Develop Reference

adjust console.log behaviour of custom object

is there any way to influence what console.log gives out custom objects?
I tried to overwrite the customObject.prototype.toString method, that did not work though.
Any ideas?

In node.js, console.log calls util.inspect on each argument without a formatting placeholder. So if you define an inspect(depth, opts) method on your object it will be called to get your custom string representation of the object.
For example:
function Custom(foo) {
this.foo = foo;
}
Custom.prototype.inspect = function(depth, opts) {
return 'foo = ' + this.foo.toUpperCase();
};
var custom = new Custom('bar');
console.log(custom);
Outputs:
foo = BAR
Or using a class:
class Custom {
constructor(foo) {
this.foo = foo;
}
inspect(depth, opts) {
return 'foo = ' + this.foo.toUpperCase();
}
}
var custom = new Custom('bar');
console.log(custom);

The previous answer has been deprecated in newer versions of node. The method one needs to implement now is the symbol [util.inspect.custom].
For example:
const util = require('util');
class Custom {
constructor(foo, bar) {
this.foo = foo;
this.bar = bar;
}
[util.inspect.custom](depth, opts) {
return this.foo + this.bar;
}
}
console.log(new Custom(3, 5)); // Prints '8'

Recent (18) Node.js version has this documentation snippet as an example of how to do this across Node and Browsers:
const customInspectSymbol = Symbol.for('nodejs.util.inspect.custom');
class Password {
constructor(value) {
this.value = value;
}
toString() {
return 'xxxxxxxx';
}
[customInspectSymbol](depth, inspectOptions, inspect) {
return `Password <${this.toString()}>`;
}
}
const password = new Password('r0sebud');
console.log(password);
// Prints Password <xxxxxxxx>

get all proto functions from object in javascript

I have an object and i can get all function in it.but i want add function with proto then get all function.how can i do?
var myObj = {
func1:function(){}
};
var myPrototype = {
func2: function(){
}
};
myObj.__proto__ = myPrototype;
alert(Object.getOwnPropertyNames(myObj));
the result is
func1
but i want all the functions
func1,func2
how can i do this??????

As the method name says, Object.getOwnPropertyNames does only get you the own property names, not the inherited ones.
To get those as well, you'd need to apply it on the prototype as well - in fact, on all prototypes. Btw, avoid using the __proto__ property.
var myPrototype = {
func2: function() {}
};
var myObj = Object.create(myPrototype);
myObj.func1 = function(){};
for (var o=myObj; o!=null; o=Object.getPrototypeOf(o))
alert(Object.getOwnPropertyNames(o));

tnx.
i do it by this function
function getAllMethods(obj) {
var result = [];
for (var id in obj) {
try {
if (typeof(obj[id]) == "function") {
result.push(id + ": " + obj[id].toString());
}
}
catch (err) {
}
}
return result;
}

Rewiring a JavaScript function

Let's say I have a function named fna() that does a simple thing such as:
var fna = function(ar) {
console.log("argument: ", ar);
return "return value is argument too: " + ar;
}
fna() is coded by some other developer and I can't access to it. He didn't bother casting any events and when it is called, I have to be aware of it. Hopefully, his method is accessible by window.fna().
I want some additional code to be executed. Let's say, add this console.log
var fna = function(ar) {
console.log("Hola, I am some additional stuff being rewired");
console.log("argument:", ar);
return "return value is argument too: " + ar;
}
And I want this to be executed even when called from fnb() by some other part of the code.
var fnb = function() {
return fna("Bonjour, I am fnb and I call fna");
}
Here is a way I found, using the utils.rewire() method. utils is just some utility belt, and it could be added to your favorite framework as a plugin. Unfortunately, it only works on Firefox.
var utils = utils || {};
// Let's rewire a function. i.e. My.super.method()
utils.rewire = function(functionFullName, callback) {
var rewired = window[functionFullName];
console.log("%s() is being rewired", functionFullName)
window[functionFullName] = function() {
callback();
return rewired.apply(this, arguments);
}
}
Use it like this.
utils.rewire("fna",function(){
console.log("Hola, I am some additional stuffs being rewired");
});
This seems to work such as shown in this jsbin, but (and here is my question:) How do I rewire obja.fna()?
var obja = {
fna = function(ar) {
console.log("argument:", ar);
return "return value is argument too: " + ar;
}
};
I cannot make it work to rewire the some.object.method() method.
Extra bonus question: Is there a more cleaner way to do this? Out-of-the-box clean concise and magic library?

Refactor rewire into a rewireMethod function which acts on any given object:
var utils = utils || {};
utils.rewireMethod = function (obj, functionName, prefunc) {
var original = obj[functionName];
obj[functionName] = function () {
prefunc();
return original.apply(this, arguments);
};
};
Note that rewire can now be written as:
utils.rewire = function (functionName, prefunc) {
utils.rewireMethod(window, functionName, prefunc);
};
Then you just call it as:
utils.rewireMethod(obja, "fna", function () {
console.log("Hola, I am some additional stuff being rewired");
});
Note that nothing special is required if you have a method like window.ideeli.Search.init(). In that case, the object is window.ideeli.Search, and the method name is init:
utils.rewireMethod(window.ideeli.Search, "init", function () {
console.log("Oh yeah, nested objects.");
});

Add a parameter to rewire that is the object containing the function. If it's a global function, pass in window.
var utils = utils || {};
// let's rewire a function. i.e. My.super.method()
utils.rewire = function(object, functionName, callback) {
var rewired = object[functionName];
console.log("%s() is being rewired", functionName)
object[functionName] = function() {
callback();
return rewired.apply(this, arguments);
}
}
utils.rewire(some.object, "method", function(){} );

You can simply use a closure to create a generic hook function that allows you to specify another function to be called immediately before or after the original function:
function hookFunction(fn, preFn, postFn) {
function hook() {
var retVal;
if (preFn) {
preFn.apply(this, arguments);
}
retVal = fn.apply(this, arguments);
if (postFn) {
postFn.apply(this, arguments);
}
return retVal;
}
return hook;
}
So, for any function that you want to hook, you just call hookFunction and pass it the function you want to hook and then an optional pre and post function or yours. The pre and post function are passed the same arguments that the original function was.
So, if your original function was this:
var fna = function(ar) {
console.log("argument:",ar);
return "return value is argument too:"+ar;
}
And, you want something to happen every time that function is called right before it's called, you would do this:
fna = hookFunction(fna, function() {
console.log("Hola, I am some additional stuff being rewired right before");
});
or if you wanted it to happen right after the original was called, you could do it like this:
fna = hookFunction(fna, null, function() {
console.log("Hola, I am some additional stuff being rewired right after");
});
Working demo: http://jsfiddle.net/jfriend00/DMgn6/
This can be used with methods on objects and arbitrary nesting levels of objects and methods.
var myObj = function(msg) {
this.greeting = msg;
};
myObj.prototype = {
test: function(a) {
log("myObj.test: " + this.greeting);
}
}
var x = new myObj("hello");
x.test = hookFunction(x.test, mypreFunc2, myPostFunc2);
x.test("hello");

Based on Claudiu's answer, which seems to be the most appreciated way, here is a solution using a for loop and proxying the context... But still, I find this ugly.
var utils = utils || {};
// Let's rewire a function. i.e. My.super.method()
utils.rewire = function(method, callback) {
var obj = window;
var original = function() {};
var tree = method.split(".");
var fun = tree.pop();
console.log(tree);
// Parse through the hierarchy
for (var i = 0; i < tree.length; i++) {
obj = obj[tree[i]];
}
if(typeof(obj[fun]) === "function") {
original = obj[fun];
}
var cb = callback.bind(obj);
obj[fun] = function(ar) {
cb();
return original.apply(this, arguments);
}
}

Well, this looks strange. Consider this
function wrap(fn, wrapper) {
return function() {
var a = arguments;
return wrapper(function() { return fn.apply(this, a) })
}
}
Example:
function foo(a, b) {
console.log([a, b])
return a + b
}
bar = wrap(foo, function(original) {
console.log("hi")
var ret = original()
console.log("there")
return ret
})
console.log(bar(11,22))
Result:
hi
[11, 22]
there
33
To wrap object methods, just bind them:
obj = {
x: 111,
foo: function(a, b) {
console.log([a, b, this.x])
}
}
bar = wrap(obj.foo.bind(obj), function(fn) {
console.log("hi")
return fn()
})

Prototypal inheritance

I have this object, dive:
var dive = new Foo.Bar();
And Foo.Bar looks like this:
var Foo = {
Bar: function() {
...
return function() {
// do stuff, no return
};
}
};
I'd like dive to have all the prototypes of another, existing object, however. Let's say window.Cow.prototype is:
{
moo: function() { ... },
eat: function() { ... }
}
What do I need to do to Foo.Bar so that I can do this:
dive.moo();
dive.eat();

var Foo = {
Bar: function() {
//...
return this; // technically unnecessary, implied by 'new' operator
}
};
Foo.Bar.prototype = new Cow(); // the secret sauce
dive = new Foo.Bar();
dive.moo(); // moo's like a Cow

Here is a working example without the Bar constructor jsFiddle

Thank you for the start, jimbojw! You were close, but you gave me enough information to get it:
function Cow() {
return {
talk: function() {
alert("mooo");
}
};
}
var Foo = {
Bar: function() {
function result() {
alert("Foo.Bar says...");
};
result.prototype = new Cow();
return new result;
}
};
new Foo.Bar().talk();

If you want to encapsulate Foo.Bar.prototype = you can do it without changing default constructor behavior:
function Cow() {
this.talk = function() {
alert("mooo")
}
}
var Foo = {
Bar: function() {
var constructor = function() {
this.eat = function() {
alert("gulp")
}
}
constructor.prototype = new Cow()
return constructor
}()
}
var foo = new Foo.Bar()
foo.talk()
foo.eat()

Calling method using JavaScript prototype

Is it possible to call the base method from a prototype method in JavaScript if it's been overridden?
MyClass = function(name){
this.name = name;
this.do = function() {
//do somthing
}
};
MyClass.prototype.do = function() {
if (this.name === 'something') {
//do something new
} else {
//CALL BASE METHOD
}
};

I did not understand what exactly you're trying to do, but normally implementing object-specific behaviour is done along these lines:
function MyClass(name) {
this.name = name;
}
MyClass.prototype.doStuff = function() {
// generic behaviour
}
var myObj = new MyClass('foo');
var myObjSpecial = new MyClass('bar');
myObjSpecial.doStuff = function() {
// do specialised stuff
// how to call the generic implementation:
MyClass.prototype.doStuff.call(this /*, args...*/);
}

Well one way to do it would be saving the base method and then calling it from the overriden method, like so
MyClass.prototype._do_base = MyClass.prototype.do;
MyClass.prototype.do = function(){
if (this.name === 'something'){
//do something new
}else{
return this._do_base();
}
};

I'm afraid your example does not work the way you think. This part:
this.do = function(){ /*do something*/ };
overwrites the definition of
MyClass.prototype.do = function(){ /*do something else*/ };
Since the newly created object already has a "do" property, it does not look up the prototypal chain.
The classical form of inheritance in Javascript is awkard, and hard to grasp. I would suggest using Douglas Crockfords simple inheritance pattern instead. Like this:
function my_class(name) {
return {
name: name,
do: function () { /* do something */ }
};
}
function my_child(name) {
var me = my_class(name);
var base_do = me.do;
me.do = function () {
if (this.name === 'something'){
//do something new
} else {
base_do.call(me);
}
}
return me;
}
var o = my_child("something");
o.do(); // does something new
var u = my_child("something else");
u.do(); // uses base function
In my opinion a much clearer way of handling objects, constructors and inheritance in javascript. You can read more in Crockfords Javascript: The good parts.

I know this post is from 4 years ago, but because of my C# background I was looking for a way to call the base class without having to specify the class name but rather obtain it by a property on the subclass. So my only change to Christoph's answer would be
From this:
MyClass.prototype.doStuff.call(this /*, args...*/);
To this:
this.constructor.prototype.doStuff.call(this /*, args...*/);

if you define a function like this (using OOP)
function Person(){};
Person.prototype.say = function(message){
console.log(message);
}
there is two ways to call a prototype function: 1) make an instance and call the object function:
var person = new Person();
person.say('hello!');
and the other way is... 2) is calling the function directly from the prototype:
Person.prototype.say('hello there!');

This solution uses Object.getPrototypeOf
TestA is super that has getName
TestB is a child that overrides getName but, also has
getBothNames that calls the super version of getName as well as the child version
function TestA() {
this.count = 1;
}
TestA.prototype.constructor = TestA;
TestA.prototype.getName = function ta_gn() {
this.count = 2;
return ' TestA.prototype.getName is called **';
};
function TestB() {
this.idx = 30;
this.count = 10;
}
TestB.prototype = new TestA();
TestB.prototype.constructor = TestB;
TestB.prototype.getName = function tb_gn() {
return ' TestB.prototype.getName is called ** ';
};
TestB.prototype.getBothNames = function tb_gbn() {
return Object.getPrototypeOf(TestB.prototype).getName.call(this) + this.getName() + ' this object is : ' + JSON.stringify(this);
};
var tb = new TestB();
console.log(tb.getBothNames());

function NewClass() {
var self = this;
BaseClass.call(self); // Set base class
var baseModify = self.modify; // Get base function
self.modify = function () {
// Override code here
baseModify();
};
}

An alternative :
// shape
var shape = function(type){
this.type = type;
}
shape.prototype.display = function(){
console.log(this.type);
}
// circle
var circle = new shape('circle');
// override
circle.display = function(a,b){
// call implementation of the super class
this.__proto__.display.apply(this,arguments);
}

If I understand correctly, you want Base functionality to always be performed, while a piece of it should be left to implementations.
You might get helped by the 'template method' design pattern.
Base = function() {}
Base.prototype.do = function() {
// .. prologue code
this.impldo();
// epilogue code
}
// note: no impldo implementation for Base!
derived = new Base();
derived.impldo = function() { /* do derived things here safely */ }

If you know your super class by name, you can do something like this:
function Base() {
}
Base.prototype.foo = function() {
console.log('called foo in Base');
}
function Sub() {
}
Sub.prototype = new Base();
Sub.prototype.foo = function() {
console.log('called foo in Sub');
Base.prototype.foo.call(this);
}
var base = new Base();
base.foo();
var sub = new Sub();
sub.foo();
This will print
called foo in Base
called foo in Sub
called foo in Base
as expected.

Another way with ES5 is to explicitely traverse the prototype chain using Object.getPrototypeOf(this)
const speaker = {
speak: () => console.log('the speaker has spoken')
}
const announcingSpeaker = Object.create(speaker, {
speak: {
value: function() {
console.log('Attention please!')
Object.getPrototypeOf(this).speak()
}
}
})
announcingSpeaker.speak()

No, you would need to give the do function in the constructor and the do function in the prototype different names.

In addition, if you want to override all instances and not just that one special instance, this one might help.
function MyClass() {}
MyClass.prototype.myMethod = function() {
alert( "doing original");
};
MyClass.prototype.myMethod_original = MyClass.prototype.myMethod;
MyClass.prototype.myMethod = function() {
MyClass.prototype.myMethod_original.call( this );
alert( "doing override");
};
myObj = new MyClass();
myObj.myMethod();
result:
doing original
doing override

function MyClass() {}
MyClass.prototype.myMethod = function() {
alert( "doing original");
};
MyClass.prototype.myMethod_original = MyClass.prototype.myMethod;
MyClass.prototype.myMethod = function() {
MyClass.prototype.myMethod_original.call( this );
alert( "doing override");
};
myObj = new MyClass();
myObj.myMethod();