Develop Reference

Buttons to select checkboxes by name

I have the following checkboxes in an HTML form.
<ul id="selection">
<span><label>First<br><input type="checkbox" name="First"></label></span>
<span><label>Second<br><input type="checkbox" name="Second"></label></span>
<span><label>Third<br><input type="checkbox" name="Third"></label></span>
<span><label>Fourth<br><input type="checkbox" name="Fourth"></label></span>
<span><label>Fifth<br><input type="checkbox" name="Fifth"></label></span>
</ul>
I'm trying to create two buttons. One that would select the first two and one that would select all of them.
I managed to select all of them with one button using this:
<input type="button" class="check btn" onClick="select(this)" value="Select All"/>
<script>
$('.check:button').click(function(){
var checked = !$(this).data('checked');
$('input:checkbox').prop('checked', checked);
$(this).val(checked ? 'uncheck all' : 'Select' )
$(this).data('checked', checked);
});
</script>
But I can't seem to get the two buttons working.
My JavaScript knowledge is pretty limited and been searching for days, unsuccessfully for a solution that works.
Can please someone help? a detailed explanation would be awesome.

Try this:
$("#selectall").click(function() {
$("input[type='checkbox']").prop('checked', true);
});
$("#selecttwo").click(function() {
$("input[name='First'], input[name='Second']").prop('checked', true);
});
$("#resetall").click(function() {
$("input[type='checkbox']").prop('checked', false);
});
DEMO

Are you looking for this, https://jsfiddle.net/wx38rz5L/1261/ ( sorry about css :P ) or https://jsfiddle.net/wx38rz5L/1262/
Reference: https://api.jquery.com/attribute-equals-selector/
$('input[name=First]').prop('checked',true);
$('input[name=Second]').prop('checked',true);
//$('input[name=First],input[name=Second]').prop('checked',true); in one line

Bootstrap set radio button checked with jquery

I have radio buttons in my html code.
I want to change their state based on my input values via jquery
Here is My Html
<div class="col-md-2 col-xs-offset-1">
<div class="radio">
<label>
<input type="radio" name="rdo_pkdrop" value="0" id="rdo_pick">
Pick-up Time
</label>
</div>
<div class="radio">
<label>
<input type="radio" name="rdo_pkdrop" id="rdo_drop" value="1">
Drop Time
</label>
</div>
</div>
An jQuery is
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{
$('#rdo_pick').prop('checked',true);
}
But This has no effect
I also tried with
$('#rdo_pick').prop('checked','checked'); and
$('#rdo_pick').attr('checked','true');
$('#rdo_pick').addClass('checked');

This is only way I could find. Although somewhat inelegant, it does work.
if(qs_trip_type == 0){
$('#rdo_pick').click();
}else{
$('#rdo_drop').click();
}

The issue with bootstrap is that you set a checked radio button by adding the active class to the corresponding label of the input. It looks like this:
<label class="btn btn-default active"> <!-- Note the class 'active' here -->
<input type="radio" name="myRadio" value="value1" checked="checked"/>Value 1
</label>
<!-- ... -->
To check a radio button using jQuery you could first select the input field with a jQuery Selector and then add the class to the parent:
var $myRadioInput = $(...);
$myRadioInput.parent('.btn').addClass('active');
Don't forget to remove the class active on the formerly selected label with jQuery removeClass('active') to first unselect them.
I also like it to set the checked property on the input itself to have the proper state on it:
$myRadioInput.prop('checked', true);
Note that the checked="checked" attribute is only the inital state for the input to be the checked input when loading the page. It does NOT change with the jQuery .prop() method, as it is an attribute and is different to the actual checked property. This is well described in jQuery Docs.

I have tried，this code is ok for bootstrap radio.
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true).click();
}else{ //not ekse
$('#rdo_pick').prop('checked',true).click();
}

there is a typo in your code replace ekse with else
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{
$('#rdo_pick').prop('checked',true);
}

if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{ //not ekse
$('#rdo_pick').prop('checked',true);
}
Here's the jsfidlle http://jsfiddle.net/urLh9qnh/

Try this
if(qs_trip_type == 0){
$('#rdo_pick').prop('checked',true);
}else{
$('#rdo_drop').prop('checked',true);
}

Try This:
after setting the value of the radio, please add this code
$("input[type='checkbox'], input[type='radio']").iCheck({
checkboxClass: 'icheckbox_minimal',
radioClass: 'iradio_minimal'
});

Here is a one line solution:
$('#rdo_pick').iCheck('check');

Get name from one element and call to another element

Disclaimer:This is a unique situation and very hackish.
I have one set of radios that are visible to users and another set that is hidden. I need to pull the name from the hidden set and assign to the visible set.
Hidden radios:
<div class="productAttributeValue">
<div class="productOptionViewRadio">
<ul>
<li>
<label>
<input type="radio" class="validation" name="attribute[139]"
value="86" checked="checked" />
<span class="name">Standard Shipping</span>
</label>
</li>
etc etc...more li's
</ul>
</div>
</div>
A visible radio:
<label>
<input type="radio" class="validation" name="PUT OTHER NAME HERE" value="86" checked="checked" />
<span class="name">Standard Shipping</span>
<p class="rl-m"><small>Earliest Date of Delivery:</small>
<small><span id="delivery-date"></span></small></p>
</label>
So, in this case, I would like the name "attribute[139]" to somehow be gotten from the hidden radio and called to the name of the visible radio. I'm thinking of something like this:
<script>
$(function() {
var name = $(".productOptionViewRadio span.name:contains('(Standard)')").attr('name');
});
</script>
I'm not too sure about the script being the right way to go about this and also not sure how I would actually get the value from the one element to populate to the other element's name field.
Thank you very much.
Update: Fiddle http://jsfiddle.net/susan999/XBcaF/

Try
$('label input[type=radio]').attr('name',
$('.productOptionViewRadio input[type=radio]').attr('name'));
http://jsfiddle.net/XBcaF/5/

Try this
$('input:radio.validation:visible').attr('name',function(){
return $('input:radio.validation:hidden').attr('name')
})
Could improve the selectors if know more about parent classes of visible radios, or what elements are actualy being set as hidden

You can try something like this:
var checkboxCount = 0;
$("#visibleCheckboxes").find("input[type=checkbox]").each(function(){
$($("#hiddenCheckboxes").find("input[type=checkbox]").get(checkboxCount)).attr('name', $(this).attr('name'));
checkboxCount++;
});
I've prepared a Fiddle for you: http://jsfiddle.net/MJNeY/1/

Enabling and disabling all the child elements

I have this issue with enabling and disabling section of fields if other section of fields have specific value.
Consider jsfiddle for html code.
Conditions are
If all the fields of partA are selected as No, then enable partB.
If all the fields of partB are selected as No, then enable partC.
Try 1
First I tried disable elements of PartB and PartC which did not work.
$(function () {
$('.group').attr('name','partB').find('input').attr('disable', true);
$('.group').attr('name','partC').find('input').attr('disable', true);
});
I am not sure how would make sure if all the child elements are selected as No in a group div.

jsBin demo
Having this HTML:
<div class="group" id="partA">
<span> PART A</span><br/>
Option 1
<input type="radio" name="optionsRadios1" value="option1"/>Yes
<input type="radio" name="optionsRadios1" value="option2"/>No
<br />
Option 2
<input type="radio" name="optionsRadios2" value="option1"/>Yes
<input type="radio" name="optionsRadios2" value="option2"/>No
</div>
jQ:
$(function () {
$('#partB, #partC').find('input').prop('disabled', true);
function testChecked(){
var $par = $(this).closest('.group');
var $rad2 = $par.find('[value="option2"]');
var allNo = $rad2.filter(':checked').length == $rad2.length;
$par.next('.group').find(':radio').prop('disabled', !allNo);
if(!allNo){
$par.nextAll('.group').find(':radio').prop({'disabled':true, 'checked':false});
}
}
$('.group :radio').change(testChecked);
});
The above will work also for more than 2 radio groups per .group
Your errors:
"disable", "true" should be "disabled", "true"
<label> can control only one inner element (so I removed it.)
<div> afaik is not supposed to have a name attribute (so I assigned an ID)

Check to see if none of the checkboxes was checked in jquery

I have two checkboxes and one of the checkboxes must be checked. I can see that it's right, no syntax errors. What should be made to my code to check if none of the checkboxes were checked?
HTML :
<input type="checkbox" value="aa" class="first" name="a"> Yes<br/>
<input type="checkbox" value="bb" class="second" name="b"> No <br/>
<button type="submit">Go!</button>
<p class="error"></p>
JavaScript:
$('button').on('click',function(){
if( $(".first:not(:checked)") && $(".second:not(:checked)") ){
$('.error').text('You must select atleast one!');
}else
$('.error').hide();
});
Example : http://jsfiddle.net/ptbTq/

Check this fiddle: http://jsfiddle.net/692Dx/
Checking code:
if($('input[type="checkbox"]:checked').length == 0) {
alert('none checked');
}

You are using selectors which do not return boolean values which is what you need when writing an if condition. Here's what you could do:
$('button').on('click',function() {
if(!$(".first").is(":checked") && !$(".second").is(":checked")) {
$('.error').text('You must select atleast one!').show();
} else {
$('.error').hide();
}
});
or if you prefer and think it could be more readable you could invert the condiciton:
$('button').on('click',function() {
if($(".first").is(":checked") || $(".second").is(":checked")) {
$('.error').hide();
} else {
$('.error').text('You must select atleast one!').show();
}
});
Also notice that you need to .show() the error message in the first case as you are hiding it in the second.
And here's a live demo.

Short:
$("input[type=checkbox]").is(":checked")
returns true if:
one of your checkboxes - from the selector ("input[type=checkbox]") - is checked.
else return false
and in your case:
$(".first, .second").is(":checked")
Do something at least one of your checkboxes is checked

Put the same class on both checkboxes and you can do something like
if ($(':checkbox.the_class:checked').length > 0) {
// at least one checkbox is checked
// ...
}

The best would be to put your checkboxes inside a div with an unique ID so you can verify all the checkboxes in there, so your code will work in all cases. Even when adding new checkboxes to the div later on.
<div id="cb">
<input type="checkbox" value="aa" class="first" name="a" /> Yes<br/>
<input type="checkbox" value="bb" class="second" name="b" /> No <br/>
<button type="submit">Go!</button>
<p class="error"></p>
</div>
Your JQuery:
$('button').click(function() {
var checked_one = $('div#cb input[type="checkbox"]').is(':checked');
if (!checked_one )
$('.error').text('You must select atleast one!');
else
$('.error').hide();
});
Live demo can be seen here: http://jsfiddle.net/ptbTq/15/