How to stub methods in a Mongoose model? - javascript

How to stub the instance method bark of the following fictitious schema?
var dogSchema = mongoose.Schema({
// ...
});
dogSchema.methods = {
bark() { console.log('Woof!') },
};
For example, if I want to test the following function barkOne():
function barkOne() {
Dog.findOne().exec().then(dog => dog.bark());
}
How would I be able to stub it, in order to test it like this?
describe('barkOne', () =>
it('should make all dogs bark', () => {
barkOne().then(() => {
assert(barkStub.calledOnce);
});
})
});
Thanks!

As of mongoose 4.4.5, I was able to stub methods with Model.prototype. e.g.
const stub = sandbox.stub(Dog.prototype, 'bark');
Dog.findOne().exec().then(dog => {
// dog[0].bark === stub
})

Related

How can I mock a class using jest?

How can I mock something to test something like the following codes. I tried to follow this official doc, but still not working for me https://jestjs.io/docs/es6-class-mocks#calling-jestmock-with-the-module-factory-parameter
// somefile.ts
export const myPublish = async (event: any, context: any): Promise<any> => {
const myExportHelper = await ExportHelper.getInstance({
...commonProps,
});
// just some other stuff
// just some other stuff
await myExportHelper.transfer(arg1, arg2);
};
export class ExportHelper {
constructor(
private readonly bucket: string,
private readonly read: AWS.S3,
private readonly write: AWS.S3
) {}
static async getInstance(props: {
param1: string;
}) {
...
...
return new ExportHelper(arg1, arg2, arg3);
};
async transfer(param1, param2) {
...
...
console.log('bla bla bla');
}
}
// testfile.test.ts
import { myPublish, ExportHelper } from '../somefile';
beforeEach(() => {
});
afterEach(() => {
jest.clearAllMocks();
jest.resetAllMocks();
});
describe('myTest', () => {
it('should run successfully', async () => {
// Arrange
const eventMock = {
Records: [
{
...
}
]
}
jest.mock('../somefile');
const mockActualExportHelper = jest.requireActual('../somefile').ExportHelper;
const mockGetInstanceImpl = () => {};
// this says cannot read property instances of undefined
const mockExportHelper = mockActualExportHelper.mock.instances[0];
mockExportHelper.getInstance.mockImplementation(mockGetInstanceImpl);
mockExportHelper.transfer.mockImplementation(mockGetInstanceImpl);
// Act
await myPublish(eventMock, jasmine.any({}));
// Assert
expect(ExportHelper.getInstance).toBeCalled();
expect(ExportHelper.transfer).toBeCalled(); // also not sure if this is valid to use ExportHelper
});
});
I think what you're looking for is not a mock. If you want to spy what functions are called, you will need to use the spyOn. In jest you can do the following:
jest.spyOn(MyClass, 'myMethod');
And you can also mock the implementation to subtitute the default behavior of a method, a generalist example can be like this:
jest.spyOn(MyClass, 'myMethod').mockImplementation(jest.fn());
With that said, I would rewrite the test to spy the methods from ExportHelper and avoid external calls:
import {ExportHelper, myPublish} from '../app';
beforeEach(() => {
});
afterEach(() => {
jest.clearAllMocks();
jest.resetAllMocks();
});
describe('myTest', () => {
it('should run successfully', async () => {
// Arrange
const eventMock = {
Records: [
{
// ...
}
]
}
jest.spyOn(ExportHelper, 'getInstance').mockImplementation(jest.fn());
jest.spyOn(ExportHelper, 'transfer').mockImplementation(jest.fn());
// Act
await myPublish('arg1', 'arg2');
// Assert
expect(ExportHelper.getInstance).toBeCalled();
expect(ExportHelper.transfer).toBeCalled();
});
});
I just replaced this piece of code:
jest.mock('../somefile');
const mockActualExportHelper = jest.requireActual('../somefile').ExportHelper;
const mockGetInstanceImpl = () => {};
// this says cannot read property instances of undefined
const mockExportHelper = mockActualExportHelper.mock.instances[0];
mockExportHelper.getInstance.mockImplementation(mockGetInstanceImpl);
mockExportHelper.transfer.mockImplementation(mockGetInstanceImpl);
with
jest.spyOn(ExportHelper, 'getInstance').mockImplementation(jest.fn());
jest.spyOn(ExportHelper, 'transfer').mockImplementation(jest.fn());
Because jest will track down and watch any of these method's calls and then we can use jest's matchers to test if both of them were called. And the mockImplementation will isolate any further calls to be maded.
One thing that I noticed while reproducing your example, is that the transfer method is not being treated as a method when you get the instance from getInstance and therefore, the tests will not pass. But I think this question is not in the scope of the topic. Dunno if just happens to me.

How to mock a node module with jest within a class?

I need to mock the DNS node module in a class but I am unsure how to do so as it is enclosed in the class. Here is a sample of what the class looks like...
import { lookup } from 'dns';
class Foo {
// ...
protected async _bar(IP: string) {
// I want to mock "lookup"
await new Promise<undefined>((resolve, reject) => {
lookup(IP, (err, addr) => {
if (err) reject(new Error('DNS Lookup failed for IP_ADDR ' + IP));
resolve();
});
});
// If dns found then return true
return true;
}
// ...
}
I would like to create a test file foo.spec.ts that contains a test similar to the following:
import { Foo } from './Foo';
describe('Foo', () => {
it('Bar Method returns true on success', () => {
const test = new Foo();
expect(test._bar('192.168.1.1')).resolves.toBeTruthy();
});
});
I am unsure how to mock the lookup call within the class Foo given that the class definition is in a separate file from the test itself.
Any help would be appreciated!
The way you are using lookup won't work since it doesn't return a Promise...
...but you can convert it to a version that does return a Promise by using util.promisify.
The code would end up looking something like this:
import { lookup as originalLookup } from 'dns'; // <= import original lookup...
import { promisify } from 'util';
const lookup = promisify(originalLookup); // <= ...and promisify it
export class Foo {
async _bar(IP: string) {
await lookup(IP).catch(err => { throw new Error('Failed'); });
return true;
}
}
You could then mock lookup in your test using jest.mock like this:
import { Foo } from './Foo';
jest.mock('dns', () => ({
lookup: (hostname, callback) => {
hostname === 'example.com' ? callback() : callback('error');
}
}))
describe('Foo', () => {
it('Bar Method returns true on success', async () => {
const test = new Foo();
await expect(test._bar('example.com')).resolves.toBeTruthy(); // Success!
await expect(test._bar('something else')).rejects.toThrowError('Failed'); // Success!
});
});
Note that the mock needs to be created using jest.mock (and not something like jest.spyOn) since calls to jest.mock get hoisted and run first. The mock needs to be in place before Foo.js is imported since the first thing it does is create and store the promisified lookup.
From jest's tutorial,
jest.mock('./sound-player', () => {
return function() {
return {playSoundFile: () => {}};
};
});
so you could do sth like jest.mock('dns', () => ({ ... }));

How to change mock implementation on a per single test basis?

I'd like to change the implementation of a mocked dependency on a per single test basis by extending the default mock's behaviour and reverting it back to the original implementation when the next test executes.
More briefly, this is what I'm trying to achieve:
Mock dependency
Change/extend mock implementation in a single test
Revert back to original mock when next test executes
I'm currently using Jest v21. Here is what a typical test would look like:
// __mocks__/myModule.js
const myMockedModule = jest.genMockFromModule('../myModule');
myMockedModule.a = jest.fn(() => true);
myMockedModule.b = jest.fn(() => true);
export default myMockedModule;
// __tests__/myTest.js
import myMockedModule from '../myModule';
// Mock myModule
jest.mock('../myModule');
beforeEach(() => {
jest.clearAllMocks();
});
describe('MyTest', () => {
it('should test with default mock', () => {
myMockedModule.a(); // === true
myMockedModule.b(); // === true
});
it('should override myMockedModule.b mock result (and leave the other methods untouched)', () => {
// Extend change mock
myMockedModule.a(); // === true
myMockedModule.b(); // === 'overridden'
// Restore mock to original implementation with no side effects
});
it('should revert back to default myMockedModule mock', () => {
myMockedModule.a(); // === true
myMockedModule.b(); // === true
});
});
Here is what I've tried so far:
mockFn.mockImplementationOnce(fn)
it('should override myModule.b mock result (and leave the other methods untouched)', () => {
myMockedModule.b.mockImplementationOnce(() => 'overridden');
myModule.a(); // === true
myModule.b(); // === 'overridden'
});
Pros
Reverts back to original implementation after first call
Cons
It breaks if the test calls b multiple times
It doesn't revert to original implementation until b is not called (leaking out in the next test)
jest.doMock(moduleName, factory, options)
it('should override myModule.b mock result (and leave the other methods untouched)', () => {
jest.doMock('../myModule', () => {
return {
a: jest.fn(() => true,
b: jest.fn(() => 'overridden',
}
});
myModule.a(); // === true
myModule.b(); // === 'overridden'
});
Pros
Explicitly re-mocks on every test
Cons
Cannot define default mock implementation for all tests
Cannot extend default implementation forcing to re-declare each mocked method
Manual mocking with setter methods (as explained here)
// __mocks__/myModule.js
const myMockedModule = jest.genMockFromModule('../myModule');
let a = true;
let b = true;
myMockedModule.a = jest.fn(() => a);
myMockedModule.b = jest.fn(() => b);
myMockedModule.__setA = (value) => { a = value };
myMockedModule.__setB = (value) => { b = value };
myMockedModule.__reset = () => {
a = true;
b = true;
};
export default myMockedModule;
// __tests__/myTest.js
it('should override myModule.b mock result (and leave the other methods untouched)', () => {
myModule.__setB('overridden');
myModule.a(); // === true
myModule.b(); // === 'overridden'
myModule.__reset();
});
Pros
Full control over mocked results
Cons
Lot of boilerplate code
Hard to maintain on long term
jest.spyOn(object, methodName)
beforeEach(() => {
jest.clearAllMocks();
jest.restoreAllMocks();
});
// Mock myModule
jest.mock('../myModule');
it('should override myModule.b mock result (and leave the other methods untouched)', () => {
const spy = jest.spyOn(myMockedModule, 'b').mockImplementation(() => 'overridden');
myMockedModule.a(); // === true
myMockedModule.b(); // === 'overridden'
// How to get back to original mocked value?
});
Cons
I can't revert mockImplementation back to the original mocked return value, therefore affecting the next tests
Use mockFn.mockImplementation(fn).
import { funcToMock } from './somewhere';
jest.mock('./somewhere');
beforeEach(() => {
funcToMock.mockImplementation(() => { /* default implementation */ });
// (funcToMock as jest.Mock)... in TS
});
test('case that needs a different implementation of funcToMock', () => {
funcToMock.mockImplementation(() => { /* implementation specific to this test */ });
// (funcToMock as jest.Mock)... in TS
// ...
});
A nice pattern for writing tests is to create a setup factory function that returns the data you need for testing the current module.
Below is some sample code following your second example although allows the provision of default and override values in a reusable way.
const spyReturns = returnValue => jest.fn(() => returnValue);
describe("scenario", () => {
beforeEach(() => {
jest.resetModules();
});
const setup = (mockOverrides) => {
const mockedFunctions = {
a: spyReturns(true),
b: spyReturns(true),
...mockOverrides
}
jest.doMock('../myModule', () => mockedFunctions)
return {
mockedModule: require('../myModule')
}
}
it("should return true for module a", () => {
const { mockedModule } = setup();
expect(mockedModule.a()).toEqual(true)
});
it("should return override for module a", () => {
const EXPECTED_VALUE = "override"
const { mockedModule } = setup({ a: spyReturns(EXPECTED_VALUE)});
expect(mockedModule.a()).toEqual(EXPECTED_VALUE)
});
});
It's important to say that you must reset modules that have been cached using jest.resetModules(). This can be done in beforeEach or a similar teardown function.
See jest object documentation for more info: https://jestjs.io/docs/jest-object.
Little late to the party, but if someone else is having issues with this.
We use TypeScript, ES6 and babel for react-native development.
We usually mock external NPM modules in the root __mocks__ directory.
I wanted to override a specific function of a module in the Auth class of aws-amplify for a specific test.
import { Auth } from 'aws-amplify';
import GetJwtToken from './GetJwtToken';
...
it('When idToken should return "123"', async () => {
const spy = jest.spyOn(Auth, 'currentSession').mockImplementation(() => ({
getIdToken: () => ({
getJwtToken: () => '123',
}),
}));
const result = await GetJwtToken();
expect(result).toBe('123');
spy.mockRestore();
});
Gist:
https://gist.github.com/thomashagstrom/e5bffe6c3e3acec592201b6892226af2
Tutorial:
https://medium.com/p/b4ac52a005d#19c5
When mocking a single method (when it's required to leave the rest of a class/module implementation intact) I discovered the following approach to be helpful to reset any implementation tweaks from individual tests.
I found this approach to be the concisest one, with no need to jest.mock something at the beginning of the file etc. You need just the code you see below to mock MyClass.methodName. Another advantage is that by default spyOn keeps the original method implementation but also saves all the stats (# of calls, arguments, results etc.) to test against, and keeping the default implementation is a must in some cases. So you have the flexibility to keep the default implementation or to change it with a simple addition of .mockImplementation as mentioned in the code below.
The code is in Typescript with comments highlighting the difference for JS (the difference is in one line, to be precise). Tested with Jest 26.6.
describe('test set', () => {
let mockedFn: jest.SpyInstance<void>; // void is the return value of the mocked function, change as necessary
// For plain JS use just: let mockedFn;
beforeEach(() => {
mockedFn = jest.spyOn(MyClass.prototype, 'methodName');
// Use the following instead if you need not to just spy but also to replace the default method implementation:
// mockedFn = jest.spyOn(MyClass.prototype, 'methodName').mockImplementation(() => {/*custom implementation*/});
});
afterEach(() => {
// Reset to the original method implementation (non-mocked) and clear all the mock data
mockedFn.mockRestore();
});
it('does first thing', () => {
/* Test with the default mock implementation */
});
it('does second thing', () => {
mockedFn.mockImplementation(() => {/*custom implementation just for this test*/});
/* Test utilising this custom mock implementation. It is reset after the test. */
});
it('does third thing', () => {
/* Another test with the default mock implementation */
});
});
I did not manage to define the mock inside the test itself so I discover that I could mock several results for the same service mock like this :
jest.mock("#/services/ApiService", () => {
return {
apiService: {
get: jest.fn()
.mockResolvedValueOnce({response: {value:"Value", label:"Test"}})
.mockResolvedValueOnce(null),
}
};
});
I hope it'll help someone :)
It's a very cool way I've discovered on this blog https://mikeborozdin.com/post/changing-jest-mocks-between-tests/
import { sayHello } from './say-hello';
import * as config from './config';
jest.mock('./config', () => ({
__esModule: true,
CAPITALIZE: null
}));
describe('say-hello', () => {
test('Capitalizes name if config requires that', () => {
config.CAPITALIZE = true;
expect(sayHello('john')).toBe('Hi, John');
});
test('does not capitalize name if config does not require that', () => {
config.CAPITALIZE = false;
expect(sayHello('john')).toBe('Hi, john');
});
});

A sinonjs stub in the "then"

I have a class A , and I want to test the eventHandler method.
class A () {
eventHandler (controller) {
controller.exec().then((() => {
this._afterHandler(); // I can't stub it.
}))
// this._afterHandler(); // I can stub it !!!
}
_afterHandler() {
xxxxx...;
}
}
This is my test code . I find that I can not stub the _afterHandler method. when the method in the then. but when I move the method to the "then" outside. I can stub it.
it('xxxx', () => {
const a = new A();
const stub = sinon.stub(a,'_afterHandler');
a.eventHandler({ exec: () => {return Promise.resolve(1)} })
sinon.assert.calledOnce(stub);
});
How can I stub the _afterHandler method ?? Thanks ~~
_afterHandler is getting stubbed by Sinon.
The problem here is that sinon.assert.calledOnce(stub) is getting called before the stubbed _afterHandler - thanks to the use of promises.
In terms of making this testable, one option is like:
class A {
eventHandler (controller) {
return controller.exec().then(() => {
this._afterHandler();
})
}
_afterHandler() {
xxxxx...;
}
}
and the test:
it('xxxx', async () => {
const a = new A();
const stub = sinon.stub(a,'_afterHandler');
await a.eventHandler({ exec: () => {return Promise.resolve(1)} });
sinon.assert.calledOnce(stub);
});

Mock construction of es6 collaborator

I have a class that leverages helper classes, and I'd like to verify it constructs those objects correctly. So, I'm trying to stub the "constructor" method in my classes, but I'm clearly not doing it right:
"use strict";
class Collaborator {
constructor(settings) {
console.log("Don't want this to be called!")
this.settings = settings;
}
}
class ThingToTest {
constructor(settings) {
this.helper = new Collaborator(settings);
}
}
const assert = require("assert");
const sinon = require("sinon");
describe("ThingToTest", () => {
let settings = "all the things"
context("spying on constructor", () => {
let spy = sinon.spy(Collaborator, "constructor")
after(() => spy.restore())
describe("constructor", () => {
it("creates a Collaborator with provided settings", () => {
new ThingToTest(settings);
sinon.assert.calledWith(spy, settings)
})
})
})
context("spying on prototype constructor", () => {
let spy = sinon.spy(Collaborator.prototype, "constructor")
after(() => spy.restore())
describe("constructor", () => {
it("creates a Collaborator with provided settings", () => {
new ThingToTest(settings);
sinon.assert.calledWith(spy, settings)
})
})
})
context("stub constructor", () => {
before(() => {
sinon.stub(Collaborator, "constructor", (settings) => {
console.log("This should be called so we can inspect", settings);
})
})
after(() => { Collaborator.constructor.restore() })
describe("constructor", () => {
it("creates a Collaborator with provided settings", () => {
new ThingToTest(settings);
})
})
})
context("stub prototype constructor", () => {
before(() => {
sinon.stub(Collaborator.prototype, "constructor", (settings) => {
console.log("This should be called so we can inspect", settings);
})
})
after(() => { Collaborator.prototype.constructor.restore() })
describe("constructor", () => {
it("creates a Collaborator with provided settings", () => {
new ThingToTest(settings);
})
})
})
})
Running this produces these (undesirable) results:
ThingToTest
spying on constructor
constructor
Don't want this to be called!
1) creates a Collaborator with provided settings
spying on prototype constructor
constructor
Don't want this to be called!
2) creates a Collaborator with provided settings
stub constructor
constructor
Don't want this to be called!
✓ creates a Collaborator with provided settings
stub prototype constructor
constructor
Don't want this to be called!
✓ creates a Collaborator with provided settings
It seems like stubbing is sort of working since putting the stub tests before the spy tests errors with the dreaded "TypeError: Attempted to wrap constructor which is already wrapped". So, clearly figuring out how to mock the Collaborators constructor is only half of what I'm doing wrong . . . I'm not restoring the constructor correctly either. Any suggestions?
This is not the solution I want, however for the time being I may end up using this (but please, if you have a suggestion, save me from myself):
context("checking Collaborator in a more integration style test", () => {
describe("constructor", () => {
it("creates a Collaborator with provided settings", () => {
let thing = new ThingToTest(settings);
assert.equal(thing.helper.settings, settings)
})
})
})
This passes and verifies the Collaborator has the correct settings set. But now if I want to refactor the Collaborator constructor, I'm going to break the ThingToTest. Again, I'm still holding out hope someone can suggest a way to actually unit test this class!
Not sure this is my final answer, but I ended up using proxyquire, as it's the best solution I've found so far. To show how it works, I've separated the classes under test into their own directory, and the test file in a child "test" directory. This illustrates how the paths in proxyquire work (which took me some time to figure out). So, here's what I ended up with:
/Collaborator.js
"use strict"
class Collaborator {
constructor(settings) {
console.log("Don't want this to be called!")
this.settings = settings;
}
}
module.exports = Collaborator
/ThingToTest.js
"use strict"
const Collaborator = require("./Collaborator")
class ThingToTest {
constructor(settings) {
this.helper = new Collaborator(settings)
}
}
module.exports = ThingToTest
/test/ExampleTest.js
"use strict";
const proxyquire = require('proxyquire')
const mockCollaborator = sinon.stub();
const ThingToTest = proxyquire("../ThingToTest", { "./Collaborator" : mockCollaborator })
const assert = require("assert");
const sinon = require("sinon");
describe("ThingToTest", () => {
let settings = "all the things"
context("checking Collaborator in a more integration style test", () => {
describe("constructor", () => {
it("creates a Collaborator with provided settings", () => {
let thing = new ThingToTest(settings);
assert.equal(mockCollab.firstCall.calledWith(settings))
})
})
})
})
Note how the path inside proxyquire("../ThingToTest", { "./Collaborator" : mockCollaborator }) matches what "ThingToTest" uses, not the path from the test class. I hope this help others, but I'm still open to other ideas and suggestions!

Categories

Resources