I made a simple image gallery, I'm adding a password protected upload. With some help I'm using this php (thanks to sulthan-allaudeen). Attached the code I'm using.
The problem is that I can't find a way to have on the left side the thumbnails of all the images in the folder, but with this code I have the full-width images only. any idea?
thanks
<body>
<div id="containerfoto">
<div id="gallery">
<div id="minipics">
<?php
$dir = 'Images/photo/';
$files = scandir($dir);
$i = 1;
foreach ($files as $key)
{
if ($i>3)
{
$j = $i-3;
echo "<a href='Images/photo/".$key."'><img src ='Images/photo/".$key."'>".$key."</a>";
}
$i++;
}
?>
<div style="clear:left"> </div>
</div>
<div id="zoom">
<img src="Images/foto/foto7.jpg" id="bigimage" alt="">
<h3 id="titolo">Click to enlarge images.</h3>
</div>
</div>
</div>
<script>
window.onload=function(){
if(!document.getElementById || !document.getElementsByTagName) return;
links=document.getElementById("minipics").getElementsByTagName("a");
for(i=0;i<links.length;i++)
links[i].onclick=function(){Show(this);return(false)}
}
function Show(obj){
bigimg=document.getElementById("bigimage");
bigimg.src=obj.getAttribute("href");
smallimg=obj.getElementsByTagName("img")[0];
t=document.getElementById("titolo");
t.removeChild(t.lastChild);
t.appendChild(document.createTextNode(smallimg.title));
}
</script>
</body>
Scandir() put's the file names within your directory into an array. Therefore, we can print each image using a for loop. I've given you an example below:
<?php
$dir = 'Images/photo/';
$files = scandir($dir);
for($number = 0; $number <= count($files); $number++) { ?>
<div class="thumbnail">
<img src="<?php echo $dir; echo $files{$number} ?>">
</div>
<?php } ?>
Now you just need to apply some css to the .thumbnail class and it should do the trick. For starters, you just need to apply some width and height to .thumbnail img, let me know if you need help with that too.
Related
The images are fetched from the PHP PDO database from the directory "Images" where there are multiple images in it using SQL queries. When I try to click on the source link of the image and try to open the modal image, only the first image is been viewed by all other images too. I tried to change the ID names, but still it is showing the same first page. I have attached my code and the output below. Requesting anyone to help me in this and also the procedure to change the ID values.
if($data=$stmt->fetchAll(PDO::FETCH_ASSOC)) // to display all the images from the given condition
{
$link_id=0;
foreach($data as $row)
{
//$img=$row['images'];
$id=$row['id'];
$link_id=$link_id+1;
$query="SELECT images FROM pictures WHERE id=$id";
$stmt2=$conn->query($query);
$pictures=$stmt2->fetchAll(PDO::FETCH_ASSOC);
foreach($pictures as $rowimg)
{
$img=$rowimg['images'];
?>
<b><a id='<?php echo $link_id;?>' class='link_class' onclick='myfunc();'> <?php echo $img;?> </a></b>
<br><br>
<div id='modal_id' class='modal_class'>
<div class='modal_content_class'>
<img id='<?php echo $id;?>' class='img_class' src="images/<?php echo $img;?>" width='300' height='260'>
<span id='close_id' class='close_class' onclick="modal.style.display='none'">×</span>
</div>
</div>
<script>
var modal = document.getElementById("modal_id");
var closebtn =modal.getElementsByClassName("close_class");
function myfunc()
{
modal.style.display='block';
document.getElementById('<?php echo $id; ?>'). src="images/<?php echo $img;?>";
console.log(123);
};
</script>
}
}
}
Output
Output
I am checking if there is a Thumbnail image in a blog post using has_post_thumbnail(), if no thumbnail image, a JavaScript script function is called to change the layout of .blog-post to display from flex to block.
To do this: I am using a JavaScript function with the conditional statement. Like below:
content.php
<div class="blog-post">
<?php /* POST FEATURED THUMBNAIL*/
if(has_post_thumbnail()) { ?>
<div class="post-thumbnail">
<?php the_post_thumbnail('feature-image'); ?>
</div>
<?php } else { ?>
<script type="text/javascript"> alert("asdsas"); xfullWidthPostWithThumbnail(); </script>
<?php } ?>
<article class="post-article para-text">
<p id="blog-title"><?php the_title(); ?></p>
<p id="blog-info-text"><?php the_time('F jS, Y'); ?> | By <?php the_author();?> | Posted In
<?php
$categories = get_the_category();
$seperator = ", ";
$output = '';
if($categories) {
foreach ($categories as $category) {
$output .= '' . $category->cat_name . '' . $seperator;
}
echo trim($output, $seperator);
}
?></p>
<p><?php echo get_the_excerpt(); ?> Read more »</p>
<p></p>
</article>
</div>
JavaScript function
/* INDEX PAGE -- ADD DISPLAY BLOCK FOR FULL WIDTH OF POST EXCERPT IF NOT POST THUMBNAIL */
function xfullWidthPostWithThumbnail() {
alert("hhhhhhhhhhhhhhhh");
jQuery(".blog-post").css("display","block !important");
jQuery(".blog-post").css("color","red !important");
}
The problem: Currently the error I am getting:
Uncaught ReferenceError: xfullWidthPostWithThumbnail is not defined
at (index):155
Why is the function not defined? Any ideas??
There is no need to use Javascript to do this - its adding unnecessary processing on the client side.
All you want to do is change the CSS for .blog-post, so create a separate CSS class, and apply it if there is no thumbnail.
Create a new CSS class for the rules you want to apply
Check if the thumbnail exists.
If it doesn't, add your new class to the div
If it does, display as normal
CSS:
Create a class called no_thumbnail to add your styles. FYI You should avoid using !important.
.blog-post.no_thumbnail{
display: block !important;
color: red !important;
}
PHP:
/* declare a variable for your extra class */
$blogpostclass = "";
/* If thumbnail doesn't exist, add your 'no_thumbnail' class */
if(!has_post_thumbnail()) $blogpostclass = "no_thumbnail"; ?>
/* add the class variable to your blog-post div */
<div class="blog-post <?php echo $blogpostclass; ?>">
/* If there is a thumbnail, add it as usual */
<?php
if(has_post_thumbnail()) { ?>
<div class="post-thumbnail">
<?php the_post_thumbnail('feature-image'); ?>
</div>
<?php } ?>
[...]
</div>
you should do in this way
$("".blog-post"").css("display","block !important");
I use a foreach loop to get some tabs with different id's. This way I get tabs with ids tab1, tab2, tab3, etc. Than, when I want to get the id of each tab using javascript, it returns only the id of the first tab and uses this for all tabs. It does not loop as php do. Why?
<?php
foreach ($DB_con->query($foos) as $foo) {
?>
<div id='tab<?php echo $counter_foo; ?>'>
<div id="divid" style="visibility: hidden"><?php echo $counter_foo; ?></div>
<script>
$(document).ready(function() {
var dividvalue = document.getElementById('divid').innerHTML;
alert(dividvalue);
});
</script>
<?php
}
?>
Change the id in your HTML to class, and use getElementsByClassName instead of getElementById your in JavaScript.
Your div:
<div class="divid"> <!-- etc -->
and your JS..
var dividvalue = document.getElementsByClassName('divid')[0].innerHTML;
Also consider changing divid to divclass for consistency's sake.
Full edited code:
<script>
var i = 0;
</script>
<?php
foreach ($DB_con->query($foos) as $foo) {
?>
<div id='tab<?php echo $counter_foo; ?>'>
<div class="divclass" style="visibility: hidden"><?php echo $counter_foo; ?></div>
<script>
$(document).ready(function() {
var divclassvalue = document.getElementsByClassName('divclass')[i].innerHTML;
alert(divclassvalue);
i++;
});
</script>
<?php
}
?>
I recently download this Slideshow with jmpress.js for a website. I'm using PHP and a database in MYSQL. I used a recordset in Dreamweaver to get the data from database to the site. Then I tried to create a Repeat Region to show the latests posts in the slider.
Headings, images and text are working fine. The problem is on the href (links), which are not changed and remain the same (the ID of the latest post) for all records.
In the head I have these files:
SlideshowJmpress/css/style.css
http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js
SlideshowJmpress/js/jmpress.min.js
SlideshowJmpress/js/jquery.jmslideshow.js
SlideshowJmpress/js/modernizr.custom.48780.js
Here is the HTML Code:
<section id="jms-slideshow" class="jms-slideshow">
<?php do { ?>
<div class="step" data-color="color-1">
<div class="jms-content">
<h3><?php echo $row_slider['packageTitle']; ?></h3>
<p><?php echo $row_slider['packageDescription']; ?></p>
<a class="jms-link" href="article.php?ID=<?php echo $row_slider['ID']; ?>">Read more</a>
</div>
<img src="<?php echo $row_slider['packageGraphic']; ?>" width="300px;" height="300px;" />
</div>
<?php } while ($row_slider = mysql_fetch_assoc($slider)); ?>
</section>
<script type="text/javascript">
$(function() {
$( '#jms-slideshow' ).jmslideshow({
});
});
</script>
Here is the php code for the recordset:
$maxRows_slider = 4;
$pageNum_slider = 0;
if (isset($_GET['pageNum_slider'])) {
$pageNum_slider = $_GET['pageNum_slider'];
}
$startRow_slider = $pageNum_slider * $maxRows_slider;
mysql_select_db($database_nipvlach, $nipvlach);
$query_slider = "SELECT * FROM pages ORDER BY `date` DESC";
$query_limit_slider = sprintf("%s LIMIT %d, %d", $query_slider, $startRow_slider, $maxRows_slider);
$slider = mysql_query($query_limit_slider, $nipvlach) or die(mysql_error());
$row_slider = mysql_fetch_assoc($slider);
if (isset($_GET['totalRows_slider'])) {
$totalRows_slider = $_GET['totalRows_slider'];
} else {
$all_slider = mysql_query($query_slider);
$totalRows_slider = mysql_num_rows($all_slider);
}
$totalPages_slider = ceil($totalRows_slider/$maxRows_slider)-0;
Error is either in IDs in your DB or in the slideshow script i think.
Look at source of your page. Are the links right ?
I think that the problem is in the script or in the jmpress.min.js
When I changed slider, everything worked fine!
I have a div containing php that loads a random image from a directory. This bit works fine when i reload the page. The code:
<div id="imageArea">
<?php
$dir = 'images/assets/';
$images = scandir($dir);
$i = rand(2, sizeof($images)-1);
?>
<img src="images/assets/<?php echo $images[$i]; ?>" alt="<?php echo str_replace(array('.jpg', '.png', '.gif'), '', $images[$i]); ?>"/>
</div>
And further down the page i have another div that contains a button. I want it so that when people click this button it loads a new random image, i guess it would reload the div, but i don't want it to reload the page, is that possible? The button:
<div id="newPic">
<input type="button" value="Reload" id="Reload"/>
</div>
I have tried:
<script>
$(document).ready(function(){
$("#Reload").click(function(){
$("#imageArea").html("result reloaded successfully");
});
});
</script>
and:
$(document).ready(function(){
$("#Reload").click(function(){
$("#imageArea").html(ajax_load).load(loadUrl);
});
});
I am new to php and javascript and so i have been following other peoples instructions.
Thank you
split your php script to another file (just echo the img tag), and then use ajax to call that page.
$("#reload").click(function(){
$.ajax({
url:"demo.php",success:function(ajax_load){
$("#imageArea").html(ajax_load)
}});
});
php file
<?php
$dir = 'images/assets/';
$images = scandir($dir);
$i = rand(2, sizeof($images)-1);
?>
<img src="images/assets/<?php echo $images[$i]; ?>" alt="<?php echo str_replace(array('.jpg', '.png', '.gif'), '', $images[$i]); ?>"/>
have you tried to use ajax to update the div with the image?
here's the code
$(document).ready(function(){
$('#clickme').click(function(){
var number = 1 + Math.floor(Math.random() * 10);
$('#contentimg').attr('src','0'+number+'.jpg');
});
});
this would work given that the images are in the same folder else give the src of image accordingly