I have searched my problem before posting this question, but failed to find a solution.
I need to send a json string to php file but unable to do so, can some one please help with my problems below: I'm new to php and jquery and is struggling, Need your cooperation please.
I have a function that captures data on the text file:
function updateVal() {
var node_list = document.getElementsByTagName('input');
var c = 0;
var fieldName = [];
var fieldText = []
var ID = [];
for (var i = 0; i < node_list.length; i++) {
var node = node_list[i];
if (node.getAttribute('type') == 'text') {
fieldName[c] = node.name;
fieldText[c] = node.value;
ID[c] = node.id;
c++;
}
}
var postData = {
fieldName: fieldName,
fieldText: fieldText,
ID: ID
};
var dataString = JSON.stringify(postData);
console.log(JSON.stringify(postData));
$.ajax({
type: "POST",
dataType: "json",
url: "update.php",
data: {myData:postData}
})
//return JSON.stringify(postData);
}
My update.php is like this:
<?php
$json = $_POST['json'];
$result = json_decode($json);
echo $result;
echo $_POST['myData']);?>
On loading this: I'm getting the following error:
Failed to load resource: the server responded with a status of 500 (Internal Server Error)
Moreover, I'm not sure if the data being sent to php or not.
Can experts pls validate.
The 500 (internal server error) means something went wrong on the server's side. So check the apache error log for more details
you may find apache log here /var/log/apache2/
On client side (javascript code):
data: JSON.stringify(postData)
On server side (PHP code):
json_decode($_POST["data"])
u commented the closing braces of the function with the return statement.
change this :
//return JSON.stringify(postData);}
to:
//return JSON.stringify(postData);
}
Also :
data: JSON.stringify(postData),
IN update.php
$json = $_POST['myData'];
$result = json_decode($myData);
var_dump($result);
Comment from #Tushar helped me resolving the issue
contentType: 'application/x-www-form-urlencoded; charset=UTF-8', data: {json: JSON.stringify(postData)
sent Ajax request to php Page to Get data
$.ajax({ method: "POST", // it may be Get url: "some.php", //page where you sent request data: { name: "John", location: "Boston" } //attibutes you want to take on that page }) .done(function( msg ) { // sucessfull reponse alert( "Data Saved: " + msg ); });
Related
I am trying to transfer a javascript array to a php array and I used the following code in my php file to do so:
var rowArr=[];
var currow=$(this.closest('tr'));
var col1=currow.find('td:eq(0)').text();
rowArr.push(col1);
var col2=currow.find('td:eq(1)').text();
rowArr.push(col2);
var col3=currow.find('td:eq(2)').text();
rowArr.push(col3);
var myJSONText = JSON.stringify( rowArr );
$.ajax({
type: "POST",
url: "jsonRecieve.php",
data: { emps : myJSONText},
success: function() {
alert("Success");
}
});
so when I run this code, I get the success alert but I am not seeing any of the array elements being printed out. I am also not getting any error messages.Here is my jsonRecieve.php:
<?php
$rowAr=$_POST['emps'];
print_r($rowAr);
?>
is there a way to verify that it has been transferred? I don't believe it has but if it hasn't can someone help?
Seems you need to decode the json string with json_decode() to get your emps value on the server side and to alert the server response need to send something from the server. Let's debug this way-
ON JS
$.ajax({
type: "POST",
url: "jsonRecieve.php",
data: { emps : myJSONText},
success: function(data) {
alert(data); // alert your data to see that returns from server
}
ON PHP
<?php
$rowAr=$_POST['emps'];
$array = json_decode($rowAr,1); // 2nd params 1 means decode as an array
print_r($array);
die('response from the server');
?>
I'm using a Json in my HTML to get data from Database but I can't access the data of returned Json here is my HTML function :
$.ajax({
type: "POST",
url: 'fetch.php',
dataType: 'json',
data: {func:"viewCert",tracking_code:tracking_code},
success: function (data) {
if (data!=null) {
document.getElementById("generation_date").textContent = data.certInfo.timestamp;
} else {
alert("Something's Wrong! Try Later");
window.location = "../views/failed.html";
}
}
});
and here is fetch.php function :
function viewCert($tracking_code) {
$connect = connection();
$connect->set_charset("utf8");
$sql = "SELECT timestamp FROM certificate WHERE tracking_code=?";
$result = $connect->prepare($sql);
$result->bind_param("s",$tracking_code);
$result->execute();
$res=$result->get_result();
while ($row=$res->fetch_object()) {
$output[]=$row;
}
echo json_encode(array('certInfo' => $output));
}
Sorry for this question I'm just new in HTML and Javascript , so anyone know why timestamp won't be set in 'generation_date' element?
any help will be much appreciated
In your PHP, $output seems to be an array. So in your javascript you need to access on the good index to get the data.
Try :
document.getElementById("generation_date").textContent = data.certInfo[0].timestamp;
----------------------------------------------------------------------^^^
My php is updating the table but not refreshing in javascript have tried several different ways of doing this and nothing is working.
PHP
$sql = "UPDATE INTOXDM.ASTP_FORM SET SUPERVISOR_EID = '".$newSuper."' WHERE FORMID = '".$formId."'";
$row = $xdm->fetch($sql);
$return["color"] = $row['APPRENTICE_SIGNATURE'];
$return["json"] = json_encode($return);
echo json_encode($return);
?>
Javascipt
var data = {
"formId": formID,
"newSuper": newSuper
};
data = $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "src/GetInfo.php",
data: data,
success: function() {
location.reload();
}
});
I'd start by modifing the code like this:
var data = {
"formId": formID,
"newSuper": newSuper
};
// No need for serialization here,
// the 'data' parameter of jQuery.ajax accepts JS object
// data = $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "src/GetInfo.php",
data: data,
// As suggested by Rocket Hazmat, try to add an error callback here
error: function(jQueryXHR, textStatus, errorMessage) {
console.log("Something went wrong " + errorMessage);
},
success: function(jsonResponse) {
// Try to reference the location object from document/window
// wd = document or window as seen here http://stackoverflow.com/questions/2624111/preferred-method-to-reload-page-with-javascript
// Also watch out, usually browsers require a user confirmation before reloading if the page contains POST data
// One of these should be fine
wd.location.assign(wd.location.href) : go to the URL
wd.location.replace(wd.location.href) : go to the URL and replace previous page in history
wd.location.reload(<true/false/blank>) : reload page from server/cache/cache
}
});
Also, this might be a shot in the dark but the parameter dataType gave me problems sometime in the past, so if you are sure about the json returned by your php script, you could use the eval function to jsonify the response
$.ajax({
...
// Remove data type
// dataType: "json",
...
success: function(plainTextResponse) {
// Eval response, NOT SAFE! But working
var jsonResponse = eval('('+ plainTextResponse +')');
...
}
});
Your ajax is expecting json data and your php is sending malformed json string. Send a correct json string and your script will work fine.
Your php json_encode should be like this:
$data = json_encode($return);
echo $data;
I have a select list where in using javascript i get the selected values i want this selected values to pass through php file init.php so that i can use those variables in mysql query.
my javascript code is as follows:
$(document).ready(function(){
var e = document.getElementById("product");
var pro = e.options[e.selectedIndex].text;
alert(pro);
});
$('select').change(function(){
var e = document.getElementById("city");
var cit = e.options[e.selectedIndex].text;
alert(cit);
I have used ajax to send variables to init.php. my ajax code below is not working,can anyone tell whats the issue in this code:
$.ajax({
url: 'init.php',
type: 'POST',
data: { x:'cit',y:'pro' },
success: function(data) {
console.log(data);
}
});
and in init.php i have written :
<?php
$var1 = $_POST['y'];
$var2 = $_POST['x'];
$result = "Select amount from ". _DB_PREFIX_ ."demo_detail where product = '". $var1 ."' and city = '" . $var2 . "' ";
//echo json_encode($result);
Can you alter the url line to include the / to make sure that you're referring init.php relative to the root of your directory?
So it should look like this:
$.ajax({
url: '/init.php',
type: 'POST',
data: { x:'cit',y:'pro' },
success: function(data) {
console.log(data);
}
});
I don't know enough to say for sure but there's a chance that AJAX is making a POST request to the wrong URL.
Have you tried to pass absolute as well as relative path in url. What I mean is
have you tried using:
url:'localhost:xxxx/myapp/init.php'
or
url:'/init.php'
If you're passing variables into the data parameter in Ajax, they don't have to be in quotes.
$.ajax({
url: 'init.php',
type: 'POST',
data: { x: cit, y: pro },
success: function(data) {
console.log(data);
}
});
Use Query String. HTML5's Session Storage can also help you.
Try to replace your script code with following and see if it makes a difference
$(document).ready(function(){
$('select').change(function(){
var e = document.getElementById("product");
var pro = e.options[e.selectedIndex].text;
alert(pro);
var e = document.getElementById("city");
var cit = e.options[e.selectedIndex].text;
alert(cit);
$.ajax({
type: 'POST',
url: 'init.php',
data: { x:'cit',y:'pro' },
success: function(data) {
console.log(data);
}
});
});
});
First part is completed, The data is successfully sent to php using ajax as json (I did it by following an answer to an already posted question on this site).
Now how to access these values in php, and after using the string in abc[2] as sql query and printing the result in php(second page) using html in a table format (in second page), how to receive that response after ajax call completes in first page to show it in a div in first page.
Actually I am not asking about the procedure of running query and displaying values.
I am facing problem in accessing these array values in php and displaying them back in first page using ajax.
whenever I return some value from first page (using echo or print function), I receive an alert about syntax error: unexpected tocken after the ajax call comes back from second page. The code in first page is
var abc= {};
abc[0] = {};
abc[0]['name'] = 'first col';
abc[0]['width'] = 123;
abc[1] = {};
abc[1]['name'] = 'second col';
abc[1]['width'] = 456;
abc[2]="abcdefghijklmnopqrstuvwxyz";
$.ajax(
{
type: "POST",
url: "query.php",
data: {abc: abc},
dataType: "json",
beforeSend:function()
{
// Do something before sending request to server
},
error: function(jqXHR, textStatus, errorThrown)
{
alert(errorThrown);
},
success: function(data)
{
alert(data);
}
});
I don't know exactly...
you can try this one..
$param = cleanAll();
You can do it in this way :
Send parameter to your query.php file using ajax.
In query.php file write logic to process on posted data save/edit/fetch data from/to DB
and create html to print in div and echo that html
Inside your ajax call when success put that html to div which is returned from query.php.
Here are few changes on your ajax code:
Array will like this
var abc= {abc :[{name:'first col',width:123},{name:'second col',width:456},{name:"abcdefghijklmnopqrstuvwxyz",width:456}] };
Ajax will like this
$.ajax(
{
type: "POST",
url: "query.php",
data: abc,
dataType: "json",
beforeSend:function()
{
// Do something before sending request to server
},
error: function(jqXHR, textStatus, errorThrown)
{
alert(errorThrown);
},
success: function(my_html)
{
$('#my_div').val(my_html);
}
});
Code is not tested but it should work.
As I understand from my recent experiment, array will be placed to object before converting to JSON. Below my code:
JavaScript:
...
var read_numbers = new Array();
...
function read_ajax_done(num, num_in_word){
rec_count_in_cache = rec_count_in_cache + 1;
var number = {"num" : "", "word" : ""}; // Object type
number.num = num;
number.word = num_in_word;
read_numbers[rec_count_in_cache-1] = number; // Array is multidimensional
}
function save_to_db(read_numbers) {
var object_read_numbers = {"read_numbers" : read_numbers}; // Array placed to object
JSON_read_numbers = JSON.stringify(object_read_numbers); // Object converted to JSON
request = $.ajax({
type : "POST",
url : "post.php",
data : {read_numbers : JSON_read_numbers}
});
request.done(function(msg) {
alert("Respond: "+ msg);
});
request.fail(function(jqXHR, textStatus) {
alert("Function inaccessible: " + textStatus)
});
}
PHP:
if (isset($_POST["read_numbers"])) {
$read_numbers = json_decode($_POST["read_numbers"], TRUE);
.....
$response = $read_numbers["read_numbers"][n]["word"];
}
echo $response;
Second Page PHP
<?php
//need for displaying them back to the $.ajax caller
header('Content-type: application/json');
//accessing data
$post = $_POST['abc'];
/*
* how to access multid array
* $post[0]['name'] = 'first col'
* $post[0]['width'] = 123
* $post[1][name] = 'second col'
* $post[2] = 'abcdefghijklmnopqrstuvwxyz'
*/
//now to pass them back to your $.ajax caller
echo json_encode($post);
?>
First Page
$.ajax(
{
type: "POST",
url: "query.php",
data: {abc: abc},
dataType: "json",
success: function(data)
{
//prints your response variable
console.log(data);
}
});