Javascript regex
I have following regex, i want to un-match zeros after decimal, 1.0 or 1.00 should not match but should match 1.25 or 1.2
^(?!0\.)(?:\d{1,3}(?:,\d{3})+|\d+)(?:\.\d{1,2})?$
it accepts following inputs
1.00
1.25
does not accept leading zero ex. 0.25
100
1000
1,000
100,000
You need to add a negative lookahead at the end:
^(?!0\.)(?:\d{1,3}(?:,\d{3})+|\d+)(?:\.(?!0+$)\d{1,2})?$
^^^^^^^
See the regex demo
The (?!0+$) negative lookahead restricts the subsequent consuming subpattern \d{1,2})?$ so that the \d{1,2} cannot match 00 or 0 any longer.
This looks at it from the opposite approach at what is allowed instead of excluded:
^[1-9],?[0-9]*.?[1-9]*$
Related
What is regex for age with 2 decimal points value with max value 99.11
Valid examples:
1
12.01
16.06
20.11
Invalid examples:
.0
1.12 (decimal value should be <12)
1.13 (decimal value should be <12)
12.111
100.00 (2 digit before decimal point, max 99.11)
I have tried ^[0-9]\d{0,1}(\.\d[0-1]\d{0,1})*(,\d+)?$ regex but it is not following all criteria.
can anyone help me?
You can try with this pattern:
/^\d{1,2}(\.(0[0-9]|1[01]))?$/
var pattern = /^\d{1,2}(\.(0[0-9]|1[01]))?$/;
console.log(pattern.test('1'));
console.log(pattern.test('12.01'));
console.log(pattern.test('16.06'));
console.log(pattern.test('20.11'));
console.log(pattern.test('.0'));
console.log(pattern.test('1.12'));
console.log(pattern.test('1.13'));
console.log(pattern.test('12.111'));
console.log(pattern.test('100.00'));
Try this.
/^\d\d?(\.(0\d|1[01]))?$/
Description:
^\d\d? - from the start of the string, match 1 or 2 numbers
After that/those numbers, optionally match . plus 2 numbers
The two numbers must be 0 and any number, else 1 and 0 or 1
Anchor to the end of the string
You are missing the two different patterns of floating part, which must be handled with a |.
A character-optimal solution is ^\d{1,2}(\.[0]\d|\.1[01])?$.
i want a regular expression for length limit 10 digit with 2 decimal place numbers with only numbers allowed.10 digit before decimal
allowed
1
1111111111
111
1111111111.22
.2
1.2
1.22
Not allowed
4.
.
-1
abc
Null
Emptystring
""
1.222
-1.22
111111111111
tried but not working
^[0-9]*(\.[0-9]{0,2})?$
You're almost there - all you have to do is include a check that the string is not empty (which can be accomplished with a positive lookahead for .{1,10} right after the ^), and check that its first digit string has at most 10 characters (just use a {0,10} quantifier for the digits). Also note that [0-9] simplifies to \d.
In order to also exclude trailing dots, repeat the digit after the dot with {1,2} instead of {0,2}:
^(?!$)\d{0,10}(?:\.\d{1,2})?$
https://regex101.com/r/Ah8dNu/5
I have also prepared below RegEx.
Seems this will also work.
^[0-9]{1,10}((\.)[0-9]{0,2}){0,1}$
With reference to my previous question currency regex
I want to add an condition, i want to allow decimal only if it starts with 0
example
0.25 should be allowed
1.25 not allowed
current regex is as following
/^(?:\d{1,3}(?:,\d{3})+|\d+)(?:\.\d+)?$/
which matches comma trailing etc.
This will match all the currency matches from before without decimals or decimals with 0.x*
/^((?:\d{1,3}(?:,\d{3})+|\d+)|(?:0\.\d+))$/
If you only want to match 0.xx instead of an arbitrary number of decimal places use
/^((?:\d{1,3}(?:,\d{3})+|\d+)|(?:0\.\d{2}))$/
This one changes \d+, one or more digits, to \d{2}, exactly 2 digits.
It seems I'm stuck again with a simple regex.
What I'd like:
A number between 1 and 999
Optional: a comma , sign
If the comma sign is entered, minimum 1 decimal and maximum 3
decimals should be presebt.
Allowed:
100
999,0
999,999
999,99
Disallowed:
-1
0
999,
999,9999
This is what I have so far:
^[0-9]{1,3}(?:\,[0-9]{1,3})?$
Any tips?
You can use this regex:
/^[1-9]\d{0,2}(?:\,\d{1,3})?$/
RegEx Demo
Main difference from OP's regex is use of [1-9] which matches digits 1 to 9 before rest of the regex.
This regex should work :
^[1-9]\d{0,2}(?:,\d{1,3})?$
Here is the explanation :
^[1-9]: It should begin with a number between 1 and 9
\d{0,2}: Followed by minimum 0, maximum 2 digits (0-9)
(?:,: Followed by a comma
\d{1,3})?: IF there is a comma it should be followed by one to three digits
$: End of line
EXAMPLE
Thanks #dev-null for this link: Explanation
I'm trying to build a regex expression for numbers, only separated with dot, comma is forbidden.
I've tried this code
^(\d+|\d+\.\d{1,4})[1-5]$
but it doesn't help for this rules:
minimum: one number 1 to 9
maxmimum: five numbers 0.0001 or 12345
range: 0.0001 to 99999
allowed examples:
12345
1234.1
123.12
12.345
1.2345 1
0.1
0.01
0.001
0.0001
thanks
You could try the below regex. Negative lookahead at the start asserts that there isn't 99999.<any-num> or only 0.one or more zeros present.
^(?!99999\.\d|0+(?:\.0+)?$)\d{1,5}(?:\.\d{1,4})?$
DEMO