$.ajax({
url: 'http://localhost/apsd4/core/main_quota.html',
success: function(data) {
$('#tabs-2').html(r);
$('#tabs-2 #nini').remove();
}
});
I would like to change data response before echo data
Stages:
remove '#tabs-2 #nini'
html()
I think as what I understand on your problem, you wanted to improve your $.ajax
$.ajax({
type: "POST",
url: "http://localhost/apsd4/core/main_quota.html",
success: function(result) {
$('#tabs-2').html(data).find('#nini').remove();
// do some code here
}
});
Related
I am going to print the response data from test.php in JSON format to print it on particular field
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = $.parseJSON(response);
$(document).ready(function(){
$("#test").click(function(){
$("#bemail").val(result.email);//when i prints only result than it displays [object object]
});
});
}
});
Try it like this . You have to put your ajax inside $(document).ready
$(document).ready(function(){
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = JSON.parse(response);
$("#bemail").val(result.email);
}
});
});
you are calling document.ready() inside the AJAX success handler which doesn't get invoked since AJAX call doesn't invoke the document loading again, DOM has already loaded and it loads only once in the life cycle of a page session.
This much should do
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = JSON.parse(response);
$("#bemail").val(result[0].email); //after you explained the JSON response
}
});
Your code is totally wrong, it should be
function displayEmail() {
$.ajax({
type: 'POST',
url: 'test.php',
data: data,
success: function(response) {
var result = $.parseJSON(response);
//Just Print the Result in Console using console.log(result)
$("#bemail").val(result.email);
}
});
}
$(document).ready(function() {
$("#test").click(function() {
displayEmail();
});
});
I am trying to make two jQuery ajax calls, the second should be made from the success callback of the first. I have tried a couple variations of code e.g just messing with the brackets.
Here is what I tried.
$.ajax({
url: 'inc/grab_talk.php?name='+encoded_name+'&loc='+encoded_address+'&lat='+encoded_lat,
type: 'post',
success: function () {
$.ajax({
url: 'inc/talk_results.php',
type: 'post',
success: function (dat) {
alert(dat);
}
});
}
});
I am receiving '500 (internal server error) in console
Try this, you can use either POST or GET, but in your case GET seems to be more appropriate.
$.ajax({
type: "GET",
url: "some.php",
data: { name: "somename", location: "somelocation" },
success: function(){
$.ajax({
type: "GET",
url: "someother.php",
success: function(){
alert('test');
}
});
}
});
Check this example
$.ajax({
type: "post",
url: "ajax/example.php",
data: 'page='+btn_page,
success: function(data){
$.ajax({
var a=data; //edit data here
type: "post",
url: "example.php",
data: 'page='+a,
success: function(data){
});
});
I use $.ajax to send some data to testajax.phpenter code here where data are processing. Result of this proces is link. How to get access to this? I think about sessions or cookies. Set in session $test and get access in another files.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: console.log('success');
data: { json : jsonObj }
});
In testajax.php I have someting like this
echo "PDF: <a href=images/test.pdf>$dir.pdf</a>";
$test = "PDF: <a href=images/test.pdf>$dir.pdf</a>";
How to get the $test or output the echo after call $.ajax
You can use success' function to get request from PHP.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'html',
data: { json : jsonObj }
success: function(data) {
var request = data;
console.log(data);
$('#link_container').html(data);
}
});
Your console now holds PDF: <a href=images/test.pdf>($dir content).pdf</a>.
Also the variable request holds the same result that you can use anywhere in the script.
Result is appended to #link_container.
Use the success() method for display the result.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
success: function (data){ // <= define handler for manupulate the response
$('#result').html(data);
}
data: { json : jsonObj }
});
Use below code It may help you.
$.ajax({
url: 'testajax.php',
type: 'post',
dataType: 'json',
data: { json : jsonObj },
onSuccess: successFunc,
onFailure: failureFunc
});
function successFunc(response){
alert(response);
}
function failureFunc(response){
alert("Call is failed" );
alert(response);
}
I am performing delete records by using jquery ajax in php. I want to refresh that content without the use of location.reload() function. I tried this,
$("#divSettings").html(this);
but, it's not working. What's the correct logic to get updated content in div.
Thanks.
Code:
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
location.reload();
//$("#divSettings").html(this);
}
});
}
You're almost there:
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
$("#divSettings").html(result); // <-- result must be your html returned from ajax response
}
});
}
You just needed to set the result into your '#divSettings' element using the .html() function :
$('#divSettings').html(result);
So a full example would look like :
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
//Sets your content into your div
$('#divSettings').html(result);
}
});
}
I believe you have to clear the section first and then you can attach the HTML again. Like
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
//Sets your content into your div
$('#divSettings').html("");
$('#divSettings').html(result);
}
});
}
I believe this way you won't see the old content.
I want to ignore tags like divs and scripts and just get the json texts.
my ajax call doesnt work if i have none json format texts. but i think it would be pointless if you have a page with pure json format only.
My ajax call
$.ajax({
url: "secpage.html",
type: "POST",
dataType: "json",
success: function(data) {
$("#load").html(data);
alert(data);
}
});
My page to be returned
<script></script>
{"msg" : "Hello"}
I want to igonre those script tags and just have the json text. plss help.
maybe something like this?
$.ajax({
url: "secpage.html",
type: "POST",
dataType: "json",
success: function(data) {
var newdata='';
data=data.split('\n');
for (var i in data) {
if (i.charAt(0)=='{'){
newdata+=i + '\n';
}
}
alert(newdata);
}
});