Parse JSON data in jQuery and display in textfield - javascript

I am going to print the response data from test.php in JSON format to print it on particular field
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = $.parseJSON(response);
$(document).ready(function(){
$("#test").click(function(){
$("#bemail").val(result.email);//when i prints only result than it displays [object object]
});
});
}
});

Try it like this . You have to put your ajax inside $(document).ready
$(document).ready(function(){
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = JSON.parse(response);
$("#bemail").val(result.email);
}
});
});

you are calling document.ready() inside the AJAX success handler which doesn't get invoked since AJAX call doesn't invoke the document loading again, DOM has already loaded and it loads only once in the life cycle of a page session.
This much should do
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = JSON.parse(response);
$("#bemail").val(result[0].email); //after you explained the JSON response
}
});

Your code is totally wrong, it should be
function displayEmail() {
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = $.parseJSON(response);
//Just Print the Result in Console using console.log(result)
$("#bemail").val(result.email);
}
});
}
$(document).ready(function() {
$("#test").click(function() {
displayEmail();
});
});

Related

Getting multimple results from Ajax post

Maybe this is a duplicate but I can not understand why mo code does not work. I am trying to get multiple results via Ajax/php.
This is from my php file:
$result11 = 'test1'
$result22 = 'test2';
echo json_encode(array("data1" => $result11, "data2" => $result22));
Ajax call:
$(document.body).on('submit','#sendmessage',function() {
$.ajax({
type: "POST",
url: "/send.php",
data: {par:par,kid:kid,ha:ha,sform:sform,editors:editors},
cache: false,
dataType:'json',
success: function(datax) {
alert(datax.data1);
}
});
return false;
});
Problem:
When I submit a form, the page refreshes instead of sending ajax request.
At the same time this works but I can't get multiple results from Php file:
$(document.body).on('submit','#sendmessagex',function() {
var str = $(this).serialize();
$.ajax({
type: "POST",
url: "/send.php",
data:str,
success: function(data) {
alert(data);
}
});
return false;
});
Add a preventDefault() call to your script
$(document.body).on('submit','#sendmessagex',function(event) {
//----------------------------------------------------^^^^^
event.preventDefault();
var str = $(this).serialize();
$.ajax({
type: "POST",
url: "/send.php",
data:str,
success: function(data) {
alert(data);
}
});
return false;
});
You have to use preventDefault() ofcourse to prevent page refresh. Then you can use the second code without datatype json. But in that case at first you have to parse the json like this way:
success: function(data){
var datax = JSON.parse(data);
//now you have object and can access like this: datax.data1, datax.data2
}
Incase you want to use first code, in php you have to set php header to define it as proper json output.
header('Content-Type: application/json');

Display page only if ajax call succeeds?

I have a subdomain protected by a service similar to cloudflare. It checks if a visitor is human or not. To save bandwidth usage I want only one file to be loaded from this subdomain as indicator if the visitor is a bot or not. If it is not loaded, the service has blocked it as bot, and nothing should be shown.
I already thought of an ajax request before the page loads to check this.
var success = 0;
function myCall() {
var request = $.ajax({
url: "sub.example.com/hello.php",
type: "GET",
dataType: "html"
});
request.done(function() {
// Load page, because the request was successfull
$.ajax({
url: 'content.php', //This is the current file
type: "POST",
dataType:'json', // add json datatype to get json
data: ({load: true}),
success: function(data){
console.log(data);
}
})
});
Is there a better way to do this?
You may try this:
var success = 0;
function myCall() {
var request = $.ajax({
url: "sub.example.com/hello.php",
type: "GET",
dataType: "html",
success: function(){
$.ajax({
url: 'content.php', //This is the current file
type: "POST",
data: dat,
success: function(data){
console.log(data);
},
error: function(data){
console.log('Error!');
}
});
},
error: function(data){
console.log('Error!');
}
});
}

Post array from javascript to php function using Ajax

i want to post an array from java script to php by ajax. But i don't know how do that, especially send it to php function like controller class. Correct me if i'm wrong, this is my java script source, as a function to send an array :
<script>
function send(){
var obj = JSON.stringify(array);
window.location.href = "post.php?q=" + obj;
}
</script>
i was try, but still fail. really need help..
As described in the JQuery API documentation, you can use
var rootPath="http://example.com/"
var jsonData = $.toJSON({ q: array });
var urlWS = rootPath + "post.php";
$.ajax({
url: urlWS,
type: "POST",
dataType: "json",
contentType: "application/json; charset=utf-8",
data: jsonData,
success: function(result) {
// do something here with returned result
}
});
var array= [];
array[0] = 'hi';
array[1] = 'hello';
$.ajax({
url: 'http://something.com/post.php',
data: {array: array},
type: 'POST'
});
try like this,
var data_to_send = $.serialize(array);
$.ajax({
type: "POST",
url: 'post.php',
data: data_to_send,
success: function(msg){
}
});
or
you can pass as json like below,
$.ajax({
type: "POST",
url: 'post.php',
dataType: "json",
data: {result:JSON.stringify(array)},
success: function(msg){
}
});
var arr = <?php echo json_encode($postdata); ?>;
ajax: {
url:"post.php"
type: "POST",
data: {dataarr: arr},
complete: function (jqXHR, textStatus) {
}
You can try this .this will work
example
ajax code:
$.ajax({
url: 'save.php',
data: {data: yourdata},
type: 'POST',
dataType: 'json', // you will get return json data
success:function(result){
// to do result from php file
}
});
PHP Code:
$data['something'] = "value";
echo json_encode($data);

How to get the PHP var after Jquery $.ajax

I use $.ajax to send some data to testajax.phpenter code here where data are processing. Result of this proces is link. How to get access to this? I think about sessions or cookies. Set in session $test and get access in another files.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: console.log('success');
data: { json : jsonObj }
});
In testajax.php I have someting like this
echo "PDF: <a href=images/test.pdf>$dir.pdf</a>";
$test = "PDF: <a href=images/test.pdf>$dir.pdf</a>";
How to get the $test or output the echo after call $.ajax
You can use success' function to get request from PHP.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'html',
data: { json : jsonObj }
success: function(data) {
var request = data;
console.log(data);
$('#link_container').html(data);
}
});
Your console now holds PDF: <a href=images/test.pdf>($dir content).pdf</a>.
Also the variable request holds the same result that you can use anywhere in the script.
Result is appended to #link_container.
Use the success() method for display the result.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: function (data){ // <= define handler for manupulate the response
$('#result').html(data);
}
data: { json : jsonObj }
});
Use below code It may help you.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
data: { json : jsonObj },
onSuccess: successFunc,
onFailure: failureFunc
});
function successFunc(response){
alert(response);
}
function failureFunc(response){
alert("Call is failed" );
alert(response);
}

jquery ajax modify data response

$.ajax({
url: 'http://localhost/apsd4/core/main_quota.html',
success: function(data) {
$('#tabs-2').html(r);
$('#tabs-2 #nini').remove();
}
});
I would like to change data response before echo data
Stages:
remove '#tabs-2 #nini'
html()
I think as what I understand on your problem, you wanted to improve your $.ajax
$.ajax({
type: "POST",
url: "http://localhost/apsd4/core/main_quota.html",
success: function(result) {
$('#tabs-2').html(data).find('#nini').remove();
// do some code here
}
});

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