: created_at,
clockedOut: created_at,
user
}
}
if (action.toLowerCase() === 'clockedin') {
checkinRecord[i] = {
...checkinRecord[i],
clockedIn: created_at,
user
}
} else if (action.toLowerCase() === 'clockedout') {
checkinRecord[i] = {
...checkinRecord[i],
clockedOut: created_at
}
}
});
}
apologies if I understood wrong but I'm also no currently at my actual computer to test any of it
You could do this whole operation in a filter reduce combination and create a groupBy object using the Entryable_id as keys.
Once loop completes get values array of that object
const checkinGroup = data.filter(({Entry_type}) => Entry_type === 'CheckIn')
.reduce((a, c)=>{
let {Entryable_id:id, Action, timestamp} = c;
a[id] = a[id] || {Entryable_id: id, ClockedIn: null, ClockedOut: null};
a[id][Action] = timestamp;
return a;
},{});
const res = Object.values(checkinGroup)
console.log(res)
<script>
const data = [{
Entryable_id: 1,
Entry_type: 'Ticket',
Action: 'Update',
timestamp: '12:01'
},
{
Entryable_id: 3,
Entry_type: 'Ticket',
Action: 'New',
timestamp: '12:07'
},
{
Entryable_id: 4,
Entry_type: 'CheckIn',
Action: 'ClockedIn',
timestamp: '14:30'
},
{
Entryable_id: 4,
Entry_type: 'CheckIn',
Action: 'ClockedOut',
timestamp: '17:30'
}
]
</script>
I've got data like this:
this.registrations = [{
event: "Juniors 18s",
day: "Friday",
group: "nonpro",
players: [{
first: "Mary",
last: "Mack",
email: "marymack#dressedinblack.com",
phone: "8888675309",
signed: false,
waivers: [{
has_signed: true,
token: "ab",
url: "somesite.com",
signatureUrl: "someothersite.com",
message: "Minor waiver"
},
{
has_signed: true,
token: "ab",
url: "somesite.com",
signatureUrl: "someothersite.com",
message: "Parental waiver"
}
]
},
{... another record like that one}
]
Is there a way to display if each player has signed all the waivers? I know there is a .every function but I'm not sure how to use it with this nested data structure.
I was thinking something like below, but it didn't work:
this.registrations.has_signed = this.registrations.waivers.every( waiver => waiver.has_signed === true )
Then I tried this one, which at least seems like it might be closer to a win (but not quite). the players.signed property isn't used, but someone put it in there as false by default, so I'd love to use it:
this.registrations.forEach(reg => {
reg.players.forEach(p => {
if (p.waivers.every(waiver => waiver.has_signed === true)) {
p.signed = true;
} else {
p.signed = false;
}
return reg;
});
});
This snippet should do the required task.
const modifiedPlayers = this.registrations.map(reg => reg.players).map(player => {
player.signed = player.waivers.every(waiver => waiver.has_signed);
return player;
});
this.registrations.players = modifiedPlayers;
this.registrations.has_signed = false;
this.registrations.forEach(registration =>
registration.players.forEach(player =>
this.registrations.has_signed = player.waivers.every(waiver => waiver.has_signed)
)
);
You have to loop the outer arrays first to get to the waivers and use every to find out the has-signed.