I recently download this Slideshow with jmpress.js for a website. I'm using PHP and a database in MYSQL. I used a recordset in Dreamweaver to get the data from database to the site. Then I tried to create a Repeat Region to show the latests posts in the slider.
Headings, images and text are working fine. The problem is on the href (links), which are not changed and remain the same (the ID of the latest post) for all records.
In the head I have these files:
SlideshowJmpress/css/style.css
http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js
SlideshowJmpress/js/jmpress.min.js
SlideshowJmpress/js/jquery.jmslideshow.js
SlideshowJmpress/js/modernizr.custom.48780.js
Here is the HTML Code:
<section id="jms-slideshow" class="jms-slideshow">
<?php do { ?>
<div class="step" data-color="color-1">
<div class="jms-content">
<h3><?php echo $row_slider['packageTitle']; ?></h3>
<p><?php echo $row_slider['packageDescription']; ?></p>
<a class="jms-link" href="article.php?ID=<?php echo $row_slider['ID']; ?>">Read more</a>
</div>
<img src="<?php echo $row_slider['packageGraphic']; ?>" width="300px;" height="300px;" />
</div>
<?php } while ($row_slider = mysql_fetch_assoc($slider)); ?>
</section>
<script type="text/javascript">
$(function() {
$( '#jms-slideshow' ).jmslideshow({
});
});
</script>
Here is the php code for the recordset:
$maxRows_slider = 4;
$pageNum_slider = 0;
if (isset($_GET['pageNum_slider'])) {
$pageNum_slider = $_GET['pageNum_slider'];
}
$startRow_slider = $pageNum_slider * $maxRows_slider;
mysql_select_db($database_nipvlach, $nipvlach);
$query_slider = "SELECT * FROM pages ORDER BY `date` DESC";
$query_limit_slider = sprintf("%s LIMIT %d, %d", $query_slider, $startRow_slider, $maxRows_slider);
$slider = mysql_query($query_limit_slider, $nipvlach) or die(mysql_error());
$row_slider = mysql_fetch_assoc($slider);
if (isset($_GET['totalRows_slider'])) {
$totalRows_slider = $_GET['totalRows_slider'];
} else {
$all_slider = mysql_query($query_slider);
$totalRows_slider = mysql_num_rows($all_slider);
}
$totalPages_slider = ceil($totalRows_slider/$maxRows_slider)-0;
Error is either in IDs in your DB or in the slideshow script i think.
Look at source of your page. Are the links right ?
I think that the problem is in the script or in the jmpress.min.js
When I changed slider, everything worked fine!
Related
The images are fetched from the PHP PDO database from the directory "Images" where there are multiple images in it using SQL queries. When I try to click on the source link of the image and try to open the modal image, only the first image is been viewed by all other images too. I tried to change the ID names, but still it is showing the same first page. I have attached my code and the output below. Requesting anyone to help me in this and also the procedure to change the ID values.
if($data=$stmt->fetchAll(PDO::FETCH_ASSOC)) // to display all the images from the given condition
{
$link_id=0;
foreach($data as $row)
{
//$img=$row['images'];
$id=$row['id'];
$link_id=$link_id+1;
$query="SELECT images FROM pictures WHERE id=$id";
$stmt2=$conn->query($query);
$pictures=$stmt2->fetchAll(PDO::FETCH_ASSOC);
foreach($pictures as $rowimg)
{
$img=$rowimg['images'];
?>
<b><a id='<?php echo $link_id;?>' class='link_class' onclick='myfunc();'> <?php echo $img;?> </a></b>
<br><br>
<div id='modal_id' class='modal_class'>
<div class='modal_content_class'>
<img id='<?php echo $id;?>' class='img_class' src="images/<?php echo $img;?>" width='300' height='260'>
<span id='close_id' class='close_class' onclick="modal.style.display='none'">×</span>
</div>
</div>
<script>
var modal = document.getElementById("modal_id");
var closebtn =modal.getElementsByClassName("close_class");
function myfunc()
{
modal.style.display='block';
document.getElementById('<?php echo $id; ?>'). src="images/<?php echo $img;?>";
console.log(123);
};
</script>
}
}
}
Output
Output
I use a foreach loop to get some tabs with different id's. This way I get tabs with ids tab1, tab2, tab3, etc. Than, when I want to get the id of each tab using javascript, it returns only the id of the first tab and uses this for all tabs. It does not loop as php do. Why?
<?php
foreach ($DB_con->query($foos) as $foo) {
?>
<div id='tab<?php echo $counter_foo; ?>'>
<div id="divid" style="visibility: hidden"><?php echo $counter_foo; ?></div>
<script>
$(document).ready(function() {
var dividvalue = document.getElementById('divid').innerHTML;
alert(dividvalue);
});
</script>
<?php
}
?>
Change the id in your HTML to class, and use getElementsByClassName instead of getElementById your in JavaScript.
Your div:
<div class="divid"> <!-- etc -->
and your JS..
var dividvalue = document.getElementsByClassName('divid')[0].innerHTML;
Also consider changing divid to divclass for consistency's sake.
Full edited code:
<script>
var i = 0;
</script>
<?php
foreach ($DB_con->query($foos) as $foo) {
?>
<div id='tab<?php echo $counter_foo; ?>'>
<div class="divclass" style="visibility: hidden"><?php echo $counter_foo; ?></div>
<script>
$(document).ready(function() {
var divclassvalue = document.getElementsByClassName('divclass')[i].innerHTML;
alert(divclassvalue);
i++;
});
</script>
<?php
}
?>
I made a simple image gallery, I'm adding a password protected upload. With some help I'm using this php (thanks to sulthan-allaudeen). Attached the code I'm using.
The problem is that I can't find a way to have on the left side the thumbnails of all the images in the folder, but with this code I have the full-width images only. any idea?
thanks
<body>
<div id="containerfoto">
<div id="gallery">
<div id="minipics">
<?php
$dir = 'Images/photo/';
$files = scandir($dir);
$i = 1;
foreach ($files as $key)
{
if ($i>3)
{
$j = $i-3;
echo "<a href='Images/photo/".$key."'><img src ='Images/photo/".$key."'>".$key."</a>";
}
$i++;
}
?>
<div style="clear:left"> </div>
</div>
<div id="zoom">
<img src="Images/foto/foto7.jpg" id="bigimage" alt="">
<h3 id="titolo">Click to enlarge images.</h3>
</div>
</div>
</div>
<script>
window.onload=function(){
if(!document.getElementById || !document.getElementsByTagName) return;
links=document.getElementById("minipics").getElementsByTagName("a");
for(i=0;i<links.length;i++)
links[i].onclick=function(){Show(this);return(false)}
}
function Show(obj){
bigimg=document.getElementById("bigimage");
bigimg.src=obj.getAttribute("href");
smallimg=obj.getElementsByTagName("img")[0];
t=document.getElementById("titolo");
t.removeChild(t.lastChild);
t.appendChild(document.createTextNode(smallimg.title));
}
</script>
</body>
Scandir() put's the file names within your directory into an array. Therefore, we can print each image using a for loop. I've given you an example below:
<?php
$dir = 'Images/photo/';
$files = scandir($dir);
for($number = 0; $number <= count($files); $number++) { ?>
<div class="thumbnail">
<img src="<?php echo $dir; echo $files{$number} ?>">
</div>
<?php } ?>
Now you just need to apply some css to the .thumbnail class and it should do the trick. For starters, you just need to apply some width and height to .thumbnail img, let me know if you need help with that too.
I have a div containing php that loads a random image from a directory. This bit works fine when i reload the page. The code:
<div id="imageArea">
<?php
$dir = 'images/assets/';
$images = scandir($dir);
$i = rand(2, sizeof($images)-1);
?>
<img src="images/assets/<?php echo $images[$i]; ?>" alt="<?php echo str_replace(array('.jpg', '.png', '.gif'), '', $images[$i]); ?>"/>
</div>
And further down the page i have another div that contains a button. I want it so that when people click this button it loads a new random image, i guess it would reload the div, but i don't want it to reload the page, is that possible? The button:
<div id="newPic">
<input type="button" value="Reload" id="Reload"/>
</div>
I have tried:
<script>
$(document).ready(function(){
$("#Reload").click(function(){
$("#imageArea").html("result reloaded successfully");
});
});
</script>
and:
$(document).ready(function(){
$("#Reload").click(function(){
$("#imageArea").html(ajax_load).load(loadUrl);
});
});
I am new to php and javascript and so i have been following other peoples instructions.
Thank you
split your php script to another file (just echo the img tag), and then use ajax to call that page.
$("#reload").click(function(){
$.ajax({
url:"demo.php",success:function(ajax_load){
$("#imageArea").html(ajax_load)
}});
});
php file
<?php
$dir = 'images/assets/';
$images = scandir($dir);
$i = rand(2, sizeof($images)-1);
?>
<img src="images/assets/<?php echo $images[$i]; ?>" alt="<?php echo str_replace(array('.jpg', '.png', '.gif'), '', $images[$i]); ?>"/>
have you tried to use ajax to update the div with the image?
here's the code
$(document).ready(function(){
$('#clickme').click(function(){
var number = 1 + Math.floor(Math.random() * 10);
$('#contentimg').attr('src','0'+number+'.jpg');
});
});
this would work given that the images are in the same folder else give the src of image accordingly
I tried to implement this mode here http://wordpressthemescollection.com/ajax-wordpress-post-popup-with-simplemodal-and-jquery-488.html but nothing seems to work.
This is what I do.
1 / Include in header
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type="text/javascript" src="<?php bloginfo("template_url"); ?>/js/jquery.simplemodal.js"></script>`
The links are goods cause I checked them both.
2 / Include in header this script
<script>
jQuery(document).ready(function() {
jQuery('a.postpopup').live('click', function(){
var id = jQuery(this).attr('rel');
jQuery('<div id="ajax-popup"></div>').hide().appendTo('body').load('<?php bloginfo('url')?>/ajax/?id='+id).modal({
opacity:90,
position: ["0%"],
overlayClose:true
});
return false;
});
});
</script>
3 / Make a custom template with this code
<?php
/*
Template Name: Ajax
*/
?>
<?php
$post = get_post($_GET['id']);
?>
<?php if ($post) : ?>
<?php setup_postdata($post); ?>
<div class="whatever">
<h2 class="entry-title"><?php the_title() ?></h2>
<div class="entry-content">
<?php the_content(); ?>
</div>
</div>
<?php endif; ?>
And after that made a page named Ajax and assign the template Ajax.
4 / Implement a link
this link
If i click on the link nothing happens.
What did I do wrong cause I did not have a clue about it?
Thanks.
jQuery .load() is ajax and so you need to do any subsequent things in a callback like this:
var $ajax-div = jQuery('<div id="ajax-popup"></div>').hide().appendTo('body');
var url = '<?php bloginfo('url')?>/ajax/?id=' + id;
$ajax-div.load(url), function() {
// the callback
jQuery('#ajax-popup').modal({
opacity: 90,
position: ["0%"],
overlayClose:true
});
});
when you create an new post or page content on wordpress admin, select the "Ajax" template for your page